Maria found the least common multiple of 6 and 15. Her work is shown below.

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . .
Multiples of 15: 15, 30, 45, 60, . . .

The least common multiple is 60.

What is Maria’s error?

Maria listed some values that were not multiples.
Maria listed factors of each number instead of multiples.
Maria should have multiplied 6 and 15 to find the least common multiple.
Maria selected a multiple that is not the least of the common multiples.

Answer:

I cant read all of that. Im sure others ant either.

Step-by-step explanation:

Answer:

i cant read it for some reason, can you type it?

Step-by-step explanation:

Answer:

39

Step-by-step explanation:

Answer:

24.99

Step-by-step explanation:

Answer: It could be, just add two dots at the smiley face, BOOM! The function of Facial muscles in humans.

Step-by-step explanation:

Answer:

(1, 2), (1,4), (1, 6)

Step-by-step explanation:

They're adding the Y-axis

ur teacher is wrong im in algebra 2 an this is correct

Answer:

$ 2,273.25

Step-by-step explanation:

Answer:

p - 6 = -14

p = -8

Step-by-step explanation:

       The difference between a number p and 6 is -14

  Let the number  = p;

Equation:

          difference between the numbers:

                         p - 6

          equality;

                         p - 6 = -14

Equation; p - 6 = -14

Solution:

                p - 6 = -14

            add (+6) to both sides of the expression;

                 p - 6 + (+6) = -14 +(+6)

                 p = -8

Answer:

The answer is 5³.

Step-by-step explanation:

You have to apply Indices Law :

[tex] {a}^{m} \times {a}^{n} ⇒ {a}^{m + n} [/tex]

[tex] {a}^{m} \div {a}^{n}⇒ {a}^{m - n} [/tex]

[tex] { ({a}^{m} )}^{n} = {a}^{mn} [/tex]

So for this question :

[tex]( {( {5}^{2}) }^{3} \times {5}^{4} ) \div {5}^{7} [/tex]

[tex] = ( {5}^{6} \times {5}^{4} ) \div {5}^{7} [/tex]

[tex] = {5}^{10} \div {5}^{7} [/tex]

[tex] = {5}^{3} [/tex]

Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x = -50 cm and x = +50 cm. The charge densities on the planes are -50 nC/m² and +25 nC/m², respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x = +80 cm? (Hint:Use Gauss’ law.)

Answer:

ΔV = 2520 V

Step-by-step explanation:

We are given;

Charge density 1; σ1 = -50 nC/m² = -50 × 10^(-9) nC/m²

Charge density 2; σ2 = +25 nC/m² = +25 × 10^(-9) nC/m²

Now, formula for electric field strength is;

E = -(½ε)(|σ1| ± |σ2|)

ε is vacuum permittivity with a constant value as 8.85 × 10^(−12) C²/N.m²

|σ1| and |σ2| means we are taking the absolute values and would therefore not use the negative sign attached to them.

Now, in between x = 0 cm(0 m) and 50 cm (0.5 m), electric field generated by both charge densities would be in the same direction and thus;

E_in = -(½ε)(|σ1| + |σ2|)

E_in = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) + (25 × 10^(-9))]

E_in = -4200 V/m

In contrast, when x ≥ 50 cm (0.5 m), electric field generated by both charge densities would be in opposite directions and thus;

E_out = -(½ε)(|σ1| - |σ2|)

E_out = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) - (25 × 10^(-9))]

E_out = 1400 V/m

The magnitude of the potential difference from the origin to x = 80 cm(0.8 m) is calculated as attached;

From the attachment, we see that;

ΔV = 2520 V

Answer:

[tex]q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]

Step-by-step explanation:

[tex]6-3q\leq 1\\\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\\\6-3q-6\le \:1-6\\\\Simplify\\\\-3q\le \:-5\\\\\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}\\\\\left(-3q\right)\left(-1\right)\ge \left(-5\right)\left(-1\right)\\\\Simplify\\\\3q\ge \:5\\\\\mathrm{Divide\:both\:sides\:by\:}3\\\\\frac{3q}{3}\ge \frac{5}{3}\\\\Simplify\\\\q\ge \frac{5}{3}\\\\q\geq 1\frac{2}{3}[/tex]

Answer:

StartRoot 58 EndRoot

Step-by-step explanation:

Given the coordinates (-4, -3) and (-1, 4)

To get the distance between the two points, we will use the formula:

D =√(y2-y1)²+(x2-x1)²

From the coordinates, x1 = -4, y1 = -3, x2 = -1 and y2 = 4

Substitute

D =√(4-(-3))²+(-1-(-4))²

D = √(4+3)²+(-1+4)²

D = √7²+3²

D = √49+9

D = √58

Hence the correct option is D

StartRoot 58 EndRoot

Answer:

D. 58

Step-by-step explanation:

Answer:

9/8

Step-by-step explanation:

change in y/change in x= slope

so in this case -9/-8 or 9/8 bc the negatives cancel out

Answer:

15

Step-by-step explanation:

12-k

12- (-3)

12+3

=15

Answer:

15

Step-by-step explanation:

Substitute the variable, "k" into "12-k" from the equation "k=(-3).

12-k

12-(-3)

12+3---> two negatives make a positive

15

Answer:

x= 16 degrees

Step-by-step explanation:

the angles can be a little hard to remember but just know that the angles that are outside of the transversal are exterior angles and if they are on the opposite sides of the line that passes through the parallel lines then they're alternate exterior angles and those angles that are inside are interior angles and if they are on the opposite sides of the line passing through the parallel then they are alternate interior angles .

Answer:

37: 36

Step-by-step explanation:

You can not simplify. Have a good day!

Answer:

It would be C. The hexagon.

Answer:It would be C because you have 3 sides for the triangle than 4 sides for the rectangle, 5 sides for the pentagon, and 6 sides for the hexagon

Step-by-step explanation:

Answer:

No solution

Step-by-step explanation:

calculate the sum) 3x-5+x+2(x+2)

distribute 2 through the parentheses) 3x-5=x+2x+4

calculate the like terms) 3x-5=3x+4

calculate equal terms on both sides of the equation) -5 = 4

-5 = 4 meaning that the statement is false!

Answer:

41

Step-by-step explanation:

Step 1:

7c + d          Equation

Step 2:

7 ( 5 ) + 6      Input c and d

Step 3:

35 + 6       Multiply

Answer:

41          Add

Hope This Helps :)

Answer:

[tex]Probability = 0.198[/tex]

Step-by-step explanation:

Given

Publish

[tex]Huge\ Success = 20\%[/tex]

[tex]Modest\ Success = 30\%[/tex]

[tex]Break\ Even = 30\%[/tex]

[tex]Losers = 20\%[/tex]

Favorable Reviews:

[tex]Huge\ Success = 99\%[/tex]

[tex]Modest\ Success = 60\%[/tex]

[tex]Break\ Even = 40\%[/tex]

[tex]Losers = 30\%[/tex]

Required

Determine the probability that a textbook is huge success and favorable

To do this, we simply multiply the probability of a textbook being huge success and being favorably reviewed. as follows;

[tex]Probability = 20\% * 99\%[/tex]

[tex]Probability = 0.198[/tex]

the answer to the question is 799

Answer:

4

Step-by-step explanation:

if you do all the steps right you  should get 4

Answer:

32%

Step-by-step explanation:

32/100 is 32%

Answer:

1.5 Quarts

Step-by-step explanation:

A quart contains 32 fluid ounces. So divide 48 by 32. You get 1.5.

So the bucket contains 1.5 Quarts.

Answer:

9 yards

Step-by-step explanation:

-5 + 14 = 9

Answer:

False

Step-by-step explanation:

x is the input and y is the output

the same input cannot have more than 1 output

-8 has 1 output

5 has 1 output

but "1" has 2 outputs

Answer:

the cist of entry for x adults

Answer:

i think it would be d)

Step-by-step explanation:

cuz like, it says to write an expression. for an expression, most of the time you need more than one like number and variable

hope this helped :)

Answer:

It should be 1/2

Step-by-step explanation:

Answer:

F

Step-by-step explanation: