Three point charges are arranged along the x axis. Charge q1 = -4. 10 nC is located at x= 0. 250 mand charge q2 = 2. 20 nC is at x= -0. 320 m. A positive point charge q3 is located at the origin.


What must the value of q3 be for the net force on this point charge to have magnitude 3. 10 μN ? (ans in nC)


What is the direction of the net force on q3? + or - direction


Where along the x axis can q3 be placed and the net force on it be zero, other than the trivial answers of x=+[infinity] and x=−[infinity]? (ans in m)

When a 100 lb rock is raised to a height of 3 feet, it takes 397.5 Joules to complete the work. It is a scalar quantity and is measured in units of energy such as Joules (J) or Foot-pounds (ft-lb).

When a force moves an object in the force's direction, work has been done. The formula: can be used to determine the amount of work completed.

work = force x distance x cos(theta)

where force is measured in newtons (N), distance is measured in meters (m) and theta is the angle between the force and the direction of motion.

In this case, the force required to lift the rock is equal to the weight of the rock, which can be calculated using the equation:

force = mass x gravity

where mass is measured in kilograms (kg) and gravity is 9.8 m/s^2.

To find the amount of work done, we need to convert the weight of the rock from pounds to kilograms, convert the height from feet to meters, and use the formula for work:

mass = 100 lb / 2.2 kg/lb = 45.45 kg

distance = 3 ft x 0.3048 m/ft = 0.9144 m

work = force x distance x cos(theta) = 45.45 kg x 9.8 m/s^2 x 0.9144 m = 397.5 J

So the amount of work done is 397.5 Joules.

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The current in a resistor change if the voltage across the resistor is

decreased by a factor of 4.

What is meant by resistor ?

Voltage, V = IR where I = current and R = resistance.

So,V₁ = I₁R. So, I₁ = V₁/R. Now the new current is I₂ = V₂/R

If V₂ = V₁/4, then I₂ = V₂/R = (V₁/4)/R = V₁/4R = I₁/4

I₂ = I₁/4

The current is reduced by 1/4

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Magnitude of electrostatic force between two charged balls is 63 Nm²/C²

The electrostatic force is an attractive as well as repulsive force caused by the electric charge particles. It is also known as Coulomb's force. The Coulomb attraction would be named after Charles-Augustin de Coulomb, a French scientist. One of nature's four basic forces however is electrostatic force.

In this question we have ,

                 F = Q1 × q₂ ×K / R²

                         K = 9 × 10⁹

From above equation by solving his we get value of electrostatic force is 63 Nm²/C²

An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.It also refers to the physical field for a system of charged particles

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The mechanical advantage of a pulley is the ratio of the output force to the input force.

For example, if a pulley is used to lift a weight of 100 pounds, and the input force is 10 pounds, then the mechanical advantage is 10:1 (100/10).

This means that for every 10 pounds of input force, the pulley can lift 100 pounds of weight. The mechanical advantage of a pulley is determined by the number of strands of rope that are used in the pulley system. The more strands of rope, the higher the mechanical advantage will be.

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With a static friction coefficient of 0.66 against the pavement at 29.131 m/s.

Explanation:

Describe the free body diagram. There are three forces at work: weight force mg drawing the object downward, normal force N pushing perpendicular to the road, and friction force N pushing the object downward similarly to the road.

force total acting in a centripetal direction:

F = ma N sin + N cos = m v2/r N (sin + cos) = m v2/r.

Combined forces acting vertically:

F = ma N (cos sin ) = mg N = mg / (cos sin ), where:

G (sin + cos) = v2 / r v2 = gr (sin + cos) / (cos sin) is the replacement for the equation: mg (sin + cos) / (cos sin)

Values to be entered:

v² = (9.8 m/s²) (39 m) (sin 30° + 0.72 cos 30°) / (cos 30° − 0.72 sin 30°)

v = 29.131 m/s

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Answer:

I do not know this one sorry

The magnitude of the acceleration of the point charge assuming that only the electric field force acts on it is 1.54×[tex]10^{7}[/tex].

The magnitude of the acceleration of the point charge can be calculated using the equation a = F/m, where F is the electric field force and m is the mass of the point charge. The electric field force is equal to the charge of the point charge times the magnitude of the electric field, or

F = (8.47 ×[tex]10^{-6}[/tex] C) x (914 N/C).

