magnitude of the normal force exerted by en in the figure below. What is the
A suitcase of mass mis resting on an inclined plane
?

Answer:

A) i) using statistical theory of floxy

(Pa)c = 0.816

(Pb)c = 0.816

ii) using Carothers theory

( Pc ) = 0.917

B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol  will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different

Explanation:

Given data :

Polycondensation reaction takes place between : 1.2 moles of dicarboxylic acid , 0.4 moles of glycerol and 0.6 moles of ethylene glycol

A) Calculate the critical extents of reaction for gelation

i) using statistical theory of floxy

(Pa)c = 0.816

(Pb)c = 0.816

ii) using Carothers theory

( Pc ) = 0.917

attached below is the detailed solution

B) To Obtain the measured value of critical extent of reaction ( 0.866) 1 mol of Glycerol  will react with 1 mol of dicarboxylic acid, but the same can not be applied to our obtained value because our stoichiometry is different

Answer:

Power = Work / Time

P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s

= 392 Watts

The magnitude of power the monkey demonstrated is equal to 392 J/S.

To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:

                                              [tex]P = \frac{m\times g\times d}{t}[/tex]

Thus, applying the values ​​given by the statement we have:

                                          [tex]P = \frac{80 \times 9.8 \times 15}{30}[/tex]

                                           [tex]P = 392 J/s[/tex]

So, the power performed by the monkey climbing 15 meters is equal to 392J/s.

Learn more about power in: brainly.com/question/8671146

Answer:

yes it is a great question. Thank you .

Answer:

Explanation:

From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.

So, in light of that, to determine the electric charges values & signs on each of them, we have:

on a = +3 C

on b = -7 C

on c = -7 C

on d = +3 C

on e = -7 C

Answer:

–I6 N

Explanation:

From the question given above, the following data were obtained:

Spring constant (K) = 80 N/m

Initial position = 0.6 m

Final position = 0.4 m

Force (F) =?

Next, we shall determine the compression of the spring. This can be obtained as follow:

Initial position = 0.6 m

Final position = 0.4 m

Compression (x) =?

Compression = Final position – Initial position

Compression (x) = 0.4 – 0.6

Compression (x) = – 0.2 m

Finally, we shall determine the force. This can be obtained as follow:

Spring constant (K) = 80 N/m

Compression (x) = – 0.2 m

Force (F) =?

F = Kx

F = 80 × –0.2

F = –I6 N

Answer:

The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Explanation:

Given the data in the question;

from the Newton's second law of motion;

F = ma

where m is the mass, a is acceleration and F is the force exerted on the pipe due to the airflow in it

now in terns of mass flow;

F = [tex]m^{"}[/tex]V

where [tex]m^{"}[/tex] is the mass flow rate, V is the velocity(

so

[tex]m^{"}[/tex] = pAV

[tex]m^{"}[/tex] = p × ([tex]\frac{\pi }{4}[/tex] d² ) × V

where d is the diameter of the pipe( 0.5 m)

p is the density( 1.23 kg/m³ )

velocity v is 100 m/s

so we substitute

[tex]m^{"}[/tex] = 1.23 × ([tex]\frac{\pi }{4}[/tex] (0.5)² ) × 100

[tex]m^{"}[/tex] = 30.75 × [tex]\frac{\pi }{4}[/tex]

[tex]m^{"}[/tex] = 24.15 kg/s

Now lets write the equation for the force exerted on the pipe by the airflow

F = [tex]m^{"}[/tex]( V₁ - V₂)

where V₁ is velocity at inlet ( 100 m/s )

V₂ is velocity at exit ( - 100 m/s )

so we substitute

F = 24.15 ( 100 - (-100))

F = 24.15 × 200

F = 4830 N

The pipe is symmetric about horizontal axis so the force should also b acting only in the horizontal direction since any force component in the vertical direction is nullified due to this symmetry

Therefore, The magnitude of the force exerted on the pipe by the air is 4830 N and it acts horizontally

Answer:

17280 J or 17.28 kJ

Explanation:

Given that the voltage drop,

U = U2 - U1

U = 9 - 6

U = 3V

Also, we're told that the current, I is equal to 20 mA with the discharge time, t being 80 hrs.

Converting the time from h oi urs to seconds, we have

t = 80 * 3600

t = 288000

Now, to find the energy needed, we're going to use the formula

w = pt, where p = U * I

p = 3 * 20*10^-3

p = 60*10^-3

w = 60*10^-3 * 288000

w = 17280 J or 17.28 kJ

Therefore, the total energy the battery delivers in the 80 hrs is 17.28 kJ

Answer:

chinese

Explanation:

Answer:

B chinese

hope this helps you

Answer:

I don't understand the question

Explanation:

sorry I cant help because I am just a first former

Question:

A particle is trapped in a 20 nm wide infinite potential well. What is the wavelength of the particle corresponding to n = 7 in nm?

Answer:

[tex]\lambda_n = 5.71\ nm[/tex]

Explanation:

Given

[tex]L = 20nm[/tex] --- the width

[tex]n = 7[/tex]

Required

Determine the wavelength ([tex]\lambda[/tex])

This is calculated as:

[tex]\lambda_n = \frac{2L}{n}[/tex]

Substitute values for L and n

[tex]\lambda_n = \frac{2*20nm}{7}[/tex]

[tex]\lambda_n = \frac{40nm}{7}[/tex]

[tex]\lambda_n = \frac{40}{7}nm[/tex]

[tex]\lambda_n = 5.71428571\ nm[/tex]

[tex]\lambda_n = 5.71\ nm[/tex] --- approximated to 3 significant figures

Answer:

true

Explanation:

Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Heavier objects also have more friction because they press together with greater force. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.

Explanation:

true but not going to copy and paste,

Answer:

Explanation:

emf   due to movement of a rod of length L in a perpendicular to magnetic field B with velocity v is given as

emf = BLv

Putting in the given values ,

E = 2.45 x 12.5 x 10⁻² x 2.4

= .735 V

This emf produces current in resistance . Power consumed by resistance

V² / R where R is resistance , V is emf induced .

Power = .735² / 1.2

= .45 W .

Answer:

The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period

Answer:

High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.

Where's the following words?

Answer:

No kinetic energy-because there is no movement

Explanation:

It states that the monk is at complete rest so there is no movement.

Answer:

B

Explanation:

Acid reacts with base to give salt and water.

HCL - Acid

Mg(OH)2 - Base

H2O - Water

MgCl2 - Salt

Answer: B because A p e x

Explanation:

Answer:

The net force will be:

[tex] F_{net} = 142.53\: N[/tex]

Explanation:

The net force is given by:

[tex] F_{net} = W_{b}+F[/tex]

[tex] F_{net} = m_{b}g+15[/tex]

[tex] F_{net} = 142.53\: N[/tex]

I hope it helps you!

Answer:

1)  LIQUID, 2) LIQUID, 3) GASEOU, 4)  GASEOUS,    v = 0.76 m³ / kg

Explanation:

In this exercise it is asked to determine the state of the water, that is, if it is solid, liquid or gas. For this we must use a phase diagram of water which is a graph of Pressure versus Temperature. Let's describe the water diagram

* Below 0ºC and normal pressure the water is in a solid state

* Below this temperature and at low pressure it becomes a gaseous state

* Above 0.01ºC and normal pressure is in liquid state

* Above 0.01ºC and low pressure is in a gaseous state

there are two important points

* The triple point at t + 0.01ºC and P = 0.006 atm where the three states coexist

* The critical point T = 374ºC and P = 218 atm where water decomposes into hydrogen and oxygen

Specific volume is related to density

        v = 1 / ρ

        ρ = 1 / v

the density of water is approximately 1000 kg / m³ in the liquid state at t = 4ºC and decreases with increasing pressure 960 kg / m³ at T = 100ºC (but without changing to the gaseous state

With the above considerations we can answer the questions

1) P = 300 kPa = 3 105 Pa

   v = 0.5 m³ / kg

atmospheric pressure is Patm = 1.01 105 Pa

     P = 3 105 Pa (1 atm / 1.01 105 Pa) = 3 atm

From the phase diagram described, the water can be in two liquid or gaseous states, depending on the temperature, as indicated by the speed of the same state, the water must be LIQUID

the parameter v that you indicate is the

with the other parameter we can calculate the density

     rho = 1 / 0.5

     rho = 2.0 kg / m³

in a thermodynamic system the three basic properties are: pressure, volume and temperature,

we can calculate the body temperature

The body must be at a temperature between 0 <T <100ºC

2) P = 28 Mpa = 28 106 Pa

   P = 28 106 Mpa (1 atm / 1.01 105 Pa) = 280 atm

   T = 200ºC

When examining the diagram it can be seen that the water is in the range of the LIQUID state

3) P = 1MPa

   P = 1 106 Pa (1atm / 1.01 105Pa) = 10 atm

   T = 405ºC

In this case, the only accessible state is the GASEOUS

4) T = 100ºC

     x = 60%

Examining the phase diagram at this temperature depending on the pressure the possible states are Vapor and liquid, for pressures below 1 atm the state is GASEOUS

for the gaseous state we can use the ideal gas equation

            PV = nR T

let us perform the calculation for a mole of gas n = 1, the ideal gas constant is R = 8,206 10-2 atm / mol K

          V = nRT / p

           V = 1 8,206 10-2 100/1

           V = 8,206 m³

          v = V / m

The mass of the water is 18 Kg / mol, which indicates that 60% is in the gaseous state, so the mass in this state is

         m = 0.60 18

         m = 10.8 kg

          v = 8.206 / 10.8

          v = 0.76 m³ / kg

Answer:

a)   E = 1.69 10⁶6 N / C,  b)  F = 3.38 10⁶ N

Explanation:

a)  In this exercise using Gauss's law we can consider the charge of the generator sphere as if it were at its center, therefore the electric field is

          E = k [tex]\frac{q}{r^2}[/tex]

let's calculate

         E = 9 10⁹ 3.00 10⁻³ / 4²2

         E = 1.6875 10⁶ N / C

          E = 1.69 10⁶6 N / C

b) let's calculate the electric force

          F = q E

          F = 2.00 1.69 10⁶

          F = 3.38 10⁶ N

Answer:2

Explanation:

spray him in the eyes and you have until he washes it put

Answer:

300

Explanation Hope I'm not wrong.

Answer:

L = 30.85 m

Explanation:

First, we calculate the resistance of the wire by using Ohm's Law:

V = IR

where,

V = Potential Difference = 1.5 V

I = Current = 0.42 A

R = Resistance of Wire = ?

Therefore,

[tex]R = \frac{1.5\ V}{0.42\ A}\\\\R = 3.57\ Ohms[/tex]

Now, the cross-sectional area of wire will be:

[tex]Area = A = \frac{\pi d^{2}}{4}\\\\A = \frac{\pi (0.00054\ m)^{2}}{4}\\\\A = 2.29\ x\ 10^{-7}\ m^{2}[/tex]

Now, the resistance of the wire is given as:

[tex]R = \frac{\rho L}{A}\\\\L = \frac{RA}{\rho}[/tex]

where,

L = Length of Wire = ?

ρ = resistivity of aluminum = 2.65×10⁻⁸ Ohm.m

Therefore,

[tex]L = \frac{(3.57\ Ohms)(2.29\ x\ 10^{-7}\ m^{2})}{2.65\ x\ 10^{-8}\ Ohm.m}[/tex]

L = 30.85 m

Answer:

write something like after the spacecraft launched all of the potential energy transformed into kinetic energy causing the spacecraft to go at an abnormal spped.

Explanation:

Answer: i use this in ss class

Explanation:

Explanation:

It depends upon the magnitude of the charge, the velocity of the particle and its strength .