oof oof oof I need help again lol

Answer:

Step-by-step explanation:

in the rough drawing i've included we want to find the distance of AC and BC and the subtract the shorter from the longer  or

BC- AC = AB

does this strategy seem like a good one?

use the mnemonic SOH CAH TOA to remember how sin, cos, and tan, fit on a triangle

SOH     Sin = Opp / Hyp

CAH    Cos =Adj / Hyp

TOA   Tan = Opp / Adj

where Opp = Opposite side,  Adj = Adjacent side , and Hyp = Hypotenuse

we are given an angle and the Opposite side so we can use Tan , since that has the thing we want to find, and the things we know.

when  AC is the Adj side it's

Tan(60) = 70 / Adj

Adj = 70 / Tan(60)

Adj = 40.4145

Dist. of AC = 40.4145 m

When BC is the Adj side it's

Tan(40) = 70 / Adj

Adj = 70/ Tan(40)

Adj = 83.42275

Dist. of BC = 83.42275

BC - AC = AB

83.45575 - 40.4145 =43.008

to the nearest tenth  AB = 43.0 m

Answer:

37 - 22 =  WC height

Step-by-step explanation:

Answer:

x=4.5

Step-by-step explanation:

The sum of all the angles in a square=360°

20(4.5)=90

90×4=360

Answer:

Angle 1 is 51, Angle 2 is 51, Angle 3 equal 39, Angle 4 is 51

Step-by-step explanation:

A rhombus diagonals are perpendicular so all the angles in the middle of the rhombus measure is 90 degrees. So this means we are dealing with 4 right congruent triangles.

Since a rhombus is a paralleogram, it opposite sides are parallel. Since there is a line that it cuts through the parallel line, Angle 3 and 39 are alternate interior angles.

Alt. interior angles are congruent so Angle 3=39.

In the upper left triangle, angle 3 ,angle 4, and the middle angle form 180 degrees since it a triangle. The middle angle measure 90 degrees. so we can find angle 4.

[tex]39 + 90 + x = 180[/tex]

[tex]129 + x = 180[/tex]

[tex]x = 51[/tex]

so angle 4=51.

Angle 4 and Angle 1 are alt. interior angles so that means Angle 1 also equal 51.

Rhombus also has angle bisectors to angle 1=angle 2.

Angle 2=51.

Step-by-step explanation:

y=42

x=90

Since the triangle has the hypotenuse as the diameter of the circle, the angle opposite the hypotenuse which is x is equal to 90 degrees.

Whenever there is a triangle with the corner of the triangle touching the side of the triangle, the distance between the two legs of the triangle on the circle is 2 times the angle of the corner that is touching. So 21(2)=42

Hope this helps :)

Answer:

7) [tex]4 \ log_3(x) - 4 \ log_3(y)[/tex]

9) [tex]5log_4(7) - 5log_4(12)[/tex]

11) [tex]5log_5 \ (x) - log_5 \ (y)[/tex]

Step-by-step explanation:

[tex]log_3 (\frac{x}{y})^{4}[/tex]

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Use Logarithm of a Quotient which states

[tex]log_b \frac{M}{N} = log_b M-log_bN[/tex]

And also use Logarithm of a Power which states

[tex]log_b\ M^{n} = n\log_bM[/tex]

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So using these two properties,

7. [tex]4 \ log_3(x) - 4 \ log_3(y)[/tex]

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For #9, use the same logarithm propertied

[tex]log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)[/tex]

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#11 is also the same concept

[tex]log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)[/tex]

It is not  - 5 log5(y) since only x is to the power of 5 not y

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Hope this is what you were looking for and helps you! Have a nice day/night :)

Answer: x=3/4

Step-by-step explanation:

To solve, first express the left side as one logarithm. To do so, apply the quotient rule which is log_bM/N=log_bM-log_bN .

log((2x+1)/(3x-2))=1

Then, express the equation to its equivalent exponential form to eliminate the logarithm.

Note that the exponential form of log_b M=a is M=b^a .

Since the base of the logarithm in the given equation is not written, it indicates that its base is 10.

So re-writing the equation, it becomes:

log_10((2x+1)/(3x-2))=1

And its exponential form is:

(2x+1)/(3x-2)=10^1

(2x+1)/(3x-2)=10

Now that the equation has no more logarithm, the next step is to remove the x in the denominator.

To do so, multiply both sides by 3x-2.

(3x-2)*(2x+1)/(3x-2)=10*(3x-2)

2x+1=30x-20

Next, combine like terms.

To combine 30x and 2x, bring them together on one side of the equation. So, move 2x to the right side by subtracting both sides by 2x.

2x-2x+1=30x-2x-20

1=28x-20

To combine 20 and 1, bring them together on the side opposite the term with x. So, add both sides by 20.

1+20=28x-20+20

21=28x

And, divide both sides by 28 to have x only at the right side.

21/28=(28x)/28

3/4=x

Hence, the solution to the given equation is x=3/4 .

Answer:

55 lbs of $0.40 and 45 lbs of $1.40  

Step-by-step explanation:

Let's say that we have two buckets, one that weighs x pounds and the candies in it are $0.40 per pound and another that weighs 100-x pounds (because we know the two added together must be 100 pounds) and the candies in it are $1.40 per pound.

There is a third bucket that is made when you combine the two, it weighs 100 pounds and the candies in it are $0.85. Multiply the cents per pound by the pounds of the candy for each bucket and you get this equation:

0.4 * x + 1.4 (100-x) = 0.85 * 100

Solve!

0.4x + 140 - 1.4x = 85

-x + 140 = 85

-x = -55

x = 55

From this we get that 100 - x = 45.

So, the answer is 55 lbs of $0.40 and 45 lbs of $1.40

the answer is C because Cos is adj/hyp. Since there is only one option that even has cos involved, it must be the correct answer.

9514 1404 393

Answer:

  E.  16

Step-by-step explanation:

If the order of points on the line is ABCD, the distance between A and D is ...

  AB +BC +CD = 5 + 9 + 3 = 17

If the order of points on the line is BADC, the distance between A and D is ...

  BC -BA -DC = 9 -5 -3 = 1

Then the difference between the longest and shortest possible distances AD is ...

  17 - 1 = 16 . . . . matches choice E

Answer:

6^(2/3)

Step-by-step explanation:

exponent fraction rule

Answer:

the first one, 6^2/3

Step-by-step explanation:

Answer:42.7in^2

that what answer i am sure of

Answer:

9 6/7 is the answer

Answer:

Slope = 5/3

Step-by-step explanation:

5x - 3y = 9

Write in slope y-intercept form: y = mx +b

-3y = -5x + 9

Divide the whole equation by (-3)

[tex]\frac{-3y}{-3}=\frac{-5x}{-3}+\frac{9}{-3}\\\\y =\frac{5}{3}x- 3[/tex]

Slope =5/3

Answer:

[tex](x-3)^{2} +(y+2)^{2} =5^{2}[/tex]

Step-by-step explanation:

The equation of the circle with center A=(a,b) and radius = r are:

[tex](x-a)^{2}+(y-b)^{2} =r^{2}[/tex]

When A=(3,-2) and radius=r=-5

[tex](x-3)^{2} +(y+2)^{2} =5^{2}[/tex]

Answer:

D because you going up to the surface

Answer:

its c

Step-by-step explanation:

Given:

The vertices of a triangle are A (-2, 4) , B (-2,3) , and C (-5,2).

Triangle ABC is reflected across the line y = -1 to produce the image of A'B'C'.

To find:

The coordinate of B' after a reflection across the line y=-1.

Solution:

If a figure is reflected across the line y=b, then

[tex](x,y)\to (x,-(y-b)+b)[/tex]

[tex](x,y)\to (x,-y+b+b)[/tex]

[tex](x,y)\to (x,2b-y)[/tex]

The given triangle ABC is reflected across the line y=-1. So, the rule of reflection is

[tex](x,y)\to (x,2(-1)-y)[/tex]

[tex](x,y)\to (x,-2-y)[/tex]

The coordinates of point B are (-2,3). So,

[tex]B(-2,3)\to B'(-2,-2-3)[/tex]

[tex]B(-2,3)\to B'(-2,-5)[/tex]

Therefore, the coordinates of point B' are (-2,-5).

Answer:

so what exactly is the question? it's not complete yet, I guess..what do you want me to find?

Answer:

give me brainliest

Given a line AB with Point C outside it.

Mark point D on the line AB. Join CD

With D as center, and any radius, draw an arc intersecting AB at E, and CD at F.

With C as center, and same radius as before, draw an arc intersecting CD at G.

Open a compass to length EF

Now,with G as center, and compass opened the same radius as before, draw an arc intersecting the previous arc at H.

Draw a line m passing through C and H.

Thus m is the line parallel to AB, and passing through point C

∴m∣∣AB

Step-by-step explanation:

Answer:

C, D, A

Step-by-step explanation:

Distributive property

Combining like terms

Communitive property

Answer:

The perimeter of a rectangular field is 100 meters

Step-by-step explanation:

The given data of the rectangular field are;

The unit cost of levelling the rectangular field, U[tex]_c[/tex] = 50/m²

The total cost of levelling the field, T[tex]_c[/tex] = 30,000

The length to breadth ratio of the field, L:B = 3:2

Where;

L = The length of the field

B= The breadth of the field

From the given data of the field, we have;

The area of the field, A = T[tex]_c[/tex]/U[tex]_c[/tex]

∴ A = 30,000/(50/m²) = 600 m²

The area of the field, A = 600 m²

The formula for the area of a rectangle, A = Length, L × Breadth, B

A = L × B

We are given that the length to breadth ratio of the field, L:B = 3:2

∴ L/B = 3/2

L = (3/2) × B

The area of the rectangular field, A = L × B

∴ The area of the rectangular field, A = (3/2) × B × B = (3/2) × B²

A = (3/2) × B²

From the calculation for the cost of levelling the field, we have, A = 600 m²

∴ A = (3/2) × B²

A = 600 m²

By transitive property, we have;

(3/2) × B² = 600 m²

B² = (2/3) × 600 m² = 400 m²

B = √(400 m²) = 20 m

The breadth of the field, B = 20 m

From L = (3/2) × B, we have;

L = (3/2) × B

∴ L = (3/2) × 20 m = 30 m

∴ The  length of the field, L = 30 m

The perimeter, 'P', of a rectangle given the length, 'L' and breadth, 'B', is given as follows;

The perimeter of a rectangle, P = 2·L + 2·B

Therefore, for the rectangular field, we have;

P = 2 × 30 m + 2 × 20 m = 60 m + 40 m = 100 m

The perimeter of a rectangular field, P = 100 m.

Answer:

74%

Step-by-step explanation: