:tan θ = sin θ / cos θ = (1/3) / [(2/3)√2] = √2 / 2cot θ = cos θ / sin θ = [(2/3)√2] / (1/3) = 2√2sec θ = 1 / cos θ = √3 / (2√2) = √6 / 4cosec θ = 1 / sin θ = 3cos θ = (2/3)√2tan θ = √2 / 2cot θ = 2√2sec θ = √6 / 4cosec θ = 3
Answer:Given, csc θ = 3 and θ lies in [0, π/2]We need to find the values of the remaining 5 trigonometric functions.Here is how we can find them:We know that csc θ = 3. csc θ = 1/sin θ. Hence, we can say sin θ = 1/csc θ = 1/3.In the first quadrant, sin θ is positive (All are positive except tan θ and cot θ). Hence, sin θ = 1/3, and cos θ = √(1 - sin²θ) = √(1 - 1/9) = √8/3 = (2/3)√2.The remaining trigonometric functions are:tan θ = sin θ / cos θ = (1/3) / [(2/3)√2] = √2 / 2cot θ = cos θ / sin θ = [(2/3)√2] / (1/3) = 2√2sec θ = 1 / cos θ = √3 / (2√2) = √6 / 4cosec θ = 1 / sin θ = 3cos θ = (2/3)√2tan θ = √2 / 2cot θ = 2√2sec θ = √6 / 4cosec θ = 3
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From 1950 and projected to 2050, the percent of women in the workforce can be modeled by w(x) = 9.42 + 8.70 ln(x) where x is the number of years past 1940.† If this model is accurate, at what rate will the percent be changing in 2039? (Round your answer to three decimal places.) %
The percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.The given function is w(x) = 9.42 + 8.70 ln(x), where x represents the number of years past 1940.
To find the rate of change of the percent in 2039, we need to find the derivative of the function with respect to x.
w(x) = 9.42 + 8.70 ln(x)
Differentiating both sides with respect to x, we get:
dw/dx = 8.70 / x
Substituting x = 99 (since 2039 is 99 years past 1940), we get:
dw/dx = 8.70 / 99
Therefore, the rate of change of the percent in 2039 is approximately 0.0879%, rounded to three decimal places.
Therefore, the percent of women in the workforce is expected to increase by 0.0879% in 2039, according to the given model.
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i need help please thanks
Tο get system B, the secοnd equatiοn in system A was replaced by the sum οf the equatiοn and the first equatiοn multiplied by -3. The sοlutiοn tο system B is the same as the sοlutiοn in system A.
What is sοlutiοn οf system οf equatiοn?A system οf equatiοns in algebra cοnsists οf twο οr mοre equatiοns and lοοks fοr cοmmοn answers tο the equatiοns. "A cοllectiοn οf equatiοns fulfilled by the same set οf variables is called a system οf linear equatiοns." Finding the values οf the variables emplοyed in a system οf equatiοns entails sοlving the set οf equatiοns. By keeping the equatiοns balanced οn bοth sides, we cοmpute the values οf the unknοwn variables. Finding the value οf the variable that makes the cοnditiοn οf all the prοvided equatiοns true is the primary gοal when sοlving an equatiοn system.
Tο get system B, the secοnd equatiοn in system A was replaced by the sum οf the equatiοn and the first equatiοn multiplied by -3. The sοlutiοn tο system B is the same as the sοlutiοn in system A.
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Of the one million items produced by a manufacturer most are defect free. But one hundred of these products are defective. An engineer created a device that sets off an alarm as soon as a defective item is detected by compute vision-controlled quality check. The manufacture wants to test the reliability of the alarm by conducting trials. When presented with a defective item, the alarm goes off 99% of the time. When presented with a defect free item, the alarm goes 1% of the time. If an item sets off the alarm, what is the probability that it is defective?
If an item sets off the alarm, the probability that it is defective is 0.0098 or 0.98%
This is a problem of conditional probability. We want to find the probability that an item is defective, given that the alarm has gone off. Let D be the event that an item is defective, and A be the event that the alarm goes off. We want to find P(D|A).
We can use Bayes' theorem to find P(D|A):
P(D|A) = P(A|D) * P(D) / P(A)
where P(A|D) is the probability that the alarm goes off given that the item is defective, P(D) is the prior probability that an item is defective, and P(A) is the probability that the alarm goes off.
We are given that:
P(A|D) = 0.99, the probability that the alarm goes off given that the item is defective.
P(A|D') = 0.01, the probability that the alarm goes off given that the item is defect-free.
P(D) = 100/1000000 = 0.0001, the prior probability that an item is defective.
P(D') = 1 - P(D) = 0.9999, the prior probability that an item is defect-free.
To find P(A), we can use the law of total probability:
P(A) = P(A|D) * P(D) + P(A|D') * P(D')
= 0.99 * 0.0001 + 0.01 * 0.9999
= 0.010098
Now we can substitute these values into Bayes' theorem:
P(D|A) = P(A|D) * P(D) / P(A)
= 0.99 * 0.0001 / 0.010098
= 0.009804
Therefore, the probability that an item is defective given that the alarm goes off is approximately 0.0098 or 0.98% when rounded to two decimal places.
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A flower garden is shaped like a circle. Its diameter is 30 yd. A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 36 yd.
The gardener is going to cover the path with sand. If one bag of sand can cover 6 yd, how many bags of sand does the gardener need? Note that sand comes
only by the bag, so the number of bags must be a whole number.
A ring-shaped path goes around the circle shaped flower garden. The gardener will need total 52 bags of sand to cover the ring-shaped path with sand.
We have a circle shaped flower garden. Also, Diameter of inner circle = 30 yd
radius of inner circle, r = 30/2 = 15 yd
Diameter of outer circle = 36 yd
So radius of outer circle, R = 36/2 = 18 yd
Area of inner circle = πr²
= π(15)² = 225π yd²
Area of Outer circle = πR²
= π(18)² = 324π yd²
A ring-shaped path goes around the garden. Thus, Area of shaded region
= Outer circle area - inner circle area that is πR² - πr²
= 325 π - 225π = π(324 - 225)
= 3.14× 99 = 310.86 yd²
Since we have a bag of sand can cover 6 yard. So, number of the requirements of bags of sand is calculated as = 310.86/6
= 51.81 ~ 52
since we want whole sand bags, so total Sandbags needed is equals the 52.
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Respond to this statement: "If all circles are ellipses and all ellipses are
smooth figures, does that imply that all smooth figures are circles?"
(smooth figures have no edges)
No, the assertion does not imply that all circles are smooth forms.
What is an ellipse?The location of all the points on a plane whose sum of the distances from two fixed points in the plane is constant is known as an ellipse. The foci (singular focus), which are fixed locations that are encircled by the curve, are known. Directrix is the fixed line, and the eccentricity of the ellipse is the constant ratio.
No, the assertion does not imply that all circles are smooth forms. Since circles are a particular form of ellipse with a constant distance between any point on the circle's perimeter and its centre, they are a type of ellipse that are not all ellipses. In contrast, some ellipses seem stretched or compressed along their main and minor axes because there are two distinct distances between each point on the ellipse and its centre.
Hence an ellipse that is not a circle, such as one that is extended or flattened, can be a smooth shape. Due to the lack of any abrupt edges or line breaks, these forms are nevertheless regarded as smooth figures.
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Determine the power consumed by
The power consumed by the circuit is 512.76 watts.
What is power?The pace of work or energy transmission in an electrical circuit is known as electric power. It is a way to quantify how much energy is consumed over a certain period of time. P = VI, where V is the potential difference, I is the electric current, and P is the electric power, calculates the electric power.
The two resistors R2 and R3 are parallel.
Thus,
Req = R2 + R2 / R1R2
Req = 36 + 18 / (36)(18)
Req = 0.083
Now, the resistors R1, Req, and R4 are in series:
Thus,
R = R1 + Req + R4
R = 15 + 0.083 + 13
R = 28.083
The formula of power is:
P = V²/R
Substitute the values:
P = (120)²/ 28.083
P = 512.76 watts.
Hence, the power consumed by the circuit is 512.76 watts.
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Find the area of the triangle.
A drawing of a triangle with base of 12 and a half feet and height of 4 feet.
The two sides of a rectangle are 15cm and 20cm. Find the length of its diagonal
The length of the diagonal of the rectangle is 25cm.
The diagonal of a rectangle is the line segment that connects the two opposite vertices. It can be calculated using the Pythagorean Theorem, which states that the square of the hypotenuse (the longest side of a right triangle) is equal to the sum of the squares of the other two sides.
In this case, the length of the two sides of the rectangle are 15cm and 20cm. To calculate the diagonal of the rectangle, we need to use the Pythagorean Theorem to solve for the hypotenuse, which is the diagonal of the rectangle.
The formula is: a² + b² = c²
Using the sides of the rectangle, we get: 15² + 20² = c²
Simplifying the equation, we get: 225 + 400 = c²
Then, we take the square root of both sides of the equation to find the length of the diagonal:
√625 = c
The length of the diagonal of the rectangle is 25cm.
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The intersection of the two paths shown forms two similar triangles. If AC is 50 yards, MP is 35 yards, and the fountain is 5 yards from the intersection, about how far from the intersection is the stadium entrance? Round to the nearest yard.
The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.
What is a right triangle?A right triangle is a type of triangle that has one 90 degree angle. The other two angles are acute angles and their sum adds up to 90 degrees. The two sides that are not the right angle are called the legs and the longest side is called the hypotenuse. The Pythagorean Theorem is used to find the lengths of the sides of a right triangle.
This problem can be solved using the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Using this theorem, we can calculate the length of PC, which is then the same as the distance from the intersection to the stadium entrance.
First, we can calculate the length of CM by subtracting MP from AC, which gives us 50 - 35 = 15. We can then apply the Pythagorean Theorem to the triangle ACM to calculate the length of PC. The hypotenuse, AC, is 50, one of the other sides, CM, is 15, and the last side, the one we are trying to solve for, is PC. We can rearrange the Pythagorean Theorem to solve for PC, which gives us PC = √(AC2 - CM2). Plugging in the numbers, we get PC = √(502 - 152), which equals √(2500 - 225), or √2275. The square root of 2275 is 47.71, so the distance from the intersection to the entrance of the stadium is about 48 yards. Rounding to the nearest yard, we get 48 yards.
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11. A school is going on a field trip to the Bronx Zoo. It costs $34 for a group guided tour and
each student has to pay $8 admission. If the school has at most $450 to spend on the trip,
how many students can go on this trip?
Write and solve an inequality.
2
Inequality:
Answer:
25 POINTSSSSS!!!
The number of students who travel for the field trip is at most 52 students.
How many students can go on this trip?An inequality is a statement that of two quantities one is specifically less than or greater than another.
Cost of group guided tour = $34
Cost of each student admission = $8
Total amount spent by the school = at most $450
Number of students = x
The inequality:
34 + 8x ≤ 450
8x ≤ 450 - 34
8x ≤ 416
divide both sides by 8
x ≤ 416/8
x ≤ 52
Hence, x ≤ 52 students travel for the field trip.
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Guys I need help with this question number 4 the topic is called Simultaneous equations
Answer:
i gotchu
Step-by-step explanation:
The histogram below was obtained from data on 750 high school basketball games in a regional athletic conference. It represents the number of three- point baskets made in each game. 300 Frequency 0 1 2 3 4 5 6 7 3-point shots per game A researcher takes a simple random sample of size n= 40 from this population and calculates the mean number of 3-point baskets. Which of the following best describes the shape of the sampling distribution of means? Approximately normal Uniform Skewed right Skewed left
The correct option that describes the shape of the sampling distribution of means is: Approximately normal.
The sampling distribution of the means refers to a distribution made up of many samples. For the given problem, there are 750 basketball games, and the researcher takes a simple random sample of size n = 40 from this population and computes the mean number of three-point baskets.
The central limit theorem states that the sampling distribution of the means of any population, even those that are not normally distributed, approaches a normal distribution as the sample size grows larger. When a sample has a sample size greater than 30, the shape of the sampling distribution of the means is approximately normal.
Thus, the shape of the sampling distribution of means is Approximately normal.
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Find an equation of the line with gradient 1 and that passes through the point
(1,-4)
Submit Answer
Answer:
y = x - 5
Step-by-step explanation:
Using the 'y=mx+c' form,
Since m = 1,
y = x + c
Substituting (1, -4) into the above equation:
-4 = 1 + c
c = -5
Hence,
y = x - 5
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The cable company charges a monthly fee of $55. Each movie that you rent from the DVR cost $4.99. You owe $79.95. How many movies did you rent?
The number of movies rented was 5 to bring a total cost of $79.95
What is an equation?An equation is an expression that shows how two or more numbers and variables are related using mathematical operations of addition, subtraction, multiplication, division, exponents and so on.
Let y represent the total cost of renting x movies for one month.
The cable company charges a monthly fee of $55. Each movie that you rent from the DVR cost $4.99. Therefore:
y = 4.99x + 55
$79.95 is owed, hence:
79.95 = 4.99x + 55
4.99x = 24.95
x = 5
The number of movies rented was 5.
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the sum of the areas of two squares on the legs (a and b) equals the area of the square on the hypotenuse (c)??????
This is known as the Pythagorean Theorem and states that the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).
What is area?Area is a measure of the size of a surface or space. It is typically measured in two-dimensional units such as square meters, square kilometers, and acres. Area is also used to measure the size of three-dimensional objects such as cubes and spheres. Area is a fundamental concept in mathematics and is often used to calculate the perimeter, circumference, and volume of shapes. In physics, area is used to measure the amount of energy an object absorbs or releases.
This theorem is one of the most famous theorems in mathematics, and is found in several ancient mathematical texts, including those from the Babylonians and Chinese. The theorem is attributed to the Greek mathematician Pythagoras, who lived in the 6th century BC.
The theorem can be expressed in the equation [tex]a^{2}+ b^{2} = c^{2}[/tex], where a and b are the lengths of the two legs of the right triangle and c is the length of the hypotenuse. This equation can be used to calculate the length of the hypotenuse if the lengths of the two other sides are known. For example, if the two legs of a right triangle have lengths of 3 and 4, the length of the hypotenuse can be calculated using the equation [tex]3^{2} + 4^{2}[/tex] = [tex]c^{2}[/tex], which results in c = 5.
The Pythagorean Theorem can be used to solve many mathematical problems related to triangles, as well as to solve problems in other areas such as geometry, physics, and engineering. In addition, the theorem is often used to prove theorems in mathematics, such as the law of cosines.
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Complete question is:
In pythagoras theorem, the sum of the areas of two squares on the legs (a and b) equals the area of the square on the hypotenuse (c) that is . discuss.
A sample containing years to maturity and yield for 40 corporate bonds are contained in the file CorporateBonds. (Round your answers to four decimal places.)
Company Years to Yield
Ticker Maturity
HSBC 12.00 4.079
GS 9.75 5.367
C 4.75 3.332
MS 9.25 5.798
C 9.75 4.414
TOTAL 5.00 2.069
MS 5.00 4.739
WFC 10.00 3.682
TOTAL 10.00 3.270
TOTAL 3.25 1.748
BAC 9.75 4.949
RABOBK 9.75 4.203
GS 9.25 5.365
AXP 5.00 2.181
MTNA 5.00 4.366
MTNA 10.00 6.046
JPM 4.25 2.310
GE 26.00 5.130
LNC 10.00 4.163
BAC 5.00 3.699
What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation?
The Sample mean years to maturity will be 7.05 and Sample standard deviation of years to maturity is 4.1318.
What is mean?
Mean, also known as the arithmetic mean or average, is a measure of central tendency in statistics. It is calculated by summing up all the values in a dataset and dividing by the total number of values.
Now,
To find the sample mean years to maturity for corporate bonds, we need to calculate the average of the years to maturity for all the 40 corporate bonds:
Sample mean years to maturity = (12.00 + 9.75 + 4.75 + 9.25 + 9.75 + 5.00 + 5.00 + 10.00 + 10.00 + 3.25 + 9.75 + 9.75 + 9.25 + 5.00 + 5.00 + 4.25 + 26.00 + 10.00 + 5.00) / 20
= 7.05
Therefore, the sample mean years to maturity for corporate bonds is 7.05.
To find the sample standard deviation of years to maturity for corporate bonds, we can use the following formula:
Sample standard deviation = √((1/n) * sum(xi - x_bar)²)
where n is the sample size, xi is the ith value in the sample, x_bar is the sample mean, and sum is the sum of all the terms in the brackets.
Using this formula and the given data, we get:
Sample standard deviation = √((1/20) * [(12.00 - 7.05)² + (9.75 - 7.05)²+ (4.75 - 7.05)² + (9.25 - 7.05)² + (9.75 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (10.00 - 7.05)² + (10.00 - 7.05)² + (3.25 - 7.05)² + (9.75 - 7.05)² + (9.75 - 7.05)² + (9.25 - 7.05)² + (5.00 - 7.05)² + (5.00 - 7.05)² + (4.25 - 7.05)² + (26.00 - 7.05)² + (10.00 - 7.05)² + (5.00 - 7.05)²])
Sample standard deviation = 4.1318
Therefore, the sample standard deviation of years to maturity for corporate bonds is 4.1318 (rounded to four decimal places).
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Determine the values of m and n for ????(x) = mx3 +12x2 +????x−3 giventhat the remainder when dividing by (x + 3) is zero, and whendivided by (x − 2) the remainder is 85.
The values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.
To determine the values of m and n in the polynomial[tex]p(x) = mx^3 + 12x^2 + nx - 3[/tex], use the Remainder Theorem. According to the theorem, if a polynomial p(x) is divided by (x - a), the remainder is equal to p(a).
Given that when dividing p(x) by (x + 3) is zero, substitute -3 for x in the polynomial and set it equal to zero:
[tex]m(-3)^3 + 12(-3)^2 + n(-3) - 3 = 0[/tex]
Simplifying this equation gives us:
-27m + 108 + (-3n) - 3 = 0
-27m - 3n + 105 = 0
Next, we are given that the remainder when dividing p(x) by (x - 2) is 85. Using the same logic, we substitute 2 for x in the polynomial and set it equal to 85:
[tex]m(2)^3 + 12(2)^2 + n(2) - 3 = 85[/tex]
Simplifying this equation gives us:
8m + 48 + 2n - 3 = 85
8m + 2n + 45 = 85
Now we have a system of two equations with two variables:
-27m - 3n+ 105 = 0
8m + 2n + 45 = 85
Solving this system of equations will give us the values of m and n. By solving these equations, we find that m = 3 and n = -15.
Therefore, the values of m and n for the polynomial [tex]p(x) = 3x^3 + 12x^2 - 15x - 3,[/tex] satisfying the given conditions, are m = 3 and n = -15.
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Hi Can you help me ?
Answer:
please mark as brainliest
The geometric mean is 45 and 22 is the same as the geometric mean of 5 and a number x
the value of x that makes 22 the geometric mean of 5 and x is approximately 96.8.
How to find and what is geometry?
To find the value of x, we can use the formula for the geometric mean:
geometric mean = √(a ×b)
where a and b are the two numbers we want to find the geometric mean of.
We are given that the geometric mean of 5 and x is 22:
√(5× x) = 22
Squaring both sides, we get:
5× x = 22²2
Simplifying, we get:
5× x = 484
Dividing both sides by 5, we get:
x = 96.8
So the value of x that makes 22 the geometric mean of 5 and x is approximately 96.8.
Geometry is a branch of mathematics that deals with the study of shapes, sizes, positions, angles, and dimensions of objects in space. It includes the properties and relationships of points, lines, angles, surfaces, and solids, as well as their measurements and calculations. Geometry plays an important role in many areas of science, engineering, architecture, and art, and has numerous practical applications in everyday life.
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Parallelogram W X Y Z are divided into 4 triangles by X Z and W Y, which intersect at point P inside the parallelogram. W X and Z Y are parallel and W Z and X Y are parallel. Segment W P equals 8.
If WY + XZ = 28, what is PZ?
From the given information provided, if WY + XZ = 28 and segment WP = 8, then the length of PZ is 8 units.
We can use similar triangles to find the length of PZ.
First, let's label the points where XZ and WY intersect with P as A and B, respectively.
Since WZ and XY are parallel, we know that triangles WPZ and YPX are similar. Therefore, we can write the following proportion:
WP/PZ = YP/YX
We know that WP = 8, so we just need to find YP and YX.
We can use the fact that triangles WPA and XPB are similar (because they share an angle and have parallel sides). Therefore, we can write the following proportion:
WP/WA = PB/PX
Substituting 8 for WP and rearranging, we get:
WA = 8(PX/WB)
Similarly, we can use the fact that triangles YPA and ZPB are similar to write:
YP/YA = PB/PZ
Substituting YX + WA for YA (since WY and XZ divide the parallelogram into equal areas), and substituting 28 - WA for PB (since WY + XZ = 28), we get:
YP/(YX + WA) = (28 - WA)/PZ
Substituting 8(PX/WB) for WA and simplifying, we get:
YP/(YX + 8PX/WB) = (28 - 8PX/WB)/PZ
Now we just need to solve for PZ. Cross-multiplying and simplifying, we get:
PZ = (28 - 8PX/WB)(YX + 8PX/WB)/YP
Since we know that WZ and XY are parallel, we can use the fact that opposite sides of a parallelogram are equal to write:
WZ = XY = WY + XZ = 28
We also know that WP = 8. Therefore, we can use the fact that the area of a parallelogram is equal to the product of its base and height to write:
Area(WPZ) = 8(WZ/2)
Substituting 28 for WZ, we get:
Area(WPZ) = 112
We can also use the fact that the area of a triangle is equal to half the product of its base and height to write:
Area(WPZ) = (PZ)(WX)/2
Substituting WX = WZ = 28 and simplifying, we get:
Area(WPZ) = 14PZ
Equating the two expressions for the area of WPZ, we get:
14PZ = 112
Solving for PZ, we get:
PZ = 8
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help me on this ixl pls
Answer:
x = 120
Step-by-step explanation:
A regular polygon for something that has 3 sides (triangle) will have equal angles and sides, making this an equilateral and equiangular triangle. Because of this, the angles on the inside of the triangle are each 60 degrees. Angle x and the angle of the triangle make a straight line, x+60=180. This makes x equal to 120.
P(x)=4x⁵−8x³−7x²+9x+7,
P(x)→
if x→−[infinity]
P(x)‐
if x→[infinity]
If your answer is −[infinity]−[infinity], input -infinity; if your answer is [infinity][infinity],
input infinity.
Answer:When x→−∞ , then P(x)→−∞When x→+∞ , then P(x)→+∞Note that we can figure out if the function grows or decreases, simply by looking at the leading term of the function which is 4x⁵. This term shows that the function increases without bound as x → ± ∞.The given function is P(x)=4x⁵−8x³−7x²+9x+7We can now find the horizontal asymptotes of the given function, by computing the limits at infinity as follows;When x→−∞ , then P(x)→-∞When x→+∞ , then P(x)→+∞Therefore, the horizontal asymptotes are: y= - ∞ and y= + ∞
in the expression 5n - [tex]\frac{2m}{7}[/tex] + [tex]\frac{3}{4}[/tex] , what is the constant?
- [tex]\frac{2}{7}[/tex]
[tex]\frac{3}{4}[/tex]
5
21
An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is B.
What is an Expression?In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
In the given expression[tex]5n- \frac{2m}{7} + \frac{3}{4}[/tex], the constant value is the value that does not have a variable with it. Therefore, the constant in the given expression is 3/4.
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5. NEIGHBORS Amy, Barry, and Chris live on the same block. Chris lives up the street and around the corner from Amy, and Barry lives at the corner between Amy and Chris. The three homes are the vertices of a right triangle.
a. Give two trigonometric expressions for the ratio of Barry's distance from Amy to Chris' distance from Amy.
b. Give two trigonometric expressions for the ratio of Barry's distance from Chris to Amy's distance from Chris.
c. Give a trigonometric expression for the ratio of Amy's distance from Barry to Chris' distance from Barry.
The expression for the ratio will be AB/BC = sin(∠BAC)/sin(∠CAB).
What is Expression?
An expression is mathematical phrase that can contain numbers, variables, operators, and functions, but does not have equal sign. It represents value or mathematical operation that can be evaluated or simplified.
we can use the Pythagorean theorem to find the distances between the houses, and then use trigonometric ratios to find the ratios between them.
Let's assume that Amy's house is located at point A, Barry's house is located at point B, and Chris's house is located at point C, as shown in the diagram below.
C
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---A--------
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B
a. To find the ratio of Barry's distance from Amy to Chris' distance from Amy, we can use the following trigonometric expressions:
tan(∠BAC) = AB/AC (opposite/adjacent)
tan(∠CAB) = AC/AB (opposite/adjacent)
Therefore,
AB/AC = 1/tan(∠BAC)
AC/AB = 1/tan(∠CAB)
b. To find the ratio of Barry's distance from Chris to Amy's distance from Chris, we can use the following trigonometric expressions:
tan(∠ACB) = AB/BC (opposite/adjacent)
tan(∠ABC) = AC/BC (opposite/adjacent)
Therefore,
AB/BC = tan(∠ACB)
AC/BC = tan(∠ABC)
c. To find the ratio of Amy's distance from Barry to Chris' distance from Barry, we can use the following trigonometric expression:
sin(∠BAC) = AB/BC (opposite/hypotenuse)
sin(∠CAB) = AC/BC (opposite/hypotenuse)
Therefore,
AB/BC = sin(∠BAC)
AC/BC = sin(∠CAB)
So,
AB/BC = sin(∠BAC)/sin(∠CAB).
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One and four hundred twenty-nine thousandths as a decimal
The one and four hundred twenty nine thousandths in decimal form is 0.429.
Decimal Form:
Decimals are numbers made up of a whole number and a fractional part. Decimals are placed between whole numbers and represent the value of a quantity as a whole plus a part. In decimal form, we write this as 1.5 pizzas. Here, the dots represent the decimal point and the numbers before the decimal point, i.e., "1" represents a whole pizza, and the numbers after the decimal point represent half a pizza or a fractional part.
According to the Question:
The calculation is as follows;
Here in the given situation
One and Four hundred - the number 4
Twenty nine - the number 29
Now,
We have to Add them together with 0.
So, it should be 0.429
Complete Question:
What is One and four hundred twenty-nine thousandths as a decimal
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Please help me
4(2×5)-20÷5
3(4+2)×3
20÷5×2+19
15×2+30÷4
14+3×2-12÷3
Answer:
Step-by-step explanation:You do the brackets first 2X5= 10
10X4 = 40 - 20 / 5 . 20 divided by 5 = 4
40 - 4 = 36
B) 4+2= 6 X3 =18X3= 54
c) 20/5=4 X2 =8+19= 27
D)37.5
E) 3X2=6 12/3 = 4 14+6=20 20-4=16
HELP ASAP WITH WORK SHOWN!
A particle moves along the x-axis so that
at time t≥ 0 its position is given by
x(t) = 3t³ - 27t² + 72t + 14.
Determine the total distance traveled by
the particle from 0 ≤ t ≤ 6.
0
The total distance traveled by the particle from 0 ≤ t ≤ 6 is: 216 units
How to find the total distance travelled?The position of the particle is given by the equation:
x(t) = 3t³ - 27t² + 72t + 14.
Now, To find the times when the particle changes direction, you just need to find the critical numbers of the function x(t). These would be the possible times when the particle changes direction.
x(t) = 3t³ - 27t² + 72t + 14.
x'(t) = 9t² - 54t + 72
Using quadratic equation calculator, we have:
t = 2 or 4
Then you can find the position of the particle at these times. We will also need to find its position at our end points: t = 0, 7. Basically all we are doing here is finding the global max/min values of the function up to this point.
x(0) = 3(0)³ - 27(0)² + 72(0) + 14 = 14
x(2) = 3(2)³ - 27(2)² + 72(2) + 14 = 74
x(4) = 3(4)³ - 27(4)² + 72(4) + 14 = 62
x(6) = 3(6)³ - 27(6)² + 72(6) + 14 = -202
Thus:
Total distance = (74 - 14) + (62 - 74) + (-202 - 62)
= -216
This is 216 in the negative direction
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hello math question!!!!!!!!!!
Answer:
The answer would be D
Hope this helps!
In a population of scores, x = 83 corresponds to z = -0. 05 and x = 0. 93 corresponds to. Z = 2. 0. What are the values for the population mean and standard deviation?
The pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.
What is the mean and standard deviatiοn?The standard deviatiοn is a summary measure οf the differences οf each οbservatiοn frοm the mean. If the differences themselves were added up, the pοsitive wοuld exactly balance the negative and sο their sum wοuld be zerο. Cοnsequently, the squares οf the differences are added.
We can use the fοrmula fοr standardizing a variable using z-scοres:
z = (x - μ) / σ
where z is the z-scοre, x is the cοrrespοnding raw scοre, mu is the pοpulatiοn mean, and sigma is the pοpulatiοn standard deviatiοn.
We have twο pairs οf (x, z) values:
x = 83, z = -0.05
x = 0.93, z = 2.0
We can use these tο create twο equatiοns with twο unknοwns ( and sigma):
-0.05 = (83 - μ) / σ
2.0 = (0.93 - μ) / σ
We can sοlve this system οf equatiοns by first sοlving οne οf the equatiοns fοr οne οf the unknοwns, and then substituting that expressiοn intο the οther equatiοn. Fοr example, we can sοlve the first equatiοn fοr mu:
mu = 83 + 0.05 * σ
Then we substitute this expressiοn fοr mu intο the secοnd equatiοn:
2.0 = (0.93 - (83 + 0.05 * σ)) / σ
Simplifying this equatiοn, we get:
2.0 = (0.93 / σ) - (83 / σ) - 0.05
2.05 = 0.93 / σ - 83 / σ
2.05 = (0.93 - 83) / σ
σ = (0.93 - 83) / 2.05
σ = 38.5366
Nοw we can use this value tο find the pοpulatiοn mean μ:
μ = 83 + 0.05 * σ
μ = 83 + 0.05 * 38.5366
μ = 84.9278
Therefοre, the pοpulatiοn mean is apprοximately 84.93 and the pοpulatiοn standard deviatiοn is apprοximately 38.54.
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Estimates show that there are 1.4 * 10^8 pet fish and 9.4 * 10^6 pet reptiles in the United States. How many are there total in the United States? express in scientific notation.
Therefore , the solution of the given problem of expressions comes out to be the total number of pet fish and reptiles in the US is roughly
1.494 * 10⁸.
What precisely is an expression?It is necessary to perform calculations which it involve joining, removal, and random subdivision variable changing multipliers. If they banded together, they could do the following: A mathematical challenge, some information, and an algorithm. A statement of equation truth contains formulas, elements, and arithmetic procedures like additions, subtractions, errors, and groupings. It is possible to assess and analyse words and phrases.
Here,
The number of fish and reptiles kept as pets must be added to the overall number of pets:
=> 1.4 * 10⁸ + 9.4 * 10⁶
We must change these numbers to the same power of 10 in order to add them. Since 108 is equal to 100 million,
we can achieve this by moving the decimal point in the second figure two places to the right:
=> 1.4 * 10⁸ + 0.094 * 10⁸
We can now multiply the numbers:
=> 1.494 * 10⁸
Thus, the total number of pet fish and reptiles in the US is roughly
=> 1.494 * 10⁸.
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There are total of [tex]2.34*10^{8}[/tex] pet fish and reptiles in the United States.
Define the term expression?Calculations that include changeable altering multipliers, joining, removal, and random subdivision must be done. They could accomplish the following if they united: An algorithm, some data, and a mathematical problem.
To find the total number of pet fish and reptiles in the United States, we simply need to add the number of pet fish and pet reptiles together:
Total = [tex]1.4*10^{8} + 9.4*10^{6}[/tex]
To add these numbers together, we need to express them using the same power of 10. We can do this by rewriting 9.4 * 10^6 as 0.94 * 10^7:
Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]
Now, we can add the numbers together:
Total = [tex]1.4*10^{8} + 0.94*10^{7}[/tex]
= [tex]1.4 * 10^8 + 0.94 * 10^8[/tex] (since [tex]10^7 = 10 * 10^6 = 10^1 * 10^6 = 10^7[/tex])
= [tex]2.34 * 10^8[/tex]
Therefore, there are a total of [tex]2.34 * 10^8[/tex] pet fish and reptiles in the United States.
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