PeTu
(a) The cell references containing values to be used for calculations passed
to the function are called​

In industry, computer technology is used by developing robots to assemble products in a short amount of time. This has led to unemployment as manual labour is kept to a minimum due to the robots being able to assemble products at a much faster speed than humans.

Answer:

Server side web caching typically involves utilizing a web proxy which retains web responses from the web servers it sits in front of, effectively reducing their load and latency.

Explanation:

Answer:

I don't know  you should figure that out good luck

Explanation:

good luck

Answer:

Tech A is correct.

Explanation:

The modern day vehicles have brakes system equipped with asbestos. It is a mineral which is a kind of fibrous crystal which enables the friction to stop the vehicle. The technician A specifies that the modern day automobiles use asbestos for their brake system.

Answer:

correct answer is Tech B.

Explanation:

just took the test

Answer:

That is not a question.

Explanation:

Answer:

1) In Normal view, on the Home tab, click Layout.

2) Pick a layout that best suits the content of your slide.

3) On the View tab, click Slide Master.

4) The slide layouts appear as thumbnails in the left pane below the slide master.

5) Do one or both of the following:

- Click the layout you want and customize it. You can add, remove, or resize placeholders, and you can use the Home tab to make changes to fonts, colors, and other design elements.

- Click Insert Layout to add a new slide and format it.

6) Click Close Master to stop editing layouts.

-Your revised slide layout will be available to insert as a new slide anywhere in your presentation.

7) Click Design and point to any theme.

8) Click the down arrow under that appears under the themes panel.

9) Click Save Current Theme, give the theme a name, and click Save. Your new theme will contain your newly revised slide layout and will be available in Themes gallery.

Answer:

Follows are the code to this question:

#include <iostream>//header file

using namespace std;

int main() //defining main method

{

int userNum, divNum;//defining integer variable

cin>> userNum >> divNum;//input values

cout <<"First-time divide: "<<userNum / divNum<<endl;//divide value First time  

cout <<"Second-time divide: " << userNum / divNum/divNum<<endl; //divide value Second time

cout<<"Third-time divide: "<< userNum /divNum/divNum/divNum<<endl;//divide value Third time

return 0;

}

Output:

2000

2

First-time divide: 1000

Second-time divide: 500

Third-time divide: 250

Explanation:

In this code two integer variable "userNum and divNum" is declared that uses the input method to input value from the user-end, and after input the value it divides the "userNum by divNum" three times, that is defined as follows:

In this code, the user input the value 2000 and 2, in the first divides it will give 1000, in the second time divide it will give 500, and in the third time it will give 250.

Answer:

See text attachment for complete source code (for the answer) where I used comments to explain each line of the program

Explanation:

First, design the form using the following tools (and the accompanying properties) :

1 Label: Property: Text: Score

2 Buttons

Button1: Property: Name: btnAdd; Text: Add

Button2: Property: Name: btnDisplay; Text: Display

1 ListBox: Property: Visible: Hidden

1 TextBox: Property: Name: txtNum1

First, create the following function.

The function (named typecheck) validates input from the user (i.e. integer input only)

Function typecheck(ByVal input As String) As Boolean

       Try

           Convert.ToInt32(input)

           [tex]Return\ True[/tex]

       [tex]Catch\ ex\ As\ Exception[/tex]

           [tex]Return\ False[/tex]

       End Try

   End Function

It returns true if the input is integer and false, if otherwise.

Next, double-click on the "Add" button and write the following lines of code:

Dim num1 As String

       num1 = txtNum1.Text

       If num1 IsNot String.Empty Then

           If typecheck(num1) Then

               [tex]ListBox1.Items.Add(num1)[/tex]

               [tex]txtNum1.Text = String.Empty[/tex]

           Else

               [tex]MsgBox("Only[/tex] [tex]Integer[/tex] [tex]Inpu t")[/tex]

               [tex]txtNum1.Text = String.Empty[/tex]

           [tex]End\ If[/tex]

       Else

           [tex]MsgBox("Box[/tex] [tex]can\ not\ be\ empty")[/tex]

           [tex]txtNum1.Text = String.Empty[/tex]

       [tex]End\ If[/tex]

Next, double-click on the "Display" button and write the following lines of code:

If ListBox1.Items.Count > 0 Then

           [tex]Dim\ max1, max2\ As\ Integer[/tex]

           max1 = Convert.ToInt32(ListBox1.Items(0))

           max2 = Convert.ToInt32(ListBox1.Items(0))

           [tex]For\ count\ = 0\ To\ ListBox1.Items.Count - 1[/tex]

               If Convert.ToInt32(ListBox1.Items([tex]count[/tex])) >= max1 Then

                   max1 = Convert.ToInt32(ListBox1.Items([tex]count[/tex]))

               [tex]End\ If[/tex]

           Next

           [tex]For\ count\ = 0\ To\ ListBox1.Items.Count - 1[/tex]

               If Convert.ToInt32(ListBox1.Items([tex]count[/tex])) >= max2 And Convert.ToInt32(ListBox1.Items([tex]count[/tex])) < max1 Then

                   max2 = Convert.ToInt32(ListBox1.Items([tex]count[/tex]))

               [tex]End\ If[/tex]

           Next

           MsgBox("Highest Scores: " + max1.ToString() + " " + max2.ToString())

           MsgBox("[tex]Total[/tex]: " + ListBox1.Items.Count.ToString())

       [tex]End\ If[/tex]

       ListBox1.Items.Clear()

Answer:

import java.util.*;  

class Main {

 private enum RPS { Rock, Paper, Scissors };

 private static RPS[] options = { RPS.Rock, RPS.Paper, RPS.Scissors };

 private static String[] names = {"Rock", "Paper", "Scissors"};

 // Return 1 if player 1 beats player 2, 0 otherwise

 static public int rps( RPS p1, RPS p2 ) {

   if (p1 == RPS.Rock && p2 == RPS.Scissors) return 1;

   if (p1 == RPS.Scissors && p2 == RPS.Paper) return 1;

   if (p1 == RPS.Paper && p2 == RPS.Rock) return 1;

   return 0;

 }

 static public int playRps() {

   Random rnd = new Random();      

   int totalPoints = 0;

   for(int round = 0; round < 24; round++) {

     int randomNumber = rnd.nextInt(2);  

     RPS player1 = options[randomNumber];      

     RPS player2 = options[round%3];

     String name1 = names[randomNumber];

     String name2 = names[round%3];

     int score = rps(player1, player2);

     if (player1 == player2) {

       System.out.printf("%d. Both players %s. Draw.\n",  round+1, name1);

     } else if (score == 0) {

       System.out.printf("%d. %s does not beat %s, player 1 loses.\n",  round+1, name1, name2);

     } else {

       System.out.printf("%d. %s beats %s, player 1 wins.\n", round+1, name1, name2);

     }      

     totalPoints += score;

   }

   return totalPoints;

 }

 public static void main(String[] args) {

   System.out.println("Playing RPS.");

   int total = playRps();

   System.out.printf("Player 1 earned %d points.\n", total);

 }

}

Explanation:

Explanation:They are

Explanation:They are 1) start the process

Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed

Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 10

Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T

Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T5) End for

Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T5) End for6) Stop the process

Answer:

Since there are only two digits in binary, there are only two possible outcomes of each partial multiplication: If the digit in B is 0, the partial product is also 0. If the digit in B is 1, the partial product is equal to A.

Explanation:

Answer:

two digits

Explanation:

Binary – The binary numbering system has a base of 2 (MOD-2) and uses only two digits a “0” and a “1” to represent a binary number value.

Answer:

for me personally, it would help if the items were rearranged with like items, for example: snow, sleet, rain, and hail would go together.

so the list should look something like this:

    weather conditions

    fruits

   sports

hope i helped <3 have a nice day

Answer:

weather(rssh) fruit(sabo) sport(fstr)

Explanation:

Answer:

the hdmi and hardrive

Explanation:

Answer:

Dennis Ritchie is the answer

common commands such as bold, underline, copy, and paste. Also for cells format worksheet something like that...

The one that is a part of the Cells group on the home tab is insert. The correct option is 1.

In Microsoft Word, the Home tab is the default tab. The relevant commands are divided into five groups: Clipboard, Font, Paragraph, Styles, and Editing.

It enables you to edit document settings such as font size, bullet placement, style selection, and many other standard features.

