Object X and object Y, of charge +Q and −2Q, respectively, are separated by a distance r0, as shown in the figure.
(a) Determine an equation for the magnitude and direction of the electric force that is exerted on object Y from object X in terms of Q, r0, and physical constants, as appropriate.
(b) The charge of object X is changed so that it has a charge of −4Q, and the separation distance between the two objects is changed to 2r0. In a clear, coherent paragraph-length response that may also contain figures and/or equations, predict how the electric force exerted on object Y from object X changes from part (a), and predict how the net charge of the two object system changes from part (a).
Answers
Answer:
(a) The magnitude of the force electric force F = k ×(+Q) × (-2·Q)/r₀² = -2·Q²/(r₀²) which can be written as follows;
[tex]F = \dfrac{k \times (+ Q) \times (-2\cdot Q)}{r_0^2} = -\dfrac{k \times 2 \times Q^2}{r_0^2}[/tex]
Given that the charge of Y is twice the charge on X, we have the charge X will move towards the charge Y which is the +x direction
(b) The force, F, acting between the charges is given as follows;
[tex]F = \dfrac{k \times Q_1 \times Q_2}{r_0^2}[/tex]
When, Q₁ = X = -4Q, Q₂ = Y = -2Q, and r₀ = 2·r₀ we have;
[tex]F = \dfrac{k \times (-4\cdot Q) \times (-2\cdot Q)}{(2 \cdot r_0)^2} = \dfrac{k \times 8 \times Q^2}{4 \cdot r_0^2} = \dfrac{k \times 2 \times Q^2}{r_0^2}[/tex]
Therefore, the electric force exerted on object Y by the object X is the same and acts in an opposite direction to the force of X on Y in (a)
The net charge of the two objects in part (a) is Q - 2Q = -Q
The net charge of the two objects in part (b) is -4Q - 2Q = -6Q
Therefore, the net charge increases by a factor of 6 in part (b)
Explanation:
Related Questions
gold has a density of 19300 kg/m3 calculate the mass of 0.02m3 of gold in kilograms
Answers
Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.
What is density?Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.
Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.
Mass of an object is the product of its volume and density.
Given the volume of gold = 0.02 m³
density = 19300 kg/m³.
mass = volume × density
= 0.02 m³ × 19300 kg/m³
= 386 kg
Therefore, the mass of gold is 386 Kg.
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How long does it take for an 8 kg pumpkin to hit the ground if dropped from a height of 55 m.
Answers
Answer:
t = 3.35 s
Explanation:
It is given that,
Mass of a pumpkin, m = 8 kg
It is dropped from a height of 55 m
We need to find the time taken by it to hit the ground.
Initial velocity of the pumpkin, u = 0
Using second equation of motion to find it as follows :
[tex]h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s[/tex]
So, it will take 3.35 seconds to hit the ground.
pls answer quick & an accurate answer will get brainliest
Answers
Answer:
3.766 kg or 3.7 kg
Explanation:
F= M*A equation
what is energy?
a. the number of atoms in an object
b. a form of sound
c. the ability to do work
d. the size of an object
(ik its not b or d, but i dont know)
Answers
Answer:
c
Explanation:
c. the ability to do work or to produce heat
How many carrots does benny have if he has 8 times as many as Karen. Karen has 18 carrots.
Answers
Answer:
144
Explanation:
18 multiplied by 8 equals 144. Hope I helped! εїз
Answer:
The answer is 144.
Explanation:
18X8=144
Una larga fanja de pavimento tiene marcas a intervalos de 10m. Los estudiantes usan cronometros para registrar los tiempos en que un automovil pasa por cada marca. Asi han obtenido los datos siguientes: Distancia,m l 0 l 10 l 20 l 30 l 40 l 50 l Tiempo,s l 0 l 2.1 l 4.2 l 6.3 l 8.4 l 10.5 l A) Cual es la rapidez media del vehiculo? B) Al cabo de cuanto tiempo la distancia es igual a 34m? C) Cual es la aceleracion del automovil?
Answers
Answer:
men
Explanation:
A motorcyclist travelling at 30m/s starts to apply his brake when he is 50m from the traffic light that has just turned red .if he reached the traffic light. what is the deceleration
Answers
A 1800 kg car moves along a horizontal road at speed v₀ = 18.4 m/s. The road is wet, so the static friction coefficient between the tires and the road is only µ static = 0.188 and the kinetic friction coefficient is even lower, µ kinetic = 0.1316. The acceleration of gravity is 9.8 m/s². What is the shortest possible stopping distance for the car under such conditions? (neglect the reaction time of the driver and round your answer to 4 decimal places)
Answers
Answer:
The shortest possible distance is [tex]|s| = 91.9 \ m[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 1800 \ kg[/tex]
The speed along the horizontal road is [tex]v_o =u = 18.4 \ m/s[/tex]
The static friction coefficient is [tex]\mu_s = 0.188[/tex]
The kinetic friction coefficient is [tex]\mu_k = 0.1316[/tex]
Generally the static frictional force acting on the car is mathematically represented as
[tex]F_f = m * g * \mu_s[/tex]
Generally the force propelling the car is mathematically represented as
[tex]F = m * a[/tex]
Here a is the maximum acceleration
at the point which the car stops ,
[tex]F = F_f[/tex]
=> [tex]m * g * \mu_s = ma[/tex]
=> [tex]g * \mu_s =a[/tex]
=> [tex]a = 9.8 * 0.188[/tex]
=> [tex]a = 1.8424 \ m/s^2[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2as[/tex]
Here v is the final velocity of the car and the value is zero given that the car comes to rest
So
[tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]
=> [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]
=> [tex]|s| = 91.9 \ m[/tex]
Suppose a cart of mass 0.5 kg is placed on the table and connected to a mass hanging mass over the edge. If the hanging mass is 0.2 kg, when what would be the acceleration of the cart?
Answers
Explanation:
0.10kg
0.5kg×0.2kg=
0.10
Which of the following is a limited resource
Answers
The option that can be considered a limited resources is A: fertile soil.
Limited resources can be regarded as can be regarded as finite quantities of productive resources that can be considered to be available for economy.This resources can be considered to be part of fundamental problem of scarcity that humanity has experienced, Fertile soil can be regarded as limited resources among the option.Therefore, option A is correct.
Learn more at:
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Answer:
fertile soil
Explanation:
trust
Type the correct answer in the box. Spell the word correctly.
Read the sentence and type the correct answer in the box.
The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ) which is associated with dark energy and ___________.
Answers
Answer:
The Lambda-CDM model contains a cosmological constant, denoted by a lambda (λ), which is associated with dark energy and cold dark matter.
^Also works for Plato users.
Answer:
"cold dark matter"
Explanation:
other person is correct!!!
As the frequency of a wave decreases, the wave's -
Answers
Answer:
When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.
A model rocket Was built last weekend. We launched it in a nearby field. The rocket took off Straight up with an initial velocity 62.3 m/s. If it accelerates upward at 4.30 m/s2 until the engines stop 3.73 s later: (a) What is the maximum height the rocket reaches? (b) How long is the rocket in the air? (c) What is the velocity of the rocket as it hits the ground?
Answers
Answer:
a) y_total = 575.4 m , b) t_total = 22.56 s , c) v = 106.20 m
Explanation:
a) We can solve this exercise using the scientific relations
Let's find the height reached while the engines are running
v₁ = v₀ + a t
v₁ = 62.3 + 4.30 3.73
v₁ = 78.339 m / s
in this time it rose
y₁ = v₀ t₁ + ½ a t₁²
y₁ = 62.3 3.73 + ½ 4.30 3.73²
y₁ = 262.29 m
At this moment the engines are turned off and the rocket continues in a vertical launch, suppose that the acceleration of gravity is constant in this path
v₂ = v₁ 2 - 2 g y₂
at maximum height the velocity is zero (v₂ = 0)
y₂ = v₁ 2 / 2g
y₂ = 78.339 2/2 9.8
y₂ = 313.11 m
the total height is
y_total = y₁ + y₂
y_total = 262.29 + 313.11
y_total = 575.4 m
b) the time the rocket is in the air is
t_total = t₁ + t₂
where t₂ is the time after the engines have shut down
y = y₁ + v₁ t₂ - ½ g t₂²
y = 0
0 = 262.29 + 78.339 t₂ - ½ 9.8 t₂²
t₂² - 15.99 t₂ - 53.53 = 0
t₂ = [15.99 ±√ (15.99² +4 53.53)] / 2
t₂ = [15.99 ± 21.67] / 2
t₂´ = 18.83 s
t₂´´ = -2.84 s
since the time must be a positive quantity the correct result is t2 = 18.83 s, the total time in the air is
t_total = 3.73 + 18.83
t_total = 22.56 s
c) the speed when it hits the ground
We can perform this calculation starting with the maximum height y = 575.4 m where it has zero initial velocity (vo = 0)
v² = v₀² + 2 g y
v = √ 2gy
v = √ (2 9.8 575.4)
v = 106.20 m
submarines use ______ of air to control their depths in water
Answers
Answer:
A supply of compressed air is maintained aboard the submarine in air flasks for life support and for use with the ballast tanks. In addition, the submarine has movable sets of short "wings" called hydroplanes on the stern (back) that help to control the angle of the dive.
Explanation:
Hope this helped u
Have a nice day
THE ONE WHO WILL ANSWER IT CORRECT WILL BE MARKED AS "BRAINLIST"....... If the radius of the orbit of a spaceship from the centre of the earth is twice the radius of the earth . then calculate the acceleration due to the gravity on space ship.
Answers
Answer:
Explanation:
19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.
plz mark as brainliest
This equation shows the reaction that occurs when calcium carbonate
decomposes. what type of reaction is it? CaCO3 + energy – CaO + CO2
a. endothermic
b. synthesis
c. replacement
d. exothermic
ADD ANSWER
+6 PTS
Answers
Answer:
a. endothermic
Explanation:
The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.
Endothermic changes involves absorption of heat from the surrounding. The surrounding becomes colder at the end of the reaction. When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.Which term best explains why you hear an echo?
Answers
Answer:
reflection
Explanation:
Answer:
reflection
Explanation:
A p e x
what are some of the uses of ultra-sound
Answers
Answer:
Ultrasound has been used in a variety of clinical settings, including obstetrics and gynecology, cardiology and cancer detection. The main advantage of ultrasound is that certain structures can be observed without using radiation. Ultrasound can also be done much faster than X-rays or other radiographic techniques
Answer:
Ultrasound can be used for various purposes like diagnosing conditions, including those in the heart, blood vessels, liver and more. Yet most commonly to monitor growth and development of a fetus. A echocardiogram is a ultrasound of the heart.
Explanation:
What effect do you think thermal energy and the transfer of heat in Earth’s interior have on the surface of the planet?
A.
They cause the seasons to change.
B.
They cause the plates to move around.
C.
They cause the average global temperature to rise.
Answers
Answer:
C
Explanation:
The sun's radiation strikes the ground, thus warming the rocks. As the rock's temperature rises due to conduction, heat energy is released into the atmosphere, forming a bubble of air which is warmer than the surrounding air. This bubble of air rises into the atmosphere.
Answer:
A
Explanation:
It’s cold in the winter
hot in the summer
and in spring it’s warm
What fonts do you use to create color coded lyrics
Answers
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber's position? (c) with what speed do the supplies land in the latter case
Answers
Answer:
Explanation:
For vertical displacement of food-supply
if time taken to reach the ground be t
235 = 1/2 g t² , initial velocity downwards is zero.
t = 6.92 s
Horizontal displacement of food during this period
= 6.92 x 69.4 m
= 480.25 m .
b )
time required to cover horizontal distance of 425 m
= 425 / 69.4 = 6.124 s
This time period will be the time of vertical fall of 235 m . Let initial vertical velocity required be u
h = ut + 1/2 gt²
235 = u x 6.124 + .5 x 9.8 x 6.124²
235 = u x 6.124 + 183.76
u = 8.36 m /s
c )
v = u + gt
= 8.36 + 9.8 x 6.124
= 68.37 m /s
This will be vertical component of velocity .
horizontal velocity = 69.4 m /s
resultant velocity = √ ( 68.37² + 69.4²)
= √(4674.45 +4816.36)
= 97.42 m /s
Where does digestion begin?
Answers
Answer:
Digestion begins in the mouth, when you chew.
The chart shows the percentage of different elements in the human body.
Which element is the most prevalent in the human body?
nitrogen
hydrogen
carbon
oxygen
Answers
A man exerts a force on a large couch by pushing on it. Which of the following must be a true statement about the couch after he begins pushing?
A. The couch will maintain a constant acceleration due to the man's push.
B. The couch will remain at rest.
C. The couch will remain at rest if the push does not overcome the force of friction.
D. The couch will accelerate and then remain at a constant velocity.
Answers
Answer: the answer is c
Explanation:
In order to determine the wavelength, you must know the distance from the (2 points)
Select one:
a. trough of one wave to the crest of the next wave
b. midpoint of a wave to the highest point of the next wave
c. crest of the wave to the equilibrium of the same wave
d. the crest of one wave to the crest of the next wave
Answers
Answer:
b
Explanation:
Answer:
a
Explanation:
because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur
Which evidence did Alfred Wegener’s original theory of continental drift have access to?
Answers
Answer:
Evidence for continental drift
Wegener knew that fossil plants and animals such as mesosaurs, a freshwater reptile found only South America and Africa during the Permian period, could be found on many continents. He also matched up rocks on either side of the Atlantic Ocean like puzzle pieces.
Explanation:
How much work do you do when you push a shopping cart with a force of 20 N for a distance of 5m?
A.100J
B.10J
C.1J
D.1000J
Answers
Answer:
A.100J
Explanation:
Given parameters:
Force on car = 20N
Distance = 5m
Unknown:
Work done = ?
Solution:
Work done is the product of force and distance;
Work done = force x distance;
Insert given parameters and solve;
Work done = 20 x 5 = 100J
After carrying out a scientific investigation, Dr. Jones thinks she has just discovered new information about gravity. How should she best communicate her findings with other scientists? *
Post her discovery on the internet as fact.
Try to find new information on another topic.
Publish her discovery for other scientists to test.
Call her friends and tell them about the discovery
Answers
Answer:
Publish her discovery for other scientists to test.
Explanation:
In the context, Dr. Jones, a famous scientist conducted some experiment and has been working hard on it. She recently discovered some new information and facts about gravitation.
Now the best way to communicate and show her new discovery and results on gravity with the other scientist is to publish her findings in a famous science journal so that other scientist can work on it and make some test to find the same results.
By doing this, other scientist can work on her idea and she can tell and communicate her discovery with the other scientist and physicists.
Anyone can help me with this
Answers
Answer:
this is in the middle of the wheel and helps it rotate it is an axle
A 1500 kg car is parked at the top of a hill 5.2 m high. What is the velocity of the car, in meters per second, when it reaches the bottom of the hill?
Answers
Answer:
Explanation:
The car will fall with acceleration due to gravity which is equal to 9.8 m /s²
For downward fall ,
initial velocity u = o
acceleration due to gravity = g = 9.8 m /s
final velocity v = ?
displacement h = 5.2 m
v² = u² + 2 gh
v² = 0 + 2 x 9.8 x 5.2
= 101.92
v = 10.1 m /s