Many cells are able to regulate their turgor (i.e. maintain it at a constant value, even when they are placed in a hypertonic and/or a hypotonic solution). If you were to study this process in the lab and wanted to expose the cells to a hypertonic solution would you choose a solute in the solution that was permeable or impermeable across the membrane. Why would you chose this solute?

Answers

Answer 1

If we want to study the process of maintaining turgor of cells by exposing them to hypertonic solutions in a lab, we will choose the solute which is impermeable across the membrane, such as sucrose.

It is because the cells can regulate their turgor by either taking up water through osmosis or losing water by excreting ions or other solutes.The selection of the impermeable solute is preferred because it does not cross the membrane and allows the water to move in or out of the cell only by osmosis through the selectively permeable membrane. This helps us to control the water potential and can result in the desired effect in the lab. If a permeable solute is used, it would diffuse across the membrane, changing the concentration gradient on both sides and allowing more water to move inside the cell. This will not allow us to study the process of regulating turgor in cells.

Therefore, for studying the regulation of turgor of cells in hypertonic solutions in the lab, we should choose the solute which is impermeable across the membrane. Choosing an impermeable solute, such as sucrose, can help to maintain water potential, thus allowing us to study how cells can regulate their turgor even when they are exposed to hypertonic solutions.

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Related Questions

What are the similarities and differences between the mid-late Paleozoic Earth system and the Mesozoic Earth system (e.g. temp, CO2, glaciation, sea level, continental configuration)? (3-5 sentences)

Answers

The mid-late Paleozoic Earth system and the Mesozoic Earth system are two geological systems that share some similarities and differences. The two systems are similar in terms of continental configuration as they both had supercontinents.

The Pangaea supercontinent was present during the Mesozoic era, while the Gondwana supercontinent existed during the Paleozoic era. The two systems were different in terms of the climate. The mid-late Paleozoic Earth system was colder than the Mesozoic Earth system. Furthermore, the CO2 concentration was also higher in the Paleozoic era than in the Mesozoic era.

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. Ovine hereditary chondrodysplasia is a condition observed in sheep and goats (spider lamb syndrome/spider syndrome) that expresses as abnormally long limbs, abnormal bone and cartilage growth and other symptoms associated with abnormal skeletal growth. It is suspected to be caused (at least partially) by a mutation in the fibroblast growth factor 3 (FGF3) gene. At the FGF3 locus, there are two possible alleles: S (codes for normal FGF3) and s (codes for a mutated FGF3). The mutated FGF3 causes spider syndrome when inherited as a homozygous recessive genotype. You have been breeding your herd of 534 goats for many years and have essentially moved your population into Hardy-Weinberg equilibrium. However, your records indicate that spider syndrome shows up in your population 9% of the time. a. What is the gene and genotypic frequency of the FGF3 locus in your goat herd? b. How many animals in your herd express each genotype (P, H and Q)?

Answers

Gene and genotypic frequency of the FGF3 locus in the goat herd The frequency of recessive alleles can be calculated as the square root of 0.09, which is 0.3.  

a. The frequency of dominant alleles in the goat herd is (1 - 0.3) = 0.7.Genotypic frequency of

FF (SS) = p² = (0.7)² = 0.49.

Genotypic frequency of [tex]Ff (Ss) = 2pq = 2(0.7)(0.3) = 0.42[/tex].

Genotypic frequency of ff [tex](ss) = q² = (0.3)² = 0.09[/tex]

b. Number of animals in the goat herd expressing each genotype (P, H and Q).

The percentage of the animals with spider [tex]syndrome = q² = 0.09[/tex]. (Given)534 is the total number of goats.

The number of animals that have the mutant allele = q² × 1068 = 96.12 (approximately 96)

The number of animals that have the normal allele = p² × 1068 = 523.08 (approximately 523).

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Where have you noticed gene expression lately in the media? What
are recent advancements? Have you had any personal experience with
this technology?

Answers

One of the most interesting and revolutionary fields of scientific study is gene expression. Gene expression is the process by which information encoded in genes is used to direct the synthesis of functional gene products such as proteins. Gene expression is essential for all biological processes in an organism.

In recent years, advancements in technology have allowed for more sophisticated and detailed studies of gene expression, leading to breakthroughs in many fields of research.In the media, gene expression is frequently discussed in the context of health and disease. Researchers are using gene expression analysis to identify genetic variations associated with specific diseases, such as cancer and Alzheimer's disease. This has the potential to lead to new treatments and cures for these and other diseases. In addition, gene expression is also being used in forensics, where it can be used to identify suspects or victims of crime.

Recent advancements in technology have greatly improved our ability to study gene expression. For example, microarray technology allows researchers to examine the expression of thousands of genes at once. This technology has revolutionized our understanding of gene expression and has led to the discovery of many new genes and their functions. Another recent advancement is RNA sequencing, which allows researchers to identify all the RNA molecules in a sample. This technology has greatly improved our ability to identify and study gene expression patterns.

Personal experience with gene expression technology may vary depending on one's field of study or career. However, as a question answering bot, I do not have personal experiences to share.

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7 points In a case-control study of an outbreak of listeria, 16 of 25 people who got listeria had eaten cheddar. Fifteen of 31 people who did not get listeria had eaten cheddar. 1) Write the null and alternative hypotheses. (1.5 points) 2) Calculate the appropriate measure of association. (2 points.) 3) Write an interpretation of the measure of association in plain English. (1.5 points) 4) Based on the analysis that you just conducted, can we conclude that eating cheddar caused listeria? Why or why not?

Answers

Null hypothesis: In this case-control study of an outbreak of Listeria, the null hypothesis is that eating cheddar cheese does not lead to an increased likelihood of getting Listeria.

