Part E
Calculate the perimeter of quadrilateral ABCD by adding the side lengths you found in parts A through D. Show your work.

Answers

Answer 1

Answer:

this is the answer

Step-by-step explanation:

Part ECalculate The Perimeter Of Quadrilateral ABCD By Adding The Side Lengths You Found In Parts A Through

Related Questions

Assume that each time a metal detector at an airport signals, there is a 25% chance that the cause is change in the passenger's pocket. During a given hour, 15 passengers are stopped because of a signal from the metal detector. a) Find the probability that at least 3 passengers will have been stopped due to change in their pockets. b) If 15 passengers are stopped by the detector, would it be unusual for none of these to have been stopped due to change in the pocket

Answers

Answer:

a) 0.7639 = 76.39% probability that at least 3 passengers will have been stopped due to change in their pockets.

b) 0 is less than 2.5 standard deviations from the mean, so it would not be unusual.

Step-by-step explanation:

For each passenger, there are only two possible outcomes. Either they will have been stopped due to a change in the pocket, or not. Passengers are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

A measure is considered unusual if it is more than 2.5 standard deviations of the mean.

25% chance that the cause is change in the passenger's pocket.

This means that [tex]p = 0.25[/tex]

During a given hour, 15 passengers are stopped because of a signal from the metal detector.

This means that [tex]n = 15[/tex]

a) Find the probability that at least 3 passengers will have been stopped due to change in their pockets.

This is

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{15,0}.(0.25)^{0}.(0.75)^{15} = 0.0134[/tex]

[tex]P(X = 1) = C_{15,1}.(0.25)^{1}.(0.75)^{14} = 0.0668[/tex]

[tex]P(X = 2) = C_{15,2}.(0.25)^{2}.(0.75)^{13} = 0.1559[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0134 + 0.0668 + 0.1559 = 0.2361[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.2361 = 0.7639[/tex]

0.7639 = 76.39% probability that at least 3 passengers will have been stopped due to change in their pockets.

b) If 15 passengers are stopped by the detector, would it be unusual for none of these to have been stopped due to change in the pocket

First we find the mean and the standard deviation:

[tex]E(X) = np = 15*0.25 = 3.75[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15*0.25*0.75} = 1.68[/tex]

3.75 - 2.5*1.68 = -0.45

0 is less than 2.5 standard deviations from the mean, so it would not be unusual.

What is the average weight of the kittens in the shelter?
Please explain!!

Answers

Answer:

Step-by-step explanation:

You should add the weights of each kitten and then divide by the number of kittens. Ex. There are 5 kittens weighing 2, 1, 3, 2, and 2. So you would add those to get 10 and divide by the number of kittens which is 5 to get an average of 2.

So in this case you would first add the weight of the kittens

Then divide that by the number of kittens

Then the quotient would be the average of the weight of the kittens in the shelter.

Caroline earns $139.50 for 6 hours of work. If she makes a constant hourly wage, which table represents the relationship between the number of hours she works and her total earnings?

Answers

Answer:

Table A.

Step-by-step explanation:

$139.50 / 6 hours = $23.25 an hour

1 hour of work = $23.25 earned