Answer:
The Forces of Flight
At any given time, there are four forces acting upon an aircraft.
These forces are lift, weight (or gravity), drag and thrust. Lift is
the key aerodynamic force that keeps objects in the air. It is the
force that opposes weight; thus, lift helps to keep an aircraft in
the air. Weight is the force that works vertically by pulling all
objects, including aircraft, toward the center of the Earth. In order
to fly an aircraft, something (lift) needs to press it in the opposite
direction of gravity. The weight of an object controls how strong
the pressure (lift) will need to be. Lift is that pressure. Drag is a
mechanical force generated by the interaction and contract of a
solid body, such as an airplane, with a fluid (liquid or gas). Finally,
the thrust is the force that is generated by the engines of an
aircraft in order for the aircraft to move forward.
Explanation:
what does the gravitational attraction between earth and an object depend on
Answer:
the force of gravity acting between the earth and any other object is directly proportional to the mass of the earth, directly proportional to the mass of the object, and inversely proportional to the square of the distance that separates the centers of the earth and the object.
Explanation:
A note of frequency 200Hz has a velocity of 400m/s. What is the wave length of the note
[tex]\lambda=\frac{v}{f}=\frac{400}{200}=2[m][/tex]
The Law of Conservation of Mass states that mass can be destroyed during a chemical change.
True
False
the form of energy most responsible for producing sunlight is
Answer:
nuclear energy
Explanation:
Which waves have oscillations parallel to their direction of motion?
sound waves from a stereo speaker
Answer:
sound waves
Explanation:
this is because sound waves are longitudinal waves, and longitudinal waves are waves that travel parallel to the direction of the wave motion
thus it cannot be light or electromagnetic waves but only sound waves
hope this helps, please mark it
4. In the figure below, a current of 2.8A flows
towards the bridge circuit and no current flows
in the galvanometer, G. Calculate the current
flowing in the 4Ω resistor. .
Α. 2.8A Β. 2.4A C. 2.0AD 1.2A
Answer:
The current flowing through the 4Ω resistor is;
C. 2.0 A
Explanation:
In the given figure, we have;
The series resistors in the bridge = 8Ω, and 4Ω are in series and 20Ω and 10Ω are in series
The sum of each of the series resistors are;
R₁ = 8Ω + 4Ω = 12Ω
R₂ = 20Ω + 10Ω = 30Ω
The equivalent resistors of the series resistors, R₁ and R₂ are parallel to each other
The current flowing through the 4Ω resistor = The current in R₁ = I₁
By the current divider rule, we have;
[tex]I_1 = \dfrac{R_2}{R_1 + R_2} \cdot I[/tex]
[tex]I_1 = \dfrac{30\Omega }{12 \Omega + 30 \Omega} \times 2.8 \, A = 2.0 \, A[/tex]
Therefore, I₁ = 2.0 A
The current flowing through the 4Ω resistor = I₁ = 2 A
Question 13 (1 point)
A 24 kg crate is pulled along a horizontal surface by a force of 95 N. The force is applied at an angle of 33° with the horizontal. The
coefficient of kinetic friction is 0.21. What is the acceleration of the crate?
Round to 2 decimal places. Units go in the second blank.
Blank 1:
Blank 2:
Answer:
papa's donuteria
Explanation:
:rawr:
7. What causes some metallic bonds to be stronger than others?
A.the number of donated valence electrons
B.the number of metallic bonds
C.the fineness of the metal
D.the number of metal ions
Answer:
the number of donated valence electrons
Explanation:
A metallic bond is formed when atoms come together in a metallic crystal lattice.
The metal atoms are usually ionized such that in a metallic crystal lattice consists of metal ions and a sea of mobile electrons. Attraction between these positively charged ions and the sea of electrons constitutes the metallic bond.
Hence, the more the number of donated valence electrons, the stronger the metallic bond.
Do you think aksionov is able to get justice in the end? Why?
You are stirring some soup on the stove and you notice that the metal spoon is getting hot. What type of heat transfer?