Therefore, the magnitude of the acceleration can be calculated as

a = (8.47×[tex]10^{-6}[/tex]C x 914 N/C)/(5.49 ×[tex]10^{-6}[/tex] kg) = 1.54 ×[tex]10^{7}[/tex] m/s2.

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The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade would be 2673.87 feet.

Stopping sight distance (SSD) is a measure of the distance a vehicle needs to travel in order to come to a complete stop after the driver perceives a potential hazard on the road. It is calculated by taking into account the driver's perception-reaction time, the vehicle's speed, the road's gradient, and the road's surface friction. SSD helps ensure that drivers have enough time and distance to stop safely in case of an emergency. It is often used to determine the appropriate placement of signs, signals, and other traffic control devices on a road.

The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade can be calculated using the formula: SSD = (Speed x Perception-Reaction Time) + (Speed² / (2 x G x Friction Coefficient))

Where, Speed = 65 mph = 65 x 1.46667 = 94.44 ft/s

Perception-Reaction Time = 2 seconds = 2 x 1.46667 = 2.933 ft/s

G = 32.17 ft/s² (acceleration due to gravity)

Friction Coefficient = 0.25

Therefore,

SSD = (94.44 x 2.933) + (94.44² / (2 x 32.17 x 0.25))

SSD = 277.33 + 2396.54

SSD = 2673.87 ft

So, the stopping sight distance is 2673.87 feet.

This means that a driver should be able to see an obstacle at least 2673.87 feet ahead of them in order to be able to stop safely in case of an emergency.

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The image of the meter stick is 8 cm long which is found by the mirror's formula.

Given:

Focal length of the convex mirror = f = -40 cm

Length of the stick =1m = 100 cm

Distance of the nearer/front end = s1 = 60 cm

Distance of the far/back end  = s2 = 60 + 100 = 160 m

By finding out the image positions of the nearer end and the far end. We can find out the length of the image a meter stick.

Mirror formula,

              1/s + 1/s' = 1/f

Using mirror formula we find expression for s',

s' = sf/(s-f)

To find the image position of front end of the stick facing towards the convex mirror

s'1 = (60 x- 40) / (60-(-40))

s'1  =  -24 cm

Similarly, the image position of back end of the stick

s'2 = -32 cm

The length of the image is given by

s'1 - s'2 = -24 -(-32)

            = 8 cm

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The distance traveled by object is 120 m in given time 10 seconds.

If other information is known, a set of four equations called the kinematic equations can be used to predict unknown information about an object's motion.

The equations can be applied to any motion that can be classified as either a constant velocity motion (with an acceleration of 0 m/s/s) or a constant acceleration motion. They are never permitted to be used over any time frame in which the acceleration is changing.

Four variables are present in each of the kinematic equations. The fquations offer a useful method of predicting details about an object's motion.

The kinematic equation for distance is,

[tex]\boxed{\mathrm{ d = (v +v_0) \dfrac{t}{2} }}[/tex]

Where,

[tex]\mathrm{V_0}[/tex] - initial speed = 8 m/s

V - final speed = 16 m/s

t - time = 10 s

Put the values in formula,

[tex]{\mathbf{ {d = (16+9) \dfrac{10}{2} }}[/tex]

[tex]\mathbf{d=120m}[/tex]

Thus, The distance traveled by object is 120 m in given time 10 seconds.

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Answer:

Answer is in attached photo.

Explanation:

Solution is in attached photo, take note of the formula:

Force = Mass x Acceleration.

In an adiabatic process,The initial temperature is 340 K then the final temperature: 95.2K

In an adiabatic process, an ideal gas follows the equation P[tex]V^{y}[/tex] = constant, where y is the ratio of the specific heat at constant pressure to the specific heat at constant volume.

Since the initial volume is V1 and the final volume is V2, we can write:

                      [tex]P_{1} V^{y}[/tex]₁ = P₁[tex]V^{y}[/tex]₂

As the process is adiabatic, no heat is exchanged with the environment, so the internal energy of the gas remains constant.

The internal energy of an ideal gas is , U = 3/2nRT where n is the number of moles, R is the gas constant and T is the temperature in kelvins.

So we can write:

                             3/2nRT₁ = 3/2nRT₂

As the process is adiabatic, the work done by the gas also remains constant. So the work done on the gas is equal to the work done by the gas.

                P( V₂ - V₁) = - P( V₁ - V₂ )

So we can write:

          P₁V₁ = P₂V₂

V₂ = V₁/ 12 P₁V₁ = P₂(V₁ /12) T₂

          = 340 K × 1/12 ( 1.67 -1 )

            = 340 K× ( 1/3.55)

                      = 95.2 K

Now, combining the above equations we can find the final temperature: 95.2K

An ideal gas is a theoretical gas that is composed of a large number of atoms or molecules that are so small compared to the distance between them, that they do not interact with each other except during rare collisions. The properties of an ideal gas are defined by a set of assumptions that include: The gas is composed of a large number of identical particles (atoms or molecules) that have no volume and no interactions except for instantaneous, elastic collisions.

The gas is considered to be a perfect gas, meaning it follows the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvins.

The gas is considered to be a diatomic gas, meaning it follows the adiabatic index , y = 1.67

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The package should be dropped 25 m short of the target.

A package is a collection of related items, such as software components, that are combined into a single unit and distributed for installation or use. Packages can provide a wide range of functionality, from basic data types and libraries, to complete applications and services.

The package should be dropped 25 m short of the target.
To calculate this, we use the formula d = vt,
where d is the distance,
v is the velocity, and t is the time.
We know the velocity (160 m/s) and the time (0.15625 s).
We can determine the distance by plugging these values into the formula: d = 160 m/s × 0.15625 s = 25 m.
Therefore, the package should be dropped 25 m short of the target.

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Different from the forces operating on objects A and B, object C is subject to a force that is twice as great. Therefore, the electric force exerted on object C by its charge is of the highest magnitude.

F AB = (kqq)/r2, where k is the Coulomb's constant, q is the charge on object A, and r is the separation between object A and B, determines the electric force acting on object A.

F AC is calculated using the formula (kq2q)/r2, where r is the distance between item A and C, q is the charge on object A, and 2q is the charge on object C.

F BC = (kq2q)/r2, where k is the Coulomb's constant, q is the charge on object B, 2q is the charge on object C, and r is the separation between objects B and C, determines the electric force acting on object B.

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The brightness of a tungsten filament is determined by several factors, including its temperature, size, shape, and material properties, as well as the properties of the surrounding environment, such as the pressure and composition of the gas.

Tungsten is a chemical element with the symbol W and atomic number 74. It is a dense, silvery-white metal that is highly valued for its high melting point and its ability to withstand high temperatures. It is often used in the production of filaments for incandescent light bulbs, electrical contacts, and other electrical and electronic applications. Tungsten is also used in alloys, such as high-speed steel, to improve the hardness and strength of the materials.

It is not possible to determine the expected increase in brightness of a tungsten hairpin filament simply by knowing that its operating temperature has been increased from 800°C to 900°C. The brightness of a tungsten filament is determined by several factors, including its temperature, size, shape, and material properties, as well as the properties of the surrounding environment, such as the pressure and composition of the gas.

In general, increasing the temperature of a tungsten filament can increase its brightness, as higher temperatures can lead to increased rates of thermionic emission, which is the process by which electrons are emitted from a hot metal surface. However, increasing the temperature also has other effects on the filament, such as changes in its shape, which can also impact its brightness.

It is important to note that increasing the temperature of a tungsten filament beyond a certain point can result in rapid degradation of the filament and eventually cause it to fail. Therefore, it is important to carefully control the temperature of tungsten filaments and monitor their performance to ensure that they are operating within safe and reliable limits.

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Negative electrons are more prevalent than positive protons or vice versa in charged things.

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Saturn's moons has evidence for the existence of a subsurface ocean of liquid water known as Enceladus

Enceladus is a living moon with a vast ocean of liquid salty water beneath its crust. Furthermore, jets of icy particles from that ocean, laced with a brew of water and simple organic chemicals, erupt from this fascinating ocean world on a continuous basis.

