Answer:
45,86N
Explanation:
Fk=Uk×N
=0,78×6×9.8
=45,86N
A guitar string transmits waves at
315 m/s, and oscillates at 370 Hz.
What is the length of the string?
(Unit = m)
Answer:
The wavelength of the waves on the string is found using v = λf:
λ = v/f = 315/370 = 0.85135m
The first harmonic (fundamental) standing wave formed on the string has nodes only at the ends (see diagram in link) so:
String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)
g One arm of a Michelson interferometer has a section of length 2.1 cm where the air can be evacuated. The dielectric constant of air is 1.00059. Find the number of fringes which will shift in the interference pattern of the interferometer when the air is evacuated for an interferometer illuminated with light of 663 nm wavelength.
Answer:
The answer is "12388.17"
Explanation:
[tex]l = 2.1 cm = 2.1 \times 10^{-2}\ m\\\\k = 1.00059\\\\\eta = \sqrt{k}= \sqrt{1.00059}\\\\\lambda = 663 nm = 663 \times 10^{-9}\ m[/tex]
Users now know that perhaps the number of fingers the shift is provided when a path difference [tex]\Delta d[/tex] are inserts between both the two arms
[tex]N = \frac{\Delta d}{\lambda}[/tex]
The optical pull-up in the arm is initially given by
[tex]d = 2\eta l[/tex]
Its new length of the different sense as the reflection coefficient adjustments between [tex]\eta[/tex] (air) and 1 so if we evacuate air from of the arm (vacuum).
The new length of a path is therefore
[tex]d'' = 2l[/tex]
Therefore, the different path
[tex]\Delta d=d-d''=2l(\eta -1)[/tex]
So, The fringe shifts number are
[tex]N= \frac{2l(\eta -1)}{\lambda}[/tex]
[tex]= \frac{2 \times 2.1 \times 10^{-2} (\sqrt{1.00059}-1)}{663 \times 10^{-9}}\\\\=12388.17[/tex]
While measuring the distance of the magnetic sensor in your phone from the center of the magnet (or coil) you decided to include uncertainties from two places. One is the uncertainty in locating the center of the magnet (or coil) and you estimated it as 0.25 cm. The other is the uncertainty in locating the position of the sensor in the phone and you estimated it as 0.45 cm. What is the uncertainty in the distance measurement when calculated using quadrature method
Answer:
the uncertainty in the distance measurement is 0.5148
Explanation:
Given the data in the question;
uncertainty in locating the center of the magnet is estimated to be 0.25 cm,
uncertainty in locating the position of the sensor in the phone is estimated to be 0.45 cm,
Using quadrature method, uncertainty in the distance measurement = ?
We know that;
Using quadrature method, Combined Uncertainty calculated by;
U[tex]_c[/tex] = √( U₁² + U₂² + ........... )
where U₁ is uncertainty in first measurement and U₂ is uncertainty in second measurement, et cetera.
now we substitute;
U[tex]_c[/tex] = √( U₁² + U₂² )
U[tex]_c[/tex] = √( (0.25)² + (0.45)² )
U[tex]_c[/tex] = √( 0.0625 + 0.2025 )
U[tex]_c[/tex] = √( 0.265 )
U[tex]_c[/tex] = 0.5148
Therefore, the uncertainty in the distance measurement is 0.5148
1. For the masses shown with the indicated velocities. Consider the increasing
direction of the x-axis toward the right.
9.0 kg 4.0 m/s
8.0 m/s
6.0 kg
a) Find the magnitude of the momentum of the system. (Do not include the units
in the answer)
Your answer
b) What is the direction of the momentum of the system?
Choose
c) Determine the total kinetic Energy of the System. (Do not include the units in
the answer)
Your answer
Yellow light has a frequency of 5.21 x 10^15 Hz. What is the wavelength of yellow light?
Answer: The yellow light with a frequency equal to 5.21 x 1014 Hz will have a wavelength of E) 576 nm
A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same speed.
Answer:
A. The bus has more kinetic energy than the car.
Explanation:
We know that
Kinetic energy is the energy amount possessed from the body as in the motion
Also, the following formula should be used to determine the kinetic energy
Kinetic energy = 1 ÷ 2mv²
Here m represents the mass of the body
and v represents the velocity of the body.
Therefore it should be based on the mass & velocity of the body
In the case when the passenger bus have more kinetic energy as compared to the car so this is because of the the big mass
Therefore, the first option is correct
0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained at 50 psia. During the phase conversion,thesystem volume decreases by 1.5 ft3; 250 Btu of heat areremoved; and the temperature remains fixed at 15F. Estimatethe boiling point temperature of this substance when itspressure is 60 psia.
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation
[tex](\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}[/tex]
[tex](\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }[/tex]
where [tex]h_{fg[/tex] is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
[tex]V_{fg[/tex] is specific volume ( 1.5 ft³ )
we substitute
[tex](\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})[/tex] / [tex]( (15+460)\frac{1.5}{0.5})[/tex]
[tex](\frac{dP}{dT} )_{sat } =[/tex] 272.98 Ibf-ft²/R
Now,
[tex](\frac{dP}{dT} )_{sat } =[/tex] [tex](\frac{P_2 - P_1}{T_2 - T_1})_{sat[/tex]
where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;
[tex]T_2[/tex] [tex]= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}[/tex]
[tex]T_2 = 475 + 5.2751\\[/tex]
[tex]T_2 =[/tex] 480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
PLEASE PLEASE PLEASE HELP
Answer:
Rain came along with lower temps
Explanation:
There was no rain on the warmer days
There were more clouds as the week went on
and the temp decreased during the week so rain came with lower temps is the only one that can be correct
Introduction to Forces
Warm-Up Active
How do forces affect the motion of an object?
Answer:
Forces can affect an object.
Balanced forces allow an object to continue moving at a constant motion (law of inertia).
Unbalanced forces cause a change in motion.
Answer:
Because of my physics teacher I would put this entire explanation below if i were u
Explanation:
Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving.
Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity. So forces cause acceleration.
Can sound travel through space? Why or why not?
Answer:
I think sound does not travel at all in space. The vacuum of outer space has essentially zero air. Because sound is just vibrating air, space has no air to vibrate and therefore no sound. If you are sitting in a space ship and another space ship explodes, you would hear nothing.
Explanation:
What is the average velocity of a wave that travels an average distance of 6 m in 0.25 s?
How do y’all solve this
Answer:
you Subtract
Explanation:
A = 6
B = 6
C = 0
D = 5
9-3= 6
13-7=6
11-11=0
6-1=5
Simple hope it helps
If moving charges create magnetic fields and all materials are made up of atoms that have moving charges, why are most things NOT magnetic?
Magnetism is the result of the "spin" of the electron and most of these cancel each other out in larger bodies thus most things not being magnetic.
How are cells organized:
A: Organs
B: Organelles
C: Tissues
The body has levels of organization that build on each other. Cells make up tissues, tissues make up organs, and organs make up organ systems. The function of an organ system depends on the integrated activity of its organs. For instance, digestive system organs cooperate to process food.
The answer is : C
8.
Determine the focal length of a diverging lens that produces an image that is 12.9 cm from the lens
(and on the object's side) when the object is 32.4 cm from the lens.
Answer:
=-21.43
Explanation:
::::::::::::::::::
We have that the focal length is
[tex]f=19.058[/tex]
From the Question we are told that
image distance [tex]v=12.9[/tex]
object distance [tex]u=32.4[/tex]
Generally the equation for focal length is mathematically given as
[tex]\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\\\\\frac{1}{f}=\frac{1}{12}-\frac{1}{32.4}[/tex]
[tex]f=19.058[/tex]
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A microscope has an eyepiece with a 1.8 cm focal length and a 0.8 cm focal length objective lens. Assuming a relaxed eye, calculate a) the position of the object if the distance between the lenses is 16 cm, and b) the total magnification.
Answer:
[tex]0.848\ \text{cm}[/tex]
[tex]232.66[/tex]
Explanation:
N = Near point of eye = 25 cm
[tex]f_o[/tex] = Focal length of objective = 0.8 cm
[tex]f_e[/tex] = Focal length of eyepiece = 1.8 cm
l = Distance between the lenses = 16 cm
Object distance is given by
[tex]v_o=l-f_e\\\Rightarrow v_o=16-1.8\\\Rightarrow v_o=14.2\ \text{cm}[/tex]
[tex]u_o[/tex] = Object distance for objective
From lens equation we have
[tex]\dfrac{1}{f_o}=\dfrac{1}{u_o}+\dfrac{1}{v_o}\\\Rightarrow u_o=\dfrac{f_ov_o}{v_o-f_o}\\\Rightarrow u_o=\dfrac{0.8\times 14.2}{14.2-0.8}\\\Rightarrow u_o=0.848\ \text{cm}[/tex]
The position of the object is [tex]0.848\ \text{cm}[/tex].
Magnification of eyepiece is
[tex]M_e=\dfrac{N}{f_e}\\\Rightarrow M_e=\dfrac{25}{1.8}\\\Rightarrow M_e=13.89[/tex]
Magnification of objective is
[tex]M_o=\dfrac{v_o}{u_o}\\\Rightarrow M_o=\dfrac{14.2}{0.848}\\\Rightarrow M_o=16.75[/tex]
Total magnification is given by
[tex]m=M_eM_o\\\Rightarrow m=13.89\times 16.75\\\Rightarrow m=232.66[/tex]
The total magnification is [tex]232.66[/tex].
Newton's laws of motion
21. Make sure carts are facing so that Velcro strips can stick together when they collide. Keep an extra 250g of mass on the cart 2 which starts at rest. Change sign on velocity center. Practice giving an initial velocity to cart 1 while cart 2 starts at rest so that after the collision both carts move as a combined object with mass m1 m2. What is the type of collision now you are practicing with two carts
Answer:
his type of shock is called inelastic
Explanation:
This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.
We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.
Looking for the moments
initial. Before the crash
p₀ = m₁ v₁₀
final. After the crash
p_f = (m₁ + m₂) v
the conservation of the moment is written
p₀ = p_f
m₁ v₁₀ = (m₁ + m₂) v
This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.
Who knows how to do this?
Answer:
1) F = 8.789 10² N, 2) F = 1.5 10⁴ N
Explanation:
We can solve this exercise using Coulomb's law
F =[tex]k \frac{q_1q_2}{r^2}[/tex]
Knowing that charges of the same sign repel
let's apply this equation to our case
1) the charges are q = - 0.0025 C and the distance between them r = 8 m
we calculate
F = 9 10⁹ 0.0025 0.0025 /8²
F = 8.789 10² N
as the two charges are of the same sign the force is repulsive
2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m
we calculate
F = 9 10⁹ 0.004 0.003 / 3²
F = 1.5 10⁴ N
3. How did the light wave interact with the water? | I
Answer:
Refraction is another way that waves interact with matter. ... Waves bend as they enter a new medium because they start traveling at a different speed in the new medium. For example, light travels more slowly in water than in air. This causes it to refract when it passes from air to water or from water to air.
Explanation:
i hope this helps but if it doesnt im rlly srry :p
which mountains are
YOUNGEST?
On a distance-time graph, what is the difference between a shallow slope and a steep slope?
A. A shallow slope shows the same speed as a steep slope.
B. A shallow slope shows a lower speed than a steep slope.
C. A shallow slope shows a more positive speed than a steep slope.
D. A shallow slope shows a higher speed than a steep slope.
Tin is more active than lead.
