On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+

Answer:

5.62 g of F2

Explanation:

We have to start with the chemical reaction:

[tex]Cl_2~+~3F_2~-->~2ClF_3[/tex]

We have a balanced reaction, so we can continue with the mol calculation. For this, we need to know the molar mass of [tex]Cl_2[/tex]  (70.906 g/mol), so:

[tex]3.5~ g~Cl_2 \frac{1~mol~Cl_2}{70.906~g~Cl_2}=0.049~mol~Cl_2[/tex]

Now, with the molar ratio between [tex]Cl_2[/tex]  and [tex]F_2[/tex]  we can convert from moles of [tex]Cl_2[/tex]  and [tex]F_2[/tex]  (1:3), so:

[tex]0.049~mol~Cl_2\frac{3~mol~F_2}{1~mol~Cl_2}=0.148~mol~F_2[/tex]

Finally, with the molar mass of [tex]F_2[/tex] we can calculate the gram of [tex]F_2[/tex] (37.99 g/mol), so:

[tex]0.148~mol~F_2\frac{37.99~g~F_2}{1~mol~F_2}=5.62~g~F_2[/tex]

I hope it helps!

Answer:

Consider each of the following molecules in turn: (a) dimethyl ether, (CH3)2O; (b) trimethylamine, (CH3)3N; (c) trimethylboron, (CH3)3B; and (d) carbon dioxide (CO2). Describe the hybridization state of the central atom (i.e., O, N, B, or C) of each molecule, tell what bond angles you would expect at the central atom, and state whether the molecule would have a dipole moment.

Answer:

(a) [tex]Ca(NO_3)_2(s)\rightarrow Ca^{2+}(aq)+2NO_3^-(aq)[/tex]

(b) [tex]Na_3PO_4(s)\rightarrow 3Na^++PO_4^{3-}[/tex]

(c) [tex]Ca^{2+} \ and \ PO_4^{3-}[/tex]

(d) [tex]3Ca^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Ca_3(PO_4)_2(s)[/tex]

Explanation:

Hello,

In this case, the balanced dissolution reactions are:

(a) [tex]Ca(NO_3)_2(s)\rightarrow Ca^{2+}(aq)+2NO_3^-(aq)[/tex]

(b) [tex]Na_3PO_4(s)\rightarrow 3Na^++PO_4^{3-}[/tex]

Moreover, when calcium nitrate and sodium phosphate react a double displacement reaction occurs, forming calcium phosphate, which is actually the precipitate due to its low solubility in water, and sodium nitrate:

[tex]2Na_3PO_4(aq)+3Ca(NO_3)_2(aq)\rightarrow 6NaNO_3(aq)+Ca_3(PO_4)_2(s)[/tex]

Thus, the precipitate is formed by:

(c) [tex]Ca^{2+} \ and \ PO_4^{3-}[/tex]

Finally, the net precipitation reaction shows the involved cation, anion and final product:

(d) [tex]3Ca^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Ca_3(PO_4)_2(s)[/tex]

Regards.

Answer:

The most common analgesic tablets contains a mixture of caffeine, aspirin, acetaminophen, along with binder.

The binders are neutral substances that are employed to keep tablet intact during packaging, shipping and being swallowed.  Examples of binder are silica gel, cellulose, starch etc.

And the remaining aspirin, acetaminophen and caffeine can be classified as strong acid, weak acid and base, respectively by merely observing functional groups they possess.

Explanation:

question

Acetominophen , Aspirin, Binder, ,  

Identify the strong organic acid, weak organic acid, base and neutral substance isolated in these experiments.

The strong organic acid is   __________________________________.

The weak organic acid is   __________________________________.

The organic base is __________________________________.

The neutral substance is __________________________________

explanation

Aspirin contains -COOH making it strong acid than phenol compound

Acetominophen contains phenolic -OH, making it weak organic acid

Caffeine contains Nitrogen atoms whch can donate lonepair of H⁺ , this makes it basic

Answer: Reaction 1 is non spontaneous.

Explanation:

According to Gibb's equation:

[tex]\Delta G=\Delta H-T\Delta S[/tex]

[tex]\Delta G[/tex] = Gibbs free energy  

[tex]\Delta H[/tex] = enthalpy change

[tex]\Delta S[/tex] = entropy change  

T = temperature in Kelvin

When [tex]\Delta G[/tex] = +ve, reaction is non spontaneous

[tex]\Delta G[/tex]= -ve, reaction is spontaneous

[tex]\Delta G[/tex]= 0, reaction is in equilibrium

For the given reaction 1: [tex]glucose+Pi\rightarrow glucose-6-phosphate+H_2O[/tex] [tex]\Delta G=+13.8kJ/mol[/tex]

As for the reaction 1 , the value of Gibbs free energy is positive and thus the reaction 1 is non spontaneous.

Boric acid is not what is known as a protonic acid meaning it is unable to release the H+ ions by itself. However, it can act as a traditional Lewis Acid so it is considered a weak acid.

Answer:

Boric acid is not able to release H⊕ ion on its own. It receives ӨOH ion from water molecule to complete its octet and in turn releases H⊕ ions.

It has the chemical formula H3BO3 (sometimes written B(OH)3), and exists in the form of colorless crystals or a white powder that dissolves in water. When occurring as a mineral, it is called sassolite

credit : wikipedia

Answer:

20mL of the stock solution and dilute to 100mL

Explanation:

20mM = 0.020M is the concentration of the diluted solution. As you want to prepare this solution from a 0.1M solution, dilution factor is:

0.1M / 0.020M = 5

That means you need to dilute the stock solution 5 times to obtain the 20mM sucrose solution.

As you want to prepare 100mL, you need to add:

100mL / 5 =

Answer:

0°C.

Explanation:

Hello,

In this case, given the heating curve of water on the attached document, we can notice that at 0 °C the solid starts melting, which means that the melting point is reached. Melting point is known as a physical change whereby a solid changes to liquid by the addition of heat as it allows the molecules to separate to each other.

Best regards.

Answer:

0 degrees celcius

Explanation:

I took the test

Answer:

C. As scientists have learned more about chemicals, they have  become more aware of their dangers

Explanation:

Chemicals are substances with standard compositions, held together by chemical bonds. Chemicals can exist in different phases such as solid, liquid, and gaseous phases. Over time, with a growing understanding of chemicals, their composition, and their reaction methods, scientists now have a better knowledge of the dangers chemicals can pose. To that effect, they have created standard safety measures for those who have to work with these chemicals.

When these guidelines are strictly adhered to, the chances of suffering accidents, burns, and explosions with these chemicals are significantly reduced.

Answer:

[tex][PCl_3]_{eq}=0.117M[/tex]

[tex][Cl_2]_{eq}=0.117M[/tex]

[tex][PCl_5]_{eq}=8x10^{-3}M[/tex]

Explanation:

Hello,

In this case, for the given chemical reaction at equilibrium, we can write the law of mass action as shown below:

[tex]Kc=\frac{[PCl_3][Cl_2]}{[PCl_5]}[/tex]

That in terms of the ICE methodology is written by means of the change [tex]x[/tex] due to the reaction extent:

[tex]Kc=\frac{x*x}{[PCl_5]_0-x}[/tex]

Thus, we need to compute the initial concentration of phosphorous pentachloride:

[tex][PCl_5]_0=\frac{13.0g*\frac{1mol}{208.25g} }{0.500L} =0.125M[/tex]

So we write:

[tex]1.80=\frac{x^2}{0.125-x}[/tex]

That we solve via either solver or quadratic equation to obtain the solution:

[tex]x=0.117M[/tex]

Thereby, the equilibrium concentrations are:

[tex][PCl_3]_{eq}=x=0.117M[/tex]

[tex][Cl_2]_{eq}=x=0.117M[/tex]

[tex][PCl_5]_{eq}=0.125M-x=0.125M-0.117M=8x10^{-3}M[/tex]

Best regards.

Answer:

Protons, Neutrons, and Electrons are all in atoms so the one not present would be the Element since Elements are made of atoms.

Explanation:

Answer:

C ) The rate will triple

The options of the question is not given so the options are;

(1) Mn(s)

(2) Cu(s)

(3) Ni(s)

(4) Ba(s)

Answer: Mn(s)

Explanation:

The spontaneous reaction depends on the Eo value. The positive Eo value are spontaneous and the negative Eo values are not spontaneous.

so, here the Eo values are:

Eo Zn2+/Zn = -0.763v

Eo Mg2+/Mg = 2.37v

Eo Mn2+/Mn = -1.18v

Therefore, Eo cell (with Zn as one of the half-cell) =  Eo Zn2+/Zn - Eo Mn2+/Mn

=  -0.763 - (-1.18)

 = 0.417v

Whereas, Eo cell (with Mg as one of the half-cell) =  Eo Mg2+/Zn - Eo Mn2+/Mn

=  -2.37 - (-1.18) = -1.19v

Thus, Mn(s) metal will spontaneously react because it has a positive  Eo value and  Zn2+(aq), but will not spontaneously react with Mg2+(aq) because it has negative Eo value.

Answer:

n=2 to n=4 < n=6 to n=8 < n=10 to n=12 < n=14 to n=16

Explanation:

According to Neils Bohr, electrons in an atom are found in specified energy levels. Transitions are possible from one energy level to another when the electron receives sufficient energy usually in the form of a photon of electromagnetic radiation of appropriate frequency and wavelength. The energy of this photon corresponds to the energy difference between the two energy levels. Thus the higher the energy difference between energy levels, the greater the energy of the photon required to cause the transition and the shorter the wavelength of the photon.

High energy photons have a very short wavelength. It should be noted that as n increases, the energy of successive energy levels decreases and transitions between them now occurs at longer wavelengths. Hence, the highest energy and shortest wavelength of photons are required for transition involving lower values of n because such electrons are closer to the nucleus and are more tightly bound to it than electrons found at a greater distance from the nucleus.

Hence transition involving electrons at higher energy levels occur at a longer wavelength compared to transition involving electrons closer to the nucleus. This is the basis for the arrangement of wavelengths required to effect the various electronic transitions shown in the answer.

Answer:

[tex]Kb=6.16x10^{-7}[/tex]

Explanation:

Hello,

In this case, given the pH of the base, we can compute the pOH as shown below:

[tex]pOH=14-pH=14-10.781=3.219[/tex]

Next, we compute the concentration of the hydroxyl ions when the triethanolamine is dissociated:

[tex]pOH=-log([OH^-])[/tex]

[tex][OH^-]=10^{-pOH}=10^{-3.219}=6.04x10^{-4}M[/tex]

Then, by writing the equilibrium expression for the dissociation of triethanolamine we have:

[tex]Kb=\frac{[OH^-][C6H14O2N^+]}{[C6H15O3N ]}[/tex]

That is suitable for the direct computation of Kb, knowing that based on the ICE procedure, [tex]x[/tex] equals the concentration of hydroxyl ions that was previously, computed, therefore, we have:

[tex]Kb=\frac{6.04x10^{-4}M*6.04x10^{-4}M}{0.592M-6.04x10^{-4}M}\\ \\Kb=6.16x10^{-7}[/tex]

Regards.

Explanation:

Step one look for the longest chain of carbon atoms

Longest chain is 7 C atoms

Step 2 look for double bonds or others functional groups

it is present in 3rd carbon

Therefore IUPAC name is 3-heptene

From point of stereochemistry it can also be written as trans-3-heptene as the hydrogens are placed in opposite side of the C=C bond.

Hope this helps...

The compound name is: trans 3-heptene

Molecular compounds are inorganic compounds that take the form of discrete molecules.

Looking at the given compound:

1. We need to look for the highest carbon chain, So in this compound the highest carbon chain is of 7 carbon atoms.

2. This compound also has a double bond in between that is present at the third carbon which can be detected by numbering the carbon in a order where the lowest number will come over a double bond.

3. Lastly, we can derive the name for this compound as hept-3-ene or 3-heptene.

4. Also, there is one more thing to notice here which is the position of two hydrogen that are present as substituents since they are placed opposite to each other thus we can name it as trans 3-heptene.

Thus, the compound name is: trans 3-heptene.

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Answer: The concentration of NaOH solution is 0.194 M

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of KHP = 0.294 g

Molar mass of KHP = 204.22 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of KHP}=\frac{0.294g}{204.22g/mol}=0.00144mol[/tex]

The chemical reaction follows the equation:

[tex]KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)[/tex]

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.00144 moles of KHP will react with = 0.0144 of KOH.

To calculate the molarity of NaOH, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]

We are given:

Moles of KOH = 0.00144 moles

Volume of solution = 7.42ml  = 0.00742L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

[tex]Molarity=\frac{0.00144mol}{0.00742L}=0.194M[/tex]

Hence, the molarity of NaOH solution is 0.194 M

The concentration of the NaOH solution used in complete titration has been 0.194 M.

The reaction of KHP with NaOH has been the neutralization reaction that results in the formation of salt and water.

The concentration of KHP solution has been:

Molarity = [tex]\rm \dfrac{weight}{Molecular\;weight}\;\times\;\dfrac{1000}{Volume\;(ml)}[/tex]

Molarity of KHP = [tex]\rm \dfrac{0.294}{204.2}\;\times\;\dfrac{1000}{250}[/tex]

Molarity of KHP = 0.0057 M

The concentration of the KHP solution has been 0.0057 M.

For the neutralization reaction in complete titration:

Molarity of acid [tex]\times[/tex] Volume of acid = Molarity of base [tex]\times[/tex] Volume of base

Substituting the values from the question:

0.0057 M [tex]\times[/tex] 250 ml = Molarity of NaOH [tex]\times[/tex] 7.42 ml

1.439 = Molarity of NaOH [tex]\times[/tex] 7.42 ml

Molarity of NaOH = 0.194 M.

The concentration of the NaOH solution used in complete titration has been 0.194 M.

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Answer:

Explanation:

Calculate ΔG (in kJ) for the following reaction at 1.0 atm for C2H6,

0.5 atm for O2, and

2.0 atm for CO2, and

25 oC:

C2H6 (g) + O2 (g) ---> CO2 (g) + H2O (l) (unbalanced)

ΔGfo C2H6 (g) = - 32.89 kJ/mol;

ΔGfo CO2 (g) = - 394.4 kJ/mol;

ΔGfo H2O (l) = - 237.13 kJ/mol

The balance equation of this reaction is

[tex]2C_2H_6 (g) + 7O_2 (g) ---> 4CO_2 (g) + 6H_2O (l)[/tex]

[tex]\Delta G_{rxn}=\sum G^o_f(product)-\sum G^o_f(reactant)[/tex]

[tex]=4G^o_f(CO_2)+6G^o_f(H_2O)-7G^o_f(O_2)-2G^o_f(C_2H_6)\\\\[/tex]

[tex][4(-394.4)+6(-237.13)-7(0)-2(-32.89)]kJ/mol\\\\=-1577.6-1422.78+65.78\\\\=-3000.38+65.78\\\\=-2934.6kJ/mol[/tex]

Answer:9.84x 10^-31m

Explanation: 9.84x 10^-31m

Heisenberg uncertainty principle states that  says that the position and momentum of a particle cannot be known at the same time and accurately. and that the values  of position and momentum all times must be greater than h/4π.

Using the formula for Heisenberg Uncertainty principle

Δx. Δp ≥ h / 4π

=Δx. m ΔV ≥ h / 4π

where h = Planck’s constant = 6.62607004 × 10-34 m2 kg / s

Δx is the uncertainty in position

Δp is the uncertainty in momentum

m = mass

Δv=is the uncertainty in velocity

Given,

v = 0.80m/s,

m = 0.67 g = 0.67 g / 1000

= 0.00067 kg

h = 6.62607004 × 10-34 m2 kg / s

uncertainty in the velocity is 0.1 m/s.

Δv = 0.80×0.1 = 0.080m/s

Δx. m ΔV ≥ h / 4π

Δx  ≥ h / 4πm ΔV

6.62607004 × 10-34 / 4 π x 0.08 x 0.00067

=6.62607004 × 10-34 / 4 x3.14  5.3 x 10^-5 = 9.84x 10^-31m

Answer:

CH3CH2CH2COOH

Explanation:

Both carboxylic acids and alcohols posses hydrogen bonding. The difference between the two lies in the strength of the hydrogen bonding and the structure of the molecules.

Alcohols predominantly form linear hydrogen bonds in which the dipole of the -OH group of one molecule interacts with that of another molecule. This gives a linear arrangement of hydrogen bonded intermolecular interactions which significantly impacts the boiling point of alcohols.

However, the carboxylic acids posses the carbonyl (C=O) which is more polar and interacts more effectively with the -OH bond to form dimmer species. These dimmers have a much higher boiling point than the corresponding alcohols due to stronger hydrogen bonds. Hence CH3CH2CH2COOH has a greater boiling point than CH3CH2CH2OH.

The other compounds in the options do not posses hydrogen bonds hence they will have much lower boiling points.

Answer:

a) Fe(s) + Ni^2+(aq) ----> Fe^2+(aq) + Ni(s)

b) no reaction

c) no reaction

d) 2Mg(s) + 2H2O(l)-----> 2Mg^2+(aq) + O2(g) +4H^+(aq)

e) no reaction

Explanation:

It is important to say here that the ability of a particular chemical specie to displace another chemical specie is dependent on the relative standard reduction potentials of the species involved.

All the reactions stated above are redox reactions. Let us take reaction E as an example. Mg^2+ has a reduction potential of -2.37 V while Cr^3+ has a reduction potential of -0.74V. Since the reduction potential of magnesium is more negative than that of chromium, there is no reaction when a piece of chromium metal is dipped into a solution of Mg^2+.

Similarly, though metals displace hydrogen gas from dilute acids, metals that are less than hydrogen in the reactivity series cannot do that. This explains why there is no reaction when copper and silver are dipped into dilute acid solutions.

Reaction occurs when iron is dipped into a nickel solution because the reduction potential of Fe^2+ is far more negative than that of Ni^2+.

Answer:

Explanation:

Stereoisomers are two or more atoms that  have the same bonding order of atoms but there is a difference  spatial arrangement of  the  atoms in space.

A plane of symmetry divides a molecule into two equal halves.

A chiral stereoisomer are not superimposed on a mirror image , Hence they do not posses a plane of symmetry.

As a result to that. these non-superimposable mirror images are said to be Enantiomers.

However, a Fischer Projection emanates from a two - dimensional figure which is used for presenting a three - dimensional organic molecules.

From the given question;

Fischer projection for an enantiomer of 2-bromo-2,3-dihydroxypropanal with the bromine oriented horizontally to the left and the hydroxide group oriented horizontally to the right.

we can sketch the way the enantiomer of 2-bromo-2,3-dihydroxypropanal can  be seen like the one shown below:

              CH₂OH

                   |

                   |

                   |

Br -------------|----------------OH

                   |

                   |

                   |

                 CHO

The objective of this question is to drawn the perspective formula of the molecule.

So , from the attached file below; we can see the perspective formula of the molecule in a well structured 3-D format.

Answer and Explanation:

The computation of the energy or wavelength gamma rays observed is shown below:

Since the energy of gamma rays is higher than 0.10 MeV.

Now We have to calculate transitions in between the given levels of energy that correspond to this energy.

As per the given question, we have the following information

Ground state = E where E < 0.075 MeV

For  Level 1 = 0.075 MeV

For Level 2 = 0.320 MeV

For Level 3 = 0.475 MeV

Now we have to take the below transitions:

1. [tex]3 \rightarrow 2[/tex]

Difference of energy is

= 0.475 - 0.320

= 0.155 MeV

This represents  a gamma radiation

2. [tex]3 \rightarrow 1[/tex]

Difference of energy is

= 0.475 - 0.075

= 0.4 MeV

This represents  a gamma radiation

3. [tex]3 \rightarrow ground[/tex]

Difference of energy is

= 0.475 - E > 0.155 MeV

This represents  a gamma radiation

4. [tex]2 \rightarrow 1[/tex]

Difference of energy is

= 0.320 - 0.075

= 0.245 MeV

This represents  a gamma radiation

5. [tex]2 \rightarrow ground[/tex]

Difference of energy is

= 0.320 - E > 0.245 MeV

This represents  a gamma radiation

6. [tex]1 \rightarrow Ground[/tex]

Difference of energy is

= 0.075 - E < 0.10 MeV

This represents not a gamma radiation

We can see that there are 5 transitions that contain gamma rays

Answer:

The calculated concentration of acid will be higher than the actual concentration of acid

Explanation:

We have information that all enable us to calculate the concentration of KOH in the solution. From the question, we have;

Mass of KOH= 14.555g

Molar mass of KOH= 56.1056 g/mol

Volume of solution= 500 ml

Number of moles of KOH= ???

From;

m/M= CV

m= mass of KOH

M= molar mass of KOH

C= concentration of KOH solution

V= volume of solution

Substituting values;

14.555g/56.1056 g/mol = C× 500/1000

0.259 moles = 0.5C

C= 0.259/0.5

C= 0.518 M

If the acid is HA, the reaction equation is;

KOH(aq) + HA(aq) ----> KA(aq) + H2O(l)

The concentration of the acid is usually determined via titration. This involves delivering a particular volume of acid in a burette into the base and watching out for the volume of acid used at end point. If there are air bubbles in the burette, then more volume of acid is recorded than that actually used and this will make the calculated concentration of the acid to be higher than the actual concentration of acid present.

Answer:

melting point will be higher than that of pure ethyl acetate

Explanation:

Answer:

[Ne]3s²

Explanation:

Mg

1s2 2s2 2p6 3s2   or [Ne]3s²

Abbreviated electronic configuration of magnesium is [Ne]3 s² and in complete form it is 1 s² 2 s² 2 p⁶ 3 s².

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

For an electron in 5p orbital

5,1,-1,+1/2

For an electron in 6d orbital

6,2,-2,+1/2

Explanation:

The term quantum numbers refers to a set of values that can be used to determine the region in space where it is likely to find an electron. This region in space where there is a high probability of finding an electron is known as an atomic orbital. An atomic orbital is actually a wave function according to the Schrödinger wave equation.

There are four quantum numbers used in describing an atomic orbital: the principal quantum number (n), the orbital angular momentum quantum number also called azimuthal or subsidiary quantum number (l), the magnetic quantum number (ml), and the electron spin quantum number (ms).

For a 5p orbital;

n= 5, l= 1, ml= -1,0,1 ms= +1/2 or -1/2

For 6d orbital;

n= 6, l= 2, ml= -2,-1,0,1,2, ms= +1/2 or -1/2

Since we are requested to use a four quantum number description that can be assigned to an electron in these levels;

For an electron in 5p orbital

5,1,-1,+1/2

For an electron in 6d orbital

6,2,-2,+1/2

Answer:

[tex]C_3H_8O_2[/tex]

Explanation:

Hello,

In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:

[tex]n_C=4.171gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.095molC[/tex]

Next, we compute the moles of hydrogen that is present at the water only as a product:

[tex]n_H=2.268gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} =0.252molH[/tex]

Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:

[tex]m_O=2.400g-0.095molC*\frac{12gC}{1molC} -0.252molH*\frac{1gH}{1molH} \\\\m_O=1.008gO\\\\n_O=1.008gO*\frac{1molO}{16gO} =0.063molO[/tex]

Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:

[tex]C=\frac{0.095}{0.063}=1.5\\ \\H=\frac{0.252}{0.063}=4\\ \\O=\frac{0.063}{0.063}=1[/tex]

But the smallest whole number is:

[tex]C_3H_8O_2[/tex]

Regards.

Answer: After a few aspirin tablets have been swallowed, the concentration of acetylsalicylic acid in the stomach is 0.20 M. Calculate the percent ionization of the acid under these conditions. Therefore, the percent ionization is - X 100% = 3.8%.

Answer:

See detailed answer with explanation below.

Explanation:

Valence electrons are electrons found on the outermost shell of an atom. They are the electrons in an atom that participate in chemical combination. Recall that the outermost shell of an atom is also referred to as its valence shell. Let us consider an example; if we look at the atom, sodium-11, its electronic configuration is 2,8,1. The last one electron is the valence electron of sodium which is found in its outermost or valence shell.

Positive ions are formed when electrons are lost from the valence shell of an atom. For instance, if the outermost electron in sodium is lost, we now form the sodium ion Na^+ which is a positive ion. Positive ions possess less number of electrons compared to their corresponding atoms.

Negative ions are formed when one or more electrons is added to the valence shell of an atom. A negative ion possesses more electrons than its corresponding atom. For example, chlorine(Cl) contains 17 electrons but the chloride ion (Cl^-) contains 18 electrons.

In molecular compounds, a bond is formed when two electrons are shared between the bonding atoms. Each bonding atom may contribute one of the shared electrons (ordinary covalent bond) or one of the bonding atoms may provide the both shared electrons (coordinate covalent bond). The shared pair may be located at an equidistant position to the nucleus of both atoms. Similarly, the electron may be drawn closer to the nucleus of one atom than the other (polar covalent bond) depending on the electro negativity of the two bonding atoms.

The electrons are shared in order to complete the octet of each atom by so doing, the both bonding atoms now obey the octet rule. For example, two chlorine atoms may come together to form a covalent bond in which each chlorine atom has an octet of electrons on its outermost shell.