Answer:the answer is conduction
⦁ When a force of 6O N is applied to a mass of 30 kg, the acceleration of the mass will be:
Answer:
2m/s^2
Explanation:
Force is equal to;
mass × acceleration
therefore;
acceleration equals
force divided by mass
acceleration = 2m/s ^2
Answer:
f = 60N
m = 30kg
f= m×a
60N= 30 × a
a = 60/30
a = 2
what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface
Answer:
[tex]m=1.01\times 10^6\ kg[/tex]
Explanation:
Given that,
Pressure, P = 1 atm = 101325 Pa
Area of the square surface, A = 10² = 100 m²
We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,
[tex]P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg[/tex]
So, the required mass of the vertical column of air is [tex]1.01\times 10^6\ kg[/tex].
what is the fullform of SMPS ?
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Answer:
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Explanation:
Give examples to show that friction is both friend and foe ?
Answer:
friction as friend
It helps us to hold or catch any objectit alos helps us to walk easilyfriction as foe
It causes wear and tear of tyresit also cause great damages to parts of machinehope it helps
Answer:
Wear and tear of soles of our shoes is due to friction.
When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.
Machines get heated up and produce noise because of friction.
Electromagnetic waves moving through time and
space produces what type of energy?
Answer:
motion example of kinetic energy charged particle such as electrons and protons create electromagnetic field when they move in this field transport the type of energy vehicle electromagnetic radiation or light
Please help i’ll give brainlist if i can
Answer:
yellow
Explanation:
yellow
make me brain
how does displacement, acceleration, time, and velocity affect motion?
Answer:
The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.
~Hoped this helped~
~Brainiliest?~
Answer:
We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.
Explanation:
Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.
Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.
Hope this helps :)
Two trucks that appear to be identical collide on an icy road. One was originally at rest. After the collision that trucks are stuck together and move with more than half the original speed of the moving truck. What can you conclude about the loads of the two trucks? Explain.
Answer:
The trucks must have equal masses that is they must have same load.
Explanation:
Momentum refers to the product of the mass of the object and velocity.
As momentum has both magnitude and direction, it is a vector quantity.
In the given problem, it is given that after the collision, the trucks move at more than half the original speed of the moving truck. Therefore, the trucks must have equal masses that is they must have the same load.
Draw the currect electric lines for the following charge
The speed of light in amber is
1.94*10^8 m/s. What is the index
of refraction for amber?
(No unit)
Answer:
1.55
Explanation:
that it is the standard refractive index.
Which two factors affect the electric force between two particles?
A. Gravitational force
B. The strong nuclear force
C. Their charges
D. The distance between them
E. Their mass
Answer:
A. Gravitational force
C. Their charges
Explanation:
As we'll discuss in this lesson, he found that the force between charged particles was dependent on only two factors: the distance between the particles and the amount of electric charge that they carried.
Hope it help you
have a good day :)
How much power does it take to lift 20.0 N 5.0 m high in 5.0s?
Answer:
Explanation:
20 watts
this is confusind so plzzz help me
I need help! anyone trynna help?
Answer:
300 pascals
Explanation:
P=F/A
P=15N/0.05
P=300 pascals
Compare the inner planets with the outer planets.
Inner Planets:
- Rocky
- Small
- Only 3 moons total
- Very close to each other (for space)
- Underweight
Outer Planets:
- Gassy oop-
- GIANT
- Over 200 moons total
- VERY far from each other
- Obese
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Good luck foe.
Lb.
What is hydrology?
A the study of weather patterns
B the study of oceans
C the study of movement of water
D the study of movement of air
Extra
A stone is dropped from a balloon that is descending at a uniform rate of
12 m/s when it is 1000 m from ground.
a. Calculate the velocity and position of the stone after 10 s and the time
it takes the stone to hit the ground.
b. Solve the same problem as for the case of a balloon rising at the given
velocity
Answer:
Assume that [tex]g =9.81\; \rm m\cdot s^{-1}[/tex], and that the air resistance on the stone is negligible.
a.
Height of the stone: [tex]389.5\; \rm m[/tex] (above the ground.)
Velocity of the stone: [tex]\left(-110.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)
b.
Height of the stone: [tex]629.5\; \rm m[/tex] (above the ground.)
