Compare and contrast electric potential energy and electric potential difference? Explain.

Answer:

Red

Orange

Yellow

Green

Blue

Indigo

Violet

shortest wavelength: violet (380 nanometers)

¯\(°_o)/¯

Answer:

Red    Orange    Yellow    Green   Blue   Indigo    Violet

violet has the shortest wavelength

happy to help :)

Answer:

Option A. a

Explanation:

Motion variables include:

1. Final velocity (vf).

2. Initial velocity (vi).

3. Time (t).

4. Acceleration (a)

5. Distance (x)

Considering the equation given in the question:

Δx = ½(vf + vi) t

We can see that the acceleration (a) is missing in the equation.

Answer:

As per the fossil fuel records, magnetic field reversal does not impact living beings. It will take almost a century for the poles to complete the shift. Meanwhile, the earth is left with almost zero magnetic field.

Answer:

it shows that co2 is absorbed by the atmosphere.

when the animals respire they produce co2 which is release in atmosphere and in presence of sunlight and chlorophyll the plants manufacturs the food and releases the oxygen in the atmosphere .

hope it helps..

Answer:

Its A

Explanation:

Answer:

Sound as a Longitudinal Wave

For a sound wave traveling through air, the vibrations of the particles are best described as longitudinal. Longitudinal waves are waves in which the motion of the individual particles of the medium is in a direction that is parallel to the direction of energy transport.

Answer:

Hey!

Here is your answer!

Explanation:

LONGITUDINAL WAVES:

These are waves where the transferral of energy is PARALLEL to the direction it travels in...For Example...Sound Waves are Longitudinal as they move in a series of COMPRESSIONS and RAREFACTIONS (typical of all Longitudinal Waves)...

The compressions are known in diagrams to be an area of a dense collection of PARTICLES where the energy (or sound in this case) is being transferred in the same direction as the movement...

The rarefactions are shown as almost empty area of particles where the medium (the matter of which the wave travels in) is moving...

Hope this helps!

*here's a diagram*

Answer:

104.9 m

5.63 s

45.3 m/s

Explanation:

Given:

y₀ = 100 m

v₀ = 9.8 m/s

a = -9.8 m/s²

Find: y when v = 0 m/s

v² = v₀² + 2a (y − y₀)

(0 m/s)² = (9.8 m/s)² + 2 (-9.8 m/s²) (y − 100 m)

y = 104.9 m

Find: t when y = 0 m

y = y₀ + v₀ t + ½ at²

0 m = 100 m + (9.8 m/s) t + ½ (-9.8 m/s²) t²

0 = 100 + 9.8t − 4.9t²

t = [ -9.8 ± √(9.8² − 4(-4.9)(100)) ] / 2(-4.9)

t = (-9.8 ± 45.3) / -9.8

t = 5.63 s

Find: v when y = 0 m

v² = v₀² + 2a (y − y₀)

v² = (9.8 m/s)² + 2 (-9.8 m/s²) (0 m − 100 m)

v = -45.3 m/s

|v| = 45.3 m/s

Answer:

The apparent weight of a freely falling body is zero. When a body falls freely, it is falling with an acceleration =g. Thus the entire gravitational force acting on it is utilized in accelerating it and hence its weight is not felt.

Answer:

1.) Magnitude = 5596 N

2.) Direction = 60 degrees

Explanation: You are given that the breakdown vehicle A is exerting a force of 4000 N at angle 45 degree to the vertical and breakdown vehicle B is exerting a force of 2000 N

Let us resolve the two forces into X and Y component

Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N

Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )

= 2000 + 2828.43

= 4828.43 N

The resultant force R will be

R = sqrt ( X^2 + Y^2 )

Substitutes the forces at X component and Y component into the formula

R = sqrt ( 2828.43^2 + 4828.43^2 )

R = sqrt ( 31313752.53 )

R = 5595.87 N

The direction will be

Tan Ø = Y/X

Substitute Y and X into the formula

Tan Ø = 4828.43 / 2828.43

Tan Ø = 1.707106

Ø = tan^-1( 1.707106 )

Ø = 59.64 degree

Therefore, approximately, the magnitude and direction of the resultant force on the truck are 5596 N and 60 degree respectively.

Answer:

1 feet

Explanation:

1 feet = 1 feet so its one feet

Answer:

0.8 kilogram

Explanation:

Mass:This can be defined as the quantity of matter a body contained. The S.I unit of mass if kg.

From the question,

M = mv................. Equation 1

Where M = momentum, m = mass. V = velocity

make m the subject of the equation

m = M/v.............. Equation 2

Given: M = 8.0 kilogram meters/second, v = 10 meters/second

Substitute these values into equation 2

m = 8.0/10

m = 0.8 kilogram

Mechanical Advantage is always (Output Force) / (Input Force) .

MA = (20 N) / (2 N)

MA = 10

Answer:

Muscle size and training specifiicty

Explanation:

It depends on all other factors such as anatomy and psychology, muscle fiber recruitment, motor pattern development and muscle memory but to increase modifiable strength, size plays no big role.

Answer:

c) Both the parts will weigh the same

Explanation:

center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts

(might be D if it is cutting against the center of gravity)

Explanation:

time spent to run from house to school=100/5=20s

time spent to return from school=100/10=10s

average velocity=200m/(10+20)

Answer:

Work done, W = 181238.4 J

Explanation:

We have,

Mass of a car, m = 1500 kg

Initial speed, u = 50 km/h = 13.88 m/s

Final speed, v = 75 km/h = 20.84 m/s

Let W is the work done. It is equal to the change in kinetic energy of the car. So,

[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\W=\dfrac{1}{2}\times 1500\times ((20.84)^2-(13.88)^2)\\\\W=181238.4\ J[/tex]

So, 181238.4 J of work was done by the car.

Answer: 3.75 m/s

Explanation:

Average speed is distance covered per time taken.

If the time interval is from t = 2 to t = 10s

Then, the time taken will be

t = 10 - 2 = 8s

Given that the distance covered are 10 + 8 - 2 + 10

Since distance is a scalar quantity, we will only consider the magnitude and not the direction.

Total distance = 10 + 8 + 2 + 10 = 30m

Average speed = total distance/time

Substitute total distance and time into the formula

Average speed = 30/8

Average speed = 3.75 m/s

Answer:

t = 2 seconds

Explanation:

In 2nd question, the question is given the attached figure.

Initial speed of the bus, u = 0

Acceleration of the bus, a = 8 m/s²

Final speed, v = 16 m/s

We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

t is time taken

[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{16-0}{8}\\\\t=2\ s[/tex]

The bus will take 2 seconds to reach the stop.

Answer:

(B)

Explanation:

Because what ever angle the surface is, the light will reflect of of it perpendicular.

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + [tex]v_{oy}[/tex] t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        [tex]v_{y}[/tex] = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero ([tex]v_{oy}[/tex] = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s

Answer

3m/s²

Explanation

u=o

t=25s

v=75m/s

from Newton's first law of motion,

v=u+at

75=0+a(25)

75=25a

a= 75/25

a=3m/s²

The acceleration of the airplane is 3m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Initial velocity of the airplane: u=o.

Time taken: t=25s.

Final velocity of the airplane: v=75m/s.

We have to find acceleration of the plane: a = ?

We know that for accelerating motion of the air plane; final velocity can be expressed as:

    v=u+at

⇒ 75=0+a(25)

⇒ 75=25a

⇒ a= 75/25

⇒ a= 3m/s².

hence, acceleration of the airplane is 3m/s².

Learn more about acceleration here:

brainly.com/question/12550364

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Answer:

B, Parallel.

Explanation:

Mark as brainliest pls!

The wave motion does longitudinal waves transfer energy in the direction Parallel to the wave motion. Hence, option B is correct.

Waves are disturbances that move regularly and orderly from one location to another. Although sound, lighting, and the movement of elementary particles all have wave-like characteristics, surface waves that move on water are the most well-known.

The disturbance periodically oscillates with a set frequency and wavelength in the simplest waves (see periodic motion). In contrast to electromagnetic waves, which do not require a medium to travel and may move through a vacuum, mechanical waves, like sound, need a medium to go through. A medium's characteristics determine how a wave will travel across it. Seismic wave is also seen.

Therefore, option B is correct.

To know more about Wave:

https://brainly.com/question/3639648

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Answer:

They move outwards.

They don't intersect each other at any point.

They show the electric field.

Explanation:

Answer:

Please read the answer below

Explanation:

the nature of these lines refers to the fact that positive charges generate field lines that are directed out of the positive charges, and in turn are directed towards some negative charge present somewhere in the universe.

By consensus, the electric field lines leave the positive charges and enter the negative charges. That is the reason  why in a scheme like the shown in the image, is considered implicitly the existence of a negative charge, in some place of the universe.

Answer:

Explanation:

1) The time of flight equation for projectile motion can be used here to find total time in air.

t = 2vsin∅ / g

where v is speed, Ф is launch angle

t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

D = 1.41m

3) Maximum elevation is maximum time reached

h = v² sin²Ф / 2g

h = 4²sin² 60 / 2*9.8

h = 0.61 m

Answer:

4 seconds

Explanation:

The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).

The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).

A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.

The period (T) is given as:

[tex]Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds[/tex]

Answer:

v = 3.24 m/s

Explanation:

Since we don't have time, we can use the formula;

(Final distance - initial distance)/time = (initial velocity + final velocity)/2

Thus;

(x_f - x_i)/t = ½(v_xi + v_xf)

We are given;

x_i = 0 m

x_f = 5 m

v_xi = 0 m/s

v_xf = 5 m/s

Thus, plugging in the relevant values;

(5 - 0)/t = (0 + 5)/2

5/t = 5/2

t = 2 s

Using Newton's first law of motion, we can find the acceleration.

v = u + at

Applying to this question;

5 = 0 + a(2)

5 = 2a

a = 5/2

a = 2.5 m/s²

To get the speed, in m/s, of the block when it had traveled only 2.1 m from the top, we will use the formula;

v² = u² + 2as

v² = 0² + 2(2.5 × 2.1)

v² = 10.5

v = √10.5

v = 3.24 m/s

Answer:

F = 8.23 × 10⁻⁸N

Explanation:

F= kq²/r²

k= 9×10⁹Nm²/C²

q= 1.6×10⁻¹⁹C

r= 5.29×10⁻¹¹m

F= 9×10⁹× (1.6×10⁻¹⁹)²/  (5.29×10⁻¹¹)²

F = 8.23 × 10⁻⁸N

Answer:

Gravitational force can be seen as the pull that the earth has on an piece of matter. Everything on earth has a force acting on it which is gravity. It tries to pull two object closer to each other but never apart. The numerical value for gravitational force is 9.8 m/s^2 for free falling objects

Answer:

An Electric "charge" is a property of matter that causes a force to repel or attract when placed into a magnetic field. These charges can be replicated into positive and negative electrons when made from a chemical reaction.

Answer:

an electri

Explanation:

Answer:

12m

Explanation:

To obtain the answer to the question given, we must observe the characteristics of image formed by a plane mirror.

The image formed by a plane mirror have the following characteristics:

1. Laterally inverted.

2. Same distance as the object from the mirror.

3. Same height as the object.

4. Virtual.

With the above information, we can calculate the distance between the boy and his image as follow:

Initially:

Object distance (u) = 4m

Image distance (v) = 4m

The boy moved 2m away, therefore:

Object distance (u) = 2 + 4 = 6m

Image distanc(v) = 2 + 4 = 6m

The distance between the boy and his image will be the sum of his distance (u) and image distance (v) i.e (u + v)

The distance between the boy and his image = 6 + 6 = 12m

Therefore, the distance between the boy and his image is 12m.