Meiosis does PMAT twice! That means there is prophase I and prophase II. There is metaphase I and metaphase II. If the cartoon below has chromosomes in the middle of the cell, how would you know whether it was in metaphase I or metaphase II?

Answer:

Cluster HR Diagrams: Since all the stars in a cluster formed at the same time, they are all the same age. A very young cluster will have a HR diagram with a cluster of T-Tauri stars evolving towards the main sequence. ... Each star is plotted by its color and magnitude on the HR diagram.

Answer:

V= 33.6L

Explanation:

The reaction between hydrogen and nitrogen is

3H2(g) + N2(g) + 2NH3(g)

Answer:

Acidic oxides, or acid anhydride, are oxides that react with water to form an acid, or with a base to form a salt. They are oxides of either nonmetals or of metals in high oxidation states.

Explanation:

Answer:

0.299 L

Explanation:

We'll begin by calculating the pressure of dry gas. This can be obtained as follow:

Measured pressure = 756 mm Hg

Water vapor pressure = 17.54 mm Hg

Pressure of dry gas =?

Pressure of dry gas = (Measured pressure) – (Water vapor pressure)

Pressure of dry gas = 738.46 mmHg

Finally, we shall determine the volume occupied at STP. This can be obtained as follow:

Initial volume (V₁) = 334 mL = 334 / 1000 = 0.334 L

Initial pressure (P₁) = 738.46 mmHg

Initial temperature (T₁) = 23 °C = 23 °C + 273 = 296 K

Final pressure (P₂) = 760 mmHg

Final temperature (T₂) = 273 K

Final volume (V₂)

P₁V₁/T₁ = P₂V₂/T₂

738.46 × 0.334 / 296 = 760 × V₂/273

Cross multiply

296 × 760 × V₂ = 738.46 × 0.334 × 273

224960 × V₂ = 67334.2597

Divide both side by 224960

V₂ = 67334.2597 / 224960

V₂ = 0.299 L

Thus, the volume of the dry gas st STP is 0.299 L.

Answer:

a) Concentration of salt in mg/L = 2g/100mL

b) concentration in ppm = 20000 ppm

Explanation:

Percentage composition of salt by weight in water = 2%

Density of water = 1 g/mL

100 mL of water will has a mass of 100 g

Mass of salt in 100 g of water = 2% ×100 g = 2 g

Therefore, 2 g of salt is dissolved in 100 mL of solution

Concentration of salt in 100 mL of solution = 2g/100mL

a) Concentration in mg/L

Mass of salt = 2 g = 2000 mg

Volume of solution = 100 mL = 0.1 L

Concentration in mg/L = 2000 mg/0.1 L

Concentration in mg/L = 20000 mg/L

b) Concentration in ppm

1 ppm = 1mg/L

Therefore, concentration in ppm = 20000 ppm

Base isolation is a technique used by engineers to help prevent damage to buildings by earthquakes. The main structure of the building is separate from the base and sits on a bed of springs.

Base isolation is a technique developed to prevent or minimise damage to buildings during an earthquake.

A base isolation system is a method of seismic protection where the structure (superstructure) is separated from the base (foundation or substructure). By separating the structure from its base the amount of energy that is transferred to the superstructure during an earthquake is reduced significantly.

Hence, option D is correct.

Learn more about base isolation here:

https://brainly.com/question/11337994

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what are asking commet it and I might be able to help

Answer:

physical

Explanation:

The zinc (which was already silver) coated the penny. The NaOH dissolved the zinc. (that was what made the water murky) And small pieces of zinc adhered to the penny (coated) It was a physical change because no NEW color was created.

Answer:

It is an example of natural selection (option c)

Natural selection is demonstrated by a green rat snake living within that grass as well as a brown rat snake living throughout the desert.

The process throughout which communities of sentient creatures adapt but instead transform is known as natural selection. Persons within a demographic are inherently varied, which means they are all unique under certain manner.

This variance indicates that certain people have qualities that are more adapted to their surroundings over others.

Thus "Option C" is correct.

Find out more information about Natural selection here:

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Answer:

6.64 l is the answer.......

Answer:

use research.

Explanation:

Answer:

David R. Ashbaugh

Explanation:

David R. Ashbaugh is a Canadian police officer known for his extensive research on the friction ridge identification, introducing for the first time the use of the term ridgeology in forensic identification and the ACE-V methodology.

Answer:

3:1 or 3/1

Explanation:

Look at the coefficients then set up ratio. Simplify to the base numbers and you get 3/1 or 3:1. Thus, for every 3 MgO you produce 1 Mg3N2

Answer:

B. They don't have enough energy to overcome the attractions between them.

Answer:They don't have enough energy to overcome the attractions

between them.

Explanation:

A. They have no motion and cannot even vibrate in place.

B. They don't have enough energy to overcome the attractions

between them.

C. They bounce off the walls of their container and back into place.

D. They move independently of one another.

Answer:

True

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Hope it helps

Answer:

c

Explanation:

i think if not tell me ok

Answer:

The wind pushes the sails from behind, causing the boat to move forward.

Answer:

Wind energy obtained by the machine is converted into kinetic energy as it functions and thus enabling the boat to move.

Together, the forces of drag, from the water, and the pressure from the wind against the sail itself push the craft forward. Angling too sharply into the wind causes the forces on the boat to become unbalanced, and moves the boat sideways in the water.

Answer:

Depends on what you're doing, you could be running and it goes higher, temperature isn't too much of a difference.

Explanation:

Answer:

88%.

Explanation:

The percentage yield of lead sulfate in this experiment is 88% if 2.53 is divided by 2.85 and multiply by 100. The percentage yield can be calculated when the experimental yield is divided by theoretical yield and then multiply by 100. The percentage yield tells us about the actual yield that is gained in the end of experiment which is lower than theoretical yield.

These problems can be solved using the gas laws. The combined gas law states that PV/T = k, where P is the pressure, V is the volume, T is the temperature (in Kelvin), and k is a constant. From this relationship, you can figure out the change in pressure, volume, or temperature of a gas provided that one of those three parameters remains unchanged. This will be shown in the problems given.

1. Here, the pressure and volume of a gas change while the temperature remains constant. Since PV/T = k, if T is also constant, then the relationship becomes PV = k. In other words, the pressure and volume of a gas at a constant temperature are inversely proportional to each other. This can be expressed mathematically as [tex]P_1V_1=P_2V_2[/tex] (also called Boyle's Law), where P₁ and V₁ denote the initial pressure and volume, and P₂ and V₂ denote the final (or changed) pressure and volume, respectively.

We are given a gas with an initial pressure, P₁, of 2.03 atm and an initial volume, V₁, of 4.0 L. We are also told that the gas expands to a final volume, V₂, of 12.0 L. So, we are looking for P₂: The pressure of the gas when the volume has expanded from 4.0 to 12.0 L. From Boyle's Law,

[tex]P_2=\frac{P_1V_1}{V_2}[/tex].

Thus,

[tex]\[P_2=\frac{\left ( 2.03 \text{ atm} \right )\left ( 4.0 \text{ L} \right )}{\left ( 12.0 \text{ L} \right )}\] = 0.67 atm.[/tex]

Since the pressure and volume of a gas are inversely proportional, as one increases, the other decreases, and vice versa.

2. This is another Boyle's Law problem, but this time, we have to figure out what the final volume will be when the pressure of a gas is changed. Since the pressure is reduced, we can deduce that the volume must increase (notice the parallel with the previous question). We again turn to Boyle's Law, and this time we solve for V₂:

[tex]V_2=\frac{P_1V_1}{P_2}[/tex]

from which we obtain

[tex]\[V_2=\frac{\left ( 350.0 \text{ kPa} \right )\left ( 200 \text{ mL} \right )}{\left ( 120.0 \text{ kPa} \right )}\] = 583 mL.[/tex]

It's not clear whether 200 mL (V₁) should be assigned three significant figures or one. I gave the answer to three significant figures; the answer to one significant figure would be 600 mL.

3. We use Boyle's Law once more here, but our word problem has us working backwards (it's also not explicitly mentioned that temperature remains constant, but it should be reasonable to assume so). The current pressure of the gas inside the bike tire is 150 atm at a volume of 700 mL . But we want to know what the initial pressure of the gas was at a volume of 1000 mL. In other words, we want to solve for the P₁ in Boyle's Law:

[tex]P_1=\frac{P_2V_2}{V_1}.[/tex]

Since the volume of the gas had decreased from 1000 mL (V₁) to 700 mL (V₂), and the pressure and volume of a gas at a constant temperature are inversely proportional, we would expect the pressure of the gas to have increased; that is, our P₁ should be less than 150 atm.

[tex]\[P_1=\frac{\left ( 150 \text{ atm} \right )\left ( 700 \text{ mL} \right )}{\left ( 1000 \text{ mL} \right )}\] = 105 atm.[/tex]

Answer:

D.

The substance will have the same chemical properties.

Explanation:

Physical changes do not alter the chemical composition of a substance, so the chemical properties will not change.

Answer:

Molarity of the solution = 0.08 M

Further explanation

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

0.5 lb=226,796 g

MW silver nitrat - AgNO₃ = 169,87 g/mol

mol AgNO₃ :

Molarity :

Answer:

B

Explanation:

Answer:

See explanation

Explanation:

If we look at the models, we will see that the three fluorine atoms in CF3COOH are attached to the carbon that is next to the -COOH group.

As a result of the electron withdrawing effect of the three fluorine atoms, CF3COOH  is much more acidic (104 times more acidic) than CH3COOH. This is reflected in the value of the Ka for each acid.

This electron withdrawing effect of the three fluorine atoms also stabilizes CF3COO- much more than CH3COO-.

Answer:

The steps in order are;

1. Obtain a 50-mL volumetric flask

2. Add approximately 10 mL of deionized water to the empty flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

The volume of the acetic acid to be added to the solution is 15 mL

Explanation:

The given steps are;

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

1. Obtain a 50-mL volumetric flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

2. Add approximately 10 mL of deionized water to the empty flask

The given parameters are;

The volume of the volumetric flask = 50-mL

The concentration of the final solution of acetic acid = 0.6 mg/L

The concentration of the stock solution = 2.0 mg/L

Let 'x' represent the volume of the stock solution added, we have;

2.0 mg/L·x + (50 - x)×0 = 0.6 mg/L × 50-mL

x = 0.6 mg/L × 50-mL/(2.0 mg/L) = 15 mL

The volume of the stock solution to be added, x = 15 mL

Answer:

it dies

Explanation:cause its too cold

Answer:

a mixture of molecules - Box f

atoms of a pure elementa metal - Box D

a solid compound - Box C

a mixture of elements - Box A

Explanation:

Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.