one car travels due east at 40 km/hr and a second car travels north at 40km/hr. Are their velocities equal?​

Answers

Answer 1

Answer:

No.

Explanation:

Velocity is a vector quantity which means that it has a certain direction so things that move in different directions DO NOT have the same velocity.


Related Questions

A 30.0 uC charge is moved 5.00 m West in an electric field of 4000 V/m pointing 40.0° North of East. What potential difference did the charge move through?

Answers

Answer:

20000sin(40) V

Explanation:

Consider component to the east of electric field:

[tex]E_{x} =4000 sin(40)[/tex]

The charge move along this component for 5 meter

Potential difference:

[tex]5E_{x} =20000sin(40)[/tex] = 12900 V (corr, to 3 sig,fig.)

The potential difference through which the charge moved is approximately 20.0 V.

To calculate the potential difference (ΔV) through which the charge moved, we can use the formula:

ΔV = q * E * d * cos(θ)

where:

q = charge = 30.0 uC = 30.0 x 10⁻⁶ C (converted to coulombs)

E = electric field = 4000 V/m

d = displacement = 5.00 m

θ = angle between the electric field and the displacement = 40.0°

Now, substitute the values into the formula:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(40.0°)

First, convert the angle to radians:

θ_radians = 40.0° * (π/180) ≈ 0.6981 radians

Now, calculate ΔV:

ΔV = (30.0 x 10⁻⁶ C) * (4000 V/m) * (5.00 m) * cos(0.6981) ≈ 0.02 V

So, the potential difference through which the charge moved is approximately 20.0 V.

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State four factors affecting thermal conductivity​

Answers

Answer:

∙ Temperature

∙ Concentration of electrolyte

∙ Nature of the electrolyte added

∙ Nature of solvent and its viscosity

Explanation:

Steve is planning his annual Spring Break road trip. He pulls out his map and draws out his route to visit the five locations that he has planned for this year. They go in a counterclockwise loop and he ends up at home, where he started, just in time to start classes again. Whenever he is on the road he travels a constant 60 miles/hour. When Steve adds up the total distance traveled, as measured by his odometer, and divides it by the time that his trip took, he has measured what quantity?

a. His average velocity.
b. His average speed.
c. His instantaneous velocity.
d. His instantaneous speed.

Steve’s average velocity for the whole trip is:______

a. greater than 60 miles/hour.
b. equal to 60 miles/hour.
c. less than 60 mile/hour, but greater than zero.
d. exactly zero.

Answers

Answer:

Part 1

Steve is measuring his average speed

Part 2

Average velocity is equal to 60 miles per hour

Explanation:

Part 1

Average velocity is equal to total distance travelled divided by total time taken. It also takes into consideration the change of direction through out the journey.

Hence, Steve is measuring his average speed

Option A is correct

Part 2

Average velocity is equal to 60 miles per hour only because velocity is a vector quantity

Option B is correct

Which of the following is a disadvantage of using solar energy

Answers

Please provide options.

Answer:

It requires a high initial investment

Explanation:

The Great Sandini is a 60 kg circus performer who is shot from a cannon (actually a spring gun). You don't find many men of his caliber, so you help him design a new gun. This new gun has a very large spring with a very small mass and a force constant of 1300 N/m that he will compress with a force of 6500 N. The inside of the gun barrel is coated with Teflon, so the average friction force will be only 50 N during the 5.0 mm he moves in the barrel.

Required:
At what speed will he emerge from the end of the barrel, 2.5 mabove his initial rest position?

Answers

Answer:

22m/s

Explanation:

Mass, m=60 kg

Force constant, k=1300N/m

Restoring force, Fx=6500 N

Average friction force, f=50 N

Length of barrel, l=5m

y=2.5 m

Initial velocity, u=0

[tex]F_x=kx[/tex]

Substitute the values

[tex]6500=1300x[/tex]

[tex]x=\frac{6500}{1300}=5[/tex]m

Work done due to friction force

[tex]W_f=fscos\theta[/tex]

We have [tex]\theta=180^{\circ}[/tex]

Substitute the values

[tex]W_f=50\times 5cos180^{\circ}[/tex]

[tex]W_f=-250J[/tex]

Initial kinetic energy, Ki=0

Initial gravitational energy, [tex]U_{grav,1}=0[/tex]\

Initial elastic potential energy

[tex]U_{el,1}=\frac{1}{2}kx^2=\frac{1}{2}(1300)(5^2)[/tex]

[tex]U_{el,1}=16250J[/tex]

Final elastic energy,[tex]U_{el,2}=0[/tex]

Final kinetic energy, [tex]K_f=\frac{1}{2}(60)v^2=30v^2[/tex]

Final gravitational energy, [tex]U_{grav,2}=mgh=60\times 9.8\times 2.5[/tex]

Final gravitational energy, [tex]U_{grav,2}=1470J[/tex]

Using work-energy theorem

[tex]K_i+U_{grav,1}+U_{el,1}+W_f=K_f+U_{grav,2}+U_{el,2}[/tex]

Substitute the values

[tex]0+0+16250-250=30v^2+1470+0[/tex]

[tex]16000-1470=30v^2[/tex]

[tex]14530=30v^2[/tex]

[tex]v^2=\frac{14530}{30}[/tex]

[tex]v=\sqrt{\frac{14530}{30}}[/tex]

[tex]v=22m/s[/tex]

In the absence of friction, if a force acting on a moving object stops acting, the object will

Answers

Answer:

Keep on moving

Explanation:

Newton's first law states "that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force."

What are two benefits of scientists using a diagram to model the water cycle?
A. It can be used to show how the parts of the cycle relate to one
another.
B. It can be used to show as much detail ahis present in the actual
water cycle.
c. Only a few factors in the water cycle can be shown on the
diagram
D. It can show changes that occur in many different parts of Earth at
the same time.

Answers

Answer:

Options A. and D. are correct.

Explanation:

The water cycle shows the continuous movement of water within the Earth and atmosphere.

The two benefits of scientists using a diagram to model the water cycle are as follows:

It can be used to show how the parts of the cycle relate to one  another.

It can show changes that occur in many different parts of Earth at  the same time.

Options A. and D. are correct.

If an object has a mass of 210g and the net force acting upon it is 5.0N, what is the acceleration of that object?

Answers

210g = 0.21kg

a= F/m

5.0/0.21= 23.809523

Answer:

24ms^-2 (2 sig figs)

Explanation:

F = ma

This means that the sum of all forces (or the net force) acting upon an object is equal to its mass x accelleration.

Its important to convert all parts of this equations in to SI units such that Force (N), Mass (kg) and Accelleration (ms^-2) to make sure that your answer is in the correct units.

F = ma so 5 = 0.21a

a = 5/0.21

a = 23.810 ms^-2 (5 sig figs)

Which of the following would MOST likely slow Earth's tectonic activity?
O A. Earth's crust becomes cooler.
O B. Earth's mantle becomes warmer.
O C. Earth's mantle becomes cooler.
O D. Earth's outer core becomes warmer.

Answers

The Answer to your question is:

A.

The Earth's tectonic activity occurs by the movement of the fourteen main tectonic plates of the planet, which move over the mantle continuously, and result in the formation of mountains, earthquakes, tsunamis, volcanic activities, etc.

The decrease in the Earth's tectonic activity would therefore occur if the Earth's mantle became cooler, as the tectonic plates move over the magma, which is a paste formed by silicate of iron and magnesium and whose temperature reaches 600° and 1,200° Celsius , driven by forces from inside the planet.

Therefore the letter C is correct, as with the Earth's mantle cooler, the magma would become more solid which would decrease the Earth's tectonic activity.

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A book is moved once around the perimeter of a tabletop with dimensions 1.2 m x 1.8 m.
(a) If the book ends up at its initial position, what is its displacement
(b) What is the distance traveled?​

Answers

Answer:

a) 0m

b) 6m

Explanation:

First, we need to remember:

Displacement: Difference between final and initial position.

Distance traveled: Total distance traveled.

a) If the final position is the same as the initial position, then:

final position = initial position

And we know that:

displacement = final position - initial position = 0

Then the displacement of the book is zero.

b)

We can assume that the book traveled along the perimeter of the table.

The table is a rectangle of width 1.2m and length 1.8m

Remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W

Then the perimeter of the table is:

P = 2*1.2m + 2*1.8m = 6m

This means that the distance traveled by the book is 6 meters.

Ocean waves crash on the beach at a velocity of 3.5 m/s. If the distance between the crests of each wave is 4 m, find the frequency of the waves.


a. 0.0088 Hz

b. 14.0 Hz

c. 1.14 Hz

d. 0.88 Hz

Answers

Answer:

d

Explanation:

velocity=frequency × wavelength

frequency=speed/wavelength

frequency=3.5÷4

=0.875~0.88

The frequency of the waves is (d) 0.88 Hz. So, correct answer is option (d).

What is frequency of wave?

The frequency of a sinusoidal wave is the number of full oscillations performed by any wave constituent in a unit of time. According to the definition of frequency, if a body is moving periodically, it has completed one cycle after going through a number of situations or postures and then returning to its initial position. Therefore, frequency is a quantity that describes the rate of oscillation and vibration.

Given parameter,

Velocity of the waves = 3.5 m/s.

distance between the crests of each wave, that is, wavelength of the waves = 4 m.

We know that, for a wave transmission,

velocity of wave =frequency of wave  × wavelength of wave

frequency of wave=speed of wave/wavelength of wave

frequency of wave =3.5 m/s ÷4m

=0.875 Hz

≈ 0.88 Hz

Hence, the frequency of the waves is 0.88 Hz.

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Consider the following scenario. A car for which friction is not negligible accelerates from rest down a hill, running out of gasoline after a short distance (see below). The driver lets the car coast farther down the hill, then up and over a small crest. He then coasts down that hill into a gas station, where he brakes to a stop and fills the tank with gasoline. Identify the forms of energy the car has, and how they are changed and transferred in this series of events.

Answers

Answer:

1) U-> K +W

2) K -> W

Explanation:

In this exercise, care must be taken as they indicate that the friction force (rubbing) is not negligible.

1 part at the top of the hill the car has gravitational potential energy, which is transformed in a part into kinetic energy and another part into heat by the work of the friction force that opposes the movement.

2 part when the other hill rises it loses kinetic energy that is transformed into gravitational potential energy and part in heat due to the work of the friction force on this hill.

3rd part in the last descent all the gravitational potential energy is transformed into kinetic energy and the application of the brakes is transformed into heat due to the negative lock of the friction force and filled with gasoline that has chemical energy that can be transformed in the engine.

Determine the resultant force exerted on an object if these three forces are exerted on it: F1=3.0N upwards,F2=6.0N at 45° to the horizontal and F3=5.0 at 120° from the positive x-axis​

Answers

I couldn't upload the complete pic because I'm browsing from phone

pls give me brainliest

The resolution of a telescope is ultimately limited by the diameter of its objective lens or mirror. A typical amateur astronomer's telescope may have a 6.09 in diameter mirror. What is the minimum angular separation (in arc seconds) of two stars that can be resolved with a 6.09 in scope

Answers

Answer:

 θ =  3.19  arc second

Explanation:

The resolution of a telescope is given by the rayleigh criterion, which establishes that two objects are separated if the principal maximum of diffraction of one of them coincides with the first minimum of diffraction of the second object, based on this the solution is given by the first diffraction minimum, the a slit is

        a sin θ = m λ

with m = 1

in the case of circular apertures the equation must be found in polar coordinates, therefore a numerical constant is introduced

        a sin θ = 1.22 λ

Angles are measured in radians and in these experiments they are small

        sin θ = θ

       θ= 1.22  λ  / a

in this case a = 6.09 in, the wavelength is wrong = 550 10⁻⁹ m which is the maximum resolution of the human eye

l

et's reduce the magnitudes to the SI system

        d = 6.09‘  2.54 10⁻-2 m / 1 inch = 15.4686 10-2 m

let's calculate

       θ = 1.22 550 10-9 / 15.468 10-2

       θ = 15.5 10⁻⁶ rad

       rad = 2.06 105 s

       θ = 15.5 10⁻⁶ rad  2.06 105s/ 1 rad

       θ =  3.19   s

     

The work is calculated by replacing pressure with nRT/V then pulling nRT outside the integral. We are only allowed to pull T outside the integral in that example because:

a. we are always allowed to pull T outside a volume integral
b. T is constant for an isothermal process
c. it's an expansion not a compression
d. T has a positive value in that problem

Answers

Answer: b. T is constant for an isothermal process

Explanation:

In a general case for an ideal gas, we have the relation:

dW = -pdV.

If we integrate in both sides, we get:

W = ∫-pdV

Now, as the problem says, we can replace p by n*R*T/V

This is because of the equation for ideal gases.

p = n*R*T/V

replacing that in the equation we get

W = -∫pdV = -∫(n*R*T/V)dV

Now we want to take the n*R*T part outside of the integral.

But we only could do this if T does not depend on V.

If T is cosntant, then T does not depend on V, and we know that T is constant when we are in an isothermal process.

Where an isothermal process is a process where the temperature does not change, then T = constant.

Then n*R*T = constant = k

Because this is a constant, we could take it out of the integral so we get:

W = -∫(n*R*T/V)dV ) = -(n*R*T)∫(1/V)*dV

Then the correct option is option b.

b. T is constant for an isothermal process

An object is placed in material a at point P, as shown in the diagram. The light is refracted when it strikes the interface with material b. When viewed from material b, at which point will the image appear?

Answers

B because the areas of f can be 7 or higher

help plz! what vibrates in following types of wave motion 1)light wave 2)sound waves 3)x-rays 4)water waves​

Answers

Answer:

I believe it's 2) sound waves

Explanation:

With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave, so named because the energy travels along the direction of vibration of the particles.

Metals are amazing, and they are all around us. You can probably easily identify them by their shiny surfaces and tinny sound when you tap them.

a. True
b. False

Answers

Answer:

a. True

Explanation:

Metals are amazing, and they are all around us. You can probably easily identify them by their shiny surfaces and tinny sound when you tap them.

Generally, metals are mainly hard, shiny, and can be hammered into thin sheets. Also, another property of a metal is that, it is a good conductor of heat and even electricity because there valence (outer) electrons are delocalized. Some examples of chemical elements that are metals are iron, gold, sodium, silver, copper etc.

Please help! quick and easy chart.

Answers

Answer:

sound and happiness are not matter

Explanation:

A bar magnet is attached solidly to a frictionless surface and its length is aligned with the x axis.To the right of the first magnet a short distance away is a second bar magnet with its center placed on the x axis and its length perpendicular to the x axis.The second magnet is free to move.Once placed in position at rest,which best describes the initial motion of the second magnet?

a. The magnet will move away from the fixed magnet.
b. The magnet will not move.
c. The magnet will move toward the fixed magnet.
d. The magnet will start to rotate.

Answers

Answer:

the correct answer is D

Explanation:

For this exercise we must remember that the poles of the same if not repel each other and the poles of different signs attract.

With this, let's analyze the situation presented.

The two magnets are perpendicular, with the second magnet to the right of the first.

We have two cases:

* first magnet with the north pole to the right

  If the north of the second magnet is upwards there is a repulsion and the south pole of the second magnet there is an attraction with the north pole of the first magnet, so it would have a force that has to rotate the second magnet.

The force with the south pole of the first magnet that is at a greater distance is less, so the resultant of force is determined by the nearest poles.

If the poles of the second magnet are reversed, that is, the South pole up and the North pole down, the same result is obtained, but with a twist in the opposite direction.

* first magnet with the south pole to the right

    Repels with the south pole of the second magnet and attracts with the north of the second magnet

therefore in both possibilities the second magnet acquires a rotational movement

Consequently the correct answer is D

What is cytoplasm in a animal cell?

Answers

Answer:

Cytoplasm is the jelly-like fluid that fills in all of the. space between the nucleus and the plasma membrane. All of the organelles within a cell are suspended in this fluid. The main function of the cytoplasm is to support the internal structures of the cell as well as maintaining shape and consistency of the cell.

A dog finds a toy at rest on the floor. The dog pushes the toy horizontally on a frictionless floor with a net force of 2.0 Newtons for 3.0 meters. How much kinetic energy does the toy gain? Round your answer to the nearest whole number.​

Answers

Answer:

the kinetic energy gained by the toy is 6J.

Explanation:

Given;

net applied to the toy by dog, F = 2 N

distance moved by the toy, d = 3 m

Apply the principle of work-energy theorem to determine the kinetic energy gained by the toy.

ΔK.E = W

         = F x d

         = 2 x 3

         = 6 J

Therefore, the kinetic energy gained by the toy is 6J.

Two light bulbs are 2.0 m apart. From what distance can these light bulbs be marginally resolved by a small telescope with a 4.50 cm. Assume that the lens is limited only by diffraction and λ = 600 nm

Answers

Answer:

R = 1.2295 10⁵  m

Explanation:

After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body

            θ = 1.22 λ / D

where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture

             

how angles are measured in radians

          θ = y / R

where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens

            [tex]\frac{y}{R} = 1.22 \frac{ \lambda}{D}[/tex]

            R = [tex]\frac{ y \ D}{1.22 \lambda}[/tex]

let's calculate

            R = [tex]\frac{ 2 \ 0.045}{ 1.22 \ 600 \ 10^{-9}}[/tex]

            R = 1.2295 10⁵  m

A ball is thrown vertically downward from the top of a 37.4-m-tall building. The ball passes the top of a window that is 15.4 m above the ground 2.00 s after being thrown. What is the speed of the ball as it passes the top of the window?

Answers

Answer:

v= 20.8 m/s

Explanation:

Assuming no other forces acting on the ball, from the instant that is thrown vertically downward, it's only accelerated by gravity, in this same direction, with a constant value of -9.8 m/s2  (assuming the ground level as the zero reference level and the upward direction as positive).In order to find the final speed 2.00 s after being thrown, we can apply the definition of acceleration, rearranging terms, as follows:

       [tex]v_{f} = v_{o} + a*t = v_{o} + g*t (1)[/tex]

We have the value of t, but since the ball was thrown, this means that it had an initial non-zero velocity v₀.Due to we know the value of the vertical displacement also, we can use the following kinematic equation in order to find the initial velocity v₀:

        [tex]\Delta y = v_{o} *t + \frac{1}{2} * a* t^{2} (2)[/tex]

where Δy = yf - y₀ = 15.4 m - 37.4 m = -22 m (3)Replacing by the values of Δy, a and t, we can solve for v₀ as follows:

       [tex]v_{o} = \frac{(\Delta y- \frac{1}{2} *a*t^{2})}{t} = \frac{-22m+19.6m}{2.00s} = -1.2 m/s (4)[/tex]

Replacing (4) , and the values of g and t in (1) we can find the value that we are looking for, vf:

       [tex]v_{f} = v_{o} + g*t = -1.2 m/s - (9.8m/s2*2.00s) = -20.8 m/s (5)[/tex]

Therefore, the speed of the ball (the magnitude of the velocity) as it passes the top of the window is 20.8 m/s.

If a biker rides west for 50 miles from his starting position, then turns and bikes back east for 80 miles. What is his displacement?

Answers

Answer:

Displacement = 30 miles due east.

Explanation:

Let the distance due west be A

Let the distance due east be B

Given the following data;

A = 50 miles

B = 80 miles

To find the displacement;

Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.

Thus, the displacement would be calculated by subtracting distance A from distance B because the rider rode in opposite directions.

Displacement = B - A

Displacement = 80 - 50

Displacement = 30 miles due east.

What type of bond is CO2?||

Answers

Answer:

Lol

Explanation:

CO2 would be a covalent bond, because any compound made up of non-metals will be covalent

A Gaussian surface consists of a bottom surface made of a flat disk of radius R, in the horizontal plane centered on the origin and a top surface consisting of a hemisphere of the same radius R. A dipole is arranged as show where the charges are q both plus and minus and the separation is a. a)(5 points) What is the signof the electric flux FEthrough the entire Gaussian surface

Answers

Answer:

electric flux through the entire Gaussian surface will be positive ( + )

Explanation:

The dipole is surrounded by Gaussian surface of charge q

The electric flux will be  positive

i.e.  Ф = E. ds   since the surface is a close one the direction of the area outwardly will be positive . therefore the angle between  E and A < 90°

Hence the  electric flux through the entire Gaussian surface will be positive

What power rating of resistors would you use in the application required it to handle
0.6W?

Answers

I would use a resistor rated for 1 W or more. Not less.

The power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

Electrical power

The electrical power of an appliance shows the rating of the appliance, in terms of energy consumed at a given period of time.

Electrical power is calculated as follows;

P = IV

where;

V is the voltage I is the current

[tex]P = (\frac{V}{R} )V\\\\P = \frac{V^2}{R}[/tex]

Thus, the power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

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⚠️I need help with the last question!⚠️

Answers

Answer:

I can't do your work for you but I can explain the last question;

The want you to tell them (In at least 3 sentences) Why you think your answers are correct or how your answer's match your hypothesis.

A hypothesis (for a little more help)  is an idea or explanation that you then test through study and experimentation.

Outside science, a theory or guess can also be called a hypothesis. A hypothesis is something more than a wild guess but less than a well-established theory. Anyone who uses the word hypothesis is making a guess.

Explanation:

Sorry I didnt give you the exact answer but I hope this helps :)

If a 9851.6 kg vw van is moving at a speed of 16.7 m/s, what is the momentum? Round answer to the nearest hundredth

Answers

Answer:

the momentum is 164500 kg m/s

Explanation:

The computation of the momentum is shown below:

As we know that

Momentum is

= mass × velocity

= 9851.6 kg × 16.7 m/s

= 164522 kg·m/s

= 164500 kg m/s

hence, the momentum is 164500 kg m/s

Other Questions
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