Please help due soon.

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Answer:

D.

Step-by-step explanation:

If you add them all up and subtract 30 you get 60

I MAYBE MESSED UP // haven't done this math in a while

Step-by-step explanation:

Please refer to the attachment

Answer:

Cabral is right

Step-by-step explanation:

Mark me brainleyest plz

Answer:

She can invite 66 people so 66 x 5 = $330 + 120 = $450

Step-by-step explanation:

Answer:

=4m+8

Step-by-step explanation:

=(4)(m+2)

=(4)(m)+(4)(2)

=4m+8

Answer:

4m +8

Step-by-step explanation:

Take out the parenthesis

Answer:

B.

Step-by-step explanation:

(f-g)(x) = f(x) - g(x) =

= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =

= 3x³ + 8x² - 9x + 2

Answer:

y=3x^2 -15x-42

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

[tex]\frac{6}{1}[/tex] ÷ [tex]\frac{1}{3}[/tex]

Keep Change Flip

[tex]\frac{6}{1}[/tex] × [tex]\frac{3}{1}[/tex] = [tex]\frac{18}{1}[/tex]

Answer:

-4x-y=24......1

24−4x−y=24

substituting value of−4x−y

24-24=24

it has no solution. I think question is incomplete

Answer:-8 on khan academy

Step-by-step explanation

Answer:

Step-by-step explanation:

Perimeter = 2l + 2w

With the given statement, the width of the rectangle is 4 meters less than the

length,

w = l - 4

sub that in the first equation,

Perimeter = 2l + 2(l - 4)

Perimeter = 2l + 2l - 8

Perimeter = 4l - 8

Since perimeter is 72m,

72 = 4l - 8

4l = 80

l = 20m

Answer:

x>36

Step-by-step explanation:

Hope this helps and good luck

Answer:

Step-by-step explanation:

Use pythagorean theorem

9^2 +40^2=x^2

81+1600=x^2

1681=x^2

now find the square root of each side

[tex]\sqrt{1681} =\sqrt{x}[/tex]

x=41

Answer:

20

Step-by-step explanation:

add 3ft+3ft+11ft+3ft and that's your answer

Answer:

x=0 y=2 z=5

Step-by-step explanation:

so for z

2z=10

divid both side by 2

z=5

equation one

x+2y+5=9

x+2y=4 ------eqn1

equation two

x-y+ 3(5)=13

x-y+15=13

x-y=-2-----eqn2

now you solve it by elimination

eqn1-eqn2

3y=6

y=2

put y=2 into eqn2

x-2=-2

x=0

Answer:

[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Step-by-step explanation:

Given - A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t.

To find - Find the rate at which the number of grams of salt in the tank is changing at time t.

Find the number A(t) of grams of salt in the tank at time t.

Proof -

Given that,

Total fluid in the tank = 350 litres

Total salt = 40 grams

Rate in flow = 5 L/min

Rate out flow = 5 L/min

Concentration in = 0

Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)

Now,

Total solution in the tank at time t = Total fluid in the tank + (Rate in flow - Rate out flow )t

                                                        = 350 + (5 - 5)t

                                                        = 350

⇒Solution in the tank at time t = 350

⇒Concentration out = [tex]\frac{A(t)}{350}[/tex]

Now,

Rate of change in the tank at time t = [tex]\frac{dA}{dt}[/tex]

                                                           =  (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)

                                                           = 5(0) - 5([tex]\frac{A(t)}{350}[/tex])

                                                           = 0 - [tex]\frac{A(t)}{70}[/tex]

                                                           = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{dt}[/tex] = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

Integrate both sides , we get

ln(A) = [tex]-\frac{1}{70}t + C[/tex]

⇒A(t) = [tex]e^{-\frac{t}{70}+ C}[/tex]

         = [tex]e^{-\frac{t}{70}}*e^{C}[/tex]

         = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

⇒A(t) = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

Now,

Given that,

Initially, the tank has 40 grams of salt

⇒A(0) = 40

⇒C₁ = 40

⇒A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Answer:

2

Step-by-step explanation:

The interquartile range of the given data set is 2.

We need to find the interquartile range of the data set given.

To find the interquartile range (IQR), ​first, find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

The given set of data is

0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

To find Q1:

The lower half of the numbers are

That is 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2,

So the median of the lower half (Q1)=1

To find Q3:

The upper half of the numbers are 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

So the median of the upper half (Q3)=3

Then, IQR=Q3-Q1=3-1=2

Therefore, the interquartile range of the given data set is 2.

To learn more about the interquartile range visit:

https://brainly.com/question/15686744.

#SPJ5

Answer:

20 + 75 = 95

Step-by-step explanation:

10 - 5 = 5 x 4 = 20

5 x 15 = 75

Add them together,

75 + 20 = 95

Answer:It’s the third choice y=3x+1

Step-by-step explanation:

Answer:

I use faction

Step-by-step explanation:

The first boat.

[tex]\frac{40 feet}{60 seconds}[/tex] ÷ 10 = [tex]\frac{4 feet}{6 seconds}[/tex]

[tex]\frac{4 feet}{6 seconds}[/tex] ÷ 2 = [tex]\frac{2 feet}{3 seconds}[/tex]

The first boat move [tex]\frac{2 feet}{3 seconds}[/tex]

The second one do the same

[tex]\frac{30 feet}{60 seconds}[/tex] ÷ 10 = [tex]\frac{3 feet}{6 seconds}[/tex]

[tex]\frac{3 feet}{6 seconds}[/tex] ÷ 2 = [tex]\frac{1.5 feet}{3 seconds}[/tex]

That is the speed of each boat.

The first boat need 50 minutes to get to the other side

2000 ÷ 2 =1000

1000 x 3 = 3000

3000 ÷ 60 = 50

The second boat need 66.6666666667 minutes to get to the other side

200 ÷1.5 = 1333.33333333

1333.33333333 x 3 = 4000

4000 ÷ 60 = 66.6666666667

Answer:

8.3

Step-by-step explanation:

Answer:

The system is of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

Where g is the amount of general tickets and r is the amount of reserve tickets.

35 general tickets and 25 reserve tickets were sold.

Step-by-step explanation:

Let general tickets be represented by g and reserved tickets be represented by r.

Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:

[tex]10g+15r=725[/tex]

And a total of 60 tickets were sold. Hence:

[tex]g+r=60[/tex]

Our system of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

We can solve by substitution. First, divide both sides of the first equation by 5:

[tex]2g+3r=145[/tex]

Next, we can subtract a variable (r in this case) from the second equation:

[tex]g=60-r[/tex]

Substitute:

[tex]2(60-r)+3r=145[/tex]

Distribute:

[tex]120-2r+3r=145[/tex]

Simplify:

[tex]120+r=145[/tex]

Subtract:

[tex]r=25[/tex]

Using the previous equation:

[tex]g=60-r[/tex]

Substitute and evaluate:

[tex]g=60-(25)=35[/tex]

So, 35 general tickets and 25 reserve tickets were sold.

Answer:

for 1 student it would equal 11.25

11.25 x 50 = 562.50

ur answer is 50 students hope this helps :)

Answer:

the teacher has 50 students

Step-by-step explanation:

1.75+9.50=11.25

562.50/11.25=50

Answer:

it is C.

Step-by-step explanation:

we know,

14+17= 31

so if we subtarct 17 from 31 we get 14

and if we subtract 14 from 31 we get 17

Answer:

Step-by-step explanation:

A=19000( 1 + 0.03)^8

A=24068.6315464

A≈24100

Round to the nearest hundred dollars

Answer:

Slope is -7 and the y-intercept is 8

Step-by-step explanation: