Mock June 22 1F Overview Question Progress Exam Paper Progress 42/80 Marks 10 Eric throws a biased coin 10 times. He gets 3 Tails. Sue throws the same coin 50 times. She gets 20 Tails. 10 Grade For This Paper U 3 Aadi is going to throw the coin once. (i) Which one of the following statements is correct about the probability of Aadi getting Tails? 2/5 (ii) Use Eric's and Sue's results to work out an estimate for the probability that Aadi will get Tails. Write your fraction in the form a/b 13 A Sue's estimate is best because she throws it 50 times. B Sue's estimate is best because she gets more Tails. C Sue's estimate is best because she throws it more times than Eric (1) (1) 15 Total marks: 2 16 17​

The integers greater than 999 but not greater than 4000 is 375.

Integers are the collection of whole numbers and negative numbers. Similar to whole numbers, integers also does not include the fractional part. Thus, we can say, integers are numbers that can be positive, negative or zero, but cannot be a fraction. We can perform all the arithmetic operations, like addition, subtraction, multiplication and division, on integers. The examples of integers are, 1, 2, 5,8, -9, -12, etc. The symbol of integers is “Z“.

The smallest number in the series is 1000, a4-digit number.

The largest number in the series is 4000, a4-digit number

The left most digits (thousands place) of each of the 4 digit numbers other than 4000 can take one of the 3 values 1 or 2 or 3.

The next 3 digits (hundreds, tens and units place) can take any of the 5 values 0 or 1 or 2 or 3 or 4.

Hence, there are 3×5×5×5 or 375 numbers from 1000 to 3999.

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The area of parks is 360 m² , base and height are respectively 30m and 24 m.

Given a triangle shaped park with sides 25m, 24m and 30 m.

The total area that is bounded by a triangle’s three sides is referred to as the triangle’s area.

We know that area of triangle = ½ * base * height

Clearly show that base is 30m and height is 24 m.

So, area of triangle = ½ * 30 * 24 = 720/2 = 360 m²

Therefore, area of triangle shaped park is 360m².

Base and height are respectively 30m and 24m.

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Answer:

x = 14.83 (to the nearest hundredth)

Step-by-step explanation:

Following the Pythagoras' Theorem,

a² + b² = c²

x² + 6² = 16²

       x² = 220

     ∴ x = 14.83 (to the nearest hundredth)

The required selling price of the game after two discount is $63.75.

The term discount designates a sum or a percentage subtracted from an item's usual selling price. Make sure you need all of the items you plan to get before waiting until after the holiday to make a purchase. A discount is a decrease in the cost of a commodity or service. ​

Discount = 25%,

Additional discount = 15%

Then,

Net discount is = 36.25%

We have,

Price of game = $100

Discount amount = 36.25% of $100 = $36.25

So, the selling price of the game after discount = $100 - $36.25

= $63.75

Thus, required selling price of the game is $63.75.

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The four inequalities are a + c ≤ 400, 10a + 5c ≥ 3000, a ≥ 0 and c ≥ 0. The club must sell 200 children tickets and 200 adult tickets.

What is an inequality?

In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa.

The value for one ticket is - $10

The value for one children's ticket is - $5

The total amount that need s to be earned is - $3000

The number of seats in the auditorium is - 400

Let the number of children be = c and the number of adults be = a.

Then the inequality will be -

a + c ≤ 400

10a + 5c ≥ 3000

a ≥ 0

c ≥ 0

The inequalities will have a straight line as (≤,≥) symbols are used in the inequalities.

Write the two inequalities in equation form -

a + c = 400....(1)

10a + 5c = 3000 or 2a + c = 600....(2)

Subtract equation (1) from (2) -

2a + c - (a + c) = 600 - 400

2a + c - a - c = 200

a = 200

a = 200

Substitute the value of a in equation (1) -

200 + c = 400

c = 400 - 200

c = 200

So, the intersection point is (200,200) and the number of children is 200 whereas the number of adults is 200.

Therefore, the graph is obtained.

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The school drama department is putting on a production and plans to charge $10 per ticket and $5 for a children's ticket. They need to earn at least $3,000 each night for cover the cost. The auditorium has a capacity for 400 people.

Write and graph a system of four inequalities that describe how many of each type of ticket the club must sell to meets its goal.

The equation of the total cost for the cover charge and drinks in point-slope form is y = 6x + 5.

The point-slope form of a linear equation is given by -

 [tex]y - y_1 = m(x- x_1)[/tex]

where m is the slope and [tex](x_1, y_1)[/tex] is a point on the line.

Here, the total cost for the cover charge and drinks can be represented by the equation y = mx + b, where y is the total cost, x is the number of drinks, m is the cost per drink, and b is the cost of the cover charge.

We know that the cover charge is $5 and drinks are $6 each, so, we can find the slope (m) of the equation by using the cost per drink which is m = 6.

We can also find the point [tex](x_1, y_1)[/tex] by using the cover charge cost which is (0,5).

Therefore, the equation in point-slope form of the total cost for the cover charge and drinks will be -

y - 5 = 6(x-0)

y - 5 = 6x

y = 6x + 5

Where x is the number of drinks and y is the total cost i.e. cover charge + drinks.

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A value we can put in place of a variable (such as x) that makes the equation true and the answer is  13/-10

A number that is capable of taking on any one of a range of values.

A variable's symbolic representation.

Something which can change.

A variable that could alter in a scientific experiment.

A property that can be measured and given varied values is known as a variable.

Variables include things like height, age, income, province of birth, school grades, and kind of dwelling.

Independent, dependent, and controlled variables make up the three primary variables. A automobile driving down various surfaces is one example.

A variable in programming is a value that can change based on external factors or data that has been supplied to the program.

3x+5y

= 0x+5y

=-3x+y

=-3/5x + y

= 3/5 13x + 10y

=0x + 10y

=13x+y

=13/- 10

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Answer:

$2837.04

Step-by-step explanation:

semi-annually = every 6 month

p=2000

i=6%

t=3 years = 6 periods

compound 6 times in 3years = (1+6%)^6 =1.418519

multiply principal of $2000 = 2837.04

By evaluating the exponential function on x = -2 we will get:

f(-2) = 1/9

Here we have the exponential function below:

f(x) = 3^x

And we want to find f(-2), this means that we just need to evaluate the exponential function in x = -2 (so we just replace the variable x by the number -2)

f(-2) = 3^(-2)

Remember that the negative exponent means that we need to take the inverse, then:

f(-2) = 3^(-2) = 1/3^2

f(-2) = 1/9

That is the value we wanted to find.

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The system that has the solution (-2, -2, -2) is the one in option C.

x + 2y = -6

y + 2z = -6

x - y - z = 2

We want to see which of the given systems has the solution (-2, -2, -2).

To check that, we only need to evaluate all the equations of the system on these values and see if all the equations are true.

If we look at the third system we will get:

x + 2y = -6

y + 2z = -6

x - y - z = 2

Replacing all the values of the point we get:

-2 + 2*(-2) = -6

-2 + 2*(-2) = -6

-2 + 2 + 2 = 2

All these equations are true, thus, the correct option is C.

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As per the given ratio, the amount of paint is 8 ounces needed is and the amount of sugar it will hold 120 ounces.

In math then term ratio is defined as an ordered pair of numbers a and b, written a / b where b does not equal 0

Here we have given that it takes 2 ounces of paint to completely cover all 6 sides of a rectangular prism box which holds 15 cups of sugar.

And then here we have know that they double the dimensions of the box.

Let us consider that the dimension be a.

And as we all know that double the dimensions of the box then dimensions are 2a

Then the ratio of paint and the area of the box remains constant and it can be calculated as,

=> paint / area = 2/x

=> 2/x = 6a² / 6(2a)²

When we simplify this one then we get then x is 8 ounces.

Here we know that the ratio of sugar and the volume of the box remains constant.

Then the sugar volume is calculated as,

=> 15 / X = a³ / (2a)³

When we simplify this then we get the value of x is 120

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The bag can hold a maximum of 53 pounds before breaking, and Ani has already placed 29 pounds in the bag. To find out how many more pounds she can place in the bag, we can subtract the weight already in the bag from the maximum weight the bag can hold:

53 - 29 = 24

So Ani can place 24 more pounds in the bag before it breaks.

The inequality to represent this situation is:

weight in bag + x <= 53 (x represents the amount of weight Ani can put in the bag before it breaks)

To find the solution, we can substitute the value of weight in bag and get

29 + x <= 53

Now we can solve the inequality for x

x <= 24

The solution is x <= 24, which means Ani can place 24 more pounds or less in the bag before it breaks.

To graph the solution, we can start with the number line, and plot the point 24 to the right of the origin, and shade the region to the left of the point. This represents the solution set of x <= 24, which means Ani can place 24 more pounds or less in the bag before it breaks.

Answer:

x+x+18+18=48inches

2x+36 = 48 inches

2x = (48-36) inches

2x = 12 inches

x = 6 inches

In the right-angle triangle RQS the measure of m∠R = 90°, m∠Q = 59° and m∠S = 31°.

What is a right-angled triangle?

Any two sides of a triangle's three sides must always add up to more than the third side since a triangle is a regular polygon with three sides. This distinguishing characteristic of a triangle. A right-angle triangle is one that has angles between its two sides that equal 90 degrees.

A right-angled triangle RQS is given.

The measure of ∠R is given as = 90°.

The measure of ∠Q is given as = (2x + 33)°.

The measure of ∠S is given as = (5x - 34)°.

According to the properties of the triangle, the sum of all angles of a triangle equals 180°.

So, the equation will be -

∠R + ∠Q + ∠S = 180°

Substituting the values into the equation -

90° + (2x + 33)° + (5x - 34)° = 180°

Combining the like terms -

90° + 2x + 33° + 5x - 34° = 180°

7x + 89° = 180°

7x = 180° - 89°

7x = 91°

x = 13°

The measure of ∠Q - (2x + 33)°

∠Q = 2(13°) + 33°

∠Q = 26° + 33°

∠Q = 59°

The measure of ∠S - (5x - 34)°

∠S = 5(13°) - 34°

∠S = 65° - 34°

∠S = 31°

Therefore, the measures of angles are 90°, 59° and 31°.

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The missing value in the triangle is given as follows:

28.

The theorem used to solve this problem is given as follows:

A line parallel to one side of a triangle divides the other two proportionately.

As 28 - 16 = 12, the proportional relationship between the side lengths is given as follows:

12/21 = 16/x.

Applying cross multiplication, the value of x is obtained as follows:

12x = 21(16)

Simplifying by 4, we have that:

3x = 21(4)

Simplifying by 3, we have that:

x = 7 x 4

x = 28.

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The amount of chlorine in the tank as a function of time is:

C(t) = 0.05 * e^(-6/400*t)

Let C(t) be the concentration of chlorine in the tank at time t and V(t) be the volume of the tank at time t.

At t=0, we know that:

C(0) = 0.05 g/l

V(0) = 400 l

As fresh water is pumped in at a rate of 4 l/s and the mixture is pumped out at a rate of 10 l/s, the rate of change of the volume of the tank is:

dV/dt = 4 - 10 = -6 l/s

As the concentration of chlorine is being diluted by the addition of fresh water, the rate of change of the concentration is proportional to the rate of change of the volume. So we can write:

dC/dt = - k * C(t) * (dV/dt)

where k is a proportionality constant.

We can integrate the above equation with respect to time to find the concentration of chlorine in the tank as a function of time:

C(t) = C(0) * e^(-kt)

In order to find the value of k we can use the initial condition C(0) = 0.05 g/l and V(0) = 400l

0.05 = C(0) * e^(-k*0)

0.05 = C(0)

so we can substitute this value into the above equation and solving for k:

C(0) = 0.05 = 0.05 * e^(-k*0)

0.05 = 0.05

so k = -6/400

Finally, the amount of chlorine in the tank as a function of time is:

C(t) = 0.05 * e^(-6/400*t)

This equation expresses the amount of chlorine in the tank as a function of time t. As time goes on, the concentration of chlorine will decrease exponentially.

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The expression 1/14 x³y + 8/14 xy² can be rewritten as one fourteenth xy (x² + 8y).

Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.

The given expression is [tex]\frac{1}{14}[/tex] x³y + [tex]\frac{8}{14}[/tex] xy².

We have to take the common factor of both the terms  [tex]\frac{1}{14}[/tex] x³y and [tex]\frac{8}{14}[/tex] xy² outside.

The common factor of both terms is  [tex]\frac{1}{14}[/tex] xy.

[tex]\frac{1}{14}[/tex] x³y + [tex]\frac{8}{14}[/tex] xy² =  [tex]\frac{1}{14}[/tex] xy (x² + 8y)

Hence the given expression can be rewritten as   [tex]\frac{1}{14}[/tex] xy (x² + 8y).

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If the dimensions of the rectangular fish tank are n , 6 and 18 , then the polynomial in the standard form for Volume of fish tank is  V = 108n .

The dimensions of the fish tank in shape of rectangular prism re :

length = n , width = 6 and height = 18 ;

the formula to be used to calculate the volume of rectangular fish tank is written as : Volume = length × Width × Height ;

substituting the values in the volume formula ,

we get ;

Volume of tank = n × 6 × 18 ;

= n × 108 ;

= 108n .

Therefore , the polynomial in the standard form can be written as V = 108n .

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The absolute value function that has the same graph as f(x) = 2|4x – 6| + 18 is the one in option B. f(x) = 4|2x – 3| + 18

A function will only have the same graph as f(x) = 2|4x – 6| + 18 if we can rewrite that function into f(x).

Remember that if A is positive, then we can write:

A*|x| = |A*x|

Now, we can take our absolute value function:

f(x) = 2|4x – 6| + 18

We can rewrite it into:

f(x) = 2|2*2x – 2*3| + 18

f(x) = 2*| 2*(2x - 3)| + 18

f(x) = 2*2*|2x -3 | + 18

f(x) = 4*|2x - 3| + 18

Thhis is what we can see on option B, so that is the correct one.

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The equilibrium price is p = 28.

Price is an amount of money or value that is exchanged for goods & services. It is the amount of money that an individual or business is willing to pay for a product or service. Price is often determined by factors such as the cost of production, supply and demand, and competition. Price is also shaped by factors such as the availability of substitute products, market trends,  & the strength of a company's brand.

Equilibrium quantity: q = 200

p2 + 8q = 1800         700 − p2 + 6q = 0

Adding the two equations together: 2500

q = 2500/14 q = 178.57 q ≈ 200

Equilibrium price: p = 28

p2 + 8(200) = 1800
p2 + 1600 = 1800  p2 = 200 p = √200
p ≈ 14.14
Therefore, the equilibrium price is p = 28.

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2880 ways are there to list the digits { 1, 2, 2, 3, 4, 5, 6 } so that identical digits are not in consecutive positions.

The list of the digits is: { 1, 2, 2, 3, 4, 5, 6 }

Here we have to determine how many ways are there to list the digits { 1, 2, 2, 3, 4, 5, 6 } so that identical digits are not in consecutive positions

We have one number in consecutive positions in this question

That is: (2, 2)

Number of ways that (2,2) are in consecutive positions = [tex]$\frac{6!}{2!}[/tex] = 360

The permutation of 1, (2, 2), 3, 4, 5, 6 = 6!

6! = 720

To get the total number of permutations

= [tex]$\frac{7!}{2!}[/tex]

= [tex]$\frac{5040}{2}[/tex]

= 2520

The number of ways that 2 identical digits are not consecutively positioned

= 2520 - 360 + 720

= 2880

There are 2880 ways to list the digits { 1, 2, 2, 3, 4, 5, 6 }.

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The perimeter of triangle NPQ is calculated to be 72 when NPQ is given congruent to RSQ.

Perimeter of triangle NPQ = 7x + 2

Triangle perimeter: RSQ = 10x - 4

As triangle NPQ is given congruent to triangle RSQ, we have,

NQ / RQ = PQ / SQ = 24 / 32 = 21 / 28 = 3 / 4

The above ratio can be equated to the ratio of perimeters of the triangles NPQ and RSQ.

Perimeter of triangle NPQ/Perimeter of triangle RSQ = 7x + 2/10x - 4 = 3/4

7x + 2/10x - 4 = 3/4

On cross multiplication and solving, we have, x = 10.

The perimeter of triangle NPQ = 7x + 2 = 70 + 2 = 72  

The question is incomplete. The complete question has the picture of two congruent triangles given in the below attachment.

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The context clues show that the bolded portion contain doesn't contain an error. Therefore, D. No correction is needed

When determining a word's meaning, context clues take into account the words that immediately precede the unknown word and lead us to infer its meaning.

These words, also known as visual indices, are explained or defined by other words that are used in the same sentence.

From June on to November, it lies hot, still, and unbearable, sick with violent and unrelenting storms; then on until April, it is chill, quiet, and drinks its scant rain and scanter snows. From April to the hot season again, it is blossoming, radiant, and a seductress.

In this case, it is grammatically correct. The correct option is D.

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The order of the angles from least to greatest are given as follows:

<N , <R, <Q.

The law of sines states that the ratio between the sine of the angle and the length of the opposite side of the triangle is equals.

This means that the higher the side length, the greater the opposite angle will be.

Hence:

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The greatest amount of dollar shared is $78

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls

The ratio of the three sibling is 1/2 : 1/3 : 1/4. Firstly, we multiply all the terms with the l.c.m which is 12

therefore the ratio = 6: 4: 3

The total money to be share is 169

The total ratio is 13

The share of the first sibling = 6/13 × 169

= $ 78

The share of the second sibling = 4/13 × 169 = $52

The share of the third sibling = 3/13 × 169 = $ 39

Therefore the highest number of dollars shared is $78

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Answer:

3 and 4

Step-by-step explanation:

numbers don't repeat in the X side

The total number of possible passwords is 46,620, if the lock requires a three digit sequence of left-right-left and the number can not be repeated.

We have to find the total number of possible passwords, if the lock requires a three digit sequence of left-right-left and the number can not be repeated.

A school lock has a lock of 37 numbers from 0 to 36.

The possible different possibilities is;

At the first position have 37 choices.

At the second position have 36 choices because the first number is not be repeated.

At the third position also have 35 choices because the first and second number is not be repeated.

So, The total number of possible passwords = 37 × 36 × 35

The total number of possible passwords = 46,620 ways

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The distance travelled by the car during this time  by using single  appropriate trapezium is  26.25 and the answer provided is an underestimate

A) Using a single appropriate trapezium, the estimated distance travelled by the car during the 30 seconds is approximately 55 metres.

This is calculated by taking the area of the trapezium formed by the two points of the speed graph: 8m/s and 6m/s.

The area is calculated by taking the average of the two points, multiplied by the time duration:

Area = (8+6/2) * 30

Area = 7*30

Area = 210

The area of the trapezium is then divided by the speed of the car at the start of the journey (8m/s) to get the estimated distance travelled:

Distance = 210/8

Distance = 26.25

This is rounded up to give an estimated distance travelled of 55 metres.

B) The answer of 55 metres is an underestimate of the actual distance travelled by the car. This is because the trapezium method only takes into account the start and end points of the graph, and not any of the other points in between. The actual distance travelled by the car is likely to be higher as the speed of the car is likely to have been greater at points in between the start and end points.

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