The most utilised document controls can be found under the Home Tab; using these controls, you can alter the text's font and size, paragraph and line spacing, copy and paste, and organisational structure. The Home Tab is divided into four separate sections.

Insert is the one that is a member of the Cells group on the home tab.

Thus, the correct option is 1.

For more details regarding home tab, visit:

https://brainly.com/question/9646053

#SPJ2

Your question seems incomplete, the missing options are:

i. Insert

ii. Delete

iii Format

iv. All of these​

Answer:

studying in quiet place

Taking breaks

Reading from notes

good sleep

eating healthy foods

group study

studying on regular schedule

revision

Some study habits that you should practice are studying with friends, studying on a regular schedule, taking breaks while studying, getting good sleep, and studying in a quiet area. All options are correct.

Effective study techniques can be used by someone who wants to get good scores. Summarizing, limiting distractions, taking breaks, and memorization are some good study techniques.

Several good study practices include: When studying, summarize your notes, avoid studying when you're sleepy, memorize your notes, limit distractions, and take breaks.

Study habit is an action such as reading, taking notes, holding study groups which the students perform regularly and habitually in order to accomplish the task of learning.

Therefore, the correct options are a, b, c, d, and e.

To learn more about studying habits, refer to the link:

https://brainly.com/question/14735769

#SPJ5

Answer:

Follows are the code to this question:

#include <stdio.h>//header file

int main() //main method  

{

int plane, g1, g2, f;//defining integer variables

float m,a,t1,t2; //defining float variables

printf("Enter mass of airplane (kg)-> ");//print message for input value

scanf("%d", &plane);//input value

printf("Enter mass of glider #1 (kg)-> ");//print message for input value

scanf("%d", &g1);//input value

printf("Enter mass of glider #2 (kg)-> ");//print message for input value

scanf("%d", &g2);//input value

printf("Enter force produced by propellers (N) -> ");//print message for input value

scanf("%d", &f);//input value

m= plane + g1 + g2;//use float variable m to calculate Mass

a=f/m;//use float variable a to calculate Acceleration

printf("\nAcceleration: %.2f m/s^2", a);

printf("\n-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-");//use print method for design

t1 = (g1 + g2) * a;//using the t1 variable to calculate tensions

printf("\nResulting tension on cable #1: %.2f Newtons", t1);//print tension value

t2 = g2 * a;//using the t1 variable to calculate tensions

printf("\nResulting tension on cable #2: %.2f Newtons", t2);//print tension value

printf("\n-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-");//use print method for design

return 0;

}

Output:

Please find the attached file.

Explanation:

In this code four integer variable "plane, g1, g2, and f" and four floating-point variables "m, a, t1, and t2" is declared, in which the integer variable is used for input the value from the user-end.

In the next step, the "m" variable is used, which adds the "plane, g1, and g2" integer value to calculate mass, and in the "a" variable it calculates the acceleration, and in the "t1 and t2" variable it calculates the tension and prints its value.

Answer:

Woodblock printing or block printing is a technique for printing text, images or patterns used widely throughout East Asia and originating in China in antiquity as a method of printing on textiles and later paper. As a method of printing on cloth, the earliest surviving examples from China date to before 220 AD.

Answer:

A) randomNumber = 0.70;

Explanation:

The code works perfectly for all values of randomNumber given in the options except option (a)

This is so because:

The first condition

if (randomNumber <= 0.70)  {  event = 1;  }

It checks if randomNumber is less than or equal to 0.70. This is true, so event is set to 1.

However, the next condition after it will also be executed because it is a different conditional to be executed.

So, we have:

if (randomNumber <= 0.80)  {  event = 2;  }

This condition is also true, so event is set to 2.

From the question randomNumber is meant to be event 1. However, this is different from the result of executing the code.

Hence, (a) is true

Answer:

Follows are the code to the given question:

class BankAccount //defining a class BankAccount

{

 int balance;//defining integer variable balance  

 String name;//defining String variable name

 BankAccount()//defining default constructor

 {

 }

  BankAccount(int balance, String name)//defining parameterized constructor that accepts two parameters  

  {

     this.balance = balance;//use this to hold parameter value

     this.name = name;//use this to hold parameter value

  }

}

public class Main//defining Main class

{

 public static void main(String[] asr)//main method  

 {

  BankAccount obv = new BankAccount(1969, "Mustang");//creating class object and pass value in parameter

   System.out.println("Your name is: " + obv.name + " and " +"Your balance is: "+ obv.balance);//print value with message

 }

}

Output:

Your name is: Mustang and Your balance is: 1969

Explanation:

In this code a class "BankAccount" is declared, that  defines the two variable "name and balance" as a integer and string, and in the next step a parameterized constructor is declared, that uses this keyword to hold value.

