What is the function of a
catalyst?
A. Build enzymes
B. Speed up chemical reactions
C. Regulate the function of an enzyme
I believe it is to speed up chemical reactions
A 0.750 M sample of phosphorus pentachloride decomposes to give phosphorus trichloride and chlorine gases.If the equilibrium concentration of PCl5 is 0.650M,what is the equilibrium constant for the reaction?
PCl5(g) --------> PCl3(g)+ Cl₂(g)
A) Keq = 0.0133
B) Keq = 0.0154
C) Keq = 0.133
D) Keq = 0.154
E) Keq = 65.0
Answer:
Explanation:
Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M
PCl₅(g) --------> PCl₃(g)+ Cl₂(g)
1 mole 1 mole 1 mole
Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M
PCl₃(g) and Cl₂(g) formed are .10 M and .10 M
Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]
= .10 M x .10 M / .65 M
= .0154
B ) is the correct choice .
During a laboratory experiment, 36.12 grams of Aboz was formed when O2 reacted with aluminum metal at 280.0 K and 1.4 atm. What was the volume of O2
used during the experiment?
30 2+ 4A1 -- 2AI2O3
8.70 liters
9.22 liters
10.13 liters
12.81 liters
Answer:
8.70 liters
Explanation:
3O₂+ 4Al → 2AI₂O₃First we convert 36.12 g of AI₂O₃ into moles, using its molar mass:
36.12 g ÷ 101.96 g/mol = 0.354 mol AI₂O₃Then we convert AI₂O₃ moles into O₂ moles, using the stoichiometric coefficients of the reaction:
0.354 mol AI₂O₃ * [tex]\frac{3molO_2}{2molAl_2O_3}[/tex] = 0.531 mol O₂We can now use the PV=nRT equation to calculate the volume, V:
1.4 atm * V = 0.531 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 280.0 KV = 8.708 LIn distillation,separation is achieved by difference in---
Answer:
relative volatility.
mark me brainliestt :))
Answer: in temperature
A 3L sample of an ideal gas at 178 K has a pressure of 0.3 atm. Assuming that the volume is constant, what is the approximate pressure of the gas after it is heated to 278 K?
Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
Explanation:
Given: [tex]T_{1}[/tex] = 178 K, [tex]P_{1}[/tex] = 0.3 atm
[tex]T_{2}[/tex] = 278 K, [tex]P_{2}[/tex] = ?
According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.
Formula used to calculate the pressure is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\[/tex]
Substitute the values into above formula is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{0.3 atm}{178 K} = \frac{P_{2}}{278 K}\\P_{2} = 0.468 atm[/tex]
Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
If the plant population decreased, the amount of carbon in the atmosphere would _______.
Increase
Stay the same
Decrease
Answer:
increase answer
Explanation:
i hope that is right
how to solve x² in differential
Answer:
x² = mutiphy by them self
Explanation:
The blending together of some genes is called:
Answer:
its called molding
Explanation:
chemical properties of citric acid
Answer:
Citric Acid is a weak acid with a chemical formula C6H8O7.
...
Properties of Citric Acid – C6H8O7.
C6H8O7 Citric Acid
Molecular Weight/ Molar Mass 192.124 g/mol
Density 1.66 g/cm³
Boiling Point 310 °C
Melting Point 153 °C
Hope it helps❤️
What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
(4 Points)
Ksp=[Ca⁺²] x [C₂O₄⁻²]
Ksp=[Ca⁺²]² x [C₂O₄⁻²]
Ksp=[Ca⁺²]⁴ x [C₂O₄⁻²]
Ksp=[Ca⁺²] x [C₂O₄⁻²]²
Answer:
Ksp = [Ca⁺²] × [C₂O₄⁻²]
Explanation:
Step 1: Write the balanced reaction for the dissociation of calcium oxalate
CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)
Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate
The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.
Ksp = [Ca⁺²] × [C₂O₄⁻²]
How many grams of carbon are In 25 g of CO2?
Answer: almost 7g
Explanation: 25 grams of carbon dioxide contains 6.818 grams of carbon.
3.05 moles of H2O is equivalent to (blank amount) molecules of water.
Show your work.
Answer:
[tex]1 \: mole \: = 6.02 \times {10}^{23} \: molecules \\ 3.05 \: moles \: = (3.05 \times 6.02 \times {10}^{23} ) \: molecules \\ = 1.8361 \times {10}^{24} \: molecules[/tex]
Which of the following
describes the zone of the
ocean where no light reaches?
A. up to 200 meter depth and includes
photosynthetic plants, sea anemones,
sponges, crabs, and clams
B. the "twilight zone" between 200-1000
meters deep and includes whales and octopi
and little life
C. permanent darkness below 1000 meters
with bioluminescent bacteria, bottom
feeders, and angler fish
Answer:
Bathypelagic
54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.
Explanation:
The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.
Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.
What is Darkness?This is referred to the state of being dark as a result of absence of light in the area.
The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.
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Which molecule will have double bonds?
(4 Points)
Fluorine
Nitrogen
Hydrogen
Oxygen
Thermal energy naturally flows from _________ matter to _______ matter.
Answer:
Warmer
Cooler
Explanation:
Heterozygous- a person having two different alleles for a gene is also called
Answer:
heterozygous.
Explanation:
A genotype consisting of two different alleles of a gene for a particular trait (Aa). Individuals who are heterozygous for a trait are referred to as heterozygotes.
Enthalpy change is the
a. amount of energy absorbed or lost by a system as heat during a process at constant pressure.
b. entropy change of a system at constant pressure.
c. pressure change of a system at constant temperature.
d. temperature change of a system at constant pressure.
Answer:
I believe is A
Explanation:
Enthalpy change is the name given to the amount of heat evolved or absorbed in a reaction carried out at constant pressure.
what is an example of a change in genetic traits of an organism do to human affect
Answer:
A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.
Explanation:
What happens to an endothermic reaction when an equilibrium system is heated? (5 points)
a
The system shifts forward.
b
The system shifts backward.
c
The equilibrium does not shift to maximize the stress.
d
The equilibrium does not shift to restore original conditions.
Answer: a (the system shifts forward)
In which heating an endothermic reaction will cause the products to increase and the reactants to decrease.
When an equilibrium system is heated to an the endothermic reaction then,
The system shifts forward.So option A is correct one.
What factors affecting equilibrium reaction?The factors affecting equilibrium reaction are,
Temperature: If reaction is endothermic then on increasing temperature the reaction goes to forward direction. But the reaction is exothermic then the on increasing temperature, the reaction goes to backward direction.PressureConcentrationVolume What is endothermic reaction?The reaction in which energy is required for conversion of reactant to product is called endothermic reaction.
Learn about endothermic reaction
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The system we will be observing in this lab involves the cobalt(II) ion. This
ion can form two complexes, one with water and one with the chloride
ion (CI'). Below is a reaction showing the addition of chloride ions to the
cobalt - water complex.
Co(H2016 + Cl <--> COC142- + H2O
2+
pink
blue
What happened when HCl was added?
Answer:
See Explanation
Explanation:
In the equilibrium shown in the question,on the left hand side is a pink hexaaquacobalt II complex which is pink in colour. On the right hand side, we have a tetrachlorocobalt II complex which is blue in colour.
The equilibrium can be shifted from left to right by adding HCl (a source of chloride ions).
Hence, when HCl is added to the system, the equilibrium position is shifted to the right thereby yielding the blue solution of the tetrachlorocobalt II complex.
n-hexane boils at 68.7 oC at 1.013 bar and the heat of Vaporization is 28850
J/mol. Calculate Its Entropy ?
The concentration of citric acid (H3C6H5O7) in citric fruits ranges from 0.005 M to 0.30 M. Consider a 80.1 mL sample of pure lime juice with a citric acid concentration of 0.223 M. How many moles of citric acid are in the sample?
0.0179 citric acid
Explanation:
0.223 M citric = 0.223 mol citric/L
# mol citric = (0.223 mol citric/L)(0.0801L)
= 0.0179 mol citric acid
What is the pH of a 6.2 x 10-5 M NaOH solution?
Answer:
4.21Explanation:
The pH of a solution can be found by using the formula
[tex]pH = - log [ {H}^{+} ][/tex]
From the question we have
[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]
We have the final answer as
4.21Hope this helps you
In an experiment, a student wants to increase the rate of a reaction that involves gases. Which change to the reactants would accomplish this? Increase the volume to decrease pressure and to increase concentration. Increase the volume to increase pressure and to decrease concentration. Decrease the volume to decrease pressure and to increase concentration. Decrease the volume to increase pressure and to increase concentratio
Answer:
Decrease the volume to increase pressure and to increase concentration
Explanation:
A gaseous reaction is affected by the volume of the reactants. To increase the rate of the forward reaction, we need to ensure that the volume of the reactants is manipulated in such a way that the forward reaction is favored.
Thus, when the volume of reactants is decreased, the pressure increases.This increase in pressure has the same effect as increase in concentration. Hence, the rate of forward reaction increases.
What happens when energy interacts with carbon dioxide and methane in the atmosphere
Answer:
The correct answer is - heat the atmosphere near the surface of the earth.
Explanation:
There are several different types of greenhouse gases such as carbon dioxide, methane, CFC, and nitrous oxide. These gases absorbed energy comes from the sun.
The radiations that come from the vibrating molecules are absorbed by greenhouse gases such as carbon dioxide and methane that increase the temperature of the atmosphere near the earth's surface and heat near the Earth's surface. Without this effect, the atmosphere would be at freezing temperature or below, so it is a somewhat natural process.
A container holds 40.0 mL of nitrogen at 30° C and at a constant pressure.
Find its volume if the temperature increases to 80° C?
Answer:
The correct answer is - 46.60 mL.
Explanation:
To find the volume of the gas at its new increased temperature we need to use Charl Law that shows the direct relationship between Volume and Temperature while Pressure remains constant.
V1 = 40 ml
T1 = 30 degree C + 273 = 303 K
V2 = ?
T2 = 80 degree C + 273 = 353 K
Charl Equation is:
V 1/T 1 = V 2/ T 2
(V1) * (T2)/ T1= V2
placing value:
40*353/303 = V2
= 14120/303
Vf = 46.60 mL
At the start of a reaction, there are 0.0249 mol N2,
3.21 x 10-2 mol H2, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. If the equilibrium constant, K, for the reaction:
N2(g) + 3H2(g)= 2NH3(g)
is 1.2 at this temperature, decide whether the system is at equilibrium or not. If it is not, predict in which direction, the net reaction will proceed.
Answer:
Explanation:
The reaction is given as:
[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]
The reaction quotient is:
[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]
From the given information:
TO find each entity in the reaction quotient, we have:
[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]
[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]
[tex][N_2] = 0.006857[/tex]
[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]
[tex][H_2] = 9.17 \times 10^{-3}[/tex]
∴
[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]
However; given that:
[tex]K_c = 1.2[/tex]
By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]
The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.
At what temperature, in Celsius, will 88.0 g of Ne exert a pressure of 350. kPa in a
48.5 L container? NOTE: You must show your calculation on the attached scratch
paper, including which of the Gas Law formulas you used. *
Answer:
191 °C
Explanation:
We'll begin by calculating the number of mole in 88.0 g of Ne. This can be obtained as follow;
Mass of Ne = 88.0 g
Molar mass of Ne = 20 g/mol
Mole of Ne =?
Mole = mass /molar mass
Mole of Ne = 88 / 20
Mole of Ne = 4.4 moles
Next, we shall determine the temperature. This can be obtained as follow:
Mole of Ne = 4.4 moles
Pressure (P) = 350 KPa
Volume (V) = 48.5 L
Gas constant (R) = 8.314 KPa.L/Kmol
Temperature (T) =?
PV = nRT
350 × 48.5 = 4.4 × 8.314 × T
16975 = 36.5816 × T
Divide both side by 36.5816
T = 16975 / 36.5816
T = 464 K
Finally, we shall convert 464 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 464 K
T(°C) = 464 – 273
T(°C) = 191 °C
Thus, the temperature is 191 °C
Combustion of a 1.031-g sample of a compound containing only carbon, hydrogen,
and oxygen produced 2.265 g of CO2(g) and 1.236 g of H2O(g). What is the
empirical formula of the compound?
3 국
Molar masses in g/mol: CO2 = 44.01; H20 = 18.02; C = 12.01; H = 1.01
C3H50
Answer:
C₃H₈O
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1.031 g
Mass of CO₂ = 2.265 g
Mass of H₂O = 1.236 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen in the compound. This can be obtained as follow:
For carbon, C:
Mass of CO₂ = 2.265 g
Molar mass of CO₂ = 44.01 g/mol
Molar mass of C = 12.01 g/mol
Mass of C =?
Mass of C = molar mass of C / molar mass of CO₂ × mass of CO₂
Mass of C = 12.01/44.01 × 2.265
Mass of C = 0.618 g
For hydrogen, H:
Mass of H₂O = 1.236 g
Molar mass of H₂O = 18.02 g/mol
Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol
Mass of H =?
Mass of H = Molar mass of H₂ / Molar mass of H₂O × Mass of H₂O
Mass of H = 2.02/18.02 × 1.236
Mass of H = 0.139 g
For oxygen, O:
Mass of compound = 1.031 g
Mass of C = 0.618 g
Mass of H = 0.139 g
Mass of O =?
Mass of O = Mass of compound – (mass of C + mass of H)
Mass of O = 1.031 – ( 0.618 + 0.139)
Mass of O = 1.031 – 0.757
Mass of O = 0.274 g
Finally, we shall determine the empirical formula. This can be obtained as follow:
C = 0.618 g
H = 0.139 g
O = 0.274 g
Divide by their molar mass
C = 0.618 / 12.01 = 0.051
H = 0.139 / 1.01 = 0.138
O = 0.274 / 16 = 0.017
Divide by the smallest
C = 0.051 / 0.017 = 3
H = 0.138 / 0.017 = 8
O = 0.017 / 0.017 = 1
Therefore, the empirical formula of the compound is C₃H₈O
Based on the data provided, the empirical formula of the compound is C₃H₈O
What is empirical formula?The empirical formula of compound is its simplest formula showing the mole ratio of the elements in the compound.
First, the mass of carbon, hydrogen and oxygen in the compound is determined first as follows:
For carbon, C:
Mass of CO₂ = 2.265 g
Molar mass of CO₂ = 44.01 g/mol
Molar mass of C = 12.01 g/mol
Mass of C = 12.01/44.01 × 2.265
Mass of C = 0.618 g
For hydrogen, H:
Mass of H₂O = 1.236 g
Molar mass of H₂O = 18.02 g/mol
Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol
Mass of H = 2.02/18.02 × 1.236
Mass of H = 0.139 g
For oxygen, O:
Mass of compound = 1.031 g
Mass of C = 0.618 g
Mass of H = 0.139 g
Mass of O = Mass of compound – (mass of C + mass of H)
Mass of O = 1.031 – ( 0.618 + 0.139)
Mass of O = 0.274 g
To determine the empirical formula of a compound, the mole ratio of the elements are determined as follows:
Mole ratio = reacting mass/molar massMole ratio of the elements:
Carbon Hydrogen Oxygen
0.618 g/12.01 0.139 / 1.01 0.274 / 16
0.051 0.138 0.017
Divide by the smallest ratio to convert to whole numbers
0.051 / 0.017 0.138 / 0.017 0.017 / 0.017
3 : 8 : 1
Therefore, the empirical formula of the compound is C₃H₈O
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La fórmula CH3-CH=CH-CH2-CH2-CH2-CH3 ,se le debe llamar de la siguiente manera.
A) Hepteno
B) 1 Hepteno
C) 2 Hepteno
D) Heptinol
ayuden plis