Answer:
Seven electrons.
Explanation:
There are seven valence electrons in each fluorine atom because it belongs to halogens. Fluorine atom requires one electron to complete its valence shell to become stable so for that it form both ionic and covalent bonds with different atoms. It makes ionic bond with alkali metals by accepting one electron to complete its valence shell and also make covalent bond by sharing of electrons.
can u pls help me with this question
Answer:
B
Explanation:
A mole of a substance has a mass in grams that is equal to the molecular mass. For example, a carbon atom has a mass of 12.01 u. A mole of carbon has a mass of 12.01 g. Based on their molar masses, list the GFM of each substance.
Answer:
hello your question is incomplete attached below is the complete question
answer :
Fe2O3 = 159 g/mol
CO = 28.01 g/mol
Fe = 55.85 g/mol
CO2 = 44.01 g/mol
Explanation:
Molar mass for Fe2O3Fe = 55.85 g/mol
O = 16.0 g/mol
hence the molar mass of Fe2O3 = 2(55.85) + 3(16) = 159 g/mol
Molar mass for COC = 12.01 g/mol
O = 16.0 g/mol
hence the molar mass of CO = 28.01 g/mol
Molar mass for FeFe = 55.85 g/mol
Molar mass for CO2C = 12.01 g/mol
O = 16.0 g/mol
hence the molar mass of CO2 = 12.01 + 2(16) = 44.01 g/mol
Answer:
There ya go ;)
Explanation:
What is the answer to this?
one if them is phosphate
Calculate the molar mass of adrenaline (C9H13NO3C9H13NO3), a hormone responsible for regulating heart rate and other functions of the sympathetic nervous system. Express your answer to five significant figures.
Answer:
[tex]M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
Explanation:
Hello!
In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:
[tex]M_{C_9H_{13}NO_3}=m_C*9+m_H*13+m_N+m_O*3[/tex]
Now, we plug in the atomic masses to obtain:
[tex]M_{C_9H_{13}NO_3}=12.01*9+1.01*13+14.01+16.00*3\\\\M_{C_9H_{13}NO_3}=183.23g/mol[/tex]
Best regards!
What is the answer to this?
can u pls help me with this question
Answer:
I think the answer is b
Explanation:
the paragraph states, that it is an experiment to see if there is any oxygen in the water
Calculate the following:
1. Mass of 4.3x10-3 mol of lead
2. Mass of 3.8x1022 antimony atoms
3. Number of atoms in 15.5 kg of tungsten
Answer:
1) Mass = 890.96 g
2) Mass = 7.67 g
3) 507.65 ×10²³ atoms
Explanation:
1) Given data:
Number of moles of lead = 4.3×10⁻³ mol
Mass of lead = ?
Solution:
Mass = number of moles × molar mass
Molar mass of lead = 207.2 g/mol
by putting values,
Mass = 4.3×10⁻³ mol × 207.2 g/mol
Mass = 890.96 g
2) Given data:
Number of atoms of antimony = 3.8×10²² atoms
Mass of antimony = ?
Solution:
1 mole contain 6.022 ×10²³ atoms
3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms
0.63×10⁻¹ mol
0.063 mol
Mass:
Mass = number of moles × molar mass
Molar mass of lead = 121.76 g/mol
Mass = 0.063 mol × 121.76 g/mol
Mass = 7.67 g
3) Given data:
Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)
Number of atoms = ?
Solution:
Number of moles of tungsten:
Number of moles = mass/molar mass
Number of moles = 15500 g / 183.84 g/mol
Number of moles = 84.3 mol
1 mole contain 6.022 ×10²³ atoms
84.3 mol × 6.022 ×10²³ atoms / 1mol
507.65 ×10²³ atoms
A photon of light has an energy of 1.83 x 10-18). What is the wavelength of this light? Does this light fall in the IR, visible, or UV region of the electromagnetic spectrum?
