PLEASE HELP ASAP

solve -1/6[3-15(1/3)2]

The canoe's actual speed is approximately 9.66 mph at a bearing of 12° south of east.

To determine the canoe's actual speed and direction, we need to consider the vector addition of the canoe's velocity and the current.

Let's start by drawing a diagram to visualize the problem.

We'll use a scale where 1 cm represents 10 mph.

Draw a line segment representing the canoe's velocity of 10 mph at a bearing of 25° south of east.

From the endpoint of the canoe's velocity vector, draw another line segment representing the current's velocity of 2 mph at a bearing of 80° west of south.

Connect the starting point of the canoe's velocity vector with the endpoint of the current's velocity vector to form a triangle.

Next, we can find the resultant velocity (actual speed and direction) of the canoe by calculating the vector sum of the canoe's velocity and the current's velocity.

Using the law of cosines, we can find the magnitude of the resultant velocity:

c² = a² + b² - 2ab [tex]\times[/tex] cos(C)

Where:

a = 10 mph (canoe's velocity)

b = 2 mph (current's velocity)

C = 80° (angle between the velocities)

Substituting the values:

c² = 10² + 2² - 2 [tex]\times[/tex] 10 [tex]\times[/tex] 2 [tex]\times[/tex] cos(80°)

c² = 100 + 4 - 40 [tex]\times[/tex] cos(80°)

Solving for c, the magnitude of the resultant velocity:

c ≈ √(100 + 4 - 40 [tex]\times[/tex] cos(80°))

c ≈ √(104 - 40 [tex]\times[/tex] cos(80°))

To find the direction, we can use the law of sines:

sin(A) / a = sin(C) / c

Where:

A = 25° (angle of the canoe's velocity)

a = 10 mph (magnitude of the canoe's velocity)

C = 80° (angle between the velocities)

c ≈ √(104 - 40 [tex]\times[/tex] cos(80°)) (magnitude of the resultant velocity)

Substituting the values:

sin(25°) / 10 = sin(80°) / √(104 - 40 [tex]\times[/tex] cos(80°))

Solving for sin(80°):

sin(80°) ≈ (sin(25°) [tex]\times[/tex] √(104 - 40 [tex]\times[/tex] cos(80°))) / 10

Finally, we can use the inverse sine function to find the direction:

Direction ≈ arcsin((sin(25°) [tex]\times[/tex]√(104 - 40 [tex]\times[/tex] cos(80°))) / 10)

Calculating the numerical values using a calculator will give us the actual speed and direction of the canoe.

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The value of b in the Problem given is 0.5

The given problem can be represented mathematically as below :

We can find be in the expression thus :

4 = 8b

divide both sides by 8 in other to isolate b

4/8 = 8b/8

0.5 = b

Therefore, value of b in the expression is 1/2.

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(a) The magnitude of the rod's angular acceleration is (3g/2L) rad/s^2.

(b) The tangential acceleration of the rod's center of mass is (3g/4) m/s^2.

(c) The tangential acceleration of the rod's free end is (3g/2) m/s^2.

(a) To find the magnitude of the rod's angular acceleration, we can use the formula for rotational motion. The torque acting on the rod is due to the gravitational force acting at its center of mass.

The torque is given by τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

For a thin rod rotating about one end, the moment of inertia is (1/3)ML^2, where M is the mass of the rod and L is its length.

The torque is equal to the product of the gravitational force and the perpendicular distance from the pivot to the center of mass, which is (1/2)L.

So we have τ = (1/2)MgL, where g is the acceleration due to gravity. Substituting these values into the torque equation, we get (1/2)MgL = (1/3)ML^2 α.

Simplifying the equation, we find α = (3g/2L).

Therefore, the magnitude of the rod's angular acceleration is (3g/2L) rad/s^2.

(b) The tangential acceleration of the rod's center of mass can be found using the formula a = αr, where a is the tangential acceleration, α is the angular acceleration, and r is the distance from the center of mass to the pivot point.

In this case, the distance r is (1/2)L, so substituting the values, we get a = (3g/2L)(1/2)L = (3g/4) m/s^2.

Therefore, the tangential acceleration of the rod's center of mass is (3g/4) m/s^2.

(c) The tangential acceleration of the rod's free end is equal to the sum of the tangential acceleration of the center of mass and the product of the angular acceleration and the distance from the center of mass to the free end.

Since the distance from the center of mass to the free end is (1/2)L, the tangential acceleration of the free end is

a + α(1/2)L = (3g/4) + (3g/2L)(1/2)L = (3g/4) + (3g/4) = (3g/2) m/s^2.

Therefore, the tangential acceleration of the rod's free end is (3g/2) m/s^2.

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The end of 6 months, Ram should pay Rs. 276250 compounded half-yearly.

Ram borrowed Rs. 250000 from Sit at an interest rate of 21% per annum. To calculate the compound interest, we need to know the compounding period. In this case, the interest is compounded half-yearly, which means it is calculated twice a year.

To find out how much Ram should pay at the end of 6 months, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:
A = the amount to be paid at the end of the time period
P = the principal amount (the initial amount borrowed) = Rs. 250000
r = the interest rate per period (in decimal form) = 21% = 0.21
n = the number of compounding periods per year = 2 (since it's compounded half-yearly)
t = the number of years = 6 months = 6/12 = 0.5 years

Plugging in these values into the formula, we get:

A = 250000(1 + 0.21/2)^(2*0.5)

Simplifying the equation:

A = 250000(1 + 0.105)^(1)

A = 250000(1.105)

A = Rs. 276250

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The length of u, to the nearest inch, is 1818 inches.

To solve this problem, we can use the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant.

In this case, we'll use the following formula:

a/sin(A) = b/sin(B) = c/sin(C)

Let's label the sides and angles of the triangle:

Side a = u (length of u)

Side b = t (820 inches)

Side c = v (length of v)

Angle A = m/U (132°)

Angle B = m2V (25°)

Angle C = 180° - A - B (as the sum of angles in a triangle is 180°)

Now, we can use the Law of Sines to set up the equation:

u/sin(A) = t/sin(B)

Plugging in the given values:

u/sin(132°) = 820/sin(25°)

To find the length of u, we'll solve this equation for u.

u = (820 [tex]\times[/tex] sin(132°)) / sin(25°)

Using a calculator, we can evaluate the right side of the equation to get the approximate value of u:

u ≈ (820 [tex]\times[/tex] 0.9397) / 0.4226

u ≈ 1817.54 inches

Rounding to the nearest inch, we have:

u ≈ 1818 inches

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Answer: 21.15 ft²

Step-by-step explanation:

We can use the formula for the area of a triangle:

(b×h)/2

In this case, the base is 9 and the height is 4.7.

So, we substitute the variables with the numbers in this problem.

(9 × 4.7)/2

9 × 4.7 = 42.3

42.3/2 = 21.15

So, our final answer is 21.15 ft²

The difference between their yearly incomes is $31,304.

To calculate each person's yearly income, we need to multiply their weekly income by the number of weeks in a year. Assuming there are 52 weeks in a year, the yearly income can be calculated as follows:

For the student who drops out of high school:

Yearly Income = Weekly Income x Number of Weeks

= 451 x 52

= 23,452

For someone with a bachelor's degree:

Yearly Income = Weekly Income x Number of Weeks

= 1053 x 52

= 54,756

The difference between their yearly incomes can be found by subtracting the student's yearly income from the bachelor's degree holder's yearly income:

Difference = Bachelor's Yearly Income - Student's Yearly Income

= 54,756 - 23,452

= 31,304

Therefore, the difference between their yearly incomes is $31,304.

It is important to note that these calculations are based on the given information and assumptions. The actual yearly incomes may vary depending on factors such as work hours, additional income sources, deductions, and other financial considerations.

Additionally, it is worth considering that educational attainment is just one factor that can influence income, and there are other variables such as experience, job type, and market conditions that may also impact individuals' earnings.

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The equation of the tangent line at the point (108, 6) on the curve y² = x²/(xy - 324) is: y = 6

The equation is given as:

y² = x²/(xy - 324) at (108, 6)

Differentiating implicitly with respect to x gives:

2y(dy/dx) = (2x(xy - 324) - x²(y - 324)(dy/dx)) / (xy - 324)²

Simplifying further using power rule and chain rule gives us:

[tex]\frac{dy}{dx} = \frac{x^{2}y - 648x }{2y(-324 + xy) +x^{3} }[/tex]

We can find the slope by plugging in x = 108 and y = 6 to get

[tex]\frac{dy}{dx} = \frac{(108^{2}*6) - 648(108) }{2(6)(-324 + (108*6)) + 108^{3} }[/tex]

dy/dx = 0

To find the equation of the tangent line, we use the point-slope form:

y - y₁ = m(x - x₁),

where:

(x₁, y₁) is the given point (108, 6) and m is the slope.

Substituting the values, we have:

y - 6 = 0(x - 108)

y = 6

This is the equation of the tangent line at the point (108, 6) on the curve y² = x²/(xy - 324).

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The coefficient of x is -1, indicating that there is one fewer x term compared to the original expression. The constant term is -4, which is the result of subtracting 5 from -9.

To find the difference when subtracting 8x - 5 from 7x - 9, we can use the distributive property to distribute the negative sign to each term in 8x - 5:

(7x - 9) - (8x - 5) = 7x - 9 - 8x + 5

Next, we can combine like terms by adding or subtracting the coefficients of the same variables:

7x - 9 - 8x + 5 = (7x - 8x) + (-9 + 5) = -x - 4

Therefore, the expression that represents the difference when 8x - 5 is subtracted from 7x - 9 is -x - 4.

In this expression, the coefficient of x is -1, indicating that there is one fewer x term compared to the original expression. The constant term is -4, which is the result of subtracting 5 from -9.

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A scatter plot visually represents the relationship between two variables. It shows a positive correlation between the number of books read per month and SAT Verbal Test scores, with the equation y = 6.4828x + 520.6962.

A scatter plot is a graphical representation of a set of data that allows the observer to observe the relationship between two variables. It is used to graphically display how one variable is affected by the other. It is a chart of data points plotted on a two-dimensional graph with one variable represented on the X-axis and the other variable on the Y-axis.

Scatter Plot of the Data: From the data provided by the Language Arts department, we can create the scatter plot as shown below:
Equation of the line of best fit: The line of best fit is a straight line that is used to model the relationship between the two variables. It is determined by minimizing the sum of the squares of the differences between the observed values and the predicted values.

From the scatter plot, we can see that there is a positive correlation between the number of books read per month and the score on the SAT Verbal Test. This suggests that the more books a student reads per month, the higher their score on the SAT Verbal Test.

The equation of the line of best fit for the given data set is y = 6.4828x + 520.6962. Here, y represents the score on the SAT Verbal Test and x represents the number of books read per month.

To find the equation of the line of best fit, we can use a regression analysis tool such as Excel. The regression analysis will give us the values of the slope and intercept of the line of best fit, which we can use to write the equation of the line.

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Answer:

(Look at the picture)

The result of dividing (4x³ + 6x² + 20x + 9) by (2x + 1) using long polynomial division is 2x² + 2x + 9 with a remainder of 0.

To divide the polynomial (4x³ + 6x² + 20x + 9) by (2x + 1) using long polynomial division.

Arrange the terms of the dividend and the divisor in descending order of the degree of x:

      2x + 1 | 4x³ + 6x² + 20x + 9

Divide the first term of the dividend by the first term of the divisor and write the result on the top line:

             2x + 1 | 4x³ + 6x² + 20x + 9

                   | 2x²

Multiply the divisor (2x + 1) by the quotient obtained in the previous step (2x²) and write the result below the dividend:

             2x + 1 | 4x³ + 6x² + 20x + 9

           - (4x³ + 2x²)

           ---------------

                        4x² + 20x + 9

Subtract the result obtained in the previous step from the dividend and bring down the next term.

             2x + 1 | 4x³ + 6x² + 20x + 9

           - (4x³ + 2x²)

           ---------------

                        4x² + 20x + 9

                      - (4x² + 2x)

                      ---------------

                               18x + 9

Repeat the process by dividing the term brought down (18x) by the first term of the divisor (2x):

             2x + 1 | 4x³ + 6x² + 20x + 9

           - (4x³ + 2x²)

           ---------------

                        4x² + 20x + 9

                      - (4x² + 2x)

                      ---------------

                               18x + 9

                             - (18x + 9)

                             ---------------

                                         0

The division is complete when the degree of the term brought down becomes less than the degree of the divisor.

In this case, the degree of the term brought down is 0 (a constant term). Since we can no longer divide further, the remainder is 0.

Therefore, the result of the division is:

Quotient: 2x² + 2x + 9

Remainder: 0

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The combinations of assembling these rectangles for which it is possible to create a rectangle with the length of 15 and the width 11 with no gaps or overlapping are:

A rectangle is a plane figure with four straight sides and four right angles, especially one with unequal adjacent sides.

Required

Which group forms a rectangle of

[tex]\text{Length}=15[/tex]

[tex]\text{Width}=11[/tex]

First, calculate the area of the big rectangle

[tex]\text{Area}=\text{Length}\times\text{Width}[/tex]

[tex]\text{A}_{\text{Big}}=15\times11[/tex]

[tex]\text{A}_{\text{Big}}=165[/tex]

Next, calculate the area of each rectangle A to E.

[tex]\text{A}_{\text{A}}=11\times7[/tex]

[tex]\text{A}_{\text{A}}=77[/tex]

[tex]\text{A}_{\text{B}}=2\times11[/tex]

[tex]\text{A}_{\text{B}}=22[/tex]

[tex]\text{A}_{\text{C}}=6\times6[/tex]

[tex]\text{A}_{\text{C}}=36[/tex]

[tex]\text{A}_{\text{D}}=6\times5[/tex]

[tex]\text{A}_{\text{D}}=30[/tex]

[tex]\text{A}_{\text{E}}=13\times4[/tex]

[tex]\text{A}_{\text{E}}=52[/tex]

Then consider each option.

(a) 2C + 2D + 2B

[tex]2\text{C}+2\text{D}+2\text{B}=(2\times36)+(2\times30)+(2\times22)[/tex]

[tex]2\text{C}+2\text{D}+2\text{B}=72+60+44[/tex]

[tex]2\text{C}+2\text{D}+2\text{B}=176[/tex]

(b) A + B + C + D

[tex]\text{A}+\text{B}+\text{C}+\text{D}=77+22+36+30[/tex]

[tex]\text{A}+\text{B}+\text{C}+\text{D}=165[/tex]

(c) A + 4B

[tex]\text{A} + 4\text{B}=77+(4\times22)[/tex]

[tex]\text{A} + 4\text{B}=77+88[/tex]

[tex]\text{A} + 4\text{B}=165[/tex]

(d) 3E + 2B

[tex]3\text{E}+2\text{B}=(3\times52)+(2\times22)[/tex]

[tex]3\text{E}+2\text{B}=156+44[/tex]

[tex]3\text{E}+2\text{B}=200[/tex]

(e) E + C + D + 3B

[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=52+36+30+(3\times22)[/tex]

[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=52+36+30+66[/tex]

[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=184[/tex]

Recall that:

[tex]\text{A}_{\text{Big}}=165[/tex]

Only options (b) and (c) match this value.

[tex]\text{A}+\text{B}+\text{C}+\text{D}=165[/tex]

[tex]\text{A} + 4\text{B}=165[/tex]

Hence, options (b) and (c) are correct.

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Answer:

(-3, -2) ∪ (1, ∞)

Step-by-step explanation:

Given inequality:

[tex]\dfrac{x^2+5x+6}{x-1} > 0[/tex]

Begin by factoring the denominator:

[tex]\begin{aligned}x^2+5x+6&=x^2+2x+3x+6\\&=x(x+2)+3(x+2)\\&=(x+3)(x+2)\end{aligned}[/tex]

Therefore, the factored inequality is:

[tex]\dfrac{(x+3)(x+2)}{x-1} > 0[/tex]

Determine the critical points - these are the points where the rational expression will be zero or undefined.

The rational expression will be zero when the numerator is zero:

[tex](x+3)(x+2)=0 \implies x=-3,\;x=-2[/tex]

Therefore, -3 and -2 are critical points.

The rational expression will be undefined when the denominator is zero:

[tex]x-1=0 \implies x=1[/tex]

Therefore, 1 is a critical point.

So the critical points are -3, -2 and 1.

Create a sign chart, using open dots at each critical point (the inequality is greater than, so the interval doesn't include the values).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Chosen test values: -4, -2.5, 0, 2

For each test value, determine if the function is positive or negative:

[tex]x=-4 \implies \dfrac{(-4+3)(-4+2)}{-4-1} = \dfrac{(-)(-)}{(-)}=\dfrac{(+)}{(-)}=-[/tex]

[tex]x=-2.5 \implies \dfrac{(-2.5+3)(-2.5+2)}{-2.5-1} = \dfrac{(+)(-)}{(-)}=\dfrac{(-)}{(-)}=+[/tex]

[tex]x=0 \implies \dfrac{(0+3)(0+2)}{0-1} = \dfrac{(+)(+)}{(-)}=\dfrac{(+)}{(-)}=-[/tex]

[tex]x=2 \implies \dfrac{(2+3)(2+2)}{2-1} = \dfrac{(+)(+)}{(+)}=\dfrac{(+)}{(+)}=+[/tex]

Record the results on the sign chart for each region (see attached).

As we need to find the values for which the rational expression is greater than zero, shade the positive regions on the sign chart (see attached). These regions are the solution set.

Remember that the intervals of the solution set should not include the critical points, as the critical points of the numerator make the expression zero, and the critical point of the denominator makes the expression undefined. The intervals of the solution set are those where the rational expression is greater than zero only.

Therefore, the solution set is:

-3 < x < -2  or  x > 1

As interval notation:

(-3, -2) ∪ (1, ∞)

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The area of the figure WXYZ which can be calculated as the sum of the area of the composite triangles ΔXYZ and ΔXWZ is 12 square units

Composite figures are figures comprising of two or more regular figures.

The slope of the side WZ = 2/5

The slope of YZ = -2/1 = -2

The slope of WZ is not the negative inverse of the slope of YZ, therefore, the figure WZ is not perpendicular to YZ and the figure is not a rectangle.

Considering the two triangles formed by the diagonal XZ, we get;

The figure XYZW is a quadrilateral, which is a composite figure comprising of two triangles, triangle ΔXYZ and ΔXWZ

Area of triangle ΔXYZ = (1/2) × 6 × 2 = 6 square units

Area of triangle ΔXWZ = (1/2) × 6 × 2 = 6 square units

The area of the figure = Area of triangle ΔXYZ + Area of triangle ΔXWZ

Area of triangle ΔXYZ + Area of triangle ΔXWZ = 6 + 6 = 12 square units

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Answer:

B. 0.593

Step-by-step explanation:

Answer: 5/ 16

explanation: total= 4x4=16

red and yellow : (r,y) or (y,r)

n= 5

p= 5 1/1 16

p = 5 over 16

The statement about the zeros of function g is that they are located at x = 5 + √2 and x = 5 - √2.

When the vertex of function f is moved 4 units to the right and 2 units down, the equation of function g can be represented as g(x) = -(x-5)^2 + 2.

To determine the statement about the zeros of function g, we need to find the x-values where g(x) equals zero.

Setting g(x) = 0 and solving for x:

[tex]0 = -(x-5)^2 + 2[/tex]

Adding (x-5)^2 to both sides:

[tex](x-5)^2 = 2[/tex]

Taking the square root of both sides (considering both positive and negative roots):

x - 5 = ±√2

Adding 5 to both sides:

x = 5 ± √2

Therefore, the zeros of function g are x = 5 + √2 and x = 5 - √2.

In summary, the statement about the zeros of function g is that they are located at x = 5 + √2 and x = 5 - √2.

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The postulate or theorem that proves that two triangles are congruent if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle. Of the above choices, only ASA satisfies this condition. So the answer is (C).

ASA Congruence Theorem explains that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

This theorem is a part of triangle congruence criteria in Euclidean geometry. It states that if two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle, then the two triangles are congruent, meaning they have the same shape and size.

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The limit of the function As x → - ∞, f(x) → 2.

The limit of a function is the value the function tends to as the independent variable tends to a given value.

Given the graph of the function above, to find the limit of the function As x → -∞, f(x) →? We proceed as follows

Looking at the graph, we see that f(x) has a horizontal asymptote at y = 2. Now, we see that As x → -∞, f(x) approaches 2.

So, As x → - ∞, f(x) → 2.

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The approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.

To find the approximate mean, first, we add all the numbers in the data set, and then we divide that sum by the total number of values in the data set.

The formula for finding the approximate mean is as follows: Approximate mean = sum of the values in the data set / total number of values in the data set.

The following data set is given: Number of cars sold by a salesman in the past 10 weeks: 3, 5, 2, 4, 7, 5, 6, 3, 2, 4.

To find the approximate mean, we first need to add all the values: 3 + 5 + 2 + 4 + 7 + 5 + 6 + 3 + 2 + 4 = 41 The sum of all the values is 41.

Next, we need to divide this sum by the total number of values in the data set. In this case, the total number of values is 10. Therefore, the approximate mean for the given data set is: Approximate mean = 41 / 10 = 4.1

Therefore, the approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.

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The graph of the solution to the inequality is attached as image to this answer.

The piece-wise defined function h(x) represents different values of y (the output) depending on the value of x (the input). Each interval of x has a different value assigned to it.

In this particular case, the inequality statements define the intervals for x and their corresponding output values.

Let's break it down:

- For values of x that are greater than -3 and less than or equal to -2, h(x) is assigned the value of -1.

- For values of x that are greater than -2 and less than or equal to -1, h(x) is assigned the value of 0.

- For values of x that are greater than -1 and less than or equal to 0, h(x) is assigned the value of 1.

- For values of x that are greater than 0 and less than or equal to 1, h(x) is assigned the value of 2.

Any values of x outside of these intervals are not defined in this piece-wise function and are typically represented as "not a number" (NaN).

For example, if you were to evaluate h(-2.5), it falls within the first interval (-3 < x ≤ -2), so h(-2.5) would be equal to -1. Similarly, if you were to evaluate h(0.5), it falls within the fourth interval (0 < x ≤ 1), so h(0.5) would be equal to 2.

The graph of the piece-wise function h(x) consists of horizontal line segments connecting the specified values of y for each interval, resulting in a step-like pattern.

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The area of the given rectangle is determined by multiplying its length of 13 units by its width of 2 units, resulting in an area of 26 square units.

To find the area of the rectangle, we need to multiply its length by its width. The length of the rectangle is given as 13 units and the width is given as 2 units.

The formula to calculate the area of a rectangle is: Area = Length × Width.

Using the given measurements, we substitute the values into the formula:

Area = 13 × 2 = 26 square units.

Therefore, the area of the given rectangle is 26 square units.

To provide a more detailed explanation, the area of a rectangle represents the total amount of space enclosed by its four sides. In this case, the rectangle has a length of 13 units and a width of 2 units. When we multiply the length by the width, we are essentially finding the product of the two dimensions, which gives us the total area.

The resulting area of 26 square units implies that within the boundaries of the rectangle, there are 26 square units of space. It is important to note that the unit of measurement used for the length and width should be consistent to ensure the accuracy of the area calculation.

In summary, the area of the given rectangle is determined by multiplying its length of 13 units by its width of 2 units, resulting in an area of 26 square units.

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Answer:

the possible length and width b:

1 and 20

10 and 2

5 and 4

120 = 1*20*6

120 = 10*2*6

120 = 5*4*6

The possible length and width for Derek's rectangular prism with a volume of 120 cubic inches and a height of 6 inches is 6 inches and 20 inches, respectively.

To find the possible length and width of Derek's rectangular prism, we can use the formula for the volume of a rectangular prism:

Volume = Length x Width x Height

Given that the volume is 120 cubic inches and the height is 6 inches, we can substitute these values into the formula:

120 = Length x Width x 6

To find the possible values for length and width, we need to factorize 120 and check the combinations that satisfy the equation. Let's find the factors of 120:

1 x 120

2 x 60

3 x 40

4 x 30

5 x 24

6 x 20

8 x 15

10 x 12

Now let's substitute these factors into the equation and solve for the missing dimension:

For the combination 1 x 120:

120 = 1 x 120 x 6

This does not work because the width would be 120 inches, which is not feasible.

For the combination 2 x 60:

120 = 2 x 60 x 6

This does not work because the width would be 60 inches, which is not feasible.

For the combination 3 x 40:

120 = 3 x 40 x 6

This does not work because the width would be 40 inches, which is not feasible.

For the combination 4 x 30:

120 = 4 x 30 x 6

This does not work because the width would be 30 inches, which is not feasible.

For the combination 5 x 24:

120 = 5 x 24 x 6

This does not work because the width would be 24 inches, which is not feasible.

For the combination 6 x 20:

120 = 6 x 20 x 6

This works because the width would be 20 inches:

120 = 6 x 20 x 6

120 = 720

This combination satisfies the equation.

For the combination 8 x 15:

120 = 8 x 15 x 6

This does not work because the width would be 15 inches, which is not feasible.

For the combination 10 x 12:

120 = 10 x 12 x 6

This does not work because the width would be 12 inches, which is not feasible.

Therefore, the possible length and width for Derek's rectangular prism with a volume of 120 cubic inches and a height of 6 inches is 6 inches and 20 inches, respectively.

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Answer:

4.9 in

Step-by-step explanation:

6/11 = x/9

6/11 times 9 = x

x = 4.9

Answer:

the two numbers are 20 and 1.

f(0) = -3

I believe, since the graph has a closed circle/point at (0,-3), f(0) should equal -3. Also, the graph 3x-3 has a domain of x>=0.

However, in terms of limits, the limit approaching x-->0 does not exist since the left and right limits do not equal one another.

Hope this helps.

Answer:

(8,5)(0,-3)

Step-by-step explanation:

-y=-x+3

y=x-3

Substitute for y:

(x-3)^2-2x=9

x^2-6x+9-2x=9

x^2-8x=0

x(x-8)=0

x=0,8

if x=0,

0-y=3

y=-3

if x=8

8-y=3

-y=-5

y=5

Answer :

x - y = 3

x = 3 + y

y^2 - 2x = 9

y^2 - 2(3+y) = 9

y^2 - 2y -6 -9 = 0

y^2 - 2y -15 = 0

Factorize

y = -3 y = 5

when y = -3

x -(-3) = 3

x = 0

when y = 5

x - 5 = 3

x = 8