Mrs. E buys a pair of jeans and receives a 35% discount. If the original price of the jeans was $55, how much does Mrs. E pay before taxes?

Answers

Answer 1

Answer:

40.39

Step-by-step explanation:

35% discount off 55 is 19.25

$35.75 is the answer

to calculate the tax its 13% rate in your area or what ever

1.13 x 35.75 = 40.39


Related Questions

What are the solutions to the quadratic equation below? x^2+34x-72=0

Answers

Answer:

( x + 36 ) ( x - 2 ) = 0

Step-by-step explanation:

x^2 + 36x - 2x -72 = 0

x ( x + 36 ) - 2 ( x + 36 ) = 0

( x + 36 ) ( x - 2 ) = 0

How is it that it is (-11/4,-1/2) ?

Answers

Answer:

Choice 3

Step-by-step explanation:

A(-5,-1) and B(4, 1)

Distance AB is calculated as x²+y², where x= 4-(-5)=9 and y= 1-(-1)=2

Point P is at 1/4 of distance from point A, so its coordinates will be at 1/4 of full distance from A to B in term of both coordinates:

-5 + 9/4= (-20+9)/4= -11/4-1 +2/4= (-4+2)/4= -2/4= -1/2

So P= (-11/4, -1/2) and choice 3

PLEASE HELP ASAP THANKSSSS

Answers

Answer:

The correct answer is C

Step-by-step explanation:

As you can see Town A is on top of Town B this means that Town B has symetric points to town A. This also shows how Town A is Positively skewed.

ASAP! A boat travelling at top speed upstream moves at 15km/hr. When it travels downstream, again at top speed< it moves at 25km/hr. What is the boat's top speed in still water?

Answers

Answer: 20km/h

Step-by-step explanation:

20km/h.  Simply average 15 and 25 by doing (15+25)/2

Hope it helps <3

Which of the following can be represented by the inequality below? 69h + 126 > 540 A. Yvonne is driving more than 540 miles on a trip. She has already driven 126 miles and drives 69 miles each hour. B. Yvonne is driving less than 540 miles on a trip. She has already driven 126 miles and drives 69 miles each hour. C. Yvonne is driving less than 126 miles on a trip. She has already driven 69 miles and drives 540 miles each hour. D. Yvonne is driving more than 540 miles on a trip. She has already driven 69 miles and drives 126 miles each hour.

Answers

Answer:

The answer is A.

Step-by-step explanation:

The inequality states that the amount that Yvonne drives is more than 540 miles.  Since h represents the number of hours, we know that 69 probably means the number of miles Yvonne can drive per hour.  Finally, 126 shows the amount of miles that Yvonne has already driven.

In a group of 45 students, 5 study both Art and Biology. 8 study Biology but not Art. 9 study neither subject. Given that a randomly selected student studies Art, what is the probability the student studies Art and Biology?

Answers

Answer:

[tex]\frac{1}{9}[/tex]

Step-by-step explanation:

Data provided in the question

There is a total group of 45 students

Art + biology = 5

8 study biology but not Art

Neither subject studied = 9

Based on the above information, the probability of student that studies

art and biology is

Since there is a group of 45 students out of which 5 study both art and biology

So, the ratio is

4: 5

Now divide both sides by 5

So, now the ratio is

9:1

Therefore it means the probability is [tex]\frac{1}{9}[/tex]

Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 247 days and standard deviation sigma equals 16 days. Complete parts​ (a) through​ (f) below.

Answers

Answer:

The answer is given below

Step-by-step explanation:

a) What is the probability that a randomly selected pregnancy lasts less than 242 days

First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,

[tex]z=\frac{x-\mu}{\sigma}=\frac{242-247}{16}=-0.31[/tex]

From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783

(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.

If a sample of 17 pregnancies is obtained, the new mean [tex]\mu_x=\mu=247,[/tex] the new standard deviation: [tex]\sigma_x=\sigma/\sqrt{n} =16/\sqrt{17} =3.88[/tex]

c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{17} }=-1.29[/tex]

From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985

d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{242-247}{16/\sqrt{49} }=-2.19[/tex]

From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143

(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?

It would be unusual if it came from mean of 247 days

f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean

For x = 236 days

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{236-247}{16/\sqrt{20} }=-3.07[/tex]

For x = 258 days

[tex]z=\frac{x-\mu}{\sigma/\sqrt{n} }=\frac{258-247}{16/\sqrt{20} }=3.07[/tex]

From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939

A 7-column table with 2 rows. Column 1 is labeled Sample with entries catfish, all fish. Column 2 is labeled 1 with entries 3, 20. Column 3 is labeled 2 with entries 5, 20. Column 4 is labeled 3 with entries 7, 20. Column 5 is labeled 4 with entries 5, 20. Column 6 is labeled 5 with entries 6, 20. Column 7 is labeled 6 with entries 8, 20. The mean number of catfish in all 6 samples is approximately 5.7. If 200 fish are in the pond, which proportion can be used to predict the number of catfish in the population? StartFraction 5.7 over 20 EndFraction = StartFraction x over 200 EndFraction StartFraction 5.7 over 20 EndFraction = StartFraction 200 over x EndFraction StartFraction 34 over 20 EndFraction = StartFraction x over 200 EndFraction StartFraction 8 over 20 EndFraction = StartFraction 20 over x EndFraction

Answers

Answer: The correct option is 5.7/20 = x/200

Step-by-step explanation: Please refer to the diagram attached for more details.

From the 7-column by 2-row table drawn, you can determine that the mean number of catfish as given in the question is derived as follows;

Mean = Summation of observed data / Number of observations

Mean  = (3 + 5 + 7 + 5 + 6 + 8)/6

Mean = 34/6

Mean = 5.6667

Mean ≈ 5.7

Also the mean number of all fish is derived as follows;

Mean = Summation of observed data / Number of observations

Mean = (20 + 20 + 20 + 20 + 20 + 20)/6

Mean = 120/6

Mean = 20

Using relative frequency, we can confidently predict the number of catfish population in the pond. This simply means, if the mean number of catfish is 5.7 and the mean number of all fish is 20, then the relative frequency would be 5.7 over 20 of the total fish population.

Hence, if there is a total of 200 fish in the pond then to predict the proportion which would be catfish can be expressed as follows;

StartFraction 5.7 over 20 EndFraction = StartFraction x over 200 EndFraction.

OR better expressed as;

5.7/20 = x/200

Answer:

5.7/20 = x/200

Step-by-step explanation:

The tape diagram represents an equation. Write an equation to represent the image.

Answers

Answer:

5n = 1.75

Step-by-step explanation:

The 2 bars are equal thus lower equals upper, that is

5n = 1.75

Solve I=PRT for P if I=312.50, r=25%, and T=0.25

Answers

Answer: I = $ 19.53

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 25%/100 = 0.25 per year,

then, solving our equation

I = 312.5 × 0.25 × 0.25 = 19.53125

I = $ 19.53

The simple interest accumulated

on a principal of $ 312.50

at a rate of 25% per year

for 0.25 years is $ 19.53.

Answer:

P = 5000

You need to multiply r and T together, then divide 312.50 by that.

Mrs. Brown has 11 more boys than girls in her class and has a total of 28 students. Which of the following systems of equations could be used to solve this problem?

Answers

Answer:

g=number of girls in the class b=number of boy in the class

g+b=28

g=11+b

WILL GIVE BRAINLEIST!!!

Answers

Answer:

40

Step-by-step explanation:

Once you plot the data, the middle values will be 39 and 41. To calculate the median, you add them up and divide by two, which will result in 40!

Median is the middle value.

Write the numbers out from smallest to largest:

35, 38, 38, 39, 39, 41, 42, 43, 43, 44

There are 10 total numbers, find the middle two:

39 and 41

Add them Together and divide by 2:

39 + 41 = 80

80/2 = 40

Median = 40

SNOG HELP OR SOMEONE THANK YOUUUU

Which unit rate is equivalent to 14 miles per gallon?

two gallons over thirty two miles

thirty two miles over two gallons

three gallons over forty two miles

forty two miles over three gallons

Answers

Answer:

forty two miles over three gallons

Step-by-step explanation:

2 gallons over 32 miles simplifies to 1 gallon over 16 miles, or 1 gallon per 16 miles. This is not the desired result, so we know the first choice is incorrect.

32 miles over 2 gallons simplifies to 16 miles over 1 gallon, or 16 miles per gallon. Again, this is not the desired result, so we know the second choice is also incorrect.

3 gallons over 42 miles simplifies to 1 gallon over 14 miles, or 1 gallon per 14 miles. While this may look correct, note that 1 gallon per 14 miles and 14 miles per gallon are not the same thing, so we know that the third answer is also incorrect.

By process of elimination, we know that the correct answer must be the last option, but let's still simplify it. 42 miles over 3 gallons simplifies to 14 miles over 1 gallon, or 14 gallons per mile. This is in fact the desired result, so we know that the correct answer is the last option. Hope this helps!

Please answer this question in two minutes

Answers

Answer:

work is shown and pictured

Which equation represents a graph with a vertex at (-1,6)?

Answers

Answer:

B. [tex]y = 3x^2 -6x -3[/tex]

Step-by-step explanation:

Well, we can use the following formula to find the x coordianate of the vertex  -b / 2a.

So let’s start with a)

-6 / 6

-1

A. is wrong because its vertex starts with -1.

b)

6 / 6

1

now that we have our x coordinate we can plug it into the equation to get our y.

3 - 6 - 3

So the y coordinate is -6.

Hence, the answer choice B. [tex]y = 3x^2 -6x -3[/tex]

look at the image below.

Complete the equation of the line through (-8,8)(−8,8)left parenthesis, minus, 8, comma, 8, right parenthesis and (1,-10)(1,−10)left parenthesis, 1, comma, minus, 10, right parenthesis.

Answers

Answer:

[tex]y = -2x - 8\\OR\\2x+y+8=0[/tex]

Step-by-step explanation:

Given that there are 2 points

[tex]A(-8,8)[/tex] and

[tex]B(1,-10)[/tex]

So, the coordinates are:

[tex]x_2 = 1\\x_1 = -8\\y_2 = -10\\y_1 = 8[/tex]

Equation of a line is given as:

[tex]y =mx+c[/tex]

where 'm' is the slope of the line, formula for 'm' is given as:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex](x,y)[/tex] are the points that satisfy the equation of the line.

[tex]c[/tex] is the [tex]y -[/tex] intercept.

Calculating the value of m using the given coordinates:

[tex]m=\dfrac{-10-8}{1-(-8)}\\\Rightarrow m=\dfrac{-18}{9} = -2[/tex]

So, the equation of line becomes:

[tex]y =-2x+c[/tex]

Now, putting the coordinates of point [tex]A(-8,8)[/tex]

[tex]8 =-2\times (-8)+c\\\Rightarrow 8 = 16+c\\\Rightarrow c = -8[/tex]

Please refer to the graph of given equation of line.

The equation of line is:

[tex]y =-2x+-8\\OR\\2x+y+8=0[/tex]

Avery wants to buy a car and has a choice between two different banks. One bank is offering a simple interest rate of 3.2% and the other bank is offering a rate of 3% compounded annually. If Avery decides to deposit $7,000 for 5 years, which bank would be the better deal? 1. a simple interest rate of 3.2% 2. a compound interest rate of 3%

Answers

Answer: a simple interest rate of 3.2% will be the better deal.

Step-by-step explanation:

Hi, to answer this question we have to apply the compounded interest formula:  

A = P (1 + r/n) nt  

Where:  

A = Future value of investment (principal + interest)  

P = Principal Amount  

r = Nominal Interest Rate (decimal form, 3/100= 0.03)  

n= number of compounding periods in each year (1)  

Replacing with the values given  

A = 7000 (1+0.03/1)^(1x5)

A = 7000( 1.03)^5 = $8,114.92

For simple interest:

I = p x r x t  

Where:  

I = interest  

Replacing with the values given:

I = 7000 x (3.2/100) x 5 = $1,120

Adding the principal amount: 7000+1120 = $8,120

Since 8,120 (simple) >8,114.92(compound)

a simple interest rate of 3.2% will be the better deal.

The police department uses a formula to determine the speed at which a car was going when the driver applied the breaks, by measuring the distance of the skid marks.The equation d=0.03r^2+r models the distance, d, in feet, r miles per hour (r is the speed of the car) Factor the equation. d=?

Answers

Answer:

0.03 feet

Step-by-step explanation:

d = 0.03r² + r

When d = 0: 0.03r² + r = 0

r(0.03r + 1) = 0

∴ r = 0

When r = 0: d = 0.03 feet

Which of the following investments could be represented by the function A = 250(1 + 0.08/12)12 × 4?

Answers

hello,

the first term is 250 so this is the initial invested amount

[tex](1+\dfrac{0.08}{12})^{12}=(1+\dfrac{8\%}{12})^{12}[/tex]

is to compute 8% annual interest compounded monthly (there are 12 months in a year)

and then multiply by 4 means that it is computed for 4 years so

finally the answer is

$250 is invested at 8% annual interest compounded monthly for 4 years

hope this helps

factorise this expression as fully as possible 2x^2+6x

Answers

Answer:

(Factor out 2x from the expression)

2x (x +3)

The play director spent 190190190190 hours preparing for a play. That time included attending 35353535 rehearsals that took varying amounts of time and spending 933493 \dfrac{3}{4}9343​93, start fraction, 3, divided by, 4, end fraction hours on other responsibilities related to the play. What question does the equation 35x+9334=19035x+93\dfrac{3}{4}=19035x+9343​=19035, x, plus, 93, start fraction, 3, divided by, 4, end fraction, equals, 190 help answer?

Answers

Answer:

The equation above represents the total time the play director spent preparing for a play.

Step-by-step explanation:

The time spent by the play director for preparing for a play is, 190 hours.

Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.

Let the varying amounts of time be denoted by, x.

The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.

The equation provided is:

[tex]35x+\frac{3}{4}=190[/tex]

The equation above represents the total time the play director spent preparing for a play.

Which statement is true about the equations –3x + 4y = 12 and 1/4x-1/3y=1

Answers

Answer: No solution

Step-by-step explanation:

This system of equation has no solution because...

-3x+4y=12

1/4x-1/3y=1

[tex]-3x+4y-4y=12-4y[/tex]

[tex]-3x=12-4y[/tex]

[tex]\frac{-3x}{-3}=\frac{12}{-3}-\frac{4y}{-3}[/tex]

[tex]\frac{12}{-3}-\frac{4y}{-3}[/tex]

[tex]x=-\frac{12-4y}{3}[/tex]

substitute

[tex]\frac{1}{4}\left(-\frac{12-4y}{3}\right)-\frac{1}{3}y=1[/tex]

[tex]-1=1[/tex]

-1=1 is false so therefore this system has no solution

y=(x+9)÷(x-3)
Find the value of y when x=5​

Answers

Answer:y=7

solution,

X=5

[tex]y = \frac{x + 9}{x - 3} \\ = \frac{5 + 9}{5 - 3} \\ = \frac{14}{2} \\ = 7[/tex]

hope this helps...

Good luck on your assignment..

Answer:

When x=5

Y=(5+9)÷(5-3)

= 14 ÷2

= 7

What is the range? Explain

Answers

Answer:

Range = [5, ∞)

Step-by-step explanation:

The initial  number of snakes is 5 and it is increasing at a high rate so the maximum number is infinite. The population is increasing exponentially according to the equation  P = 5(2)^t  where t = the number of years.

I need help please help

Answers

Answer:

21u-16v+18w

Step-by-step explanation:

(7u-4v+4w) 14u-12v+14w

21u-16v+18w

Answer:

= 21u−16v+18w

Step-by-step explanation:

Let's simplify step-by-step.

7u−4v+4w−2(−7u+6v−7w)

Distribute:

=7u+−4v+4w+(−2)(−7u)+(−2)(6v)+(−2)(−7w)

=7u+−4v+4w+14u+−12v+14w

Combine Like Terms:

=7u+−4v+4w+14u+−12v+14w

=(7u+14u)+(−4v+−12v)+(4w+14w)

=21u+−16v+18w

Answer:

=21u−16v+18w


Find the missing side length

Answers

just use cosine rule

17. The length of a swing is 2.1 m. If the length
of the arc that is made by the swing
4.4 m, calculate the angle swept by the
swing​

Answers

Answer:

dose it tell you want angle the arc is at?

Step-by-step explanation:

If you are given the graph of h(x) = log6x, how could you graph M(x) = log6(x+3)?

Answers

you would just move it positive three

Answer:

Translate 3 units to the left

Step-by-step explanation:

Simple and easy question
please help

Answers

Answer:

Volume of a sphere = 4/3πr³

π = 3.14

r = radius which is 3in

Volume = 4/3 × 3.14 × 3²

= 37.68

= 38 cubic inches to the nearest hundredth

Hope this helps

Answer:

38 cubic inches

Step-by-step explanation:

A company rounds its losses to the nearest dollar. The error on each loss is independently and uniformly distributed on [–0.5, 0.5]. If the company rounds 2000 such claims, find the 95th percentile for the sum of the rounding errors.

Answers

Answer:

the 95th percentile for the sum of the rounding errors is 21.236

Step-by-step explanation:

Let consider X to be the rounding errors

Then; [tex]X \sim U (a,b)[/tex]

where;

a = -0.5 and b = 0.5

Also;

Since The error on each loss is independently and uniformly distributed

Then;

[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]

where;

n = 2000

Mean [tex]\mu = \dfrac{a+b}{2}[/tex]

[tex]\mu = \dfrac{-0.5+0.5}{2}[/tex]

[tex]\mu =0[/tex]

[tex]\sigma^2 = \dfrac{(b-a)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(0.5-(-0.5))^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(0.5+0.5)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(1.0)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{1}{12}[/tex]

Recall:

[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]

[tex]n\mu = 2000 \times 0 = 0[/tex]

[tex]n \sigma^2 = 2000 \times \dfrac{1}{12} = \dfrac{2000}{12}[/tex]

For 95th percentile or below

[tex]P(\overline X < 95}) = P(\dfrac{\overline X - \mu }{\sqrt{{n \sigma^2}}}< \dfrac{P_{95}- 0 } {\sqrt{\dfrac{2000}{12}}}) =0.95[/tex]

[tex]P(Z< \dfrac{P_{95} } {\sqrt{\dfrac{2000}{12}}}) = 0.95[/tex]

[tex]P(Z< \dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}}) = 0.95[/tex]

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1- 0.95[/tex]

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} = 0.05[/tex]

From Normal table; Z >   1.645 = 0.05

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1.645[/tex]

[tex]{P_{95}\sqrt{12} } = 1.645 \times {\sqrt{{2000}}}[/tex]

[tex]{P_{95} = \dfrac{1.645 \times {\sqrt{{2000}}} }{\sqrt{12} } }[/tex]

[tex]\mathbf{P_{95} = 21.236}[/tex]

the 95th percentile for the sum of the rounding errors is 21.236

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