Saturn, like Jupiter, has no surface but an atmosphere that contains traces of water vapor. Furthermore, Saturn's spectacular rings are mostly composed of water ice. Titan, Saturn's largest moon, has a surface made up of water ice and other hydrocarbon-based ices.

Cassini discovered water constantly spewing out of jets around Saturn's moon Enceladus' south polar region, leading scientists to conclude that its subsurface ocean contains all of the ingredients for life - liquid water, heat, and food (methane).

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The electric field strength at 16m is weaker than the electric field strength at 8m.

A charged object creates an electric field, which acts as a force field on other charged things nearby. The size of the charge generating the field and its distance from the charge both affect how strong the electric field is. Lines of force can be used to illustrate electric fields, with the direction of the lines indicating the direction of the field. Many different physical phenomena, such as how electric charges behave and how electric circuits function, can be explained by electric fields.

The electric field strength around a point charge is inversely proportional to the square of the distance from the point charge. Specifically, the electric field strength at a distance of r from a point charge is given by the equation E = kq/r^2, where k is the Coulomb constant, q is the charge of the point, and r is the distance from the point charge.

Therefore, the electric field strength at 16m is (1/2)^2 = 1/4 times the electric field strength at 8m. So the electric field strength at 16m is weaker than the electric field strength at 8m.

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The driver must be least "10 inches" away as from steering wheel when seated properly.

It is essential to become familiar with the local traffic laws when travelling to or relocating to a new nation.

No matter how you plan to use a vehicle, adhering to the traffic laws will ensure your safety.

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The specific heat capacity of the metal can be calculated using the equation: q = mCΔT, where q is the heat transfer, m is the mass of the metal, C is the specific heat capacity, and ΔT is the change in temperature. The heat transfer from the metal to the water can be determined as q = mCΔT = 100 g * C * (24.6 - 95.0) °C. The heat transfer from the water to the metal can be determined as q = mCΔT = 140.0 g * 4.184 J/g°C * (24.6 - 20.0) °C. The specific heat capacity can then be calculated as C = q / (mΔT).

The temperature change of the water and steel is used to determine the unique warmth capacity of the steel by means of calculating the warmth switch between the two materials. The warmth switch between the water and metal may be calculated using the equation: q = mcΔT, where q is the heat transfer, m is the mass of the substance, c is the precise heat capability, and ΔT is the trade in temperature. By means of the usage of this equation for each the water and metal, the heat switch among the 2 materials may be calculated and the specific heat potential of the steel can be determined.

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The specific heat capacity of the metal is 140 J/kg°C.

A metal is a chemical element that is typically characterized by its high electrical conductivity, thermal conductivity, and luster. It is usually a dense, malleable, and ductile material that is a good conductor of heat and electricity. Examples of metals include copper, silver, gold, iron, and aluminum.

The specific heat capacity of the metal can be calculated using the formula:

ΔQ = mCΔT

where ΔQ is the heat transferred, m is the mass of the metal, C is the specific heat capacity, and ΔT is the change in temperature.

First, find the heat transferred:

ΔQ = mCΔT = (140.0 g + 100.0 g)(24.6 °C - 20.0 °C) = 240.0 g * 4.6 °C = 1101.6 J

Next, find the heat absorbed by the metal:

ΔQ = mCΔT = 100.0 g * (24.6 °C - 95.0 °C) = -9700 J

Finally, solve for the specific heat capacity:

C = ΔQ / mΔT = -9700 J / 100.0 g * (24.6 °C - 95.0 °C) = -9700 J / 100.0 g * -75.4 °C = 140 J/kg°C

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The initial velocity vector of the ball is;= 25·i + 19.6·j.The falling ball's velocity as a function of time is v = -9.8 (m/s2) t j, and its location as a function of time is r = (4.9 m - 12 9.8 (m/s2) t2) j.

The parameters listed are;The ball's flight time was 4 seconds.The ball is caught 100 meters away from the plate in the horizontal direction.

Assuming that "u" stands for the initial velocity, we have;

100 m is equal to u cos(t) = u cos(4s)

u = cos() / 2 = 25 m/s (1)

∴tan() = 1.568/2 = 0.784 = arctan(0.784) 38.096°. 2usin() =

9.8 m/s2 4 s = 39.2 m/s

The ball's velocity vector's direction is 38.096°.

Equation (1) gives us u cos() = 25 m/s.

31.7672787629 m/s is equal to u = 25 m/s/cos()

= 25 m/s/cos(arctan(0.784))

The initial velocity vector's magnitude is u = 31.7672787629 m/s.

The initial velocity's vertical component is equal to u sin() = 31.7672787629 sin(arctan(0.784)).

Since the ball's starting velocity vector is approximately 31.767 m/s in a direction 38.096° above the horizontal, we can calculate the following:

u = ux(i,j) = 25(i,j) + 19.6(j)

= 25·i + 19.6·j

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The book has more potential energy because it has a greater mass. Potential energy = mass x gravitational acceleration x height.

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The total amount of matter in an object is known as its mass. The weight of an object is the gravitational pull it feels as it falls.

A substance's mass is its total amount of matter. The gravitational force an object experiences as it falls is known as its weight. Because of gravity, the object accelerates. All falling objects on Earth experience some upward air resistance force, which prevents them from ever falling completely freely.

The quantity of material in an object is measured by its mass, which is inversely proportional to the quantity and type of atoms it contains. Unless material is added to or taken away from a body, mass does not change with changes in position, motion, or shape. The kilogram serves as the unit of mass in the SI system (kg).

Therefore, the correct answer is option A) the amount of matter in something.

The complete question is:

What does the word mass mean?

A) the amount of matter in something

B) the speed an object falls

C) how high a person can jump

D) how far an object can be thrown

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The shortest chain sling ACB for a movable bin is  1.228 m.

The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works

Triangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.

According to Newton's first law, in the y-axis

∑ F = 0

w - T₁y - T₂y = 0

T₁y + T₂y = 2,100

T₁ sin θ + T₂ sin θ = 2,100

5,000 sin θ + 5,000 sin θ = 2,100

10,000 sin θ = 2,100

sin θ = 2,100 ÷ 10,000

sin θ = 0.21

θ = sin⁻¹ (0.21)

θ = 12.12°

Look at AOC

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Answer: D

Explanation:

They are exerting the same amount of force on each side which means that there is no net movement.

Answer:D

Explanation:

they are pushing at the same strength so it will not move.

The conservation of charge states that charge cannot be created or destroyed, but can be transferred between objects.

How does the conservation of charge affect the behavior of electric circuits?

The conservation of charge states that charge cannot be created or destroyed, it can only be transferred from one object to another. This principle affects the behavior of electric circuits by ensuring that the total charge in a closed circuit remains constant. This means that the charge flowing into a circuit must equal the charge flowing out of the circuit. If there is an imbalance, the circuit will not function properly.

The conservation of charge also helps to explain the behavior of electric charges in different types of circuits, such as series and parallel circuits.

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The net work that has been done by the object in free fall is -150 J.

We have to note that when an object is said to fall down under the influence of gravity that the object would be acted upon by the acceleration due to gravity.

It should be noted that as the object is falling and the height of the object is decreasing, the value of the gravitational potential energy is also decreasing like wise as the object falls;

Net work done = Final value of energy - Initial value of energy

Net work done = 250J - 400 J

= -150 J

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The ball takes 1.22s to reach the highest point. It remains in the air for 2.44 s when it is thrown vertically upwards.

Equations of motion define the behaviour of physical system in terms of the motion as a function of time.

At the topmost point, v = 0.

Gravitational acceleration is equal to a = -g = -9.8 m/s²

We know one of the equations of motion as, v = u + a t

where, v is final velocity

u is initial velocity

a is acceleration

t is time

Putting in the values in the above equation, we have,

0 = 12 -9.8 t

9.8 t = 12

t = 1.22 s

Thus, the ball reaches the highest point in 1.22 s.

To find out the time in which the ball remains in the air is can be calculated by, v² - u² = 2 a s

where, s is the distance

- 12² = 2 × (-9.8) s

19.6 s = 144

s = 7.34 m

The total time taken by the ball to reach the maximum height is 1.22 s and it takes another 1.22 s to reach the ground.

So, the ball remains in the air for 2.44 s.

The question is incomplete. The complete question is 'Ball is thrown vertically at this speed 12 m/s.'

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Answer:

f=90N

Explanation: