Matthew decided to bake cupcakes for the school fundraiser. He wants to make 2 dozen cupcakes--one dozen strawberry and one dozen chocolate. He needs 2 1/4 cups of flour for the strawberry cupcakes and 2 1/3 cups of flour for the chocolate cupcakes, but he only has 4 cups of flour. Which two expressions could be used to correctly determine the amount of flour, in cups, Matthew still needs to bake his two dozen cupcakes? 2 part what is the total amount of flour, in cups, Mathew still needs for his cupcakes? NO LINK

9514 1404 393

Answer:

  7x^3 +11x^2 -5x -8

Step-by-step explanation:

Combine like terms.

  (4x^3+6x^2+2x^2-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +2 +3)x^2 +(-5)x + (-3 -5)

  = 7x^3 +11x^2 -5x -8

_____

Noting that the first expression contains two x^2 terms, we wonder if you actually want the sum ...

  (4x^3+6x^2+2x-3) + (3x^3+3x^2-5x-5)

  = (4 +3)x^3 +(6 +3)x^2 +(2 -5)x +(-3 -5)

  = 7x^3 +9x^2 -3x -8

Answer:

too much salt will not bring taste to the cup cakes

Step-by-step explanation:

Answer:

I think C. is it

Step-by-step explanation:

Answer:

0.1771

Step-by-step explanation:

total number of cards in a deck : 52

number of face card per suite : 3

total number of suites : 4 (hearts, clubs, diamonds, spades)

3 * 4 = total number of face cards

12/52 = 0.23 = probability of drawing a face card

remaining card are non face cards

52-12 = 40

40 non face cards

40/52 = 0.77 = probability of drawing a non face card

probability of drawing a face card followed by a non face card

multiply probabilities together to find combined probability

probability of drawing a face card * probability of drawing a non face card

= 0.23 * 0.77

= 0.1771

The mean, range, and median will vary if the outlier is eliminated. Options A, B, and C are correct.

The arithmetic mean is a term used to describe the average. It's the ratio of the total number of observations to the sum of the observations.

The data set is;

1,6,8,8,8

Outliers in a dataset or graph are extreme values that stand out significantly from the main pattern of values.

There is an aberration in the graph below, on the far left. The value in January is much lower than the value in the other months.

If the outlier is removed mean, range, and median will changes.

Hence options A, B and C are correct.

To learn more about mean refer:

https://brainly.com/question/13451489

#SPJ2

Answer:

7 yards

Step-by-step explanation:

Answer:

A. A triangle can be equilateral and obtuse at the same time

Step-by-step explanation:

All angles in an equilateral triangle are 60° therefore they cannot be above 90° and less than 180°

Answer:

AB = 9

Step-by-step explanation:

Here is a simple case of a proportion.

We see that:

3:4

x:12

what can we do to make 4 into 12?

we multiply it by 3

so we do the same to 3

3*3=9

Answer:

The half-life of this radioactive substance is of 8.6 months.

Step-by-step explanation:

Exponential decay of an amount:

The equation that models an amount after t units of time, subject to exponential decay, is given by:

[tex]A(t) = A(0)(1-r)^t[/tex]

In which A(0) is the initial amount and r is the decay rate, as a decimal.

A radioactive substance decays to 30% of its original mass in 15 months.

This means that [tex]A(15) = 0.3A(0)[/tex]. We use this to find 1 - r.

[tex]A(t) = A(0)(1-r)^t[/tex]

[tex]0.3A(0) = A(0)(1-r)^{15}[/tex]

[tex](1-r)^{15} = 0.3[/tex]

[tex]\sqrt[15]{(1-r)^{15}} = \sqrt[15]{0.3}[/tex]

[tex]1 - r = (0.3)^{\frac{1}{15}}[/tex]

[tex]1 - r = 0.9229[/tex]

So

[tex]A(t) = A(0)(0.9229)^t[/tex]

Determine the half-life of this radioactive substance to the nearest tenth.

This is t for which A(t) = 0.5A(0). So

[tex]A(t) = A(0)(0.9229)^t[/tex]

[tex]0.5A(0) = A(0)(0.9229)^t[/tex]

[tex](0.9229)^t = 0.5[/tex]

[tex]\log{(0.9229)^t} = \log{0.5}[/tex]

[tex]t\log{0.9229} = \log{0.5}[/tex]

[tex]t = \frac{\log{0.5}}{\log{0.9229}}[/tex]

[tex]t = 8.6[/tex]

The half-life of this radioactive substance is of 8.6 months.

Answer:

The probability of you choosing S would be a 1/11 chance or a 0.0909090909 chance.

Answer:

1 / 11

Step-by-step explanation:

there are 11 letters in candlesick so 11 possibilities and 1 S which is 1 out of 11 or 1 / 11.

Hope this helps ( :

Answer:

Candice

Step-by-step explanation:

Answer:

The distance between the two towns is of 1000 km.

Step-by-step explanation:

This question is solved by proportions, using a rule of three.

We have that:

3 cm represents a distance of 400 km.

What is the distance represented by 7.5 cm?

3 cm - 400 km

7.5 cm - x km

Applying cross multiplication:

[tex]3x = 400*7.5[/tex]

[tex]x = \frac{400*7.5}{3}[/tex]

[tex]x = 1000[/tex]

The distance between the two towns is of 1000 km.

Answer:

what is the question?

Step-by-step explanation:

Answer:

i answered

Step-by-step explanation:

The best i could find out is 450p

The degree for 7pi/4 is : 315°

Answer:

48

Step-by-step explanation: 1 foot is 12 inches. Since the feet are going up by ones, you can say 1=12, 2=24 (+12), 3=36(+12), 4=48(+12)

Hope this helps

Answer and Step-by-step explanation:

The answer is 48.

Each value of y is a multiple of 12, so for when there is 4 feet, you multiply 12 by 4 to get 48.

For when it is 1 foot, you multiply 12 by 1 to get 12.

For when it is 2 feet, you multiply 12 by 2 to get 24.

For when it is 3 feet, you multiply 12 by 3 to get 36

For when it is 5 feet, you multiply 12 by 5 to get 60.

If you were to continue, the y-values (aka the inches) will always be a multiple of 12.

#teamtrees #PAW (Plant And Water)

Answer:

n = [tex]5\frac{4}{5}[/tex]

Step-by-step explanation:

You obviously have to solve for n

Answer:

57.5

Step-by-step explanation:

The expected frequency of West Campus and Failed :

Let :

Failed = F

East Campus = C

West Campus = W

Passed = P

Frequency of FnW :

[(FnE) + (FnW) * (PnW) + (FnW)] / total samples

[(52 + 63) * (63 + 37)] / 200

[(115 * 100)] / 200

11500 / 200

= 57.5

n(Failed n East campus)

Answer:

57.5

Step-by-step explanation:

Got it right on the test.

Answer:

[tex]0.4138[/tex]

Step-by-step explanation:

Given

[tex]x \to storm[/tex]

[tex]\mu_x = 1.0[/tex]

[tex]y \to fire[/tex]

[tex]\mu_y = 1.5[/tex]

[tex]z \to theft[/tex]

[tex]\mu_z = 2.4[/tex]

Let the event that the above three factors is greater than 3 be represented as:

[tex]P(A > 3)[/tex]

Using complement rule, we have:

[tex]P(A > 3) = 1 - P(A \le 3)[/tex]

This gives:

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

-----------------------------------------------------------------------------------------------------------

The exponential distribution formula of each is:

[tex]P(x \le k) = 1 - e^{-\frac{k}{\mu}}[/tex]

So, we have:

[tex]k = 3; \mu_x = 1[/tex]

[tex]P(x \le 3) = 1 - e^{-\frac{3}{1}} = 1 - e^{-3} = 0.9502[/tex]

[tex]k=3; \mu_y = 1.5[/tex]

[tex]P(y \le 3) = 1 - e^{-\frac{3}{1.5}} = 1 - e^{-2} = 0.8647[/tex]

[tex]k = 3; \mu_z = 2.4[/tex]

[tex]P(z \le 3) = 1 - e^{-\frac{3}{2.4}} = 1 - e^{-1.25} = 0.7135[/tex]

-----------------------------------------------------------------------------------------------------------

[tex]P(A > 3) = 1 - P(\{x \le 3\}\ n\ \{y \le 3\}\ n \{z \le 3\}\)[/tex]

[tex]P(A > 3) = 1 - (0.9502 * 0.8647 *0.7135)[/tex]

[tex]P(A > 3) = 1 - 0.5862[/tex]

[tex]P(A > 3) = 0.4138[/tex]

Answer:

1 = 100% probability that a person will wait for more than 33 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean waiting time is 55 minutes and the variance of the waiting time is 11.

This means that [tex]\mu = 55, \sigma = \sqrt{11}[/tex]

Find the probability that a person will wait for more than 33 minutes.

This is 1 subtracted by the p-value of Z when X = 33. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{33 - 55}{\sqrt{11}}[/tex]

[tex]Z = -6.63[/tex]

[tex]Z = -6.63[/tex] has a p-value of 0.

1 - 0 = 1

1 = 100% probability that a person will wait for more than 33 minutes.

Answer:

a) 120 possible experimental runs

b) 8 possible experimental runs

c) 0

Step-by-step explanation:

a. For the experiment, there are 6 different temperatures (T), 5 different pressures (P), and 4 different catalysts (C). We can find the total number of combinations using the product rule.

N = T × P × C

N = 6 × 5 × 4 = 120

b) If we use only the lowest temperature, we have T = 1, and if we use the two lowest pressures, we have P = 2. We can find the total number of combinations using the product rule.

N = T × P × C

N = 1 × 2 × 4 = 8

c) If we perform 5 experimental runs with 4 possible catalysts, it is not possible to use a different catalyst each time. At least, 1 catalyst must be repeated twice. Then, the event "a different catalyst is used on each run" has a probability of 0.

Answer:

Step-by-step explanation:

11 no

46+4x=90 degree(being perpendicular)

4x=90-46

x=44/4

x=11

12 no

They are complementary angles

6 no

angle B+27=180 degree(being straight line)

angle B=180-27

angle B=153

10 no

angle 38 +angle DFE=180 degree(being supplementary)

angle DFE=180-38

angle DFE=142 degree

5 no

They are vertically opposite angles.

7 no

angle AGF and angle CGD (because they have common arm and vertex)

Answer:

Solution given:

11.4x+46=90[being right angle]

4x=90-46

x=44/4

x=11

12.

Complementary angles

5.

vertical

6.

<ABD+27=180°[linear pair]

<ABD=180-27

<ABD=153° degree

10.

<DFE+38=180[being supplementary]

<DFE=180-38

<DFE=142 degrees.

7.

angle DGE and angle DGC

8.

<AGB and <AGE

Answer:

SA = 484 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the larger rectangular prism + (surface area of the smaller rectangular prism - base area of the smaller rectangular prism)

✔️Surface are of the larger rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 7 cm

H = 12 cm

S.A = 2(7*7 + 7*12 + 7*12) = 434 cm²

✔️Surface are of the smaller rectangular prism = 2(LW + LH + WH)

L = 7 cm

W = 2 cm

H = 2 cm

S.A = 2(7*2 + 7*2 + 2*2) = 64 cm²

✔️Base area of the smaller rectangular prism = L*W

L = 7 cm

W = 2 cm

Area = 7*2 = 14 cm²

✅Surface area of the composite figure = 434 + (64 - 14)

= 434 + 50

= 484 cm²

Answer:

Step-by-step explanation:

8 is not a function

9 is a function

10 is a function

Answer:

8.4%

Step-by-step explanation:

let x = interest rate

55,000(1 + x)^16 = 200,000

divide both sides by 55,000

(1 + x)^16 = 3.636

find the invese of 16

1 + x = 1.084

x = 0.084

x = 8.4

Answer:

Length of Line AC = 26 units

Step-by-step explanation:

Given:

Line AC = [3x + 1] + 8

Line BC = [x - 2] + 2

Find:

Length of Line AC

Computation:

Line AB ║ Line L

So,

Using Mid-Point theorem;

[3x + 1] / 8 = [x - 2] / 2

2[3x + 1] = 8[x - 2]

6x + 2 = 8x - 16

8x - 6x = 16 + 2

2x = 18

x = 9

So,

Line AC = [3x + 1] + 8

Line AC = [3(9) + 1] + 8

Line AC = [27 + 1] + 8

Line AC = 28 + 8

Length of Line AC = 26 units

Answer: I asked my teacher, she said it is c

Step-by-step explanation:

Answer:

yes it's c

have a great day

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is [tex]s = \frac{6}{\sqrt{n}}[/tex] and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 78 and a standard deviation of 6

This means that [tex]\mu = 78, \sigma = 6[/tex]

Samples of n:

This means that the standard deviation is:

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{n}}[/tex]

What are the mean, standard deviation, and shape of the distribution of x-bar for n?

By the Central Limit Theorem, the mean is 78, the standard deviation is [tex]s = \frac{6}{\sqrt{n}}[/tex] and the shape is approximately normal.

Answer:

y intercept: [tex]y = 1[/tex]

x intercept: [tex]x = -1[/tex] and [tex]x = -3[/tex]

Step-by-step explanation:

Given

The attached graph

Solving (a): The y intercepts

This is the point where [tex]x = 0[/tex]

From the attached graph, [tex]x = 0[/tex] when

[tex]y = 1[/tex]

Hence, the y intercept is 1

Solving (b): The x intercepts

This is the point where [tex]y = 0[/tex]

From the attached graph, [tex]y = 0[/tex] when

[tex]x = -1[/tex] and [tex]x = -3[/tex]

Hence, the x intercept are -1 and -3