Merry Christmas please help

Answer:

[tex]-6048[/tex]

Step-by-step explanation:

[tex]---------------------------------[/tex]

[tex]56\left(-4\cdot27\right)[/tex] = [tex]-6048[/tex] [tex]because[/tex]

[tex]---------------------------------[/tex]

[tex]56\left(-4\cdot27\right)[/tex] = [tex]?[/tex]

[tex]\left(-4\cdot27\right)[/tex] = [tex]-108[/tex]

[tex]56\left(-108\right)[/tex] = [tex]?[/tex]

[tex]56\left(-108\right)[/tex] = [tex]-6048[/tex]

[tex]---------------------------------[/tex]

Hope this helps! <3

[tex]---------------------------------[/tex]

im guessing 800 50X4 = 200 and 200X4 = 800

i never learned this but i hope its correct.

Answer:

b:q

Step-by-step explanation:

im pretty sure its that. ive learned this before.

if you flipped them so that c and r were facing the same direction, then b and q would be too.

Answer:

Explicación más abajo

Step-by-step explanation:

Integración Indefinida

La integral

[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

[tex]I=sen(t)-t.cos(t)+C[/tex]

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]

Entonces:

[tex]cos(t)=\sqrt{1-x^2}[/tex]

Devolviendo los cambios:

[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]

Es la respuesta correcta

Step-by-step explanation:

4 different vehicles,

2 different paints,

2 different seats.

Total number of combinations = 4 * 2 * 2 = 16.

Answer:

If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!

Step-by-step explanation:

4x+5 = 2x+19

2x=14

x=7

4(7)+5+2(7)+19 = 42+24 = 66

Answer:

i dont onderstand Thais

Standard form:

x - y = 7

Factored form:

y = x - 7

Answer:

y = x - 3 - 4

y = x - 7

(x - 7 = y)

(x = y + 7)

Step-by-step explanation:

Hope you got it.

Answer:

Hope this may helps you

Step-by-step explanation:

6×3(11)

6×33

198

Answer:

198

Step-by-step explanation:

6 ×3(2+9)

= 6×3×11

= 6×33

= 198

Answer:

-7d-14

Step-by-step explanation:

First, let's distribute -7 to (d+2)

-7xd

-7x2

We will get -7d-14

Answer:you are corect its negetive

Step-by-step explanation:

Answer:talk some English dude

Step-by-step explanation:

Answer:

28 i assume.

Answer:

The answer is 28% :))

Answer:

If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

To find the slope, you need to find the [tex]\frac{rise}{run}[/tex] between two points.

[tex]\frac{rise}{run}[/tex] = [tex]\frac{7-1}{3-(-3)}[/tex]

     = [tex]\frac{7-1}{3+3}[/tex]

     = [tex]\frac{6}{9}[/tex]

     = [tex]\frac{2}{3}[/tex]

Answer:

To calculate slope with any two given points the formula is y2 - y1 / x2 - x1. So to solve the problem just plug in the values: 7 - 1 / 3 - (-3),  6 / 6, the slope is 1

Answer:

I believe that all should be checked except for f(x) = x^6 which u already didn't check

Step-by-step explanation:

The equation is y = ab^x and all the equations, except that one, follow this formula

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

Answer:

Step-by-step explanation:

First of all, we will sort the data.

185 227 234 245 278 278 279 281 281 291 299

Mean:

Mean is defined as the sum of values divided by the number of values.

n = 11

[tex]Mean = \frac{sum}{n}\\= \frac{185+227 +234+ 245+ 278+ 278+ 279+ 281+ 281+ 291+ 299}{11}\\=\frac{2878}{11}\\=261.63\ pounds[/tex]

Median:

As the number of values is odd,

The median will be:

[tex]Median = (\frac{n+1}{2})th\ value\\= \frac{11+1}{2}\\=\frac{12}{2}\\=6th\ value[/tex]

The 6th value is 278

Median = 278

Mode:

Mode is the most frequent value in a data set.

In the given dataset,

278 and 281 are modes as both are repeated twice

Mid-range:

Mid-range is the average of maximum and minimum value

So,

Min = 185

Max = 299

So,

[tex]Mid-range = \frac{Max+Min}{2}\\= \frac{185+299}{2}\\= \frac{484}{2}\\= 242[/tex]

Hence,

Answer:

Because even and odd are 2 different ways to determine whether or not you get the right answer for the chosen function.

Step-by-step explanation:

Hope this helps!!!

Answer:

For even functions, we take f(-x) to be the starting function. The y-axis reflection of this function is f(-(-x)), which is equal tof(x). So the relationship f(-x) = f(x) means that the function is the same as its y-axis reflection.

For odd functions, there are two reflections that must occur. First, we start with f(-x). The y-axis reflection of this function is f(-(-x)) = f(x). When we apply an x-axis reflection to this result, we get -f(-(-x)) = -f(x). So the fact that f(-x) = -f(x) means that odd functions are the same as sequential reflections across both the x-axis and the y-axis. (The same sequence of reflections also represents a rotation 180 degrees about the origin).

Step-by-step explanation:

Answer:

when you divide 3/4 by 1/8 you get 6

Answer:

incorrect.

Step-by-step explanation:

the slope of the line perpendicular is the negative reciprocal, which in this case is -1/2

Answer:

False

Step-by-step explanation:

To find the slope of a perpendicular, flip the slope and change the sign.

The slope pf the given line is 2.

The slope of a line perpendicular to y = 2x + 1 is -1/2.

Answer: False

Answer:

The lines will not intersect, because this system has no solutions

Step-by-step explanation:

Answer:

They will not intersect!

Step-by-step explanation:

A-P-E-X

Answer:

[tex] - \frac{x + 2a}{3a + x} [/tex]

Step-by-step explanation:

[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]

i) write ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]

ii) write -2ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]

iii) factor out x from the expression

[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

iv) factor out -a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

v) factor out a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]

vi) factor out -x from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]

vii) factor out x+2a from the expression

[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]

viii) factor out 3a+x from the expression

[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]

ix) factor out the negative sign from the expression and rearrange the term

[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]

x) reduce the fraction a-x

[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]

[tex] - \frac{x + 2a}{3a + x} [/tex]

Answer:

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]

Step-by-step explanation:

Given that:

A country population at any given time (t) is:

[tex]\dfrac{dP}{dt}= kP+I[/tex]

where;

P = population at any time t

k = positive constant

I = constant rate of immigration into the country.

Using the method of separation of the variable;

[tex]\dfrac{dP}{kP+1}= dt[/tex]

Taking integration on both sides:

[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]

[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]

[tex]log (kP + I) =k t+kc_1[/tex]

By applying the exponential on both sides;

[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]

[tex]KP+I = e^{kt} *e^{kc_1}[/tex]

Assume [tex]e^{kc_1 }= C[/tex]

Then:

[tex]kP + I = Ce^{kt}[/tex]

[tex]kP = Ce^{kt}-I[/tex]

[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]

When time t = 0, The Total population of the country is also [tex]P_o[/tex]

[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]

[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]

[tex]P_o = \dfrac{C-I}{k}[/tex]

C - I = kP₀

C =  kP₀ + I

Substituting the value of C back into equation(1), we have:

[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]

[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]