Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community. Find a​ 95% confidence interval for the true proportion of all medical students who plan to work in a rural community.

Answer:

  1.39 km/h

Step-by-step explanation:

Let the initial position of ship B represent the origin of our coordinate system. Then the position of ship A as a function of time t is ...

  A = -120 +20t . . . (east of the origin)

and the position of B is ...

  B = 15t . . . (north of the origin)

Then the distance between them is ...

  d = √(A² +B²) = √((-120 +20t)² +(15t)²) = √(625t² -4800t +1440)

And the rate of change is ...

  d' = (625t -2400)/√(625t² -4800t +14400)

At t = 4, the rate of change is ...

  d' = (625·4 -2400)/√(625·16 -4800·4 +14400) = 100/√5200 = 1.39 . . . km/h

The distance between the ships is increasing at about 1.39 km/h.

Answer:

9 mile trip

Step-by-step explanation:

$15 + $15 = $30

$15 + $9 = $24

$15 + $25 = $40

$15 + $12 = $27

$30 > $25

$24 < $25

$40 > $25

$27 > $25

Answer:

it would be 3/5*4/1

Step-by-step explanation:

To divide you multiply the first number by the reciprocal of the second number. Check and you'll see that the answer is the same. Hope this helps!

Answer:

The answer is 3/5 x 4/1

Step-by-step explanation:

Answer:

S is the volume of the small cup, M the volume of the medium cup and L the volume of the large cup:

2*S + 2*M + 4*L = 160oz

2*S + 6*M + 1*L = 160oz

5*S + 1*M + 3*L = 160oz.

First, we must isolate one of the variables, for this we can use the first two equations and get:

2*S + 2*M + 4*L = 160oz = 2*S + 6*M + 1*L

We can cancel 2*S in both sides:

2*M + 4*L = 6*M + 1*L

now each side must have only one variable:

4*L - 1*L = 6*M - 2*M

3*L = 4*M

L = (4/3)*M.

now we can replace it in the equations and get :

2*S + 2*M + 4*(4/3)*M = 160oz

2*S + 6*M + (4/3)*M = 160oz

5*S + 1*M + 4M = 160oz.

simplifing them we have:

2*S + (22/3)*M +  = 160oz

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

(the first and second equation are equal because we used those to get the relation of M and L, so we now have only two equations):

2*S + (22/3)*M  = 160oz

5*S + 5*M  = 160oz.

We can take the second equation and simplify it:

S + M = 160oz/5 = 32oz

S = 32oz - M

Now we can replace it in the first equation and solve it for M

2*S + (22/3)*M = 2*(32oz - M) + (22/3)*M = 160oz

62oz - 2*M + (22/3)*M = 160oz

-(6/3)*M + (22/3)*M = 98oz

(18/3)*M = 98oz

M = (3/18)*98oz = 16.33 oz

Then:

L = (4/3)*M =(4/3)*16.33oz = 21.78 oz

and:

S = 32oz - M = 32oz - 16.33oz = 15.67oz

Answer:

D. 66

Step-by-step explanation:

Well if AD is 100 and AC is 34 that leaves CD so we can just subtraction 34 from 100 and get 66.

Answer:

D. 66

Step-by-step explanation:

AD = 100

AC = 34

The whole line is 100. A part of the line is 34. The other part will be 66.

100 - 34 = 66

Answer:

343 cm3

Step-by-step explanation:

Answer:

side(s) =7cm

volume (v)=l^3

or, v = 7^3

therefore the volume is 343cm^3.

hope its what you are searching for..

Answer:

a) Calculate the probability that at least one of them suffers from arachnophobia.

x = number of students suffering from arachnophobia

= P(x ≥ 1)

= 1 - P(x = 0)

= 1 - [0.05⁰ x (1 - 0.05)¹¹⁻⁰ ]

= 1 - (0.95)¹¹

= 0.4311999 = 0.4312

b) Calculate the probability that exactly 2 of them suffer from arachnophobia? 0.08666

=  P(x = 2)

=  (¹¹₂) x (0.05)² x (0.95)⁹

where ¹¹₂ = 11! / (2!9!) = (11 x 10) / (2 x 1) = 55

= 55 x 0.0025 x 0.630249409 = 0.086659293 = 0.0867

c) Calculate the probability that at most 1 of them suffers from arachnophobia?

P(x ≤ 1)

= P(x = 0) + P(x = 1)    

= [(¹¹₀) x 0.05⁰ x 0.95¹¹] + [(¹¹₁) x 0.05¹ x 0.95¹⁰]

= (1 x 1 x 0.5688) + (11 x 0.05 x 0.598736939) = 0.5688 + 0.3293 = 0.8981

Answer:

0.15 or 15%

Step-by-step explanation:

If the price of a stock rose 3/4 on a point, it means that 1x became 1,75x (x + 3/4x). X is the price of the stock here.

To calculate how much the price went up each day on average, we will create exponential equation.

x = price of the stock

y = average daily change

[tex]x*y^{4} =1.75x[/tex]  divide by x

[tex]y^{4} = 1.75[/tex]

We will calculate it using logarithms.

y = 1.15016, rounded to 1.15

We see that the stock goes up 0.15 points every day.If we multiply it by 100%, we get 15%

Answer:

6.09 * 10 ^-3

Step-by-step explanation:

We want one non zero digit to the left of the decimal

Move the decimal 3 places to the right

6.09

The exponent is 3 and it is negative since we move to the right

6.09 * 10 ^-3

Answer:

6.09(10⁻³)

Step-by-step explanation:

Step 1: Put number into proper scientific decimal form

6.09

Step 2: Figure out how many decimals places it moves

Since it moves to the left 3, our exponent would be -3

Answer:

C. Approaches 35

Step-by-step explanation:

If we graph the expression, we see that we have an asymptote at y = 35.

Answer:

28 miles

Step-by-step explanation:

to fin the actual distance you must multiply the didtance on the map by the map scale

3.5*8=28

What is your question?

Answer:

yeah what's your question?

Answer:

A

Step-by-step explanation:

Given the equality y > -½, it means the values of y is greater than -½.

The values of y would range from 0 upwards. I.e. 0, ½, 1, 1½, 2. . .

Thus, when graphed on a number line, the circle that appears like "o" would start from -½, and the "o" would not be full or shaded to indicate that -½ is not included in the values of y, which are greater than -½. Since the values of y are greater than -½ the direction of the arrow that indicates values of y would point towards our far right, to indicate the values included as y.

Therefore, the graph that indicates the inequality y > ½ is A

Answer:

A

Step-by-step explanation:

Answer:

a. [tex]N(1)=2600[/tex]

b. [tex]N'(a) = 470/a[/tex]

c. N(a) has no maximum value, max N'(a) = 470 (when a = 1)

d. lim a→[infinity] N′(a) = 0

Step-by-step explanation:

a.

the variable 'a' is the amount spent in thousands of dollars, so $1,000 is equivalent to a = 1. Then, we have that:

[tex]N(1)=2600 + 470ln(1)[/tex]

[tex]N(1)=2600 + 470*0[/tex]

[tex]N(1)=2600[/tex]

b.

To find the derivative of N(a), we need to know that the derivative of ln(x) is equal (1/x), and the derivative of a constant is zero. Then, we have:

[tex]N'(a) = 2600' + (470ln(a))'[/tex]

[tex]N'(a) = 0 + 470*(1/a)[/tex]

[tex]N'(a) = 470/a[/tex]

c.

The value of 'ln(a)' increases as the value of 'a' increases from 1 to infinity, so there isn't a maximum value for N(a).

The maximum value of N'(a) is when the value of a is the lower possible, because 'a' is in the denominator, so the maximum value of N'(a) is 470, when a = 1.

d.

When the value of 'a' increases, the fraction '470/a' decreases towards zero, so the limit of N'(a) when 'a' tends to infinity is zero.

Answer:

For this case we have the following confidence interval given:

[tex] 0.345 \leq p \leq 0.895 [/tex]

And for this case we want to find the estimated proportion like this:

[tex]\hat p= \frac{0.345 +0.895}{2}= 0.62[/tex]

And the margin of error for this case would be given by:

[tex] ME= \frac{0.895-0.345}{2}= 0.275[/tex]

Step-by-step explanation:

For this case we have the following confidence interval given:

[tex] 0.345 \leq p \leq 0.895 [/tex]

And for this case we want to find the estimated proportion like this:

[tex]\hat p= \frac{0.345 +0.895}{2}= 0.62[/tex]

And the margin of error for this case would be given by:

[tex] ME= \frac{0.895-0.345}{2}= 0.275[/tex]

20%

Here's a tip: Always start percentage calculating with dividing the current number by 10.

Answer:

  a.  It has exactly two odd vertices

  b.  A C E D B A D C

Step-by-step explanation:

(a) There will not be an Euler path if the number of odd vertices is not 0 or 2. Here, the graph has exactly two odd vertices: A and C.

__

(b) We are required to produce a path of the form {A, _, _, D, B, _, D, _}.

Starting at A, there is only one way to get to node D as the 4th node on the path: via C and E. Node B must follow. From B, there is exactly one way to cover the remaining three edges that have not been traversed so far.

The Euler path meeting the requirements is ...

  A C E D B A D C

It is shown by the arrows on the edges in the graph of the attachment.

Answer:

21/5

Step-by-step explanation:

if a/b = c, then b=a/c

in other words:

divide -7/25 by -1/15 to get the answer

It also helps to use the fact that a/b / c/d = a/b * d/c

-7/25 / -1/15 = -7/25 * -15/1

= 105 / 25

= 21 / 5

Answer:

[tex]4 \frac{1}{5} [/tex]

Step-by-step explanation:

[tex] \frac{ - 7}{25} \div x = \frac{ - 1}{15} [/tex]

[tex]x = \frac{ - 7}{25} \div \frac{ - 1}{15} [/tex]

[tex] = \frac{7}{25} \times \frac{15}{1} [/tex]

[tex] = \frac{21}{5} = 4 \frac{1}{5} [/tex]

Answer:

Option 2

Step-by-step explanation:

The average temperature in January is -1 degrees celsius. Last year, it was 1 degrees celsius higher than the average.

-1 + 1 = 0

Answer:

The second answer.

Step-by-step explanation:

The average temp. is -1C.

'was 1C warmer' = +1

-1+1=0

Answer: True

Step-by-step explanation: Taking the triangle from the left and moving it to the right creates a rectangle. From there just do 12.8×4.5.

Answer: -6.4

Step-by-step explanation:

(0.4)(8)(-2)

3.2*-2

-6.4

Answer:

Step-by-step explanation:

Given the sequence [tex]a_n = \frac{9+14n^{2} }{n+15n^{2} }[/tex]

To find the limit of the sequence, we will first divide the numerator and the denominator through by the highest power of n which is n² as shown;

[tex]\lim_{n \to \infty} \frac{9/n^{2} +14n^{2}/n^{2} }{n/n^{2} +15n^{2}/n^{2} }\\ \lim_{n \to \infty} \frac{9/n^{2} +14 }{1/n +15n^{2}/n^{2 }}\\[/tex]

As [tex]n[/tex] tends to [tex]\infty[/tex], [tex]\frac{a}{n}[/tex] tends to zero where n is any constant, The limit of tyhe sequence as n tends to infinity becomes;

[tex]= \frac{9/\infty+14 }{1/\infty+15 }\\= \frac{0+14}{0+15} \\= 14/15\\[/tex]

Therefore [tex]\lim_{n \to \infty} \frac{9+14n^{2} }{n+15n^{2} } = 14/15[/tex]

Since the limit of the sequence gave a finite number , the sequence converges.

Note that the only case when the sequence diverges id when the limit of the sequence is infinite

Answer:

ok I am tellin6 to you

Step-by-step explanation:

ok I will tell to you

Answer:D

Step-by-step explanation:

Answer:

8 is in the hundreds place as well as in the tens place.

Step-by-step explanation:

We use the base 10 system. 880 would represent eight hundred and eighty. So our 0 would be the ones place, 8 in the tens place, and 8 also in the hundreds place.

Answer:

0.015 radians per second.

Step-by-step explanation:

They tell us that at the moment the speed would be 6 ft / s, that is, dx / dt = 6 and those who ask us is dθ / dt.

Which we can calculate in the following way:

θ = arc sin 100/200 = pi / 6

Then we have the following equation of the attached image:

x / 100 = cot θ

we derive and we are left:

(1/100) * dx / dt = - (csc ^ 2) * θ * dθ / dt

dθ / dt = 0.01 * dx / dt / (- csc ^ 2 θ)

dθ / dt = 0.01 * 6 / (- csc ^ 2 pi / 6)

dθ / dt = 0.06 / (-2) ^ 2

dθ / dt = -0.015

So there is a decreasing at 0.015 radians per second.

The horizontal distance and the height of the kite are illustration of rates.

The angle is decreasing at a rate of 0.24 radian per second

The given parameters are:

[tex]\mathbf{Height =y= 100ft}[/tex]

[tex]\mathbf{Speed =\frac{dx}{dt}= 6fts^{-1}}[/tex]

[tex]\mathbf{Length = 200}[/tex]

See attachment for illustration

Calculate the angle using the following sine ratio

[tex]\mathbf{sin(\theta) = \frac{100}{200}}[/tex]

[tex]\mathbf{sin(\theta) = \frac{1}{2}}[/tex]

The horizontal displacement (x) is calculated using the following tangent ratio:

[tex]\mathbf{tan(\theta) = \frac{100}{x}}[/tex]

Take inverse of both sides

[tex]\mathbf{cot(\theta) = \frac{x}{100}}[/tex]

[tex]\mathbf{cot(\theta) = \frac{1}{100}x}[/tex]

Differentiate both sides with respect to time (t)

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dx}{dt}}[/tex]

Substitute known values

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 6}[/tex]

[tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

Recall that:

[tex]\mathbf{sin(\theta) = \frac{1}{2}}[/tex]

Take inverse of both sides

[tex]\mathbf{csc(\theta) = 2}[/tex]

Square both sides

[tex]\mathbf{csc^2(\theta) = 4}[/tex]

Substitute [tex]\mathbf{csc^2(\theta) = 4}[/tex] in [tex]\mathbf{-csc^2(\theta) \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

[tex]\mathbf{-4 \cdot \frac{d\theta}{dt} = \frac{6}{100}}[/tex]

Divide both sides by -4

[tex]\mathbf{\frac{d\theta}{dt} = -\frac{24}{100}}[/tex]

[tex]\mathbf{\frac{d\theta}{dt} = -0.24}[/tex]

Hence, the angle is decreasing at a rate of 0.24 radian per second

Read more about rates at:

https://brainly.com/question/6672465

Answer:

the slope of A'B' = 3

A'B' passes through point O

Step-by-step explanation:

A dilation with scale factor 3 gives the effect of stretching the line AB three times longer. As dilation does not change the direction of the line, the slope will stay the same. If point O lies on AB and is the center of dilation, then the point O must also lie on A'B'

The required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Given that,
To Select the correct answer from each drop-down menu. AB is dilated by a scale factor of 3 to form A 1 B1. Point O, which lies on AB, is the center of dilation. The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O.

The scale factor is defined as the ratio of modified change in length to the original length.

Here, is o is the center of the line AB and slope of line AB is 3 than the line dilated with scale factor 3 A1B1 has also a scale factor of 3 because Position of dilation is center 0 thus dilation did not get any orientation.
And the center of dilation is O so line A1B1 passes through O.

Thus, the required black space in the statement "The slope of AB is 3. The slope of A1 B1 is___. A1 B1 _____ through point O". is filled by 3 and passes.

Learn more about line Scale factors here:

https://brainly.com/question/22312172

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