N2+H2---2 NH3?
ASSIGN OXIDATION STATES AND
FIND OXIDIZING AND REDUCING
AGENTS?
Please with steps if possible

Answer:

vuvbuvivovoivuighhghgig

Answer:

(B. Plants and meat)

Explanation:

The water molecule is formed by the covalent bonding between oxygen and hydrogen atoms. Therefore, option C is correct.

Covalent bonding is a type of chemical bonding that involves the sharing of electrons between two atoms. In covalent bonding, the two atoms share a pair of electrons to fill their outermost electron shell and form a stable molecule.

This type of bonding usually occurs between non-metal atoms, which have a high electronegativity and tend to attract electrons strongly. In a covalent bond, the shared electrons are attracted to the positively charged nuclei of both atoms, creating a strong bond.

The strength of the bond depends on the number of shared electrons and the distance between the nuclei. Covalent bonds can be either polar or nonpolar, depending on the electronegativity difference between the two atoms.

In water the bond is formed between oxygen atom and two hydrogen atoms. Hence, C is correct.

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Answer:

they are all right

Explanation:

Answer:

0.009

Explanation:

Molarity, a measure of molar concentration of a substance is calculated thus;

Molarity = number of moles ÷ volume

According to the provided information, mass of KCl = 0.47g, volume of water = 700ml

Using mole = mass/molar mass

Molar Mass of KCl = 39.10 + 35.453

= 74.553g/mol

Mole = 0.47/74.55

Mole = 0.0063mol

Volume of water = 700ml = 700/1000 = 0.7L

Molarity = 0.006/0.7

Molarity = 0.00857

The value of molarity rounded to three decimal places (3 d.p) = 0.009

Answer:

A) actual yield

Explanation:

Theoretical yield is the amount of product expected based on the stoichiomety.

Percent yield is the actual yield over the theoretical yield.

Answer:

owa owa

Explanation:

owa owa owa owa owa ow

(I leave off the x10^23 because they both will divide out)    Use your per

Answer:

c. sublimation and melting

Hope it helps...

Have a great day : )

Answer:

Option C is your answer

C. sublimation and melting

Explanation:

hope it helps u ^_^

have a great day/night

Answer:

2.10 moles of O₂

Explanation:

2 H₂O₂ (l) → 2H₂O(l)  + O₂(g)

In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.

So ratio is 2:1, according to stoichiometry.

If we apply a rule of three;

2 moles of hydrogen peroxide can decompose to 1 mol of oxygen

Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =

2.10 moles of O₂

Answer: 12.1 ml of ethanol is needed

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CO_2=\frac{18.2g}{44g/mol}=0.414moles[/tex]  

[tex]C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)[/tex]  

According to stoichiometry :

2 moles of [tex]CO_2[/tex] is produced by = 1 mole of [tex]C_2H_5OH[/tex]

Thus 0.414 moles of [tex]CO_2[/tex] is produced by=[tex]\frac{1}{2}\times 0.414=0.207moles[/tex]  of [tex]C_2H_5OH[/tex]

 Mass of [tex]C_2H_5OH=moles\times {\text {Molar mass}}=0.207moles\times 46.07g/mol=9.54g[/tex]

Volume of ethanol = [tex]\frac{\text {Mass of ethanol}}{\text {density of ethanol}}=\frac{9.54g}{0.789g/ml}=12.1ml[/tex]

12.1 ml of ethanol is needed to produce 18.2 g of [tex]CO_2[/tex]

0.434 mol F

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 8.25 g F

[Solve] moles F

Step 2: Identify Conversions

[PT] Molar Mass of F - 19.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.434211 mol F ≈ 0.434 mol F

2900 g Au

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 14.7 mol Au

[Solve] g Au

Step 2: Identify Conversion

[PT] Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2895.46 g Au ≈ 2900 g Au

Answer:

1 in. =2.54 cm

3*(10^-4)*2.54=7.62*10^-4

Explanation:

Answer:

Mount Etna I believe

Explanation:

Answer:

Increases, decreases

Explanation:

Answer:

The final temperature of the gas would need to be approximately 158.4 K

Explanation:

The details of the sample of nitrogen gas are;

The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K

The initial volume occupied by the gas, V₁ = 12.2 L

The initial pressure of the gas, P₁ = 150.4 kPa

The final volume of the gas, V₂ = 9.7 L

The final pressure of the gas, P₂ = 101.3 kPa

Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;

[tex]\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}[/tex]

[tex]\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}[/tex]

Plugging in the values gives;

[tex]\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K[/tex]

The final temperature of the gas, T₂ ≈ 158.4 K

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

Answer:

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

Answer:

Can you send an image of the question, please?

Explanation:

Answer: See explanation

Explanation:

Based on the information given in the question, the ranking from the first step to the last step goes as follows:

1. Dissolution of salt into cations and anions

2. Hydration of anions

3. Hydration of cations

4. Dissolved cations and anions begin to deposit as a solid salt.

5. Rate of dissolution is equal to the rate of recrystallization.

Answer:

i think the answer is A....

Explanation:

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface.

Answer:

Al₂O₃ is the limiting reactant

Explanation:

The limiting reagent or limiting reactant in a chemical reaction is a reactant that is totally used up when the chemical reaction is completed and subsequently, the reaction stops as no more products can be formed from the excess reactant.

Equation of the the reaction reaction is given below:

3 Mg (s) + Al₂O₃ (s) ----> 3 MgO (s) + 2 Al (s)

Mole ratio of reactants from the equation shows that 3 moles of magnesium metal is required to react with 1 mole of aluminum oxide.

Molar mass of magnesium metal, Mg = 24 g/mol

Molar mass of aluminum oxide, Al₂O₃ = (27 * 2 + 16 * 3) = 102 g/mol

from the equation of reaction,  (24 * 3 g) 72 g of Mg reacts with 102 g of Al₂O₃

Given masses of reactants:

144 g of Mg = 144/24 6 moles of Mg

150 g of Al₂O₃ = 1.47 moles of Al₂O₃

Mole ratio of Mg to Al₂O₃ = 6/1.47 = 4.08 : 1

Therefore, magnesium is excess reactant while Al₂O₃ is the limiting reactant

Answer: In 1860s, Norwegian scientists C. M. Guldberg and P. Waage noted a peculiar relationship between the amounts of reactants and products in an equilibrium. Today, we call this observation the law of mass action. It relates the amounts of reactants and products at equilibrium for a chemical reaction. For a general chemical reaction occurring in solution, aA + bB ⇄ cC + dD the equilibrium constant, also known as Keq, is defined by the following expression: Keq = [C]c/[D]d where [A] is the molar concentration of species A at equilibrium, and so forth. The coefficients a, b, c, and d in the chemical equation become exponents in the expression for Keq. The Keq is a characteristic numerical value for a given reaction at a given temperature. That is, each chemical reaction has its own characteristic Keq. The concentration of each reactant and product in a chemical reaction at equilibrium is related; the concentrations cannot be random values, but they depend on each other. The numerator of the expression for Keq has the concentrations of every product (however many products there are), while the denominator of the expression for Keq has the concentrations of every reactant, leading to the common products over reactants definition for the Keq. Let us consider a simple example. Suppose we have this equilibrium: A ⇄ B .There is one reactant, one product, and the coefficients on each are just 1. The Keq expression for this equilibrium is Keq = [B]/[A]. Exponents of 1 on each concentration are understood. Suppose the numerical value of Keq for this chemical reaction is 2.0. If [B] = 4.0 M, then [A] must equal 2.0 M so that the value of the fraction equals 2.0: Keq = [B]/[A] = 4.0/2.0 =2.0 .By convention, the units are understood to be M and are omitted from the Keq expression. Suppose [B] were 6.0 M. For the Keq value to remain constant (it is, after all, called the equilibrium constant), then [A] would have to be 3.0 M at equilibrium: Keq = [B]/[A] = 60/3.0= 2.0 .If [A] were not equal to 3.0 M, the reaction would not be at equilibrium, and a net reaction would occur until that ratio was indeed 2.0. At that point, the reaction is at equilibrium, and any net change would cease. However, that the forward and reverse reactions do not stop because chemical equilibrium is dynamic.

3.44 × 10⁻¹⁰ g Pb

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 1.00 × 10¹² atoms Pb

[Solve] grams Pb

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Pb - 207.2 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.44072 × 10⁻¹⁰ g Pb ≈ 3.44 × 10⁻¹⁰ g Pb

Answer:

[tex]\boxed {\boxed {\sf 3.44 *10^{-10} \ g \ Pb}}[/tex]

Explanation:

1. Atoms to Moles

Use Avogadro's Number to convert atoms to moles. This number: 6.022*10²³, tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of lead.

[tex]\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Multiply by the given number of atoms.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {6.022*10^{23} \ atoms \ Pb}{1 \ mol \ Pb}[/tex]

Flip the fraction so the atoms of lead cancel.

[tex]1.00 *10^{12} \ atoms \ Pb *\frac {1 \ mol \ Pb}{6.022*10^{23} \ atoms \ Pb}[/tex]

[tex]1.00 *10^{12}*\frac {1 \ mol \ Pb}{6.022*10^{23}}[/tex]

[tex]\frac {1.00 *10^{12}\ mol \ Pb}{6.022*10^{23}} = 1.66057788*10^{-12} \ mol \ Pb[/tex]

2. Moles to Grams

Use the molar mass to convert moles to grams. This can be found on the Periodic Table. For lead it is 207.2 grams per mole.

[tex]\frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

Multiply by the number of moles we calculated.

[tex]1.66057788*10^{-12} \ mol \ Pb* \frac {207.2 \ g\ Pb}{ 1 \ mol \ Pb}[/tex]

[tex]1.66057788*10^{-12}* \frac {207.2 \ g\ Pb}{ 1 }[/tex]

[tex]1.66057788*10^{-12}* {207.2 \ g\ Pb}= 3.44071737*10^{-10} \ g \ Pb[/tex]

3. Round

The original measurement of atoms has 3 significant figures, so our answer must have the same. For the number we calculated, it is the hundredth place. The 0 in the thousandth place tells us to leave the 4.

[tex]3.44 *10^{-10} \ g \ Pb[/tex]

Answer:

a

Explanation:

the line is going down

To determine the highest angle the pendulum will swing to after the impact, we can apply the principle of conservation of momentum. Initially, the total momentum is zero since the pendulum is at rest.

After the impact, the total momentum remains zero because the block and embedded projectile move together as a single system.First, let's convert the weight units to a common system. The 5-pound rod is approximately 2.27 kg, and the 10-pound wooden block is around 4.54 kg. The projectile's weight is 0.3 oz, which is about 0.0085 kg.The momentum before the impact is zero, so the momentum after the impact must also be zero. This can be expressed as:(2.27 kg + 4.54 kg + 0.0085 kg) * V_final = 0Solving for V_final gives us V_final ≈ 0 ft/s. Since the velocity is zero after the impact, the pendulum will momentarily stop at its highest point.Therefore, the highest angle the pendulum will swing to after the impact is 0 degrees, or it will come to rest at the vertical position.

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Answer:

Explanation:

3.79 liters in one gallon.

75.0 / 3.79 = 19.79 gallons of gasoline

19.8 x 23.7 = 469 miles per tank