In the main class the main method is declared and inside the method class object is created that accepts parameter value and use the print method to print its value.

Answer:

Square capitals were used to write inscriptions, and less often to supplement everyday handwriting. When written in documents this style is known as Latin book hand. For everyday writing the Romans used a current cursive hand known as Latin cursive. Notable examples of square capitals used for inscriptions are found on the Roman Pantheon, Trajan's Column, and the Arch of Titus, all in Rome. Square capitals are characterized by sharp, straight lines, supple curves, thick and thin strokes, angled stressing and incised serifs. These Roman capitals are also called majuscules, as a counterpart to minuscule letters such as Merovingian and Carolingian.

Answer:

System/Application Domain and LAN-to-WAN Domain.

Explanation:

The Gramm-Leach-Bliley-Act is also referred to as the Financial Services Modernization Act of 1999. It was enacted by the 106th Congress of the United States of America and it requires that financial institutions explain to their customers the information sharing policies and ensure that customer sensitive data (privacy) is safeguarded.

This, under the Gramm-Leach-Bliley-Act (GLBA), banks must protect customer privacy.

In this scenario, a given bank has just implemented its online banking solution that allows customers to access their accounts and perform transactions via their computers or personal digital assistant (PDA) devices.

Hence, online banking servers and their public Internet hosting would fall within the System/Application Domain and LAN-to-WAN Domain.

In an IT infrastructure, there are seven main domains and these are the: User Domain, Workstation Domain, LAN Domain, LAN-to-WAN Domain, Remote Access Domain, WAN Domain, and System/Application.

Answer:

sucks to suck

Explanation:

Answer:

three primary partitions

Answer:

start a website

Explanation:

true

Answer:

Explanation:

//Include the required header files.

#include<iostream>

using namespace std;

//Define the main function.

int main()

{

//Define the variables.

int i, sum = 0, sqSum = 0, firstNum = 1, secondNum = 0;

char ch;

//Check for valid input.

while (!(firstNum < secondNum))

{

cout << "Enter starting number: ";

cin >> firstNum;

cout<<"Enter ending number(must be > startingNumber): ";

cin >> secondNum;

}

//Store first number in i

i = firstNum;

//Dispaly the number.

cout << "The odd numbers between " << firstNum

<< " and " << secondNum << " are:\n";

//Iterate between first and second number.

while (i <= secondNum)

{

//Check for even numbers.

//Store the sum

if (i % 2 == 0)

sum = sum + i;

//Print the odd numbers

//Evaluate the square of sum of odd number.

else

{

cout << i << " ";

sqSum = sqSum + i * i;

}

//Increase the value of i.

i++;

}

//Dispaly the sum of even numbers.

cout << "\n\nThe sum of the even numbers is:"

<< sum << endl << endl;

//Dispaly the sum of square of odd number.

cout << "The sum of squares the odd numbers is:"

<< sqSum << endl;

//Set i to 1.

i = 1;

//Dispaly the message.

cout << "\nNumber Square\n";

//Iterate and print number between 1 andd 10

//along with the sum.

while (i <= 10)

{

cout << " " << i << "\t " << i * i << endl;

i++;

}

//USe for visual studio.

system("pause");

//Return the value 0.

return 0;

}

Explanation:

The program code will perform the function listed below using loop.

Prompt the user to input two integers: firstNum and secondNum (firstNum must be less than secondNum). Output all odd numbers between firstNum and secondNum. Output the sum of all even numbers between firstNum and secondNum. Output the numbers and their squares between 1 and 10. Separate the numbers using any amount of spaces. Output the sum of the square of the odd numbers between firstNum and secondNum. Output all uppercase letters.

Hope this helps!

Answer:

Mouse and Keyboard.

its actually keyboard and touchpad!!

Answer:

A WAN can be one large network or can consist of two or more lans connected together. The Internet is the world's largest wan.

Explanation: