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4 NH3(g) + 5 O2(g) --> 4 NO(g) + 6 H2O(g)

You need 16 moles of NO(g). How many moles of O2 do you need to start with?

Answer:

atoms of C? 2.25 x 1022 atoms C x 1 mole C = 0.037 mol C

Explanation:

 How many moles of C are in 2.25 x 1022 atoms of C?

Taking into account the definition of Avogadro's number, 0.037 moles of carbon are 2.25×10²² atoms of carbon.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of moles of carbons

In this case, you can apply the following rule of three: if 6.023×10²³ atoms are contained in 1 mole of carbon, then 2.25×10²² atoms are contained in how many moles of copper?

amount of moles of carbon= (2.25×10²² atoms × 1 mole)÷ 6.023×10²³ atoms

amount of moles of carbon= 0.037 moles

Finally, 0.037 moles of carbon are 2.25×10²² atoms of carbon.

Learn more about Avogadro's Number:

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Answer:

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]

We have the final answer as

Hope this helps you

Answer:

D. C triple bond C.

Explanation:

The absorption frequency value is highest for carbon-carbon triple bond. The stretching frequencies are much higher than the bending frequency. It mainly depends upon the strength of the bonds as well as masses of the bonded atoms.

The triple bonds have higher stretching strength than the double bonds and double bonds have higher strength than single carbon to carbon bonds.

The triple bonds has a higher bond order, i.e. 3. So it has maximum stretching bonds.

Balanced Equation is

4H2SiCl2+4H2O → H8Si4O4 + 8HCl

Explanation:

E=(98-15)×400×4.2

E=139440J

t=E/P

E=139440/500=278.88s

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Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: [tex]V_{1}[/tex] = 61 L,      [tex]T_{1}[/tex] = 183 K,      [tex]P_{1}[/tex] = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L[/tex]

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Answer:

Plastics!!!!!

Explanation:

How do you print stone or honey or wood you melt plastic or filiment to print stuff

Answer:

C₃H₈O

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1.031 g

Mass of CO₂ = 2.265 g

Mass of H₂O = 1.236 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen in the compound. This can be obtained as follow:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C =?

Mass of C = molar mass of C / molar mass of CO₂ × mass of CO₂

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H =?

Mass of H = Molar mass of H₂ / Molar mass of H₂O × Mass of H₂O

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O =?

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 1.031 – 0.757

Mass of O = 0.274 g

Finally, we shall determine the empirical formula. This can be obtained as follow:

C = 0.618 g

H = 0.139 g

O = 0.274 g

Divide by their molar mass

C = 0.618 / 12.01 = 0.051

H = 0.139 / 1.01 = 0.138

O = 0.274 / 16 = 0.017

Divide by the smallest

C = 0.051 / 0.017 = 3

H = 0.138 / 0.017 = 8

O = 0.017 / 0.017 = 1

Therefore, the empirical formula of the compound is C₃H₈O

Based on the data provided, the empirical formula of the compound is C₃H₈O

The empirical formula of compound is its simplest formula showing the mole ratio of the elements in the compound.

First, the mass of carbon, hydrogen and oxygen in the compound is determined first as follows:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 0.274 g

To determine the empirical formula of a compound, the mole ratio of the elements are determined as follows:

Mole ratio of the elements:

Carbon                Hydrogen         Oxygen

0.618 g/12.01    0.139 / 1.01         0.274 / 16

0.051                   0.138              0.017

Divide by the smallest ratio to convert to whole numbers

0.051 / 0.017     0.138 / 0.017  0.017 / 0.017

3           :            8           :               1

Therefore, the empirical formula of the compound is C₃H₈O

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Answer:

3.31x10^24 atoms

Explanation:

1 mole of S atom = 6.023^23 atoms

5.5 moles            = 5.5 x 6.023^23

                           = 3.31x10^24 atoms

Answer:

I'm so sorry if this is wrong but I think its B

Answer:

I think c biological processes

Answer:

81 gm

Explanation:

The mass of 1 mole is 27 g

So, Mass of 3 moles of Aluminium would be 3 × 27 = 81 gm..Thus mass of 3 Moles of Aluminium is 81 gm.

Answer:

si.mple fe

Explanation:

ghhsshzhzbbzhh

Answer:

2731.875 J

Explanation:

Applying

Q = cm(t₂-t₁)................ Equation 1

Where Q = amount of heat, c = specific heat capacity of silver, m = mass of silver, t₂ = Final temperature of silver, t₁ = Initial temperature of silver

From the question,

Given: c = 0.235 J/g°C, m = 250 g, t₁ = 22.0°C, t₂ = 68.5°C

Substitute these values into equation 1

Q = 0.235×250(68.5-22.0)

Q = 58.75(46.5)

Q = 2731.875 J

Answer:

0.10 L

Explanation:

First we convert the 2.0 grams of solute (meaning sodium hydroxide) into moles, using its molar mass:

Then we can calculate the required volume of solution, using the definition of molarity:

Answer:

true

Explanation:

Answer:

H2(g)+I2(s)→2HI(s)

Explanation:

Hello there!

In this case, according to the given information and unbalanced chemical reaction, we infer it must be balanced in agreement with the law of conservation of mass because the reactants side has two hydrogen and iodine atoms whereas the products side has just one. In such a way, by placing a 2 on HI, we obtain the following balanced reaction:

H2(g)+I2(s)→2HI(s)

Regards!

Answer:

is has around 1/5 lyrics of water

Answer:

[tex]1 \: mole \: = \: 6.02 \times {10}^{23} \: molecules \\ 0.350 \: moles \: = \: (0.350 \times 6.02 \times {10}^{23} ) \: molecules \\ = 2.107 \times {10}^{23} \: molecules[/tex]

We have that the statement that explains why NaCl dissolves in water even though the process is endothermic the given as,

Option A

Generally ,Sodium chloride  is crystalline salt, when  its dissolved is H20 , it dissociates its ion, the ions are scattered through out the solution which results in increased  in randomness .

Therefore, the entropy increases when NaCl dissolves in water,

Option A

For more information on Heat visit

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Answer:

True

Explanation:

Diffusion is the movement of the particles of a substances from a region of higher concentration to a region of lower concentration.

Diffusion occurs in response to a concentration gradient.

In this case, the dye is at a higher concentration at the middle of the shallow dish of water. Diffusion causes the dye to spread out gradually thereby causing the red cloud to grow larger with time.

Answer: A volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.

Explanation:

Given: [tex]V_{1}[/tex] = ?,          [tex]M_{1}[/tex] = 10 M

[tex]V_{2}[/tex] = 100 mL,            [tex]M_{2}[/tex] = 5 M

Formula used to calculate the volume is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\10 M \times V_{1} = 5 M \times 100 mL\\V_{1} = 50 mL[/tex]

Thus, we can conclude that a volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.

Answer:

Climate change will make plants—and us—thirstier. The combined effects of increased CO2 levels and warmer temperatures will increase water consumption by vegetation. That will lead to water declines in streams and rivers like the Ashepoo River in South Carolina

Explanation:

Answer:

700 calories

Explanation:

Using the formula below:

Q = m × c × ∆T

Where;

Q = amount of heat required (calories)

m = mass of substance (g)

c = specific heat of substance (cal/g°C)

∆T = change in temperature (°C)

According to this question, the following information was provided;

Q = ?

m = 20g

c = 1.0 cal/g °C

∆T = 40°C - 5°C = 35°C

Using the formula; Q = m × c × ∆T

Q = 20 × 1 × 35

Q = 700 calories

Hence, 700 cal of heat energy is needed to raise 20 g of H2O from 5°C to 40°C.

Answer:

oficialismo hemostasia Jalisco

Answer:

K

Explanation:

Potassium is atomic no 19 and it is k because is from kalium, the Meldiaeval Latin for potash, which may have derived from an arabic word quality, meaning alkali.

Atomic mass, 39.098amu

Oxidation status, +1

Year discovered, 1807

Melting point, 63.28 degrees Celsius(145.90degrees Fahrenheit )

Boiling point, 760 degrees Celsius (1400 degrees Fahrenheit )

Answer:

its called molding

Explanation:

Answer:

a. 2.44 nm

b. 15.33 nm²

Explanation:

a. Calculate the thickness (in nm) of the surface film

Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²

The volume of the oil film, V' equals the volume of the oil in the teaspoon, V

V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film

So, V' = V

Ah = V

h = V/A

= 4.93 cm³/2023.43 × 10⁴ cm²

= 0.00244 × 10⁻⁴ cm

= 2.44 × 10⁻⁷ cm

=  2.44 × 10⁻⁷ cm × 1m/100 cm

= 2.44 × 10⁻⁹ m

= 2.44 nm

b. The surface area (in nm2) occupied by an oleic acid molecule on water.

Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²

r = h/2 = 2.44 nm/2 = 1.22 nm

A = 4πr²

A = 4π(1.22 nm)²

A = 4.88π nm²

A = 15.33 nm²