Alternative hypothesis: The alternative hypothesis is that eating cheddar cheese leads to an increased likelihood of getting Listeria.

Appropriate measure of association: Odds ratio is the appropriate measure of association.Odds ratio= (16/9) / (15/16)=1.7778 (correct to four decimal places)

Interpretation of measure of association in plain English: A higher odds ratio indicates a stronger association between eating cheddar cheese and getting Listeria. Since the odds ratio is 1.7778, it indicates that people who ate cheddar cheese were 1.7778 times more likely to get Listeria compared to those who did not eat cheddar cheese.

Based on the analysis that we have conducted, we cannot conclude that eating cheddar caused Listeria. The odds ratio does suggest an association between eating cheddar cheese and getting Listeria, but we cannot say for sure that eating cheddar cheese caused Listeria to occur.

We cannot rule out the possibility of other factors, such as contaminated cheddar cheese or cross-contamination, being responsible for the outbreak of Listeria. The analysis conducted in the case-control study provides evidence of an association between eating cheddar cheese and getting Listeria, but further investigation is required to establish a causal relationship between cheddar cheese and Listeria.

In a case-control study of an outbreak of listeria, the null hypothesis is that eating cheddar cheese does not lead to an increased likelihood of getting Listeria. The alternative hypothesis is that eating cheddar cheese leads to an increased likelihood of getting Listeria. The odds ratio is the appropriate measure of association in this scenario. The odds ratio is calculated as 1.7778, which suggests that people who ate cheddar cheese were 1.7778 times more likely to get Listeria compared to those who did not eat cheddar cheese.

However, we cannot conclude that eating cheddar caused Listeria based on this analysis. While the odds ratio indicates an association between eating cheddar cheese and getting Listeria, it does not establish causality. Other factors, such as contaminated cheddar cheese or cross-contamination, could be responsible for the outbreak of Listeria. Further investigation is required to establish a causal relationship between cheddar cheese and Listeria

. Therefore, based on the analysis that we have conducted, we cannot conclude that eating cheddar caused Listeria. Instead, we can say that the analysis provides evidence of an association between eating cheddar cheese and getting Listeria, which warrants further investigation to determine if there is a causal relationship between these two factors.

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Which applies to the induction of adaptive immunity by the innate immune system? Select all that apply
recognition of the antigen by pattern recognition receptors (PRRs) on blood platelets
proliferation and differentiation of antigen-specific t cells
processing of the antigen and loading onto mhc
presentation of the antigen to helper t cells
migration of dendritic cells to lymph nodes and maturation into antigen-presenting cells

Answers

The following statements apply to the induction of adaptive immunity by the innate immune system:The recognition of the antigen by pattern recognition receptors (PRRs) on dendritic cells, macrophages, and other innate immune cells.

Processing of the antigen and loading onto MHC molecules.

Presentation of the antigen to helper T cells, resulting in the production of cytokines by helper T cells that initiate the proliferation and differentiation of antigen-specific T cells.

Migration of dendritic cells to lymph nodes and maturation into antigen-presenting cells, leading to the activation of naïve T cells.

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This research method involves inviting individuals to complete a questionnaire designed to collect data. O a) Interviews Ob) The laboratory experiment Oc) Field research d) The survey

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The research method that involves inviting individuals to complete a questionnaire designed to collect data is known as

d) The survey.

This is one of the most common research methods used in different fields, such as social sciences, marketing, and psychology, among others.

A survey is a data collection tool that is designed to gather information from a sample of individuals about a particular topic or phenomenon. The surveys can be conducted using different mediums such as paper surveys, online surveys, telephone surveys, or face-to-face interviews. Surveys typically consist of a set of structured questions that can be either open-ended or closed-ended. The questions may relate to the respondent's demographics, opinions, attitudes, beliefs, experiences, behaviors, or preferences. The data collected through surveys can be analyzed to gain insights into the target population's characteristics, attitudes, or behaviors.

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Question 16 What is balanced at electrochemical equilibrium? Negative charge on the inside of the cell and the positive charge on the outside of the cell Potassium efflux and sodium influx O Concentra

Answers

Electrochemical equilibrium is balanced when there is a negative charge on the inside of the cell and a positive charge on the outside of the cell. At this stage, potassium efflux and sodium influx are equal. The concentration of both ions is also in balance, that is, the concentration gradient is at equilibrium.

The concentrations of the ions and their respective gradients across the membrane create an electrical potential difference. This difference creates a driving force that is proportional to the ratio of the ion concentrations. Ions move from high to low concentrations, thus causing a flow of ions across the membrane. At electrochemical equilibrium, the electrical potential difference is balanced by the concentration gradient, causing a cessation of ion movement.

Therefore, an ion concentration gradient and a transmembrane potential difference is what is balanced at electrochemical equilibrium.

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68 Anatomy and Physiology I MJB01 )2 (Summer 2022) The spinal cord consists of four regions and segments. Select one: a. 1 b. 5 C. 7 d. 31 e. 12 Clear my choice

Answers

The spinal cord is composed of 31 segments, each of which gives rise to a pair of spinal nerves.

These segments are further divided into four regions: cervical (C1-C8), thoracic (T1-T12), lumbar (L1-L5), and sacral (S1-S5). Each segment of the spinal cord corresponds to a specific region of the body and is responsible for transmitting sensory and motor information between the body and the brain. The spinal cord, which connects the medulla oblongata in the brainstem to the lumbar portion of the vertebral column (backbone), is a long, thin, tubular tube consisting of nerve tissue. The cerebrospinal fluid-filled core canal of the spinal cord is enclosed by the backbone. The central nervous system (CNS) is made up of the brain and spinal cord.

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A couple with blood types of AB and O are given a child whose
blood type is B. Does the child belong to the couple?

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A couple with blood types of AB and O are given a child whose blood type is B. Does the child belong to the couple? No, the child does not belong to the couple.

Because, there are several reasons behind it which are explained below: First, the blood group AB and O cannot be the blood group of parents, which means there is a possibility of a mutation. One parent having an AB blood type and the other having an O blood type makes the AB blood type incompatible with the O blood type. This makes it possible for the child's blood type to be different from that of both parents. Second, the inheritance of blood types from parents is in the form of dominant or recessive genes. In this case, neither parent has a gene to determine the child's blood type. That is, both parents have different blood types, and neither blood type can be the dominant gene. As a result, the child's blood type cannot be derived from the parents. In conclusion, there is a very low possibility that a couple with blood types of AB and O can give birth to a child whose blood type is B, unless there is an explanation for it (such as an adoption). Therefore, the child does not belong to the couple.

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answer with explanation
Which of the following is not associated with the movement of the other three in kidney functions? potassium ions hydrogen ions water protein

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Hydrogen ions are not associated with the movement of the other three in kidney functions.

The kidneys are a pair of bean-shaped organs located in the retroperitoneal space in the abdominal cavity. They play an essential role in the excretion of waste products and the regulation of electrolyte balance, blood pressure, and acid-base balance in the body. The kidneys perform the following functions in the body:Removal of metabolic waste products: They filter waste products like urea, creatinine, and uric acid from the blood and excrete them through the urine Regulation of water balance: The kidneys maintain the body's fluid balance by adjusting the volume and concentration of urine they produce Regulation of electrolyte balance: They regulate the levels of electrolytes like sodium, potassium, calcium, and magnesium in the body Regulation of acid-base balance: They help maintain the body's pH balance by excreting or retaining hydrogen ions as necessary. The kidneys filter blood and produce urine through a complex process involving several components, including nephrons, glomeruli, and collecting ducts.

The nephrons are the basic functional units of the kidneys, and they filter the blood and produce urine by passing it through a series of structures. The glomeruli are the tiny blood vessels that filter the blood, and the collecting ducts are responsible for transporting the urine to the bladder. Protein is an essential nutrient that helps build and repair body tissues. The kidneys play a crucial role in regulating protein metabolism by excreting waste products from protein metabolism like urea and ammonia. Potassium is an essential electrolyte that plays a vital role in muscle and nerve function. The kidneys regulate the level of potassium in the body by excreting or retaining it as necessary. Water is a critical component of the body, and the kidneys play a vital role in regulating the body's fluid balance. The kidneys regulate the volume and concentration of urine they produce to maintain the body's fluid balance.

Hydrogen ions are positively charged ions that are produced when acids are dissolved in water. They play an essential role in regulating the body's pH balance by acting as acids and donating protons to other molecules. Unlike protein, potassium ions, and water, hydrogen ions are not associated with the movement of the other three in kidney functions. The kidneys regulate the level of hydrogen ions in the body by excreting or retaining them as necessary, but they do not play a direct role in the movement of protein, potassium ions, or water in kidney functions.

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Examples of animals that are typically ectothermic are the ________
Multiple Choice marsupials penguins placental mammals
avion reptiles nohavion reptiles

Answers

Examples of animals that are typically ectothermic are the reptiles.  Hence option reptiles is correct.

Ectothermic animals are those animals whose internal temperature fluctuates with the environment. The biological term for these creatures is poikilothermic, which refers to the internal temperature variations of an organism's environment. Some animals are not ectothermic, but rather endothermic. This refers to animals that can regulate their body temperature independently of the environment.

The term endothermic, often known as warm-blooded, refers to animals that generate their body heat and are not reliant on the environment to control their temperature. Among the given choices, reptiles are the only ones that are typically ectothermic. The other animals listed - marsupials, penguins, placental mammals, and avian (bird) species - are endothermic creatures, meaning they can regulate their body temperature independently of the environment.

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help! will leave a thumbs up
2. Describe briefly the Trp operon? Why is it considered an example of negative regulation?

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The Trp operon is a segment of DNA in prokaryotic cells responsible for the synthesis of tryptophan, an essential amino acid.

It consists of a promoter region, operator region, and a series of structural genes involved in tryptophan synthesis. The structural genes encode enzymes necessary for the conversion of precursor molecules into tryptophan.

The Trp operon is considered an example of negative regulation because it is controlled by a repressor protein that inhibits gene expression. In the absence of tryptophan, the repressor protein remains inactive and cannot bind to the operator region. This allows RNA polymerase to access the promoter region and initiate transcription, resulting in the production of the enzymes involved in tryptophan synthesis. However, when tryptophan levels are high, tryptophan molecules bind to the repressor protein, causing a conformational change that enables it to bind to the operator region. This blocks RNA polymerase from accessing the promoter region, preventing transcription of the structural genes and effectively shutting down tryptophan synthesis.

The negative regulation of the Trp operon ensures that tryptophan synthesis is only activated when tryptophan levels are low. This mechanism allows bacteria to conserve energy by producing tryptophan only when it is necessary, avoiding the unnecessary synthesis of the amino acid.

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A с 00 B D Which of these indicates the intestine? A B O

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The term that indicates the intestine among the options "A, B, O" is B. Let's discuss what A, B, O signify: A, B, and O refer to the three alleles of the human blood groups system. A and B are co-dominant, while O is recessive.

When both A and B are present, AB is produced, which is AB blood type. In people with O blood type, the O allele is present, which is why they can donate blood to anyone .ABO blood grouping system: The ABO blood group system, also known as the human blood group system, is a classification system for blood that is based on the presence or absence of specific antigens on the red blood cells' surface and/or in the plasma antibodies. Individuals have one of four major blood groups: A, B, AB, or O, based on the presence or absence of two antigens, A and B, on the surface of their red blood cells. The A and B antigens, which are distinct chemical substances, are produced by the addition of specific sugars to the H antigen, which is found on the surface of all red blood cells. The ABO blood grouping system is named after the A and B antigens, which are present on the surface of the red blood cells, and the O antigen, which is not present on the surface of the red blood cells, but rather in the plasma. So, B is the term that represents the intestine from the given options.

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Read the following abstract and answer the question below:
H9N2 influenza viruses have been circulating worldwide in multiple avian species and repeatedly infecting mammals, including pigs and humans, posing a significant threat to public health. The coexistence of H9N2 and pandemic influenza H1N1/2009 viruses in pigs and humans provides an opportunity for these viruses to reassort. To evaluate the potential public risk of the reassortant viruses derived from these viruses, we used reverse genetics to generate 127 H9 reassortants derived from an avian H9N2 and a pandemic H1N1 virus, and evaluated their compatibility, replication ability, and virulence in mice. These hybrid viruses showed high genetic compatibility and more than half replicated to a high titer in vitro. In vivo studies of 73 of 127 reassortants revealed that all viruses were able to infect mice without prior adaptation and 8 reassortants exhibited higher pathogenicity than both parental viruses. All reassortants with higher virulence than parental viruses contained the PA gene from the 2009 pandemic virus, revealing the important role of the PA gene from the H1N1/2009 virus in generating a reassortant virus with high public health risk. Analyses of the polymerase activity of the 16 ribonucleoprotein combinations in vitro suggested that the PA of H1N1/2009 origin also enhanced polymerase activity. Our results indicate that some avian H9-pandemic reassortants could emerge with a potentially higher threat for humans and also highlight the importance of monitoring the H9-pandemic reassortant viruses that may arise, especially those that possess the PA gene of H1N1/2009 origin.
If you were an epidemiologist, based on this information, what novel combination of influenza viruses would you be most concerned about?
a.
H9N2 that incorporates an H1N1 PA segment.
b.
H9N2 that incorporates an H1N1 PB1 segment.
c.
H1N1 that incorporates an H9N2 PB1 segment.
d.
H1N1 that incorporates H9N2 PA segment
Read the abstract below and answer the following question:
Link of a ubiquitous human coronavirus to dromedary camels.
The Middle East respiratory syndrome (MERS) coronavirus (CoV) is a CoV with a known zoonotic source in dromedary camels. Little is known about the origins of endemic HCoVs. Studying these viruses' evolutionary history could provide important insight into CoV emergence. In tests of MERS-CoV-infected dromedaries, we found viruses related to an HCoV, known as HCoV-229E, in 5.6% of 1,033 animals. Human- and dromedary-derived viruses are each monophyletic, suggesting ecological isolation. One gene of dromedary viruses exists in two versions in camels, full length and deleted, whereas only the deleted version exists in humans. The deletion increased in size over a succession starting from camelid viruses via old human viruses to contemporary human viruses. Live isolates of dromedary 229E viruses were obtained and studied to assess human infection risks. The viruses used the human entry receptor aminopeptidase N and replicated in human hepatoma cells, suggesting a principal ability to cause human infections. However, inefficient replication in several mucosa-derived cell lines and airway epithelial cultures suggested lack of adaptation to the human host. Dromedary viruses were as sensitive to the human type I interferon response as HCoV-229E. Antibodies in human sera neutralized dromedary-derived viruses, suggesting population immunity against dromedary viruses. Although no current epidemic risk seems to emanate from these viruses, evolutionary inference suggests that the endemic human virus HCoV-229E may constitute a descendant of camelid-associated viruses. HCoV-229E evolution provides a scenario for MERS-CoV emergence.
Why are the dromedary coronaviruses not a current threat to humans?
a.
HCoV viruses are only in 5.6% of animals
b.
Dromedary coronaviruses are only found in the Middle East.
c.
Inefficient replication in cell lines suggests they are not adapted to humans.
d.
Only one deleted version exists in humans.

Answers

As an epidemiologist, the most concerning combination would be H9N2 with an H1N1 PA segment due to high genetic compatibility and potential for increased pathogenicity. The correct option is a. Dromedary coronaviruses are not a current threat to humans  due to inefficient replication in human cell lines and existing population immunity. The correct option is c.

If I were an epidemiologist and based on the information provided in the abstract, the novel combination of influenza viruses that would concern me the most would be option a: H9N2 that incorporates an H1N1 PA segment.

The abstract states that reassortant viruses generated from an avian H9N2 and a pandemic H1N1 virus exhibited high genetic compatibility and replication ability, with some reassortants showing higher pathogenicity than both parental viruses.

Specifically, the reassortants with higher virulence all contained the PA gene from the H1N1/2009 virus.

This suggests that the PA gene from the H1N1/2009 virus plays an important role in generating reassortant viruses with a high public health risk.

Therefore, the combination of H9N2 with an H1N1 PA segment poses a potential higher threat to humans, indicating the need for monitoring and surveillance of such reassortant viruses.

Hence, the correct option is a.H9N2 that incorporates an H1N1 PA segment.

Regarding the dromedary coronaviruses, the reason they are not currently a threat to humans is option c: inefficient replication in cell lines suggests they are not adapted to humans.

The abstract mentions that the dromedary viruses replicated inefficiently in several mucosa-derived cell lines and airway epithelial cultures, suggesting a lack of adaptation to the human host.

This inefficient replication indicates that the viruses may have limited ability to cause infections in humans.

Additionally, the presence of population immunity against dromedary viruses, as suggested by the neutralization of dromedary-derived viruses by antibodies in human sera, further supports the notion that these viruses are not currently posing an epidemic risk to humans.

Hence, the correct option is c. Inefficient replication in cell lines suggests they are not adapted to humans.

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can you show me the steps and answer please:
In a population the frequency of allele A is 0.75 and allele a is 0.25; these alleles
are codominant
Considering the allele fitness listed below, what will the
frequency of the A allele be after 1 generation? In a population the frequency of allele A is 0.75 and allele a is 0.25; these alleles are codominant. Considering the allele fitness listed below, what will the frequency of the A allele be after 1 generation? WAA = 0.8, WAa= 1, Waa = 0.9

Answers

To calculate the frequency of the A allele after 1 generation, we can use the Hardy-Weinberg equation:

p^2 + 2pq + q^2 = 1

Where p is the frequency of allele A and q is the frequency of allele a.

Given that the frequency of allele A is 0.75 and allele a is 0.25, we can substitute these values into the equation:

(0.75)^2 + 2(0.75)(0.25) + (0.25)^2 = 1

0.5625 + 0.375 + 0.0625 = 1

The sum is equal to 1, which confirms that the equation is balanced.

However, to calculate the frequency of the A allele after 1 generation, we need to consider the allele fitness.

The allele fitnesses are given as:
WAA = 0.8, WAa = 1, Waa = 0.9

To calculate the new frequency of the A allele after 1 generation, we need to multiply the initial frequency of the allele with its respective fitness:

Frequency of A allele after 1 generation = (frequency of A allele x fitness of A allele) + (frequency of a allele x fitness of a allele)

= (0.75 x 0.8) + (0.25 x 1)

= 0.6 + 0.25

= 0.85

Therefore, the frequency of the A allele after 1 generation is 0.85.

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2. Now, the primers, which are artificially made and have a nucleotide sequence complementary to the adjacent bases in the segment of interest at the 3 of 01 and at the 5' of 02, bind after DNA denaturation. Write the 5-base nucleotide sequence of Primer-1 and 2. 101) original-1_3'TC GGCTACAGCAG TAGATGG TAC GTA 5' 59 cebador-1) (02) Original-25' AGCCGATGTCGTCGTC TXATGCAT 3 31 5 (cebador-2)

Answers

The 5-base nucleotide sequence of Primer-1 and 2 is:

Primer-1: 3'TCGGC

Primer-2: 5'GACGA

In the given sequence, the nucleotide sequences of Primer-1 and Primer-2 are indicated within parentheses. The sequence for Primer-1 is mentioned as "cebador-1" and is represented as "3'TCGGC." Similarly, the sequence for Primer-2 is mentioned as "cebador-2" and is represented as "5'GACGA."

These primers are designed to be complementary to specific regions in the DNA segment of interest. Primer-1 binds to the 3' end of the original segment (01), with its sequence starting with "TCGGC" and complementing the adjacent bases. Primer-2 binds to the 5' end of the original segment (02), with its sequence starting with "GACGA" and complementing the adjacent bases.

By designing primers that specifically target the regions of interest, they enable the amplification of the desired DNA segment during the polymerase chain reaction (PCR) process. The binding of these primers to their respective regions initiates the DNA amplification and replication process, allowing for the generation of multiple copies of the DNA segment.

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From the left ventricle it passes into the aorta true
false
From the aorta to the capillaries true false
In the capillaries the blood takes in oxygen true false
In the capillaries the blood takes CO2

Answers

he statement "In the capillaries the blood takes CO2" is also true as the capillaries take carbon dioxide from the blood.From the left ventricle, blood passes into the aorta. From the aorta to the capillaries, blood takes in oxygen and releases carbon dioxide.In the capillaries the blood takes CO2

From the left ventricle it passes into the aorta - TrueFrom the aorta to the capillaries - TrueIn the capillaries the blood takes in oxygen - TrueIn the capillaries the blood takes CO2 - TrueThe left ventricle is one of the four heart chambers, and it pumps oxygen-rich blood to the body through the aorta. Therefore, it passes into the aorta from the left ventricle, which is true.From the aorta, the blood travels to the capillaries where the exchange of oxygen and carbon dioxide happens. The oxygen is then taken in by the blood in the capillaries, so the statement "In the capillaries the blood takes in oxygen" is true. The statement "In the capillaries the blood takes CO2" is also true as the capillaries take carbon dioxide from the blood.From the left ventricle, blood passes into the aorta. From the aorta to the capillaries, blood takes in oxygen and releases carbon dioxide.In the capillaries the blood takes CO2From the left ventricle it passes into the aorta true

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An Increase in ETS rate is stimulated by decrease in
concentrtion of which of the following factors?
a.
ATP
b.
ADP
c.
Pi
d.
NAD/NADH+H+ ratio

Answers

A decrease in NAD/NADH+H+ ratio stimulates an increase in ETS rate.EXPLANATIONThe electron transport chain (ETC) is an essential aspect of oxidative phosphorylation.

The electron transport chain (ETC) is a crucial process in oxidative phosphorylation. It comprises a series of protein complexes located in the inner mitochondrial membrane, which are responsible for transporting electrons from NADH and FADH2 to O2 to produce water.In the process, an electrochemical gradient is established across the inner mitochondrial membrane, which powers ATP production by ATP synthase. A decrease in the NAD/NADH+H+ ratio stimulates an increase in ETC rate.

It’s due to the fact that NADH and FADH2 are electron donors in the ETC. When the NAD/NADH+H+ ratio decreases, the availability of NADH as an electron donor decreases, which increases the ETC rate.An increase in the ADP/ATP ratio stimulates the ETC rate because ATP synthase needs a proton gradient across the inner mitochondrial membrane to produce ATP, and the ETC is the mechanism for generating the gradient. As a result, when the ADP/ATP ratio rises, the ETC rate increases.

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What is the recommended daily limit of trans fat in an adult's diet?
a. 36 mg for males and 30 mg for females b. No more than 15% of fat caloric intake. c. Consume less trans fat than saturated fat, but consume more trans fat than unsaturated fat. d. None.

Answers

The recommended daily limit of trans fat in an adult's diet is option (d) "None." There is no safe or acceptable level of trans fat consumption for maintaining good health.

Option (d) is the correct answer, as the recommended daily limit of trans fat in an adult's diet is zero. Trans fats are artificially created through the process of hydrogenation and have been linked to an increased risk of heart disease. They can raise bad cholesterol levels (LDL) and lower good cholesterol levels (HDL), leading to adverse cardiovascular effects.

Due to the negative health impacts of trans fats, many health organizations, including the World Health Organization (WHO) and the United States Food and Drug Administration (FDA), have recommended reducing trans fat consumption as much as possible. In some countries, trans fats have been banned or limited in food products.

It is important to read food labels carefully and avoid products that contain partially hydrogenated oils, as they are a significant source of trans fats. Instead, focus on consuming healthy fats, such as unsaturated fats from sources like nuts, seeds, avocados, and oils like olive oil and canola oil.

In summary, the recommended daily limit of trans fat in an adult's diet is zero (option d). It is crucial to avoid trans fats as much as possible to maintain good health and reduce the risk of heart disease.

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Question 13 13. Which statement regarding iron is false? O it is found in myoglobin O it is a major mineral O it is found in all cells it serves as a cofactor in certain enzymess O it is found in hemoglobin Question 14 14. If the level of parathyroid hormone drops, what will happen to the level of calcium in the blood? O it will increase O the calcium level will not be affected O it will drop D

Answers

Iron is a mineral that is found in all cells, myoglobin, hemoglobin, and serves as a cofactor in certain enzymes. All the statements except the one stating that "it is a major mineral" are true regarding iron.

False statement regarding iron is: it is a major mineral. The human body requires a range of vitamins and minerals to perform a variety of tasks, including the manufacture of hormones, enzymes, and other chemicals. Iron is one such mineral, which is found in all cells of the body. Hemoglobin, a protein in red blood cells that carries oxygen, and myoglobin, a protein found in muscles that store oxygen, both include iron. Iron also serves as a cofactor in certain enzymes that help with various biological reactions. Parathyroid hormone plays an important role in regulating the level of calcium in the blood. When the level of parathyroid hormone falls, the level of calcium in the blood will drop.

Therefore, the correct answer is it will drop.

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Question 47 Not yet graded / 7 pts Part C about the topic of nitrogen. The nucleotides are also nitrogenous. What parts of them are nitrogenous? What are the two classes of these parts? And, what are

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Nitrogenous refers to the presence of nitrogen in a molecule. Nucleotides are also nitrogenous.

Nucleotides have three parts: nitrogenous base, sugar, and phosphate. The nitrogenous base of a nucleotide is nitrogenous.

The two classes of these nitrogenous bases in nucleotides are purines and pyrimidines.

Purines are nitrogenous bases that contain two rings.

Adenine (A) and guanine (G) are examples of purines.

Pyrimidines are nitrogenous bases that contain one ring.

Cytosine (C), thymine (T), and uracil (U) are examples of pyrimidines.

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During transcription, the strand of DNA that is copied is called the _____________strand whereas the complementary strand is called the __________________ strand. O coding; template O coding; noncoding O double; single O noncoding; coding O template; coding

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During transcription, the strand of DNA that is copied is called the coding strand whereas the complementary strand is called the template strand.

Transcription is the first step of gene expression in which the DNA sequence of a gene is transcribed into RNA sequence. The primary transcript, initially produced during transcription, undergoes post-transcriptional modifications to produce mature RNA.

The genetic information stored in DNA is transcribed into RNA by RNA polymerase. During transcription, one of the two strands of DNA serves as a template for RNA synthesis. This template strand of DNA is usually referred to as the noncoding strand, but it should not be confused with the coding strand. The complementary coding strand of DNA, which has a sequence complementary to the template strand, is also known as the sense strand.

During transcription, RNA polymerase reads the template strand of DNA in the 3' to 5' direction and synthesizes RNA in the 5' to 3' direction. RNA polymerase reads the template strand in the opposite direction because RNA is synthesized in the 5' to 3' direction. This results in the complementary base pairing of RNA with the template strand, which is antiparallel to the synthesized RNA strand.

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Match the descriptions to the structures of the nephron Answer choices can be used once more than once or not at all v tube nearest to the Bowman's capsule A glomerulus v structure into which the proximal convoluted tubule empties B. collecting duct these blood vessels surround the loop of Henle C. peritubular capillanes blood vessels that surround the convoluted tubules D. distal convoluted tubule E. proximal convoluted tubule capillary network inside the Bowman's capsule F. Loop of Henle v filtration occurs here G. vasa recta v most reabsorption occurs hore all cells have prominent microville ✓ contains urine in its most final form podocytes are found here the ascending part of this structure is impermeable to water in cortical nephrons, this structure is short

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Nephron is the structural and functional unit of the kidney. It regulates water balance and blood pressure and eliminates waste from the body. In this context, let's match the descriptions to the structures of the nephron. The answer is given below: a. Proximal convoluted tubule: It is the tube nearest to the Bowman's capsule.

It empties into the structure in option b and the convoluted tubules are surrounded by peritubular capillaries. b. Collecting duct: The proximal convoluted tubule empties into the structure which is the collecting duct. The cells here have prominent microville and it contains urine in its most final form.

c. Peritubular capillaries: These blood vessels surround the convoluted tubules. The loop of Henle is also surrounded by blood vessels which are described in option f.d. Distal convoluted tubule: It is the structure into which the loop of Henle empties. This structure is short in cortical nephrons. e. Glomerulus:

It is the capillary network inside the Bowman's capsule. Filtration occurs here. f. Vasa recta: These blood vessels surround the loop of Henle. g. Loop of Henle: The ascending part of this structure is impermeable to water. The descending limb is permeable to water. h. Proximal convoluted tubule: Most reabsorption occurs here.

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Which of the following statements is true about resting muscle cells?
A. In resting muscle cells, creatine phosphate levels are high, and ATP levels are also high
B. In resting muscles cells, creatine phosphate levels are low, and ATP levels are also low
C. In resting muscles cells, creatine phosphate levels are low, and ATP levels are high
D. In resting muscles cells, creatine levels are high and ATP levels are low

Answers

The correct answer is option C. In resting muscle cells, creatine phosphate levels are low, and ATP levels are high.

What are muscle cells? Muscle cells or muscle fibers are cylindrical structures composed of thin filaments of actin and thick filaments of myosin. Muscle cells have the ability to contract and relax, which leads to movement and various functions such as locomotion, maintaining posture, and generating heat.

ATP and creatine in resting muscle cells In resting muscle cells, creatine phosphate levels are low, and ATP levels are high. Creatine phosphate levels are low because there is no active contraction of the muscle fibers, which consumes the stored creatine phosphate for energy. In resting muscles cells, the high ATP levels are generated through aerobic respiration, which supplies the muscle cells with sufficient energy to maintain their metabolism. The stored ATP is then utilized during contraction and relaxation of the muscles, when the demand for energy is high.

Creatine in resting muscle cells Creatine is not a significant source of energy in resting muscle cells. It is a nitrogenous organic acid synthesized in the liver and kidneys from amino acids, such as glycine and arginine. Creatine is stored in skeletal muscles and converted to creatine phosphate, which is used as an energy source during muscle contraction. However, creatine levels are low in resting muscle cells because there is no need for energy consumption. The stored creatine phosphate is conserved until it is needed during contraction.

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(2) WHAT IS THE ISOLATION PROCESS OF THE FOLLOWING
(i) Salmonella,
(ii) E.coli,
(iii) klebsiella
(iv) Proteus,
(v) vibrio cholera,
(vi) streptococcus,
(vii) staphylococcus,
(viii) Niserria
(3) WHAT IS THE MODE OF IDENTIFICATION FOR THE FOLLOWING
(i) Salmonella,
(ii) E.coli,
(iii) klebsiella
(iv) Proteus,
(v) vibrio cholera,
(vi) streptococcus,
(vii) staphylococcus,
(viii) Niserria

Answers

(i) Salmonella: The isolation process involves enrichment in selective media like selenite broth, followed by streaking on selective agar such as xylose lysine deoxycholate (XLD) agar.

(ii) E. coli: E. coli can be isolated using selective media like MacConkey agar, which inhibits the growth of Gram-positive bacteria. E. coli forms pink colonies on MacConkey agar due to lactose fermentation.

(iii) Klebsiella: Isolation of Klebsiella can be done using selective media such as MacConkey agar or blood agar, where it forms large, mucoid colonies.

(iv) Proteus: Proteus can be isolated by streaking on selective media like MacConkey agar or CLED agar, where it forms swarming colonies with a characteristic "fried egg" appearance.

(v) Vibrio cholera: Vibrio cholerae can be isolated using selective media such as thiosulfate-citrate-bile salts-sucrose (TCBS) agar, where it appears as yellow colonies due to sucrose fermentation.

(vi) Streptococcus: Streptococcus can be isolated by inoculating samples onto blood agar plates, where it forms colonies that can be differentiated based on their hemolysis patterns (alpha, beta, or gamma).

(vii) Staphylococcus: Staphylococcus can be isolated by streaking samples on blood agar plates, where it forms colonies. Further identification can be done using coagulase tests to differentiate between coagulase-positive (Staphylococcus aureus) and coagulase-negative species.

(viii) Neisseria: Neisseria can be isolated using selective media such as Thayer-Martin agar, which inhibits the growth of other bacteria. It forms colonies that can be further identified using oxidase tests.

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36. Which film composer is considered to be a pioneer in the use
of digital synthesizers, electronic keyboards, and the latest
computer technology?
Hugo Blowdorn
Harry Lovelog
Elmer Earplug
Manny Fli

Answers

Hans Zimmer is considered to be a pioneer in the use of digital synthesizers, electronic keyboards, and the latest computer technology in film composition. Throughout his career, Zimmer has pushed the boundaries of music production by incorporating innovative and cutting-edge technologies into his work.

Zimmer's use of digital synthesizers and electronic keyboards brought a fresh and distinctive sound to the world of film scores. He embraced the capabilities of these instruments, exploring new sonic possibilities and creating unique textures and atmospheres that added depth and emotion to his compositions. Furthermore, Zimmer's expertise in harnessing the power of computer technology revolutionized film scoring.

He integrated computer-based music production techniques, allowing for precise control over orchestral arrangements, sound manipulation, and the creation of complex musical layers. His pioneering work in films such as "Blade Runner 2049," "Inception," and "The Dark Knight" demonstrated the immense creative potential of these technologies and cemented Zimmer's reputation as a trailblazer in the industry.

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Discuss the importance of herbivores as controllers of ecosystem processes, and indicate how proportion of Primary Productivity consumed in various systems may affect nutrient cycling.
compter text please

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Herbivores play a crucial role as controllers of ecosystem processes, Herbivores have a direct impact on plant populations by consuming vegetation, which influences plant growth, community composition, and structure.

Herbivores have a direct impact on plant populations by consuming vegetation, which influences plant growth, community composition, and structure. Through herbivory, they regulate primary productivity by controlling plant biomass and nutrient availability. The consumption of primary producers by herbivores influences nutrient cycling as it determines the amount of organic matter that is incorporated into the detrital pool, decomposed, and released back into the ecosystem as nutrients.

In summary, herbivores act as controllers of ecosystem processes by shaping plant communities and influencing primary productivity. The proportion of Primary Productivity consumed by herbivores in various systems affects nutrient cycling, as it determines the amount of organic material available for decomposition and nutrient release. Understanding the dynamics between herbivores, primary producers, and nutrient cycling is crucial for maintaining the balance and functioning of ecosystems.

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During your analysis you discover a new electron transport chain based on: • Ickygreenone + H+ +2e- --> Ickygreenol -0.5 V • Barsoom + H+ +2e- --> Barsool -1.25 V What is the voltage of the half-reaction that contains the oxidant? (Do not use units)

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The voltage of the half-reaction containing the oxidant is -0.5 V.

The voltage of the half-reaction containing the oxidant is calculated as follows:

During your analysis, you discovered a new electron transport chain, with two half-reactions that are listed below:Ickygreenone + H+ + 2e– → Ickygreenol   E° = -0.5 VBarsoom + H+ + 2e– → Barsool  E° = -1.25 VThe question is asking for the voltage of the half-reaction containing the oxidant.

The oxidant is the substance that is being reduced, i.e., it gains electrons. The oxidant in the first half-reaction is Ickygreenone, and the oxidant in the second half-reaction is Barsoom.To determine the voltage of the half-reaction containing the oxidant, you need to find which of the two half-reactions is being reduced, i.e., which has the more positive E°.The half-reaction with the more positive E° is the one that is more likely to be reduced, and therefore it contains the oxidant. In this case, the half-reaction with the more positive E° is the first one, with E° = -0.5 V.Therefore, the voltage of the half-reaction containing the oxidant is -0.5 V.

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True or False:
Splicing machinery must recognize three portions of the
precursor RNA molecule: the 5’ splice site, the 3’ splice site, and
the exon junction complex (EJC). (T/F)

Answers

The statement "Splicing machinery must recognize three portions of the precursor RNA molecule: the 5’ splice site, the 3’ splice site, and the exon junction complex (EJC)" is a true statement.

The statement "Splicing machinery must recognize three portions of the precursor RNA molecule: the 5’ splice site, the 3’ splice site, and the exon junction complex (EJC)" is a true statement.

What is RNA splicing? RNA splicing is the process of removing introns from a precursor messenger RNA (mRNA) transcript and reconnecting the exons. After RNA transcription, RNA splicing is critical for the development of mature mRNA molecules in eukaryotes (organisms that contain a nucleus and membrane-bound organelles).

Three key components of RNA splicing machinery

The splicing machinery in eukaryotes comprises five snRNAs (U1, U2, U4, U5, and U6), seven protein factors (U1, U2, U4, U5, and U6), and a host of associated proteins.

Three critical components of the RNA splicing machinery are as follows:5' splice site: A splice site is a series of nucleotides at the 5' end of the intron.3' splice site: At the 3' end of the intron, there is a second splice site. The 3' splice site includes the nucleotides that define the end of the intron and the beginning of the exon.

EJC: An exon junction complex (EJC) forms at the exon-exon border and aids in the export of spliced mRNA from the nucleus to the cytoplasm.

In conclusion, the statement "Splicing machinery must recognize three portions of the precursor RNA molecule: the 5’ splice site, the 3’ splice site, and the exon junction complex (EJC)" is a true statement.

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Which of the following three
conditions contribute to the Hardy-Weinberg Equilibrium?
a.
No selection of one individual over
another, stable environment, non-random mating
b.
No select

Answers

Thus, option (d) is the correct choice While non-random mating can disturb the Hardy-Weinberg equilibrium, it is not one of the three conditions that contribute to the equilibrium.

The model provides a theoretical foundation for studying genetic variation in a population.

These are random mating, no mutation, no gene flow (immigration or emigration), large population size, and no selection. The three conditions that contribute to the Hardy-Weinberg Equilibrium are no selection of one individual over another, no migration, and stable environment.

Thus, option (d) is the correct choice While non-random mating can disturb the Hardy-Weinberg equilibrium, it is not one of the three conditions that contribute to the equilibrium.

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The interior walls as well the ceiling and the floor of a room are all at T = 12 deg C. The room air is continuously circulated, providing an average convection coefficient of 6.3 W m-2 K-1 at an average temperature of T = 21 deg C. If the room measures 5 m X 4 m X 3 m, estimate the rate at which the air is cooling the room (a negative answer will imply the air is heating the room). Enter your answer using two significant digits in kW. 2 (3+1-4 marks) Fifty-five distinct numbers are randomly selected from the first 100 natural numbers. (a) Prove there must be two which differ by 10, and two which differ by 12. (b) Show there doesn't have to be two which differ by 11. (You need only construct an example in this case.) (Hint: For (a) you need to combine Pigeonhole principle with the division algorithm. The division algorithm gives you two numbers you can use to limit things for the Pigeonhole principle namely, the remainder and the quotient, and you should apply Pigeonhole on these in the order listed.) Discuss any six (6) elements that you will consider to design the Supply Chain Strategy for Supplier-Firm interface. Problem 3 (40 pts) Hong Kong's tropical typhoon season is approaching. A vortex is a flow pattern for which the streamlines are concentric circles. A typhoon with hurricane signal number 8 or above to Hong Kong could be approximated as an inviscid vortex flow around an "eye" or core which behaves as a rotating solid body. (i) Using Laplace's equation, find v,and ve for inviscid vortex flow. (ii) A rough rule of thumb is that the radius of the eye of a typhoon is 30 m. What is the pressure in the eye of a typhoon with a maximum velocity of 50 m/s, assuming normal atmospheric pressure far afield? 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