Answer:
v = 0.489 m/s
Explanation:
It is given that,
Mass of a box, m = 1.5 kg
The compression in the spring, x = 6.5 cm = 0.065 m
Let the spring constant of the spring is 85 N/m
We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.
[tex]\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2[/tex]
[tex]v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s[/tex]
So, the speed of the box is 0.489 m/s.
What is the overall charge of the wall?
Answer:
The overall charge on the wall is zero.
Explanation:
Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.
Two identical long wires of radius a = 2.80 mm are parallel and carry identical currents of i = 5.00 A in opposite directions. Their center-to-center separation is W = 19.0 cm. Neglect the flux within the wires but consider the flux in the region between the wires. What is the inductance per unit length of the wires?
Answer:
Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
Explanation:
Radius of the wire, a = 2.80 mm
Currents carried by each of the wires, i = 5.00 A
Center-to-Center Separation, W = 19.0 cm
The flux in the wires is given by the equation, ∅ = Li
The Net flux of the region between the wires is given by the equation:
[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]
Divide both sides by l to get the net flux per unit length
[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
Using the free-body diagram, calculate the net force acting on the sled. Is the sled in a state of dynamic equilibrium?
The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.
Explanation:
The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.
Since the net force acting on the sled is zero, the sled is in some state of equilibrium...
Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.
Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.
From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.
So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.
Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.
Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...
EXTRA
Given is that the sled is moving with a constant speed.
No imagine two situations and try to predict what will happen.... Here we go...
Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.
Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...
Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.
Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.
Answer:
yes
Explanation:
edg 2020
What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon.
Answer:
The jug drowns because the density of the jug is more than that of the density of water.
Answer:
it gets force upwards .
as there is presence of atmospheric pressure in it which causes upthrust and push upwards.
Wood has chemical energy which can be used to generate thermal and radiant energy when burned in a fire place which best explains what happens to the total amount of energy in this scenario
Answer:
c i took the test
Explanation:
The total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.
What happens to the total amount of energy in this scenario?The energy present in the wood change into other forms of energy such as heat and radiant energy. We know that during a reaction, matter is transformed into another form with the release of different types of energy.
So we can conclude that he total amount of energy in this scenario is transformed into other forms of energy because of the burning process of the wood.
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Differences Between light year and astronomical unit in two points .
Answer:
A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc.
Answer: A light year is the distance light travels in a year. ... And an astronomical unit is the average distance between the earth and the sun. So the distance to the sun is by definition one AU. A parsec is the distance at which one astronomical unit subtends an angle of one second of arc
Explanation:
A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?
Answer:
we have to measure distances and time, possibly with an automated system since the values are very small
Explanation:
For this exercise we can use the relationship between momentum and momentum
I = ∫ F dt = Δp
F t = m [tex]v_{f}[/tex] - mv₀
In the exercise they indicate that the final speed is zero
F t = - m v₀
F = -m v₀ / t
With this equation we can find what measurements should be carried out.
To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.
During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.
In summary we have to measure distances and time, possibly with an automated system since the values are very small
What is the magnitude of these two vectors: 101 m 60.0 degrees 85.0 m
Answer:
85.0 please I don't understand
Inertia law what happens when You are standing on the bus and the bus stops abruptly:
Answer:
You will fly forward in the bus until you hit something.
Explanation:
While standing there on the bus, you are traveling at the same speed as the bus. If the bus suddenly stops, you will still be traveling at the same speed you started with. That is until you hit something hard enough or big enough to stop you.
Answer:
You will fall towards the front of the bus i.e towards its front seat
Explanation:
When the bus is moving, you are supposed to be in that motion. Your body is experiencing a forward force as the bus is moving forward So when bus stops suddenly your inertia does not allow you to stay in that standing position it will let you move forrward to maintain your inertia so you will feel a forward push. (If you were sitting on a seat with seatbelt on you that seatbelt will make you come back when car or bus stops.)
HELPPP!!! I will give Brainliest!!! super easy question
I have a question. If a question has the numbers 500kg and 3000N, how many significant digits should the answer have?
Answer:
most likely just 1
Explanation:
I sucked at sig figs in middle school, in fact it was the lowest test grade i ever received, but it is relatively simple.
because there is only one sig fig involved in each number, there can't be multiple sig figs here. 3000/500=6
500/3000=2(round up from 1.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666) you get the point.
Sound travels at approximately 1,500 m/s in sea water. How far will a sonar pulse travel in 90 s?
Answer:
135,000 m
Explanation:
(1500 m/s) (90 s) = 135,000 m
The distance travelled by sonar pulse will be 135,000 m. Distance is a numerical representation of the distance between two objects or locations.
What is wavelength ?The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometers, and other units since it is a distance measurement.
The distance travelled by sonar pulse is found as;
[tex]\rm d = v \times t \\\\ \rm d = 1500\times 90 \\\\ \rm d = 135,000 \ m[/tex]
Hence, the distance travelled by sonar pulse will be 135,000 m.
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Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57 The 5-number summary is nothing, nothing, nothing, nothing, and nothing, all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)
Answer:
The 5-number summary is
1. Median = 0.93 W/kg
2. Lower quartile = 0.69 W/kg
3. Upper quartile = 1.16 W/kg
4. Minimum value = 0.54 W/kg
5. Maximum value = 1.42 W/kg
Explanation:
We are given the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones.
1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57
What is 5-number summary?
A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.
These statistical characteristics are:
1. Median
2. Lower quartile
3. Upper quartile
4. Minimum value
5. Maximum value
1. Median:
Arrange the data in ascending order
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
(n+1)/2 gives the median value of the data set.
(11 + 1)/2 = 6th position
Therefore, 0.93 W/kg is the median of the data set.
2. Lower quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The lower quartile is the median of the lower half of the data set.
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
The median is 6/2 = 3rd position
Therefore, the lower quartile of the data set is 0.69 W/kg
3. Upper quartile:
Divide the data set into two equal halfs (include median in both if n = odd)
Lower half = 0.54 0.57 0.69 0.75 0.85 0.93
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The upper quartile is the median of the lower half of the data set.
Upper half = 0.93 0.95 1.16 1.17 1.18 1.42
The median is 6/2 = 3rd position
Therefore, the upper quartile of the data set is 1.16 W/kg
4. Minimum value:
The minimum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the minimum value of the data set is 0.54 W/kg
5. Maximum value
The maximum value is the least value in the data set.
0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42
Therefore, the maximum value of the data set is 1.42 W/kg
The box plot is illustrated in the attached diagram.
why is urbanization a contribution to pollution?
Answer:
people in urban areas strip the soil of nutrition and makes it difficult to grow crops. people of urban areas consume more energy,food,and water. people in urban areas remove minerals and metals from the ground so, urbanization is a contribution to pollution .
Explanation:
it may help you and give me brainliest
Answer:
pollution and loss of trees not to mention how much electricity we use which doesnt benefit the world.
Explanation: because when we urbanize things we get rid of natural resources around us
What will be the resistance Rstretched of the wire if it is stretched to twice its original length? Assume that the density and resistivity of the material do not change when the wire is stretched.
Answer:
Hence, the resistance of the stretched wire will be four times that of the original wire.Explanation:
The resistance of a material is expressed as R = ρL/A
Volume of the original material V = Area * Length = A*L
ρ is the resistivity of the material
R is the resistance
A is the cross sectional area
L is the length of the wire.
If the wire is stretched o twice its original length then new length of the wire L₂ = 2L. Note that an increase in the length of wire will affect its area but its volume and density will not change.
This means V = V₂
A*L = = A₂*L₂
A*L = A₂*(2 L)
A = 2 A₂
A₂ = A/2
The new resistance of the material Rf = ρL₂/A₂
R₂ = ρ(2 L)/(A/2)
Rf = 2ρL * 2/A
Rf = 4(ρL/A)
Since R = ρL/A
R₂ = 4R
Hence, the resistance of the stretched wire will be four times that of the original wire.
If the wire is stretched to twice its original length, the new resistance would be quadrupled.
The resistance (R) of a wire is given by:
[tex]R=\rho\frac{L}{A} \\\\where\ L\ is\ length\ of\ wire, A\ is\ the\ cross\ sectional\ area\ and\ \rho\ \\is\ the\ resistivity[/tex]
Since the wire is stretched, the new length (L₁) is twice its original length, hence:
L₁ = 2L
An increase in length affects the area, the new area (A₁) is:
initial volume = volume after stretch
AL = A₁L₁
AL = A₁(2L)
A₁ = A/2
The resistance of the stretched wire (R₁) is:
[tex]R_1=\rho\frac{L_1}{A_1} \\\\R_1=\rho\frac{2L}{A/2} \\\\R_1=4\rho\frac{L}{A}=4R[/tex]
Therefore if the wire is stretched to twice its original length, the new resistance would be quadrupled.
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the dimension of relative density and tension
Answer:
Relative density is proportional to the frequency of a material's density to its water density. Because both have had the same proportions, their proportion is also dimensionless.
Explanation:
The dimension of relative density:-
Relative Density of a Substance (R.D.) = Substance Density / Water Density.
Therefore, R.D. Is just a ratio or a number. There are no units or dimensions to it.
For example:- The density of iron is 8.5 GM's/cm^3 & the density of water is 1 gm/cm^3 (in cgs units).
Tension:- Surface tension is the propensity of the new worlds and infographics to reduce to the particle size which is least appropriate. Atmospheric pressure helps insects (e.g. water striders) can travel or move and on a water surface, typically object is sensed rather than water.
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At which point does the satellite have the most gravitational potential energy?
O A. Point A
O B. Point B
O C. Point
OD. Point D
Answer:
Since gravitational potential is generally defined to be zero at infinity
and gravity does work as an object moves from infinity in a gravitational field,
(the potential becomes more negative) the farther the satellite is from the attractive force the greater is its gravitational potential. Since point E is most distant from the attractive force it has the most gravitational potential.
The Gravitational potential energy connected to a planet's position within the gravitational field of a central object, such as a star or a larger planet, is referred to as its gravitational energy.
The gravitational potential energy is given by:
PE = -G × (M × m) ÷ r
Here, (G) is the gravitational constant, (M) is the mass of a planet, (m) is the mass of a planet, and distance (r).
From the given figure, points E and A are the farthest.
Hence, at points E and A satellite have the most gravitational potential energy
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Swamp coolers are effective because _____.
A. the water is colder than the air.
B. the water pulls heat from the room to undergo a phase change.
C. the thermal energy of the water is decreasing.
D. the water's latent heat of vaporization is being pulled from the air.
Answer:
D. the water's latent heat of vaporization is being pulled from the air.
Explanation:
A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.
In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.
Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.
The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.
The swamp coolers are typically made up of the following essential components, these are;
1. Float.
2. Blower.
3. Pump.
4. Evaporative pad.
5. Water supply valve.
Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.
Answer:
B and D
Explanation:
The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration. A. 0.24 g
Answer:
Magnitude of the acceleration(g) = 9.7 meters/second²
Explanation:
Given:
Height of tower = 56 meter
Time taken = 3.4 second
Final velocity (v) = 33 meters/second
Initial velocity (u) = 0 meters/second
Find:
Magnitude of the acceleration(g)
Computation:
Using first equation of motion:
v = u + at
Magnitude of the acceleration(g)
v = u + gt
33 = 0 + g(3.4)
g = 33 / 3.4
g = 9.7 meters/second²
Magnitude of the acceleration(g) = 9.7 meters/second²
Indicar tipo de unión química que presentan los siguientes compuestos. Realizar a representación de Lewis, molecular o iónica, según corresponda: a-CH4 b-SrO c-HBr d-NH3 e-Cl2O f-Li2O g-CO2 h-MgCl2
Answer:
Explanation:
a. CH₄- Covalent bonding(ligação covalente)
b. SrO- ionic bonding (ligação iônica)
c. HBr- Polar Covalent bonding (ligação covalente polar)
d. NH₃ - covalent bonding(ligação covalente)
e. Cl₂O - Covalent bonding (ligação covalente)
f. Li₂O- ionic bonding (ligação iônica)
g. CO₂ - double covalent bonding (ligação covalente dupla)
h. MgCl₂- ionic bonding(ligação iônica)
magnetic moment is scaler or vector??
Which vector has an x-component with a length of 4?
Answer:
C.) vector C
Explanation:
From the graph provided:
Four vectors are present :
Vectors a, b, c and d.
The x-component of the vector is its magnitude along the x-axis.
Taking the coordinate of each vector:
Vector a = (1,4) : length of x- component = 1
Vector b = (1, 1) : length of x- component = 1
Vector c = (4, -4) : length of x- component = 4
Vector d = (-3, 4) : length of x- component = - 3
Therefore, vector c has an x-component length of 4
The volume of an object as a function of time is calculated by v = At3+B÷t where t is time measured in seconds and v is in cubic metres. Determine the dimension of the constants A and B.
Answer:
A = m³/s³ = [L]³/[T]³ = [L³T⁻³]
B = m³s = [L³T]
Explanation:
We have the equation:
V = At³ + B/t
where, the dimensions of each variable are as follows:
V = m³ = [L]³
t = s = [T]
substituting these in equation, we get:
m³ = A(s)³ + B/s
for the homogeneity of the equation:
A(s)³ = m³
A = m³/s³ = [L]³/[T]³ = [L³T⁻³]
Also,
B/s = m³
B = m³s = [L³T]
A projectile is fired with an initial speed of 60.3 m/s at an angle of 34.2 above the horizontal on a long flat firing range.
Part A: Determine the maximum height reached by the projectile.
Part B: Determine the total time in the air.
Part C: Determine the total horizontal distance covered (this is, the range).
Part D: Determine the speed of the projectile 1.20 s after firing.
Part E: Determine the direction of the projectile 1.20 s after firing.
Answer:
A.) H = 58.6 m
B.) T = 6.92 s
C.) 345.12 m
D.) V = 22.13 m/s
E.) Ø = 32.1 degree
Explanation:
Given that the
initial speed U = 60.3 m/s
Angle Ø = 34.2 degree
A.) At maximum height, final velocity V is equal to zero.
Using the third equation of motion under gravity.
V^2 = U sin Ø^2 - 2gH
Substitute for U and g. Where g = 9.8 m/s^2
0 = (60.3 sin 34.2)^2 - 2 × 9.8 × H
1148.78 = 19.6 H
H = 1148.78/19.6
H = 58.6 m
B.) To Determine the total time in the air, let us use the formula
V = UsinØ - gt
At maximum height, V = 0
t = UsinØ/g
Total time T = 2t
Therefore, T = 2UsinØ/g
T = (2 × 60.3 × sin 34.2)/9.8
T = 67.79/9.8
T = 6.92 s
C.) To determine the total horizontal distance covered which is the range, we will use second equation of motion.
S = UcosØT - 1/2gt^2
Where S = range R
g = 0, since the range is not a vertical distance
T = total time
Substitute all the parameters into the formula
R = 60.3 cos 34.2 × 6.92
R = 345.12 m
D.) After 1.2 s firing,
V = UsinØ - gt
Where t = 1.2 s
Substitute into the formula
V = 60.3 × sin34.2 - 9.8 × 1.2
V = 33.89 - 11.76
V = 22.13 m/s
Therefore the speed of the projectile 1.20 s after firing is 22.13 m/s
E.) The direction will be determined by using the formula
t = VsinØ/ g
Cross multiply
VsinØ = gt
Make SinØ the subject of formula
SinØ = gt/V
SinØ = (9.8×1.2)/22.13
Sin Ø = 11.76/22.13
Sin Ø = 0.53
Ø = sin^-1( 0.53 )
Ø = 32.1 degree
WILL MARK AS BRAINLIEST..... A constant force vector f =2i cap+3j cap-5k cap acts on a particle and displaces it from (1,2,-3) m to (2,5,-1) m. find the work done by the force . Plzzzzzzzz helppppppppp !!!!!!!!!
Answer:
W = 1 J
Explanation:
Given that,
A constant force, [tex]F=2i+3j-5k[/tex]
The particle displaces it from (1,2,-3) m to (2,5,-1) m. We need to find the work done by the force.
The position vector from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) i.e. (1, 3, 2) m
Work done is given by :
[tex]W=F{\cdot} d\\\\W=(2i+3j-5k){\cdot} (i+3j+2k)[/tex]
From dot product, i.i = j.j = k.k = 1
So,
[tex]W=2+3\times 3-5\times 2\\\\W=1\ J[/tex]
So, the work done by the force is 1 J.
Examples of drawing packages
Answer:
The answer are given above in attachment.
A machine can never be 100% efficient because some work is always lost due to which factor?
A.friction
B.gravity
C.static
D.input force
Answer:
A. can never be efficient due to friction
HEY!!
Answer:
A. friction
Explanation:
Now if we obtain output work same as input energy then it is 100% efficient.
but this is only possible when we have no energy loss while it is not possible due to many reasons:
one of the main cause of energy loss is friction
A machine can never be 100% efficient because some work is always lost due to the lack of materials or equipment that would convert work by 100%. but so far, no machine has got 100% efficiency.
So when the machine are working there must be a friction between its working parts due to which the out-input energy is lost in different parts and hence we can never be 100% efficient machine.
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Neptune moves in an elliptical orbit with the sun at one of the foci. The length of half of the major axis is kilometers, and the eccentricity is 0.0086. Find the perihelion distance of Neptune from the sun. Round your answer to the nearest kilometers.
Given that,
Eccentricity = 0.0086
Suppose, The length of half of the major axis is [tex]1\times10^{9}\ km[/tex]
We need to calculate the distance from the center to the foci
Using formula of eccentricity
[tex]e=\dfrac{c}{a}[/tex]
[tex]c=e\times a[/tex]
Where, e = eccentricity
a = major axis
c = the distance from the center to the foci
Put the value in to the formula
[tex]c=0.0086\times1\times10^{9}[/tex]
[tex]c=8600000[/tex]
We need to calculate the perihelion distance of Neptune from the sun
Using formula of distance
[tex]d=a-c[/tex]
Put the value into the formula
[tex]d=1\times10^{9}-0.0086\times10^{9}[/tex]
[tex]d=991400000\ km[/tex]
Hence, The perihelion distance of Neptune from the sun is 991400000 km.
It takes 12.8 N of force to pull the
spring in a toy dart gun back
0.0715 m. What is the spring
constant of the spring?
(Unit = N/m)
Answer:
179.02N/m
Explanation:
spring constant = force/extension
(12.8)/(0.0715)= 179.02N/m
If a body gains 360 electrons, what is its electric charge?
Answer:
5.76×10⁻¹⁷ C
Explanation:
An electron has a charge of 1.6×10⁻¹⁹ C.
360 × (1.6×10⁻¹⁹ C) = 5.76×10⁻¹⁷ C
Please someone to help me with this will be very grateful In a light bulb, how is electrical energy transformed into light? and in an LED, will it be the same?
Answer:
LED;
The energy of photons emitted by an LED is dictated by the band gap of the semiconductor used – the energy required to make an electron–hole pair. When an electron and hole recombine in a radiative process, a photon carries away the extra energy.
BULB
In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. ... 1, chemical potential energy is converted to electrical energy, which is immediately converted to light energy and heat energy
This flow of charge converts chemical potential energy into electrical energy. In the light bulb, the flow of charge through the filament heats it up and causes it to glow. In this way, the light bulb converts electrical energy to heat energy and light energy. bulb have a fillament but LED have no filament they produce energy through clod process but bulb have a filament and they produce energy through hot process
Explanation:
This progression of charge changes over substance expected vitality into electrical vitality. In the light, the progression of charge through the fiber warms it up and makes it shine. Along these lines, the light believers electrical vitality to warm vitality and light vitality.
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