O A. True O B. False
Answer:
It would be false
Explanation:
Lead is more reactive if thats what you mean
Objectives
Pecina
y
01:Posttest 01:Motion Along a Straight Line
eration
1. An elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each
elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is
positive.
tant Acceleration
O Both elevators are moving at 8 m/s.
y Falling Objects
O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.
O Both elevators are moving at 4 m/s.
tive Velocity
O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.
Posttest
on in a Plane
ton's Laws of Motion
>
1 of 25
Submit
blications of Newton's
Description
440
11:53 PM
4/4/2021
Answer:
B
Explanation: Given that an elevator moving down passes its neighbor, an elevator moving up. Their speed relative to one another is 8 m/s. What is the velocity of each elevator relative to someone standing on the first floor? Assume that the elevators are traveling at the same speed, and that the upward direction is positive.
O Both elevators are moving at 8 m/s.
y Falling Objects
O One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s.
O Both elevators are moving at 4 m/s.
tive Velocity
O One elevator is moving at 8 m/s; the other elevator is moving at -8 m/s.
Solution.
Since the upward direction is positive, the downward direction will be negative.
For their speed relative to one another to be 8 m/s, the individual velocity will be:
4 - ( - 4 ) = 8
Therefore, the correct answer is:
One elevator is moving at 4 m/s; the other elevator is moving at -4 m/s
Which is option B
Because the negative sign multiply by negative sign will give positive.
That is,
4 + 4 = 8
01:Posttest 01:Motion Along a Straight Line
5. At the same moment, one rock is thrown upward at 4.5 m/s and another thrown downward at 3.4 m/s. What is the relative velocity of the first rock
from the perspective of the second rock? Assume that up is positive.
ration
0 -7.9 m/s
O 7.9 m/s
jects
O 1.1 m/s
0-1.1 m/s
Motion
wton's
<
5 of 25
>
Submit
Description
12:00 AM
99
Answer:
D
Explanation:
Given that one rock is thrown upward at 4.5 m/s and another thrown downward at 3.4 m/s. What is the relative velocity of the first rock
from the perspective of the second rock? Assume that up is positive.
Solution.
Since both of them are moving in the opposite direction, the relative velocity of the first rock from the perspective of the second rock will be
Relative velocity = 3.4 - 4.5
Relative velocity = - 1.1 m/s
Therefore, the relative velocity from the perspective of the second rock is negative 1.1 m/s.
The correct answer is option D.
Define wheel and axle 4 example of wheel and axle
Answer:
A system of two co-axial cylindersof different diameters which rotate together is called wheel and axle example; the door knob , knob of the tap ,screw driver,water tap
describe the hydrogen fusion?
Answer:
Fusion is the process that powers the sun and the stars. It is the reaction in which two atoms of hydrogen combine together, or fuse, to form an atom of helium. In the process some of the mass of the hydrogen is converted into energy. ... The sun and stars do this by gravity.
Explanation:
hope it helps friend
An aircraft lands at a speed of 180km/h
and stops in 2 minutes. The mass of the
aeroplane is 10,000kg. Find the length
of the distance of runway.
a. 18 km
b. 6 km
c. 4 km
d. 3 km
Hook’s law describes the behavior of which kind of material under tension
Answer:
Hooke law describes the behaviour of elastic material under tension
A motorcyclist is moving 24.5 m/s
away from a stationary siren, and
hears an 894 Hz sound. What is
the frequency of the siren when the
cyclist is stationary?
(Hint: 894 Hz is the Doppler-shifted
frequency)
(Speed of sound = 343 m/s)
(Unit = Hz)
w
Answer:962 hz
Explanation: got it right on acellus
The frequency of the siren when the cyclist is stationary will be 963 Hz.
What is frequency ?The frequency of a wave is the number of cycles per second.
FRom the doppler effect,
f =f'[ (V+Vs/V-Vo) ]
Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s
Substitute the value into the expression , we get
f = 894 x [(343/343 - 24.5)}
f = 963 Hz
Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.
Learn more about frequency.
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