Answer:
a change of position in relation to another object.
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.
Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, displacement, position, etc.
Hence, motion is a change of position in relation to another object.
how does displacement, acceleration, time, and velocity affect motion?
Answer:
The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.
~Hoped this helped~
~Brainiliest?~
Answer:
We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.
Explanation:
Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.
Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.
Hope this helps :)
Which of the following is an example of an electromagnetic wave ?
Answer:
Its a wave
Explanation:
THis is one
Answer: a light wave
Explanation: a pex
How much power does it take to lift 20.0 N 5.0 m high in 5.0s?
Answer:
Explanation:
20 watts
When a wool cloth is rubbed on the surface of a balloon, it tends to give away electrons causing the surface of the balloon to become :
positively charged
negativity charged
neutrally charged
Answer:
It is negativity charged
Answer:
positively charged
Explanation:
a wool has neutral charges hence when rubbed against a balloon it will generate positive charges
PLZ ANSWER FOR 25 POINTS AND BRAINLIEST
Answer:
the answer is all of the above
Explanation:
brainliest please
the image represents a sound wave as it goes through several changes. Describe how the waves changes. where does it get louder? where does it get softer?how does the pitch change? how do you know?
someone please help me TvT
Answer:
At point A. it gets kinda loud then at point B. it gets very loud than at point C. it gets quieter than at point D. it gets more silent.
Explanation:
Because you can tell when the waves get large it gets louder and then when the waves get more far apart then it get more quiet. Hope this helped!
A room is 5.0 m long, 4.0 m wide, and 3.0 m high. What is the mass of the air it contains?
Answer:
Here u go
Explanation:
Mass of air in the room m= volume of room×density of air
=(5m×4m×3m)(1.20kgm3)=72kg
Weight of air, W=mg=(72kg)(9.8ms2)=706N.
Answer:
person above is correct, i did the work and got the smae answer
HELP PLZZZ
Which optical devices can form images that are larger than the original
object?
Answer: B- A and C
Explanation:
A P E X
The optical devices uses light. The correct option for the optical devices can form images that are larger than the original object is B i.e A and C.
What is optical device?The device which uses light for the meaningful purpose is called optical devices.
The device which form the images larger than the object are the converging type of lens or mirror.
The lens which is converging is the convex lens denoted by C in diagram and the converging mirror is the concave mirror denoted by A.
Therefore, the correct option for the optical devices can form images that are larger than the original object is B i.e A and C.
Learn more about optical devices.
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A crowbar is used to lift a load of 1200 N by placing it at a distance of 25 cm from the fulcrum.
the force required at 60 cm from the fulcrum to balance the load.
Answer:
500 N
Explanation:
From the question,
Sum of clockwise moment = sum of anti clockwise moment.
F×d = F'×d'.................. Equation 1
Where F = Force applied to lift the load, d = distance, F' = Force required, d' = distance of the required force from the fulcrum
Make F' the subject of the equation
F' = F×d/d'.................. Equation 2
Given: F = 1200 N, d = 25 cm, d' = 60cm.
Substitute these values into equation 2
F' = 1200×25/60
F' = 500 N.
Hence the force required to balance the load is 500 N
I need help asap
What is a homopolar motor?
a. The first electric motor ever made.
b. A motor made by in the North Pole.
c. A motor used in homes in the winter.
Answer: The answer is A
Explanation:
Explain how a current is induced in the wire?
Answer:
If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire. (It cannot be the magnetic force since the charges are not initially moving). ... that determines the induced current.
Simplify the expression in part H. Following the five payments, what is the net change in the loan amount from Qulana's viewpoint?
Answer:
I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2
Explanation:
pretty scary gameplay
Answer:
After five monthly payments, Quiana’s loan amount changes by $1,237.15.
Explanation:
A car of mass 800 kg goes round a corner of radius 65 m at a
speed of 10 m/s
b) Suggest how this force is likely to be obtained.
Answer:
Centrifugal force = 1230.77 Newton.
Explanation:
The force associated with the car is generally referred to as centrifugal force and it can be calculated using the formula;
Centrifugal force = mv²/r
Given the following data;
Mass = 800kg
Radius = 65m
Velocity = 10m/s
To find the force;
Centrifugal force = (800*10²)/65
Centrifugal force = (800*100)/65
Centrifugal force = 80000/65
Centrifugal force = 1230.77 Newton.
this is confusind so plzzz help me
A guitar string vibrates 600 times in 2 seconds.
Find its frequency and time period.
Steps Required.
frequency is equal to number of oscillations or vibrations upon time
therefore,
check picture
How does convection play a role in ocean currents?
Three charges lie along the x-axis. One positive charge, q1 = 4.80*10^-18 C, is at x = 3.72 m, and another positive charge, q2 = 1.60*10^-19 C, is at the origin.
At what point on the x-axis must a negative charge, q3, be placed so that the resultant force on it is zero?
Answer:
The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].
Explanation:
Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].
These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].
Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)
Let [tex]k[/tex] denote Coulomb's constant.
The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].
Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:
[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:
[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].
[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].
[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].
By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].
Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].
[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].
[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].
[tex]\sqrt{30}\, x = 3.72 - x[/tex].
Therefore:
[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].
[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].
Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].
A child pushes a toy truck 2.5 m across a floor with a constant force of 22 N. How much work does the child do on the toy truck?
22/2.5= 8.8 J
22 x 2.5= 55 W
22/2.5= 8.8 W
22 x 2.5= 55 J
Answer:
55j
Explanation:
work= force × distance
We have that When A child pushes a toy truck 2.5 m across a floor with a constant force of 22 N.The work done by the child on the toy truck
W= 55 Joules
22 x 2.5= 55 J
Option D
From the question we are told that
A child pushes a toy truck 2.5 m
A constant force of 22 N.
Generally the equation for the Workdone is mathematically given as
W=f*d
W=22N*2.5
W= 55 Joules
Therefore
When A child pushes a toy truck 2.5 m across a floor with a constant force of 22 N.The work done by the child on the toy truck
W= 55 Joules
22 x 2.5= 55 J
Option D
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A motorist wishes to travel 40 kilometers at an average speed of 40 km/h. During the first 20 kilometers, an average speed of 40 km/h is maintained. During the next 10 kilometers. however, the motorist averages only 20 km/h. To drive the remaining 10 kilometers and average 40 km/h, the motorist must drive
a) 60 km/h. b) 80 km/h. c) 90 km/h. d) faster than the speed of light
poste en français s’il vous plaît
what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface
Answer:
[tex]m=1.01\times 10^6\ kg[/tex]
Explanation:
Given that,
Pressure, P = 1 atm = 101325 Pa
Area of the square surface, A = 10² = 100 m²
We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,
[tex]P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg[/tex]
So, the required mass of the vertical column of air is [tex]1.01\times 10^6\ kg[/tex].
The Law of Conservation of Mass states that mass can be destroyed during a chemical change.
True
False
Which image shows an example of the strong nuclear force in action?
i think this is the incomplete page that you are showing but the answer is
:-
BThe observation that energy transformations are rarely 100% efficient is seen by scientists as a violation of the Law of Conservation of Energy.
true or false ???
Answer:
l
Explanation:
Answer:
true I believe
Explanation:
Compare the inner planets with the outer planets.
Inner Planets:
- Rocky
- Small
- Only 3 moons total
- Very close to each other (for space)
- Underweight
Outer Planets:
- Gassy oop-
- GIANT
- Over 200 moons total
- VERY far from each other
- Obese
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Good luck foe.
Lb.
a dogs tail hit a 1.3kg flower vase, knocking it over. the net force on the flower vase over time is shown below
what is the bases speed at t=20 ms?
round answer to two significant figures
note that time is in ms.
Answer: 0.15 m/s
Explanation:
Give examples to show that friction is both friend and foe ?
Answer:
friction as friend
It helps us to hold or catch any objectit alos helps us to walk easilyfriction as foe
It causes wear and tear of tyresit also cause great damages to parts of machinehope it helps
Answer:
Wear and tear of soles of our shoes is due to friction.
When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.
Machines get heated up and produce noise because of friction.
Solar energy heats the surface of the Earth, including the ground, rocks, and even roadways. As the temperature of these surfaces increases, heat energy is released back into the atmosphere, forming a pocket of warm air. As the warm air pocket rises, it is replaced by cooler air. This process is responsible for many of the weather patterns in our atmosphere and is known as
Answer:
convection
Explanation:
I hope this helps
what is the fullform of SMPS ?
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Answer:
A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.
Explanation:
Match the symbol of each element to its name :)
Answer:
H-Hydrogen
B-Boron
O-Oxygen
Au-Gold
Co-Cobolt
He-Helium
Na-Sodium
S-Sulfur
K-Potassium
Ag-Silver
Explanation:
Normally, chemical symbols are either the first letter or the first two letters of the element.
However, there are some exceptions where they use the Latin names e.g:
Aurum-Au-Gold
Natrium-Na-Sodium
Kalium-K-Potassium
Argentum-Ag-Silver
Hope this helps :)
A 5.00 kg block of metal with
c = 650 J/(kg*C) at 80.0 °C comes
in contact with a 1.25 kg glass
block at 20.0 °C. They come to
equilibrium at 63.9 °C. What is the
specific heat of the glass?
Answer:
953.5 J/kg.°C
Explanation:
From the question,
Heat lost by the metal = heat gained by the glass.
cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1
Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature
Make c' the subject of the equation
c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2
Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C
Substitute these values into equation 2
c' = 5×650(80-63.9)/1.25(63.9-20)
c' = (5×650×16.1)/(1.25×43.9)
c' = 52325/54.875
c' = 953.5 J/kg.°C
Answer:
960 J/(kg*C)
Explanation:
i got this right in acellus trust me :D