Velocity of the stone: [tex]\left(-86.5\; \rm m \cdot s^{-1}\right)[/tex] (the stone is travelling downwards.)
Explanation:
If air resistance on the stone is negligible, the stone would be accelerating downwards at a constant [tex]a = -g = -9.81\; \rm m \cdot s^{-2}[/tex].
Let [tex]h_0[/tex] denote the initial height of the stone (height of the stone at [tex]t = 0[/tex].)
Similarly, let [tex]v_0[/tex] denote the initial velocity of the stone.
Before the stone reaches the ground, the height [tex]h[/tex] (in meters) of the stone at time [tex]t[/tex] (in seconds) would be:
[tex]\displaystyle h(t) = -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0[/tex].
Similarly, before the stone reaches the ground, the velocity [tex]v[/tex] (in meters-per-second) of the stone at time [tex]t[/tex] (in seconds) would be:
[tex]v(t) = -g\cdot t + v_0[/tex].
In section a., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = -12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling downwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:
[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + \left(-12\; \rm m \cdot s^{-1}\right) \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 389.5\; \rm m \end{aligned}[/tex].
Indeed, the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is greater than zero. The stone hasn't yet hit the ground, and both the representation for the height of the stone and that for the velocity of the stone are valid.
[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s - 12\; \rm m\cdot s^{-1} \\ &= -110.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].
The value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative, meaning that the stone would be travelling downwards at that time.
In section b., [tex]h_0 = 1000\; \rm m[/tex] while [tex]v_0 = 12\; \rm m\cdot s^{-1}[/tex] (the stone is initially travelling upwards.) Evaluate both [tex]h(t)[/tex] and [tex]v(t)[/tex] for [tex]t = 10\; \rm m \cdot s^{-1}[/tex]:
[tex]\begin{aligned} h(t) &= -\frac{1}{2}\, g \cdot t^{2} + v_0 \cdot t + h_0 \\ &= -\frac{1}{2}\ \times 9.81\; \rm m\cdot s^{-2}\times (10\; \rm s)^{2} \\&\quad\quad + 12\; \rm m \cdot s^{-1} \times 10\; \rm s + 1000\; \rm m \\[0.5em] &= 629.5\; \rm m \end{aligned}[/tex].
Verify that the value of [tex]h(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is indeed greater than zero.
[tex]\begin{aligned} v(t) &= -g\cdot t + v_0 \\ &= -9.81\; \rm m\cdot s^{-2}\times 10\; \rm s + 12\; \rm m\cdot s^{-1} \\ &= -86.5\; \rm m \cdot s^{-1} \end{aligned}[/tex].
Similarly, the value of [tex]v(t)[/tex] at [tex]t = 10\; \rm m \cdot s^{-1}[/tex] is negative because the stone would be travelling downwards at that time.
We've seen that stout tendons in the legs of hopping kangaroos store energy. When a kangaroo lands, much of the kinetic energy of motion is converted to elastic energy as the tendons stretch, returning to kinetic energy when the kangaroo again leaves the ground. If a hopping kangaroo increases its speed, it spends more time in the air with each bounce, but the contact time with the ground stays approximately the same. Explain why you would expect this to be the case. Drag the terms on the left to the appropriate blanks on the right to complete the sentences._ stays the same) [doesn't depend on the amplitude] [decreases) is in inverse proportion with the amplitude is in direct proportion with the amplitude [increases) When in contact with the ground it is like a spring in simple harmonic motion. When kangaroo is hopping faster, the amplitude of the oscillation _____, while the period _____ because it _____, hence the time in contact with the ground
Answer:
Follows are the soplution to this question:
Explanation:
In the given scenario it would be like a fluid in a simple harmonic in contact with the earth. Whenever a cheetah hops quicker, oscillatory amplitude rises, while the duration stays the same since it does not depend on frequency, which mostly means that time will be the same if you're in contact with the substrate.
I need help asap
What is a homopolar motor?
a. The first electric motor ever made.
b. A motor made by in the North Pole.
c. A motor used in homes in the winter.
Answer: The answer is A
Explanation:
PLZ ANSWER FOR 25 POINTS AND BRAINLIEST
Answer:
the answer is all of the above
Explanation:
brainliest please