Answer:
1.09 × 10⁻⁷ m
UV region
Explanation:
Step 1: Given and required data
Energy of the photon of light (E): 1.83 × 10⁻¹⁸ J
Planck's constant (h): 6.63 × 10⁻³⁴ J.s
Speed of light (c): 3.00 × 10⁸ m/s
Step 2: Calculate the wavelength (λ) of this photon of light
We will use the Planck-Einstein's relation.
E = h × c/λ
λ = h × c/E
λ = 6.63 × 10⁻³⁴ J.s × (3.00 × 10⁸ m/s)/1.83 × 10⁻¹⁸ J = 1.09 × 10⁻⁷ m
This wavelenght falls in the UV region of the electromagnetic spectrum.
Please help me thanks so much....I’ll mark you?!?!:)))) ( 32 points)
Answer:
I believe it's chemical
Answer:
physical
Explanation:
it's not changing form or substance
For this experiment you will need to perform a serial dilution of CO(NO3)2 solutions, meaning that you will begin with a stock solution, dilute it to make a new solution, and then use that new solution as the stock solution for the next dilution. You will start with a 0.25 M CO(NO3)2 solution. Using the values below, calculate the volume of solution and water needed at each step of the dilution.
Concentration of original solution mL of original solution required mL of water required Concentration of new solution
0.25M 0.1M
0.1M 0.05M
0.05M 0.01M
Answer:
See answer below
Explanation:
In this case, I will put the original photo of this exercise, because we are missing one data. The first picture is the original exercise.
Now, according to this, we need to make a serial dilution of CO(NO₃)₂. We don't know the volume of this solution, but we do know the total volume of the preparing solution (In the picture states that the total volume will be 10 mL).
So, we know the final volume of the solutions to be prepared, so, le'ts use the expression that will help us to solve this:
C₁V₁ = C₂V₂
Where:
C₁: Concentration of the given solution (stock)
V₁: volume required to prepare the dilluted solution
C₂; Concentration of the dilluted solution
V₂: Total volume of the dilluted solution.
Now that we know the expression to use and the meaning of each value, let's prepare the solutions:
To prepare 10 mL of 0.1 M using a 0.25 M, we will replace these values in the above expression; from there, we will solve for V₁, that value will tell us the required volume to prepare solution 2, and then, by difference we can calculate the volume of water:
Volume of water (Vw) =V₂ - V₁
Now replacing the values:
0.25V₁ = 0.1 * 10
V₁ = 1/0.25 = 4 mL
V₁ = 4 mLThis means that we need 4 mL of the stock to prepare the 0.1 M of dilluted solution, therefore, the volume of water required is:
Vw = 10 - 4
Vw = 6 mLUsing these same steps for the other two solutions we will get V1 and V2 for both of them. In this case, I will go straight to the procedure without further explanation because it's the same of this one.
For solution 2:
0.1V₁ = 0.05 * 10
V₁ = 0.5/0.1
V₁ = 5 mLVw = 10 - 5
Vw = 5 mLFinally for solution 3:
V₁ = 0.01 * 10 / 0.05
V₁ = 2 mLVw = 10 - 2 mL
Vw = 8 mLHope this helps
In a lab, you produce a quantity of the radioactive isotope thorium-234. Over the course of several weeks, the unstable isotope decays, and you measure the amount of thorium-234 remaining in the sample. You obtain the following data. What is the half life of Thorium-234? How much Thorium 234 will there be after two half lives?
Days Elapsed Grams of Thorium 234 Remaining
0 16
12 11
24 8
36 6
a. 36 days
b. 12 days
c. 24 days / 4 grams
Answer:
Option C. 24 days / 4 grams
Explanation:
From the question given above, the following data were obtained:
Days Elapsed >>>> Mass Remaining
0 >>>>>>>>>>>>>>> 16
12 >>>>>>>>>>>>>>> 11
24 >>>>>>>>>>>>>>> 8
36 >>>>>>>>>>>>>>> 6
A. Determination of the half-life of Thorium-234.
To determine the half-life, it is important to know the definition of half life.
Half-life is defined as the time taken for a substance to reduce to half its original mass.
From the table given above, we can see that the original mass of the isotope is 16 g (i.e at 0 day). By day 24, the mass of the isotope is 8 g (i.e half the original mass). Thus, the half-life of the isotope is 24 days.
B. Determination of the mass of the isotope remaining after 2 half lives.
Original amount (N₀) = 16 g
Number of half-lives (n) = 2
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2² × 16
N = 1/4 × 16
N = 4 g
Thus, 4 g of the isotope is remaining after 2 half lives.
Summay:
Half-life = 24 days
Amount remaining after 2 half-lives = 4 g
Option C gives the correct answer to the question.
During the process of condensation, water vapor:____________.
(1) releases 334 J/g of heat energy
(2) releases 2260 J/g of heat energy
(3) gains 334 J/g of heat energy
(4) gains 2260 J/g of heat energy
Answer: (2) releases 2260 J/g of heat energy
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Latent heat of condensation is energy released when 1 mole of vapor condenses to form liquid droplets.
The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.
Phase transition refers to the changes in the states of matter between gas, liquids, and solids.
The correct answer is:
Option 2. releases 2260 J/g of heat energy
The process can be explained as:
1. Condensation is the process of conversion of water vapor into the liquid state.
2. Latent heat of vaporization is defined as the amount of heat required for 1 mole of liquid to convert into a gaseous phase at atmospheric pressure.
3. The change in the temperature does not occur during the condensation, and the heat required for the phase transition is latent heat. The heat of condensation of water vapor is 2,260 J/g.
Thus, the correct answer is Option 2.
To know more about condensation, refer to the following link:
https://brainly.com/question/15563071
Is it more difficult to remove a valence electron from a Magnesium (Mg) atom or a Chlorine (Cl) atom
Answer: It is more difficult to remove a valence electron from a Chlorine (Cl) atom
Explanation:
Ionization energy is the energy required to remove the valence electron from an isolated gaseous atom.
Magnesium (Mg) is the 12th element of periodic table and has an atomic number of 12. The electronic configuration is 2, 8, 2. It can easily lose its valence 2 electrons to attain stable configuration.
Chlorine (Cl) is the 17th element of periodic table and has an atomic number of 17. The electronic configuration is 2, 8, 7. It has a tendency to gain electron to attain stable configuration. It cannot lose its valence electron easily as the valence electrons experience more nuclear charge.
Thus it is more difficult to remove a valence electron from a Chlorine (Cl) atom
Chlorine(Cl) is the more difficult to remove a valence electron from which is
because it needs one electron to achieve a stable octet configuration.
Magnesium (Mg) is an element which has an atomic number of 12. The
electronic configuration is 2, 8, 2. This means it has to lose its 2 valence
electrons needed to attain a stable octet configuration.
Chlorine (Cl) is an element which has an atomic number of 17. The electronic
configuration is 2, 8, 7. This means it has to gain one valence electrons
needed to attain a stable octet configuration.
Thus it is more difficult to remove a valence electron from a Chlorine (Cl)
atom than Magnesium atom.
Read more on https://brainly.com/question/20714034
In the following pair, determine whether the two represent resonance contributors of a single species or depict different substances. If two structures are not resonance contributors, explain why. Select the single best answer.
N-N ≡ N: and N=N=N:
Answer:
They are resonance contributors
Explanation:
Resonance structures are structures that differ only in the distribution or placement of electrons.
Considering the two structures, we can easily see that the two species have the same total number of bonds and electrons differing only in the distribution of these electrons.
Hence, they are resonance contributors.
At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same conditions 285.8 KJ is released when one mole of H2O is formed from its elements. Find Delta h of the vaporization of water at these conditions
Answer:
44Kj
Explanation:
These are the equations for the reaction described in the question,
Vaporization which can be defined as transition of substance from liquid phase to vapor
H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H
-241.8kj -------eqn(1)
H2(g)+ 1/2 O2(g) ------>H2O(l).
Δ H =285.8kj ---------eqn(2)
But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as
H2O(l) ------>>H2O(g)---------------eqn(3)
But the equation from eqn(2) the eqn does go with vaporization so we can re- write as
H2O ------> H2(g)+ 1/2 O2(g)
Δ H= 285.8kj ---------------eqn(4)
To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)
Δ H=285.8kj +(-241.8kj)= 44kj
What was a key discovery in the advancement me up early information transfer
Answer:
The transfer was essential to understand the mutation and the possibility of new, more resistant strains in microorganisms.
Explanation:
the transfer of microorganisms is based on the transfer of genetic data through conductive pathways that penetrate the membranes, called pili or genetic bridges.
These mutated genes with higher resistance are transmitted and resistance is generated in entire populations and even species.
Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and characteristic colors by which we can identify them. Therefore, in the analysis of mixtures of metal ions, it is very common to precipitate the metal ions by using dihydrogen sulfate (commonly called hydrogen sulfide), H2S. Suppose you had a mixture of Fe2+, Cr3+, and Ni2+. Complete the net ionic equations for the precipitation of these metal ions by the use of H2S. (Type your answers using the format Fe2+ for Fe2+.)
Answer:
See explanation
Explanation:
For Fe;
Fe2+(aq) + 2H+(aq) + S2-(aq) ----> FeS(s) + H2(g)
For Ni
Ni2+(aq) + 2H+(aq) + S2-(aq) ----> NiS(s) + H2(g)
For Cr
2Cr3+(aq) + 6H+(aq) + 3S2-(aq) ----->Cr2S3(s) + 3H2(g)
We must remember that in writing these equations, the number of electrons lost or gained must be balanced. The number of electrons lost by the metal must equal the number of electrons gained by hydrogen. This rule was followed in writing all the equations above.
when aqueous solutions of sodium hypochlorite and nitric acid are mixed, an aqueous solution of sodium nitrate and hypochlorous acid results. Write the net ionic equation for the reaction.
Answer:
H+ (aq) + ClO- (aq) ---> HClO(aq)
Explanation:
The net ionic reaction equation is a chemical equation that explicitly shows only the particular ions that undergo a chemical change in the course of a given reaction.
In this particular reaction, the molecular reaction equation is shown as follows;
HNO3(aq) + NaOCl(aq) -----------> NaNO3(aq) + HOCl(aq)
Ionically;
H+ (aq) + ClO- (aq) ---> HClO(aq)
what would be a logical explanation for why carbon dioxide increased over the time shown in the graph.
A. the area of land for crops incresed
b. the amount of plants eaten by animal increased
c. the amount of fossil fuels being burned increased
d. the amount of wood being burned by pepole increased
Answer:
c. the amount of fossil fuels being burned increased
Explanation:
Carbon dioxide gas concentration increased over the time due to burning of fossil fuels increased. Fossil fuels are organic compounds which releases carbondioxide gas as a result of burning of fossil fuels in the engines of vehicles and industries. With the passage of time, number of vehicles increases in the world which needs more fossil fuels and due to burning of that fossil fuels, more carbondioxide gas is released.
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 3.00 molesmoles of aluminum sulfate, Al2(SO4)3Al2(SO4)3. Express the number of moles of AlAl, SS, and OO atoms numerically, separated by commas.
Answer:
[tex]n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO[/tex]
Explanation:
Hello!
In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:
[tex]\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}[/tex]
Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:
[tex]n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO[/tex]
Best regards!
Which gas is most abundant in Earth’s atmosphere?
Answer:
nitrogen
Explanation:
The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere. Why do I care?
nitrogen is the most abundant gas in the atmosphere
2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11
Answer:
11
Explanation:
Moles of KOH = [tex]10^{-2}[/tex]
Volume of water = 10 liters
Concentration of KOH is given by
[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]
[tex][KOH][/tex] is strong base so we have the following relation
[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]
[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]
[tex]\Rightarrow pH=14-3=11[/tex]
So, pH of the solution is 11
Xander is gaining weight. Which best describes what he can do to prevent obesity? exercise every day and also make healthy choices in his diet excercise once a week but make no change in his diet exercise once a week and also make healthy choices in his diet exercise every day but make no change in his diet
Answer:
exercise every day and also make healthy choices in his diet
Explanation:
This is going to prevent Xander from getting more overweight and will help him lose some pounds.
This is also something I need to do lol
<3
Answer:
A
Explanation:
Exercise every day and also make healthy choices in his diet
Please help me thanks so much....I’ll mark you?!?!:))))
Answer:
Extreme heat
Explanation:
Because when matter is heated up The molecules move faster.
Answer:
I think it's extreme heat
Calculate the number of grams of solid aluminium chloride that will form when a mixture containing 0.150 g of aluminum powder and 1.00 g of chlorine gas is allowed to react.
2Al (s) + 3Cl2 (g) ---> 2AlCl3 (s)
a. 741 g AlCl3
b. 471 g AlCl3
c. 0.741 g AlCl3
d. 246 g AlCl3
Answer:
the answer is B:) have a good day
The wavelength of green light from a traffic signal is centered at 5.20 x 10-7 m.
Calculate the frequency.
Answer: 5.77 * 10¹⁴s⁻¹
Explanation:
Speed = Frequency * Wavelength
Frequency = Speed/ Wavelength
Speed of light = 3 * 10⁸ m/s
Frequency = (3 * 10⁸ m/s) / (5.20 x 10⁻⁷m)
= 5.77 * 10¹⁴hz
= 5.77 * 10¹⁴s⁻¹
A covalent bond forms when
Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.
Answer:
66.5753 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (⁶⁵X):
Mass of A = 65.0457 amu
Abundance of A = 20.53%
Isotope B (⁶⁷X):
Mass of B = 66.9704 amu
Abundance of B = 79.47%
Atomic mass of X =?
The atomic mass of X can be obtained as follow:
Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]
= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]
= 13.3539 + 53.2214
= 66.5753 amu
Therefore, the atomic mass of X is 66.5753 amu.
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
What is the average atomic mass?The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.
Element X has 2 isotopes:
⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).We can calculate the average atomic mass of X using the following expression.
mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X
mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947
mX = 66.58 amu
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
Learn more about atomic mass here: https://brainly.com/question/6200158
For the following reaction, 22.5 grams of iron are allowed to react with 35.0 grams of chlorine gas . iron(s) chlorine(g) iron(III) chloride(s) What is the maximum mass of iron(III) chloride that can be formed
Answer:
53.31g of FeCl3
Explanation:
The equation of the reaction is given as;
2Fe(s) + 3Cl2(g) --> 2FeCl3(s)
From the stochiometry of the reaction;
2 mol : 3 mol : 2 mol
112g : 213g : 324.4g
Converting the masses given to moles;
Number of moles of Fe = mass / molar mass = 22.5 / 56 = 0.4018
Number of moles of Cl2 = mass / molar mass = 35 / 71 = 0.4930
In this reaction, the limiting reactant is Cl2
213 g of Cl2 produces 324.4g of FeCl3,
35g of Cl2 would produce xg of FeCl3
213 = 324.4
35 = x
x = (35 * 324.4) / 213 = 53.31g
how does mixture relate to life
Answer:
For example, when we bake a cake, it's a result of a mixture of eggs, flour, sugar, and other ingredients. Any time two or more items are combined, a mixture is formed. Sometimes, the different parts of a mixture can be separated into individual entities. Other times, they're married for as long as they exist.
Explanation: