Answer:
I love you...I Miss u and love you too...I miss my mom
The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doubled, the new force would have what magnitudes?
Answer:
F' = F
Explanation:
The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]
where,
F = Force of attraction
G = Universal gravitational costant
m₁ = mass of first object
m₂ = mass of second object
r = distance between objects
Now, if the masses and the distance between them is doubled:
[tex]F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}[/tex]
F' = F
A car pulled by a tow truck has an acceleration of 2.0 m/s^2. What is the mass of the car if the net force on the car is 3,500 N?
Answer:
ans: 1750 kg
Explanation:
F = ma
so ,
m = F/a
= 3500 / 2
= 1750 kg
A volleyball is served at a speed of 8 / at an angle 35° above the horizontal. What is the speed of the ball when received by the opponent at the same height?
Is an object on the surface of Earth sitting still relative to outer space?
Answer:
The object is not still as it observe from the outer space.
Explanation:
Our earth is not stationary.
It rotates about its own axis with the period of 24 hours and it revolves around the sun with the period of 1 year.
An object is said to be at rest if the position of the object with respect to time changes.
An object is said to be in motion when the position of the object changes with respect to time.
Both the terms rest and motion are relative to each other.
If an observer observe an object on the earth from the outer space, he observe that the object s not still it is also moving as the earth is moving.
So, the object is not still as it observe from the outer space.
find the equivalent resistance.
Answer:
Explanation:
Note the connection between D-L-H shorts out the resistors on the right. Those 4 resistors can be ignored.
The connection between D-L-K means the 2 resistors between C-D and C-K are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Similarly the connection between K-L-H means the 2 resistors between J-K and J-H are in parallel. The equivalent resistance of 2 6-ohm resistors in parallel is 3 ohms.
Adding the resistors in series together:
A-C-L-J-D = 6 + 3 + 3 + 6
= 18 ohms
A truck has a mass of 1.5 x 104 kg. If the truck can reach a maximum acceleration of 1.5 m/s2, what is the net force the truck exerts?
2.25 x 105 N
2.25 x 104 N
2.3 x 104 N
2.3 x 105 N
Answer:
2.25 × 10⁴ NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1.5 × 10⁴ × 1.5
We have the final answer as
2.25 × 10⁴ NHope this helps you
hệ thống điện bao gồm những phần tử nào
which equation describes the sum of the vectors plotted below
Answer:
i think it could be d
Explanation:
I'm not sure
The sum of the vectors plotted below describes by 2x i + 4y j. Hence, option (B) is correct.
What is vector?Physical quantities that exhibit both magnitude and direction are referred to as vector quantities. As an illustration, consider displacement, force, torque, momentum, acceleration, and velocity.
It is more complicated to add vectors than it is to add scalars. It is impossible to simply add two vectors together to get their sum since vectors include both magnitude and direction. The Triangle law is used to calculate the vector addition.
According to the figure:
the sum of the vectors is position vector of second vector, that is, r = 2x i + 4y j.
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200N force was used to move 150N block on an inclined plane of length 12m with a height of 4m. The efficiency of the inclined plane will be
Answer:
42.1%
Explanation:
Applying,
E(%) = (M.A/V.R)×100............. Equation 1
Where E(%) = Percentage efficiency, M.A = mechanical advantage, V.R = Velocity ratio.
But,
M.A = L/E............... Equation 2
Where L = Load, E = Effort.
From the question,
Given: L = 150 N, E = 200 N
Substitute these values into equation 2
M.A = 200/150
M.A = 1.33
Also,
V.R for Inclined plane = 1/sin∅ =
V.R = 1/sin∅............... Equation 2
Where ∅ = angle of the inclined plane.
Where,
tan∅ = 4/12
∅ = tan⁻¹(4/12)
∅ = 18.43°
Therefore,
V.R = 1/sin18.43
V.R = 3.16.
Substituting the value of M.A and V.R into equation 1
E(%) = (1.33/3.16)×100
E(%) = 42.1%
What are the magnitude and direction of a uniform electric field perpendicular to the ground that is able to suspend a particle of mass m = 1.30 g carrying a charge of +6.90 µC in midair, assuming gravity and the electrostatic force are the only forces exerted on the particle?
Answer:
the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
Explanation:
Given the data in the question;
mass m = 1.30 g = 1.30 × 10⁻³ kg
Charge q = +6.90 µC = 6.90 × 10⁻⁶ C
we know that; g = 9.8 m/s
assuming gravity and the electrostatic force are the only forces exerted on the particle, hence the relation is;
F = mg and F = Eq
so
mg = Eq
make E subject of formula
E = mg / q
so we substitute
E = [ (1.30 × 10⁻³) × 9.8 ] / 6.90 × 10⁻⁶
E = 0.01274 / 6.90 × 10⁻⁶
E = 1846.38 N/C
Since the charge is positive ( + ), { direction is Upward }
Therefore, the magnitude and direction of the uniform electric field is 1846.38 N/C and UPWARD respectively
A proton accelerates from rest in a uniform electric field of 595 N/C. At one later moment, its speed is 1.15 Mm/s (nonrelativistic because v is much less than the speed of light). (a) Find the acceleration of the proton. (b) Over what time interval does the proton reach this speed? (c) How far does it move in this time interval? (d) What is its kinetic energy at the end of this interval?
A car with a mass of 850kg is moving at a speed of 72km/h when colliding with a concrete wall until it stops. After the collision, the car travels 2.0m before stopping. Determine the resultant of the forces acting on the car.
Answer:
Explanation:
The vehicle is experiencing a large force created by the concrete wall.
Equation
vf^2 = vi^2 + 2*a * d
Givens
vf = 0 The car eventually does stop.
vi = 72 km/hr * [ 1000 m/ km] * [1 hour / 3600 seconds]
vi = 20 meters / second
a = ?
m = 850 kg
Solution
vf^2 = vi^2 + 2a*d
0 = 20 m/s + 2* 2 *a
-20 m/s = 4a
-20/4 = a
a = - 5 m/s^2 The minus sign tells you the vehicle is slowing down. It sure should be.
Force = m * a
F = - 850 * (-5)
F = - 4250 N
The car provides a 4250 N force on it going east to west and a 4250 N force going from west to east provided by the concrete wall.
A drone flying horizontally at a height of 25 m approaches a point above a person. If the mass of the drone is 11 kg, and its speed is 9.5 m/s, what is the angular momentum of the drone with respect to the person when the it is at a horizontal distance 125 m away.
Answer:
L = 2.61 10³ kg m² / s
Explanation:
Let's approximate the drone to a particle the angular momentum is
L = r x p
L = m r v sin θ
in this case v = 9.5 m / s the mass of the drone is m = 11 kg.
The distance can therefore be found using the Pythagorean theorem, but we can see that the relation
r_perpendicular = r sin θ
r_perpendicular = 25 m
as the flight is horizontal this height does not change
L = m v r_perpendicular
let's calculate
L = 11 9.5 25
L = 2.61 10³ kg m² / s
prove first equation of motion
Answer:
Let us assume a body has initial velocity ' u ' and it is subjected to a uniform acceleration ' a ' so that the final velocity be ' v ' after a time interval ' t '. Acceleration is the rate of change of Velocity.Now , by the definition of acceleration , we have :[tex] \large{ \tt{❃ \: a = \frac{v - u}{t}}} [/tex]
[tex] \large{ \tt{ \dashrightarrow \: at = v - u}}[/tex]
[tex] \large{ \tt{∴ \: v = u + at - - - \tt{ {1}^{st} EQUATION \: OF \: MOTION}}}[/tex]
And we're done! ☂▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Which 4 human activities are the biggest contributors to Climate Change?
Answer:
I don't know if these are the biggest but they are burning fossil fuels factories that release CO2 driving cars and cutting down trees.
YO giving 49 dollars if you answer this question .
. ( )
Trace the flow of energy through the food pyramid, label the missing units of energy found at each level by calculating the change in energy
Answer:
Energy Flow
The chemical energy of food is the main source of energy required by all living organisms. This energy is transmitted to different trophic levels along the food chain. This energy flow is based on two different laws of thermodynamics:
First law of thermodynamics, that states that energy can neither be created nor destroyed, it can only change from one form to another.
Second law of thermodynamics, that states that as energy is transferred more and more of it is wasted.
Energy Flow in Ecosystem
The energy flow in the ecosystem is one of the major factors that support the survival of such a great number of organisms. For almost all organisms on earth, the primary source of energy is solar energy. It is amusing to find that we receive less than 50 per cent of the sun’s effective radiation on earth. When we say effective radiation, we mean the radiation, which can be used by plants to carry out photosynthesis.
Explanation:
Energy Flow in Ecosystem
The energy flow in the ecosystem is one of the major factors that support the survival of such a great number of organisms. For almost all organisms on earth, the primary source of energy is solar energy. It is amusing to find that we receive less than 50 per cent of the sun’s effective radiation on earth. When we say effective radiation, we mean the radiation, which can be used by plants to carry out photosynthesis.
Most of the sun’s radiation that falls on the earth is usually reflected back into space by the earth’s atmosphere. This effective radiation is termed as the Photosynthetically Active Radiation (PAR).
Overall, we receive about 40 to 50 percent of the energy having Photosynthetically Active Radiation and only around 2-10 percent of it is used by plants for the process of photosynthesis. Thus, this percent of PAR supports the entire world as plants are the producers in the ecosystem and all the other organisms are either directly or indirectly dependent on them for their survival.
The energy flow takes place via the food chain and food web. During the process of energy flow in the ecosystem, plants being the producers absorb sunlight with the help of the chloroplasts and a part of it is transformed into chemical energy in the process of photosynthesis.
This energy is stored in various organic products in the plants and passed on to the primary consumers in the food chain when the herbivores consume (primary consumers) the plants as food. Then conversion of chemical energy stored in plant products into kinetic energy occurs, degradation of energy will occur through its conversion into heat.
Then followed by the secondary consumers. When these herbivores are ingested by carnivores of the first order (secondary consumers) further degradation will occur. Finally, when tertiary consumers consume the carnivores, energy will again be degraded. Thus, the energy flow is unidirectional in nature.
Moreover, in a food chain, the energy flow follows the 10 percent law. According to this law, only 10 percent of energy is transferred from one trophic level to the other; rest is lost into the atmosphere. This is clearly explained in the following figure and is represented as an energy pyramid.
You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity
of 0.50 m/s. What is the work done by gravity on the book?
1) +10 J
2) -10
3) +5.0
4) -5.0
The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).
The force exerted on the book by gravity has magnitude
F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N
You raise the book 1.0 m in the opposite direction, so the work done is
W = (10 N) (-1.0 m) = -10 J
The work done by gravity on the book is -10 Joules. The correct option is 2.
What is gravity?The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.
Given are the three positions. The Earth has the acceleration due to gravity, g = 9.81 m/s²,
The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).
The force exerted on the book by gravity has magnitude
F = mg = 10 N x( -9.80 m/s² )= -9.8 N
F ≈ -10 N
The book is raised by 1.0 m in the opposite direction, so the work done is
W =- 10 N x 1.0 m = -10 J
Thus, the correct option is 2.
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18 of 25
The practice of science can answer only scientific questions. And scientific
questions guide the design of investigations. What must be true of the
possible answers to a scientific question?
A. They agree with all prior experiments,
B. They can be supported by evidence,
C. They are popular with a majority of scientists,
D. They lead to increased funding of scientific research,
Answer:
B
Explanation:
Cause its true
If a diffuse gas of atoms is trapped, cooled, and compressed, the de Broglie wavelengths of some atoms can become larger than the distance between atoms. The overlap between atoms leads to new states of matter. In one experiment, 87Rb atoms were cooled to 20 nK.
Required:
a. What is their de Broglie wavelength at this temperature?
b. How many times larger is this than the 0.47 nm diameter of the atoms?
Answer:
a) λ = 0.5346 10⁻⁹ m, b) 1.13
Explanation:
a) The wave-particle duality is
λ = [tex]\frac{\hbar }{p}[/tex]
the expression for energy kinetic is
E = p² / 2m
energy is also related to temperature
E = [tex]\frac{3}{2} \ kT[/tex]
we substitute
p =
λ =
Rubidium's mass is m = 85 uma
we calculate
λ =
λ=
λ = 0.5346 10⁻⁹ m
b) the relationship of the two lengths is
λ /0.47 nm = 0.53 / 0.47 = 1.13
21. The value of 'g on the surface of earth is 9.8 m/s. If mass of Jupiter is 319 times the mass of the
arth and its radius is 11 times the radius of the earth, find the value of 'g' on the surface of Jupiter.
What will be the weight of a man having mass 50 kg on the surface of Jupiter?
Vhy? Also write solve step by step
.
The answer is in the photo. Hope you are satisfied.Have a nice day ☺️
To solve this we must be knowing each and every concept related to acceleration due to gravity and its calculation. Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².
What is acceleration due to gravity?
Gravitational acceleration is indeed a vector, which implies it has a direction and a magnitude. The acceleration caused by gravity at the Earth's surface is denoted by the symbol g. It possesses a standard value of 9.80665 m/s².
Mathematically, the formula for acceleration due to gravity can be given as
g = G M /R²
G=6.674 x 10⁻¹¹ m³ kg⁻¹s⁻²
Mass of Jupiter=319×mass of earth
Radius of Jupiter=11×radius of earth
substituting all the given values in the above equation, we get
g = 6.674 x 10⁻¹¹× 319×6×10²⁴ /(11×6378 10³)²
On calculations, we get
g=25.8m/s²
Therefore, the value of 'g' on the surface of Jupiter is 25.8m/s².
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46) The rapid change of an electric field induces
A) a stronger electric field.
B) a magnetic field.
C) both of these
D) none of the above
Answer:
The answer is Option no. C because rapid changes can cause both magnetic field and stronger electric field
PLEASE HELP ME WITH THIS ONE QUESTION
Given the atomic mass of Boron-9 is 9.0133288 u, what is the nuclear binding energy of Boron-9? (Mproton = 1.0078251, Mneutron = 1.0086649, c^2 = 931.5 eV/u)
Answer:
The binding energy is -882.5 MeV.
Explanation:
The nuclear binding energy of Boron-9 can be found as follows:
[tex] B = [Zm_{p} + Nm_{n} - M]c^{2} [/tex]
Where:
Z: is the number of protons = atomic number = 5
N: is the number of neutrons = A - Z = 9 - 5 = 4
[tex]m_{p}[/tex]: is the mass of the proton = 1.0078251 u
[tex]m_{n}[/tex]: is the mass of the neutron = 1.0086649 u
M: is the atomic mass of B-9 = 9.0133288 u
c² = 931.5 MeV/u
Hence, the nuclear binding energy is:
[tex] B = [Zm_{p} + Nm_{n} - M]c^{2} = [4*1.0078251 u + 4*1.0086649 u - 9.0133288 u]*931.5 MeV/u = -882.5 MeV [/tex]
Therefore, the binding energy is -882.5 MeV.
I hope it helps you!
d. What is one watt power? Calculate the power of
a man if he can lift a load of 175 N to a height of
25 m in 10 second (1+2)
Answer:
437.5 watts.
Explanation:
One watt power (1-watt) is used to describe the situation of an electrical appliance where 1 joule of energy per seconds of time (1 J/s) is consumed or used.
According to the information in the question, a man can lift a load of 175N (Force) to a height of 25 m (distance) in 10 seconds (time).
Power = Workdone (J) ÷ time (s)
Workdone = Force (N) × distance (m)
Workdone = 175 × 25
Workdone (W) = 4375J
Power = W/t
P = 4375/10
P = 437.5 watts.
A banked curve is designed for a roadway. The curve is designed so that a car traveling at 19.2 m/s can negotiate it without relying on the force of static friction. The radius of the curve is 51.2 in and the car has a mass of 2300 kg. a. What angle is the curve banked at (degrees)? b. What is the magnitude of the Normal force (N) between the road and the car when it is traveling at the designed speed? c. If a careless driver tries to negotiate the curve at a speed of 25 m/s ,will the direction of the frictional force be inward or outward?
37 microgram to Gigagram
3.7e-1437 Gigagram
BRAINILIEST PLEASE
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Answer:
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Two blocks A and B with mA = 2.9 kg and mB = 0.87 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6 N. Determine the tension in the string connecting the two blocks.
Answer:
Tension = 1.38 N
Explanation:
Given that:
Mass of block A [tex]m_A[/tex] = 2.9 kg
mass of block B [tex]m_B[/tex] = 0.87 kg
Force F = 6 N
Assume a = acceleration of the blocks.
Then:
[tex]m_A[/tex] (a) + [tex]m_B[/tex] (a) = 6
2.9a + 0.87a = 6
3.77a = 6
a = 6/3.77
a = 1.59 m/s²
Suppose T to be the tension in the string.
If we take a look at the forces acting on the first block, then:
F - T = [tex]m_A[/tex] (a)
T = F - [tex]m_A[/tex] (a)
T = 6 - 2.9(1.59)
T = 6 - 4.62
T = 1.38 N
1.Anna Traveled 500 m to their house in 600 s. What is the speed of Anna?
A. 0.83 m/s B.2 m/s C.2.7m/s D. 3 m/s
2.What is the velocity of an object that traveled a distance of 100m due east in 10s?
A.10 m/s² B. 10m/s due east C. 10 m east D.10 m/s
3.An object traveled a distance of 50 m in 10 s,What is the speed is the object?
A. 5m/s B.5m/s² C.5m/s2 D. 5m/s due west
1=A.0.83m/s
2=10m/s
3=5m/s
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its element was drawing power for 6.3 X 10^2 min in a period of one month. Calculate the electrical energy in kWh used by the pan during the month
Answer:
378 KWh
Explanation:
We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:
10³ W = 1 KW
Therefore,
1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W
1.2×10³ W = 1.2 KW
Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:
60 mins = 1 h
Therefore,
6.3×10² mins = 6.3×10² mins × 1 h / 60 mins
6.3×10² mins = 10.5 h
Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:
Power (P) = 1.2 KW
Time (t) for 1 month (30 days) = 10.5 h × 30
= 315 h
Energy (E) =?
E = Pt
E = 1.2 × 315
E = 378 KWh
Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.
A toy plane weighing 1.5 kg is flying in the air at 8 m/s. The player
turns down its speed to 6m/s. What is the work done on it?
Use the work-energy theorem. The total work done on the plane is equal to the change in its kinetic energy:
W = ∆K
W = 1/2 (1.5 kg) (6 m/s)² - 1/2 (1.6 kg) (8 m/s)²
W = -21 J
(Note that the work must be negative since the "braking" force opposes the direction in which the plane is moving.)