Mean, Fractiles, median, and mode are called the measures of central tendency

Answer: 30.6 km away

Step-by-step explanation:

The main thing this problem requires is Pythagoras' theorem. So set the problem up by marking the airport as (0,0) on a graph. Then move 19 units to the right, and 24 units down and make a point. Now you have the two short lengths of a right-angle triangle, so all that's left is to solve for the hypotenuse. So using the formula [tex]a^{2} + b^{2} = c^{2}[/tex] you would end up with [tex]19^{2} + 24^{2} =c^{2}[/tex]. Then you get: 361+576=[tex]c^{2}[/tex]

solve for c and you get about 30.6 km!

Hope this helps!

The illustration of p - q and p + (-q) using a number line is added as an attachment

From the question, we have the following parameters that can be used in our computation:

p - q

Also, we have

p + (-q)

The above expressions mean that

To add two numbers (positive and negative), we can start from a point p, and then count backwards on the number line in q terms

Using the above as a guide, we have the following:

The illustration using a number line is added as an attachment

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Answer:

Company policies help employees to carry out their daily operations. - Yes, part of internal control accounting.

Bank reconciliation needs to be prepared for verification. - Yes, part of internal control accounting.

The organization's financial data in the computer should be in password-protected files. - Yes, part of internal control accounting.

Step-by-step explanation:

The ordered pairs representing the amount of money left after playing variable number of games is :

(Number of games played, Amount of money left)

(0, 8)

(1, 6)

(2, 4)

(3, 2)

(4, 0)

Ordered pairs gives a tabular description of data as the values of two or more variables change.

Here, the amount Gabe has before playing a game is $8 and the cost per game is $2 .

Hence, the amount he has left decreases by $2 for every increase in number of games played.

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Answer:

Do you wish for the mistake to be pointed out? If so, can you please provide the dot plot so I can answer this question?

Step-by-step explanation:

The solution is, simplification of the expression is; 71.19.

Here, we have,

the given expression is:

(5/2)^4/2 * (3/2)^6

=(5/2)^2 * (3/2)^6

as we know that, 4/2 = 2.

now, we have,

(5/2)^2 * (3/2)^6

=5²/2² ^ 3⁶/2⁶

= 5² * 3⁶ / 2² * 2⁶

=5² * 3⁶  / 2 ^ (2+6)

=5² * 3⁶  / 2 ^8

=25 * 729/ 256

=18225/ 256

=71.19

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Answer:

5/12

Step-by-step explanation:

add 12 y to both sides:

5x = 24 + 12y

subtract 24 from both sides:

12y = 5x - 24

divide all by 12:

y = (5/12)x - 2.

slope is the number in front of x.

slope is (5/12).

i) The capacities of different vessels which completely fill P vessel with exact number of fillings are:

(ii) The capacities of different vessels which completely fill Q vessel with exact number of fillings are:

One vessel of 18 I

Two vessels of 9 I each

Three vessels of 6 I each

Six vessels of 3 I each

Nine vessels of 2 I each

Eighteen vessels of 1 I each

(iii) The common capacities of vessels which completely fill P as well as Q vessels with exact number of fillings are:

Two vessels of 6 I each

Three vessels of 4 I each

Six vessels of 2 I each

Twelve vessels of 1 I each

(iv) The greatest capacity of vessel that completely fills P as well as Q vessels with exact number of fillings is 6 I.

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The rule for this translation. and the coordinates of the image point are  (x, y) = (x + 4, y - 5); (7, -6)

From the question, we have the following parameters that can be used in our computation:

translated to the right 4 units and down t units

Mathematically, this can be expressed as

(x, y) = (x + 4, y - 5)

Given that

A = (3, -1)

And, we have

(x, y) = (x + 4, y - 5)

This means that

A' = (3 + 4, -1 - 5)

Evaluate

A' = (7, -6)

So, the image point is A' = (7, -6)

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Question

ABC is translated 4 units to the right and 5 units down. Answer the questions to find the coordinates of A after the translation.

A = (3, –1)

1. The balances for each type of investment at the end of the third year are:

2. The total gain from all of the investments combined is $4,150.39.

a. Treasury bond:

Balance = Principal * (1 + (interest rate/100))^time

Balance = $12,000.00 * (1 + (5.35%/100))³

Balance = $13,964.18

CD:

Balance = Principal * (1 + (interest rate/100))^time

Balance = $3,000.00 * (1 + (4.75%/100))³

Balance = $3,429.57

Stock plan:

Principal = 0.3 * $30,000.00 = $9,000.00

Year 1: Increase of 9%, so balance = $9,000.00 * (1 + (9%/100)) = $9,810.00

Year 2: Decrease of 5%, so balance = $9,810.00 * (1 - (5%/100)) = $9,319.50

Year 3: Increase of 7%, so balance = $9,319.50 * (1 + (7%/100)) = $9,973.02

Savings account:

Balance = Principal * (1 + (interest rate/100))^time

Balance = $6,000.00 * (1 + (3.90%/100))³

Balance = $6,783.62

b. Treasury bond: Gain = $13,964.18 - $12,000.00 = $1,964.18

CD: Gain = $3,429.57 - $3,000.00 = $429.57

Stock plan: Gain = $9,973.02 - $9,000.00 = $973.02

Savings account: Gain = $6,783.62 - $6,000.00 = $783.62

Total gain from all investments combined = $1,964.18 + $429.57 + $973.02 + $783.62 = $4,150.39

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You saved $30,000.00 and want to diversify your monies. You invest 40% in a Treasury bond for 3 years at 5.35% APR compounded annually. You

place 10% in a CD at 4.75% APR for 3 years compounded annually. 30% you invest in a stock plan and the remainder is in a savings account at

3.90% APR compounded annually. The stock plan increases 9% the first year, decreases in value by 5% the second year, and increases by 7% the

third year.

1. What are the balances for each type of investment at the end of the third year?

2. What is your total gain from all of the investments combined?

After considering all the given data we conclude that the measure of m∠E is 54.46° under the condition that ADEF is a right angled triangle.

We already know that ADEF is a right angled triangle having sides EF = 6 and FD = 4, we can apply the Pythagorean theorem to evaluate the length of the hypotenuse AD.
AD = √(6² + 4²)
= √52)
≈ 7.21
Now we can apply the sine function to find the measure of angle E.
sin(E) = opposite/hypotenuse = EF/AD
E = arcsin(EF/AD)
≈ 54.46°
Therefore,  m∠E  ≈ 54.46°.
The Pythagorean Theorem is considered a fundamental relation in the context of Euclidean geometry comparing the three sides of a right triangle.
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Ans4863

Step-by-step explanation:

Answer:3

Step-by-step explanation:

subtract 3 from 3 and repeat on the other side of the equal sign. So 6 minus 3 equals 3.

To solve for f, we can rearrange the equation:

1975f = t1758 + Q2

First, we can isolate f by dividing both sides of the equation by 1975:

f = (t1758 + Q2) / 1975

So the final answer is:

f = (t1758 + Q2) / 1975

Answer:

Let x be the amount invested at 9% and y be the amount invested at 6%

.According to the problem:

x + y = 11,335 ----(1) (the total amount  invested is $11,335)0.09x - 0.06y = 865.35 ----(2) (the interest earned from the amount invested at 9% exceeds the interest earned from the amount invested at 6% by $865.35)

We can use these two equations to solve for x and y.

Multiplying equation (1) by 0.06, we get

:0.06x + 0.06y = 680.10 ----(3)

Subtracting equation (3) from equation (2), we get:

0.03x = 185.25

x = 6,175

Substituting x = 6,175 into equation (1), we get:

y = 5,160

Therefore, $6,175 is invested at 9% and $5,160 is invested at 6%.

Step-by-step explanation:

The required probability that a student is taking calculus or French, rounded to two decimal places, is 0.40.

The probability that a student is taking calculus or French is calculated by adding the number of students taking calculus and the number of students taking French and then subtracting the number of students taking both calculus and French. This gives us the number of students taking either calculus or French. We then divide this number by the total number of students, which is 100.

So, the number of students taking either calculus or French is 27 + 26 - 13 = 40.

The probability that a student is taking either calculus or French is 40 / 100 = 0.40 = 40%.

Therefore, the probability that a student is taking calculus or French, rounded to two decimal places, is 0.40.

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Jodi will need 10 half-cup measurements of flour to make 2 batches of cookies.

To double the recipe, Jodi needs to multiply the amounts of each ingredient by 2.

The original recipe calls for 2½ cups of flour. Doubling this amount gives:

2½ cups * 2 = 5 cups of flour

We may divide the total amount of flour required (5 cups) by the quantity in each 12-cup measurement to get the number of 1-1/2 cups Jodi needs.

5 cups / ½ cup = 10

Therefore, Jodi will need 10 half-cup measurements of flour to make 2 batches of cookies.

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$1356.52 is the cost price of the article.

To find the cost price of the article, we can utilize the concept of calculating the original amount based on a percentage increase.

Let's assume the cost price of the article is "x" dollars.

The trader gained a 15% interest, which means the selling price is 115% of the cost price. In other words, the selling price is 115% of "x".

To calculate the selling price, we can set up the following equation:

115% of x = 1560

To convert the percentage to a decimal, we divide it by 100:

1.15 * x = 1560

Now we can solve for x by dividing both sides of the equation by 1.15:

x = 1560 / 1.15

Using a calculator, we find:

x ≈ 1356.52

Therefore, the approximate cost price of the article is $1356.52.

This means that the trader purchased the article for around $1356.52 and then sold it for $1560.00, resulting in a 15% gain.

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The reduced row echelon form of the matrix is:

[tex]\left[\begin{array}{ccc}-1144/259&\\-321/259\\25/74\end{array}\right][/tex]

Given the matrix below

[tex]\left[\begin{array}{ccc}7&-1&-3 |-63\\0&-6&-2 |-20\\0&1&1 | 6\end{array}\right][/tex]

Divide the first row by 7:

[tex]\left[\begin{array}{ccc}1&-1/7&-3/7 |-9\\0&-6&-2 |-20\\0&1&1 | 6\end{array}\right][/tex]

Add 1/7 times the first row to the second row:

[tex]\left[\begin{array}{ccc}1&-1/7&-3/7 |-9\\0&-37/7&-17/7 |-107/7\\0&1&1 | 6\end{array}\right][/tex]

Add 3/7 times the second row to the first row:

[tex]\left[\begin{array}{ccc}1&0&-16/37 |-296/37\\0&-37/7&-17/7 |-107/7\\0&1&1 | 6\end{array}\right][/tex]

Add 17/37 times the second row to the third row:

[tex]\left[\begin{array}{ccc}1&0&-16/37 |-296/37\\0&-37/7&-17/7 |-107/7\\0&0&20/37 | 25/37\end{array}\right][/tex]

Multiply the third row by 37/20:

[tex]\left[\begin{array}{ccc}1&0&-16/37 |-296/37\\0&-37/7&-17/7 |-107/7\\0&0&1 | 25/74\end{array}\right][/tex]

Add 3/7 times the third row to the second row:

[tex]\left[\begin{array}{ccc}1&0&-16/37 |-296/37\\0&-37/7&0 |-321/259\\0&0&1 | 25/74\end{array}\right][/tex]

Add 16/37 times the third row to the first row:

[tex]\left[\begin{array}{ccc}1&0&0 |-1144/259\\0&-37/7&0 |-321/259\\0&0&1 | 25/74\end{array}\right][/tex]

Multiply the second row by -7/37:

[tex]\left[\begin{array}{ccc}1&0&0 |-1144/259\\0&1&0 |321/259\\0&0&1 | 25/74\end{array}\right][/tex]

This is the reduced row echelon form of the given matrix.

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a) Approximately 778.7 grams of thorium 234 will be left after 0.5 years.

b) Approximately 2.1 years will have passed when 115 grams of thorium 234 are left.

(a) To find the amount of thorium 234 left after 0.5 years, we can use the equation:

[tex]A_t = A_0 e^{(-10.498t)}[/tex]

where A₀ is the initial amount, which is 1000 grams, t is the time in years, and At is the amount after t years.

Substituting t = 0.5, we get:

[tex]At = 1000 e^{(-10.498\times0.5)} = 778.7 \ grams[/tex]

Therefore, approximately 778.7 grams of thorium 234 will be left after 0.5 years.

(b) To find the time at which 115 grams of thorium 234 will be left, we can use the same equation and solve for t:

[tex]A_t = A_0 e^{(-10.498t)[/tex]

Dividing both sides by A₀ and taking the natural logarithm of both sides, we get:

ln(At/A₀) = -10.498t

Substituting At = 115 grams and A₀ = 1000 grams, we get:

ln(115/1000) = -10.498t

Solving for t, we get:

t = (ln(115/1000)) / (-10.498) ≈ 2.1 years

Therefore, approximately 2.1 years will have passed when 115 grams of thorium 234 are left.

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The value of the car 4 years after it was purchased is  $16,270.86.

Depreciation is when the value of an asset declines with the passage of time as a result of wear and tear.

The equation that would be used to determine the value of car with the passage of time would be an exponential equation.

Value of the car after t years = [tex]p(1 -r)^{\frac{t}{3}[/tex]

Where:

Value of the car after 4 years  = [tex]41,000(1 -0.5)^{\frac{4}{3}[/tex] = $16,270.86

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The perimeter of the field is 4x + 6/(x + 1)(x - 1).

Given that a field has a width of 5/x²-1 and the length is 2/x+1,

We need to find the perimeter,

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle,

Perimeter of a rectangle = 2(l+w)

= 2(5/x²-1+2/x+1)

= 2((2(x-1)+5)/(x + 1)(x - 1)

= 4x + 6/(x + 1)(x - 1)

Hence the perimeter of the field is 4x + 6/(x + 1)(x - 1).

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Answer:

The correct answer is b) f^-1(n)= 4/-n-1 +1.

b

Step-by-step explanation:

I think parentheses are missing :

y = -4/(n-1)  - 1       switch n and y   then solve for y

n = -4/(y-1) - 1         add 1 to both sides of the equation

n+1 = - 4/(y-1)         multiply through by y -1

(y-1)(n+1) = - 4         divide through by (n+1)

y -1   = - 4/ (n+1)      add 1 to both sides

y = - 4/ (n+1 )  + 1     <=====this is the inverse function  y = -4/(n-1) -1

   equivalent to   4 / (-1-n)  + 1        by putting the ' - ' in the denominator

Answer:

[-infinity, 4]

Step-by-step explanation:

-9x + 3 >= -33
-9x >= -36

x<=4 (sign switched because of dividing both sides by a negative integer in an inequality)
Therefore, x is less than or equal to 4

[ - infinity, 4]

After considering the given data we conclude that the perimeter of the given swimming pool is 23 meters which is Option A.

The perimeter of a rectangle is evaluated by adding up all its sides. For the given case, we possess a rectangle with sides
a = 5m,
b = 8m,
c = 8m and
d = 2m.
Perimeter regarding the swimming pool is evaluated as
a + b + c + d
= 5m + 8m + 8m + 2m
= 23 meters
Hence the option regarding the question which satisfy the perimeter is Option A.
Perimeter the counted  measurement regarding the distance around the outside of a two-dimensional shape. In this system  the length of the outline or boundary of any two-dimensional geometric shape is defined as perimeter .
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The complete question is
If a = 5m, b = 8 m, c = 8 m, and d = 2 m, what is the perimeter of the swimming pool?
A.23 m
B. 32 m
C.29 m
D.34 m

The area under the curve over [0, 1] is 15.75.

To find the Riemann sum, divide [0, 1] into n equal subintervals of width Δx = 1/n.

Using the right endpoint, c = iΔx = i/n. The Riemann sum is:

Σ[f(c)Δx] = Σ[(21(i/n) + 21(i/n)³)(1/n)] from i=1 to n.

To find the area under the curve, take the limit as n→∞:

Area = lim(n→∞) Σ[(21(i/n) + 21(i/n)³)(1/n)].

Find the answer by using the method of definite integration.

Area = ∫(21x + 21x³)dx from 0 to 1 = [10.5x² + 5.25x⁴] from 0 to 1 = 10.5(1)² + 5.25(1)⁴ - 0 = 15.75.

The area under the curve over [0, 1] is 15.75.

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The value of f(2) is 40.5

The given function is f(x) = 1/x + 5[tex]x^3[/tex], and we need to find the value of f(2).

To do this, we substitute x=2 into the function and simplify:

f(2) = 1/2 + 5([tex]2^3[/tex])

= 1/2 + 5(8)

= 1/2 + 40

= 40.5

Therefore, the value of f(2) is 40.5.

The function f(x) has two parts: 1/x and 5[tex]x^3[/tex]. The first part of the function, 1/x, is a decreasing function that approaches zero as x gets larger. The second part of the function, 5[tex]x^3[/tex], is an increasing function that grows rapidly as x gets larger.

When we substitute x=2 in the function f(x), we get f(2) = 1/2 + 5([tex]2^3[/tex]) = 40.5. This means that at x=2, the value of the function is 40.5.

This result tells us that the function f(x) has a positive value at x=2. Moreover, since the second part of the function grows faster than the first part, the value of the function f(x) will increase as x gets larger. This means that as x increases, the value of f(x) will increase more and more rapidly.

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Answer:

113.1 in²

Step-by-step explanation:

A = 2πrh + 2πr²

r = 2 in

h = 7 in

A = 2π(2)(7) + 2π2² = 113.1 in²