the “/“ sign means division, what kind of question even is this.
9/5= 9÷5
19/28=19÷28
So for the last one, we can turn it into an improper fraction which is:
8/5 = 8÷5
4 movie tickets cost $48. At this rate, what is the cost of 11 movie tickets? *
Answer:
4 tickets =$48
1 ticket = $48/4
= $ 12
11 tickets =11*$12
= $132
Suppose a country's population at any time t grows in accordance with the rule dP dt = kP + I where P denotes the population at any time t, k is a positive constant reflecting the natural growth rate of the population, and I is a constant giving the (constant) rate of immigration into the country. If the total population of the country at time t = 0 is P0, find an expression for the population at any time t.
Answer:
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
Step-by-step explanation:
Given that:
A country population at any given time (t) is:
[tex]\dfrac{dP}{dt}= kP+I[/tex]
where;
P = population at any time t
k = positive constant
I = constant rate of immigration into the country.
Using the method of separation of the variable;
[tex]\dfrac{dP}{kP+1}= dt[/tex]
Taking integration on both sides:
[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]
[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]
[tex]log (kP + I) =k t+kc_1[/tex]
By applying the exponential on both sides;
[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]
[tex]KP+I = e^{kt} *e^{kc_1}[/tex]
Assume [tex]e^{kc_1 }= C[/tex]
Then:
[tex]kP + I = Ce^{kt}[/tex]
[tex]kP = Ce^{kt}-I[/tex]
[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]
When time t = 0, The Total population of the country is also [tex]P_o[/tex]
[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]
[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]
[tex]P_o = \dfrac{C-I}{k}[/tex]
C - I = kP₀
C = kP₀ + I
Substituting the value of C back into equation(1), we have:
[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]
[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]
[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]
A certain radioactive isotope has a half-life of 50 years. A scientist determines that there are 200 grams of the radioactive material present today. How
Much of the isotope was present 200 years ago?
im guessing 800 50X4 = 200 and 200X4 = 800
i never learned this but i hope its correct.
HELPPPPP ME PLEASEEEE
the product of 9/10 and 8/9 is...
A: between 0 and 1
B: between 1 and 2
C: between 2 and 3
D: greater than 3
6 ×3(2+9)..can you give the answer of it please
Answer:
Hope this may helps you
Step-by-step explanation:
6×3(11)
6×33
198
Answer:
198
Step-by-step explanation:
6 ×3(2+9)
= 6×3×11
= 6×33
= 198
Use the graph below to find f(-2) =
Please Help
Find the coordinates of the point P that divides the directed line segment from A to B in the given ratio.
A(-6, 9), B(2, 1); Ratio 5 to 3
Answer:
The coordinates of the point P = (x, y) = (-1, 4)
Step-by-step explanation:
Let the coordinates of P be (x, y)
(x₁, y₁) = (-6, 9)(x₂, y₂) = (2, 1)ratio = m:n = 5:3Using the section formula
x = [(mx₂ + nx₁)] / [(m+n)]
= [5(2)+3(-6)] / [5+3]
= [10-18] / [8]
= -8/8
= -1
y = [(my₂ + ny₁)] / [(m+n)]
= [5(1)+3(9)] / [5+3]
= [5+27] / [8]
= 32/8
= 4
Therefore, the coordinates of the point P = (x, y) = (-1, 4)
I need help please I am having hard time doing this
Answer:you are corect its negetive
Step-by-step explanation:
Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
Mi duda está la final, cuando queda - tcost + sent + k, no sé cómo sustituir t= arcsent
Answer:
Explicación más abajo
Step-by-step explanation:
Integración Indefinida
La integral
[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]
Se resuelve con el cambio de variables:
t=arcsen(x)
Una vez hechos los cambios, la integral se resuelve en función de t:
[tex]I=sen(t)-t.cos(t)+C[/tex]
Hay que devolver los cambios para mostrarla en función de x.
El cambio de variables también se puede escribir:
x=sen(t)
Recordando que
[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]
Entonces:
[tex]cos(t)=\sqrt{1-x^2}[/tex]
Devolviendo los cambios:
[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]
Es la respuesta correcta
Lacey is buying a new car. She can get a station wagon, a truck, a hatchback, or a convertible. The outside paint comes in yellow or green. The seats can be covered with white leather or gray fabric. Given these choices, how many different combinations does Lacey have to choose from?
Step-by-step explanation:
4 different vehicles,
2 different paints,
2 different seats.
Total number of combinations = 4 * 2 * 2 = 16.
Compré 18 cuadernos, 24 carpetas y 17 lapiceras. El precio de las carpetas excede al de los cuadernos en un 40%, mientras que el precio de las lapiceras es el 20% del precio de los cuadernos. Si el importe de la compra fue de $11.825, calcular el precio unitario de cada artículo
Answer:talk some English dude
Step-by-step explanation:
In a class 3/4 of the boys like math, 1/2 like science, 1/4 of those who like science do not like math. How many boys like neither math nor science?
A. 1/4
B. 1/6
C. 1/2
D. 1/8
12 points!! PLEASE
y =(x-3) - 4
rewrite these in standard and factored form!!
Standard form:
x - y = 7
Factored form:
y = x - 7
Answer:
y = x - 3 - 4
y = x - 7
(x - 7 = y)
(x = y + 7)
Step-by-step explanation:
Hope you got it.
if [tex]\frac{r + s}{x - y} = \frac{3}{4}[/tex] then [tex]\frac{8r + 8s}{15x - 15y}[/tex] equals
Answer:
[tex]\frac{8r+8s}{15x-15y} = \frac{2}{5}[/tex]
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyEquality PropertiesStep-by-step explanation:
Step 1: Define
[tex]\frac{r+s}{x-y} = \frac{3}{4}[/tex]
[tex]\frac{8r+8s}{15x-15y} = ?[/tex]
Step 2: Find Unknown
Multiply both sides by 8/15: [tex]\frac{8}{15} \cdot \frac{r+s}{x-y} = \frac{8}{15} \cdot \frac{3}{4}[/tex]Distribute/Multiply: [tex]\frac{8r+8s}{15x-15y}= \frac{24}{60}[/tex]Simplify: [tex]\frac{8r+8s}{15x-15y} = \frac{2}{5}[/tex]Find 56(−4⋅27). Write your answer in simplest form.
Answer:
[tex]-6048[/tex]
Step-by-step explanation:
[tex]---------------------------------[/tex]
[tex]56\left(-4\cdot27\right)[/tex] = [tex]-6048[/tex] [tex]because[/tex]
[tex]---------------------------------[/tex]
[tex]56\left(-4\cdot27\right)[/tex] = [tex]?[/tex]
[tex]\left(-4\cdot27\right)[/tex] = [tex]-108[/tex]
[tex]56\left(-108\right)[/tex] = [tex]?[/tex]
[tex]56\left(-108\right)[/tex] = [tex]-6048[/tex]
[tex]---------------------------------[/tex]
Hope this helps! <3
[tex]---------------------------------[/tex]
What is the GCF of the expression -x2y22 - xy2z?
Answer:
i dont onderstand Thais
You’ve learned to identify whether a function is even or odd both graphically and algebraically. How does the notation for reflections over the x-axis and over the y-axis relate to the notation for even and odd functions? Remember that if f(-x) = f(x), a function is even, and if f(-x) = -f(x), then the function is odd.
Answer:
Because even and odd are 2 different ways to determine whether or not you get the right answer for the chosen function.
Step-by-step explanation:
Hope this helps!!!
Answer:
For even functions, we take f(-x) to be the starting function. The y-axis reflection of this function is f(-(-x)), which is equal tof(x). So the relationship f(-x) = f(x) means that the function is the same as its y-axis reflection.
For odd functions, there are two reflections that must occur. First, we start with f(-x). The y-axis reflection of this function is f(-(-x)) = f(x). When we apply an x-axis reflection to this result, we get -f(-(-x)) = -f(x). So the fact that f(-x) = -f(x) means that odd functions are the same as sequential reflections across both the x-axis and the y-axis. (The same sequence of reflections also represents a rotation 180 degrees about the origin).
