Mean of eight observations is 25. If one observation 11 is excluded , find the mean of the remaining.​

Answer:

A sample size of 68 should be anticipated using.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Experience suggests that a reasonable estimate for the population standard deviation is 15

This means that [tex]\sigma = 15[/tex]

What minimum sample size should be anticipate using?

Margin of error at most 3, which means that the sample size is n when M = 3. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]3 = 1.645\frac{15}{\sqrt{n}}[/tex]

[tex]3\sqrt{n} = 1.645*15[/tex]

Simplifying both sides by 3:

[tex]\sqrt{n} = 1.645*5[/tex]

[tex](\sqrt{n})^2 = (1.645*5)^2[/tex]

[tex]n = 67.7[/tex]

Rounding up

A sample size of 68 should be anticipated using.

Answer:

5

Step-by-step explanation:

Answer:

Its def 5, My calculations are never wrong

Answer:

286.94 cm

Step-by-step explanation:

Data:

             Area = 8,607

             b1 = 105

             b2 = 123

      Area = 1/2 * (b1 + b2) * h

      h = 2 * Area/b1 + b2

      h = 2 * 8,607/105 + 123

     h = 286.94 cm

I'm not sure if it's right but that's what my calculator gave me.

Answer:

Step-by-step explanation:

Half of the animals are cats. If they take in 5 cats, then the total number of animals is 2×5 = 10.

If they take in 8 animals, the number of cats is ½ of 8 = 4.

If they take in 6 cats, then the total number of animals is 2×6 = 12.

If they take in 16 animals, the number of cats is ½ of 16 = 8.

Answer:

y=-1/3+4

Step-by-step explanation:

y=mx+b

mx=slope

b=y intercept

Answer:

None

Step-by-step explanation:

2(x + 10) - 17 = 2x - 2

simplify:

2x + 20 - 17 = 2x - 2

2x + 3 = 2x - 2

subtract 3 from both sides of the equation:

2x = 3x -5

no solution

Answer:

74

Step-by-step explanation:

100+75+70+x= 360° (sum of interior angles of quadrilateral)

x= 360-245= 115°

Answer:

Mr. Chan's total account receivable is of $212,500.

Step-by-step explanation:

$85,000 this month this represents 40% of our receivables

This means that 85000 is 40% = 0.4 of the receivables, which is x.

What is mr. Chan's total account receivable?

We have to find x

[tex]0.4x = 85000[/tex]

[tex]x = \frac{85000}{0.4}[/tex]

[tex]x = 212500[/tex]

Mr. Chan's total account receivable is of $212,500.

Answer:

[tex]x \ge 0[/tex]  

[tex]y \ge 0[/tex]

[tex]x + y \le 9[/tex]

[tex]8 - x \ge 0[/tex]

[tex]3 - y \ge 0[/tex]

[tex](8 - x) + (3 - y) \le 6[/tex]

Step-by-step explanation:

Given

x = Cars from Baltimore to Trenton

y = Cars from Baltimore to Philadelphia

Required

Write out 6 inequalities

First, 0 or more cars must be shipped to both locations

So:

[tex]x \ge 0[/tex]

[tex]y \ge 0[/tex]

Considering the warehouse in Baltimore.

(1) The warehouse can not ship more than the number of car it has (9).

So:

[tex]x + y \le 9[/tex]

Considering the warehouse in New York.

(1) After shipping cars to Trenton and Philadelphia, the warehouse will have 0 or more cars.

So:

[tex]8 - x \ge 0[/tex] --- To Trenton

[tex]3 - y \ge 0[/tex] --- To Philadelphia

(2) The warehouse cannot send out more than 6.

So:

[tex](8 - x) + (3 - y) \le 6[/tex]

So, the inequalities are:

[tex]x \ge 0[/tex]

[tex]y \ge 0[/tex]

[tex]x + y \le 9[/tex]

[tex]8 - x \ge 0[/tex]

[tex]3 - y \ge 0[/tex]

[tex](8 - x) + (3 - y) \le 6[/tex]

Answer:

Coefficient is your answer

Answer:

3 is a coefficient

Step-by-step explanation:

a constant is a number without a variable and that is unchanging

3 has the variable w attached to it and will change with the value of w

hope this helps <3

Answer:

B

Step-by-step explanation:

Both triangles are similar. The similarity ratio between AB and EF is 4, which must mean that FG is BC (60)/4. The area of a rectangle is base x height -> 6.25 x 15 = 93.75 square cm

Hope this helps!

Answer:

-4x + 7x - 2y + 7y =

3x + 5y

Step-by-step explanation:

Hope that this helps :)

Answer: See explanation

Step-by-step explanation:

You didn't specify the equations but let me solve the question.

55% of 80.

The above statement simply means that you need to multiply 55% by 80. This will be:

= 55% of 80

= 55/100 × 80

= 0.55 × 80

= 44

Therefore, 55% of 80 is 44

Based on your question, any other equation that doesn't give 44 as an answer cannot be used to answer the question.

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of ​35 lb.

This means that [tex]\mu = 160, \sigma = 35[/tex]

Sample of 10:

This means that [tex]n = 10, s = \frac{35}{\sqrt{10}} = 11.07[/tex]

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.​

This is 1 subtracted by the pvalue of Z when X = 158. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{158 - 160}{11.07}[/tex]

[tex]Z = -0.18[/tex]

[tex]Z = -0.18[/tex] has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be​ safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

there is not such thing as an I axis, but I will show you what happens for both x and y axis so you can fill out the assignment with the correct information.

IF you meant flipping over the x axis, then the dot will go from top to bottom, bottom to up, the x position won't change only its height(y position)

This meant that for reflecting across the x axis, (x,y)->(x,-y)

For y axis its the opposite, just flipping to the side.

This meant that for reflecting across the y axis, (x,y)->(-x,y)

Answer:hamburger

Hamburger

Step-by-step explanation:hamburger

Hamburger

Answer:

Maybe 7.

Step-by-step explanation:

Okay, the answer could be difficult to find but if you look at the x-axis and also y-axis it would be very easy and not complicated.

Answer: circle

Step-by-step explanation:

The set of points on a given plane which is equidistant from a fixed point that is called the center​ simply describes a circle.

We should note that the straight line that goes through the centre of a circle is referred to as the diameter while half of the diameter is the radius which is drawn from the center of the circle.

Answer:

12 quarts 24 pints

Step-by-step explanation:

change all measurements to gallons and solve.

1 quart= 2 pints

1 galllon = 8 pints

Answer:

12 quarts 24 pints

Step-by-step explanation:

change all measurements to gallons and solve.

1 quart= 2 pints

1 gallon = 8 pints

Answer:

0.7

Step-by-step explanation:

2,3,4,6,8,9,10 are the possible choices.

∴P(even no. or multiple of 3)

= 7/10

Answer:

7/10 or 70%

Step-by-step explanation:

1     no

2     yes

3     yes

4     yes

5     no

6     yes

7     no

8     yes

9     yes

10    yes

7/10 are even or multiples of 3, therefore you have a 70% chance of drawing one of them

Answer:

1.13

Step-by-step explanation:

Edge 2021 hope this helps

Answer:

200

Step-by-step explanation:

pi · radius · height

3.14 · 8 · 25 = 200

extra : i used symbolab.com :)

Answer:

If Jenny gives her brother 28 marbles, they will have 59 marbles each.

Step-by-step explanation:

The key to finding this answer is a mean, or average. Find it for the number of marbles:

[tex]\text{Mean}=\frac{87+31}{2}= \frac{118}{2}=59 \text{ marbles}[/tex]

So, on average, each one should have 59 marbles.

Finally, to find out how many marbles Jenny should give to her brother, subtract the average (59 marbles) from her count:

[tex]87-59=28 \text{ marbles}[/tex]

This means Jenny would give up 28 of her marbles to her brother.

Answer:

answer is third,hope i helped u

it looks correct to me

ps. i hate savvas realize

Answer:

1975------ 4.8%

1990 ------ 11.48%

1985 ------ 8.51%

Step-by-step explanation:

Given

[tex]P(t) = 0.04t + 4.6[/tex] if 0 ≤ t < 10

[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex] if 10 ≤ t ≤ 30

Where

t:=0 implies year = 1970

Solving (a): Beginning of 1975.

First, we calculate the value of t

[tex]t = 1975 - 1970[/tex]

[tex]t = 5[/tex]

This falls in the range: 0 ≤ t < 10

So:

[tex]P(t) = 0.04t + 4.6[/tex]

[tex]P(5) = 0.04 * 5 + 4.6[/tex]

[tex]P(5) = 4.80[/tex]

Solving (b): Beginning of 1990.

[tex]t = 1990 - 1970[/tex]

[tex]t = 20[/tex]

This falls in the range: 10 ≤ t ≤ 30

So:

[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex]

[tex]P(20) = -0.01005*20^2 + 0.945*20 - 3.4[/tex]

[tex]P(20) = 11.48[/tex]

Solving (c): Beginning of 1985

[tex]t = 1985 - 1970[/tex]

[tex]t = 15[/tex]

This falls in the range: 10 ≤ t ≤ 30

So:

[tex]P(t) = -0.01005t^2 + 0.945t - 3.4[/tex]

[tex]P(15) = -0.01005*15^2 + 0.945*15 - 3.4[/tex]

[tex]P(15) = 8.51375[/tex]

[tex]P(15) = 8.51[/tex]