Step-by-step explanation:
Help please!!!
Triangle ABC is similar to triangle PQR, as shown below
Answer:
b:q
Step-by-step explanation:
im pretty sure its that. ive learned this before.
if you flipped them so that c and r were facing the same direction, then b and q would be too.
Please help soon! Thanks! Solve for x
Answer:
[tex]x=30^{\circ}[/tex]
Step-by-step explanation:
Looking at [tex]\triangle LMN[/tex]:
[tex]\angle NML = 180 - (90+45)[/tex] (angle sum of triangle is [tex]180^{\circ}[/tex])
[tex]=45^{\circ}[/tex]
Looking at [tex]\triangle KNM[/tex]:
[tex]\angle KNM = 180-105[/tex] (angle of straight is [tex]180^{\circ}[/tex])
[tex]=75^{\circ}[/tex]
[tex]\angle KNM + \angle NKM + \angle KMN = 180[/tex] (angle sum of triangle is [tex]180^{\circ[/tex])
[tex]75+2x+45 = 180[/tex]
[tex]2x+120 = 180[/tex]
[tex]2x=60[/tex]
[tex]x=30^{\circ}[/tex]
Hope this helps :)
Which of these graphs represents a function?
A)
A
B)
B
C)
С
D)
D
If point C lies between two points A and B such that AC=BC, then
Answer:
If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.
simplify x^2 + ax - 2a^2÷
3a^2 - 2ax - x^2?
Answer:
[tex] - \frac{x + 2a}{3a + x} [/tex]
Step-by-step explanation:
[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]
i) write ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]
ii) write -2ax as a difference
[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]
iii) factor out x from the expression
[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
iv) factor out -a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]
v) factor out a from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]
vi) factor out -x from the expression
[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]
vii) factor out x+2a from the expression
[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]
viii) factor out 3a+x from the expression
[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]
ix) factor out the negative sign from the expression and rearrange the term
[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]
x) reduce the fraction a-x
[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]
[tex] - \frac{x + 2a}{3a + x} [/tex]
The slope of a line perpendicular to y = 2x + 1 is -2.
False
True
Answer:
incorrect.
Step-by-step explanation:
the slope of the line perpendicular is the negative reciprocal, which in this case is -1/2
Answer:
False
Step-by-step explanation:
To find the slope of a perpendicular, flip the slope and change the sign.
The slope pf the given line is 2.
The slope of a line perpendicular to y = 2x + 1 is -1/2.
Answer: False
Please help me out !!!
Answer:
If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!
Step-by-step explanation:
4x+5 = 2x+19
2x=14
x=7
4(7)+5+2(7)+19 = 42+24 = 66
please help with this question (d+2)(-7)
Answer:
-7d-14
Step-by-step explanation:
First, let's distribute -7 to (d+2)
-7xd
-7x2
We will get -7d-14
In 1992, Jason bought a gallon of gas for $1.15. Yesterday, he bought a gallon of gas for $2.12. What is the percentage increase of the price of a gallon of gas from 1992 to yesterday? If necessary, round to the nearest tenth of a percent.
A.
84.3%
B.
45.8%
C.
54.2%
D.
15.7%
Divide. Write in simplest form.
3/4 divided by 1/8
Answer:
when you divide 3/4 by 1/8 you get 6
Please help!!! I will make brainliest
Answer:
I believe that all should be checked except for f(x) = x^6 which u already didn't check
Step-by-step explanation:
The equation is y = ab^x and all the equations, except that one, follow this formula
By what percent is 16 greater than 12.
Answer:
28 i assume.
Answer:
The answer is 28% :))
The y-intercept of 2x - y = 6 is -6.
O False
True
Answer:
It is true
Step-by-step explanation:
Convert to slope-intercept form:
2x-y=6
-y=6-2x
y=-6+2x
y=2x-6
Since y=mx+b is the form we want, then b=-6, making the statement true.
Answer:
true
Step-by-step explanation:
you switch the 2x to the other side to get -y = 2x + 6
then you multiply everything by -1 to get y = -2x-6
-6 is the y int