Look the the question below

Answer:

QR= 16

Step-by-step explanation:

HOPE THIS HELPS

Answer:

122

Step-by-step explanation:

[tex]x^6+y^2[/tex]

Plug in 1 for x and 11 for y

[tex]=1^6+11^2[/tex]

1 to the power of any number will always equal 1

[tex]=1+11^2\\=1+121\\=122[/tex]

I hope this helps!

Answer:

X= 38

Step-by-step explanation:

A straight line is 180⁰ so we can subtract that by 133⁰ to get the degree on the inside of the triangle which is 47. You then add 47 and 95 to get 142. To get x you subtract 142 from 180

Answer:

Step-by-step explanation:

Adjacent angles of parallelogram are supplementary.

∠A + ∠D = 180

Divide both sides by 2

[tex]\frac{1}{2}[/tex] ∠A + [tex]\frac{1}{2}[/tex] ∠D = 90

∠PAD + ∠ADP = 90       --------------------(I)

IN ΔPAD,

∠PAD + ∠ADP + ∠APD = 180 {angle sum property of triangle}

90  + ∠APD = 180         {from (I)}

          ∠APD = 180 - 90

         ∠APD = 90

∠SPQ = ∠APD             {vertically opposite angles}

∠SPQ = 90°

Similarly, we can prove ∠PQR = 90° ; ∠QRS = 90° and ∠RSP = 90°

In a quadrilateral if each angle is 90°, then it is a rectangle.

PQRS is a rectangle.

Answer:

It is B and D

Step-by-step explanation:

They are both x and y functions

Answer:

Wut

Step-by-step explanation:

Answer:

4(2s +5)

Step-by-step explanation:

.............

Answer:

-6 -4 3 7

Step-by-step explanation:

This is right because if it goes- it goes lower and if it goes up on + it goes higher.

Answer:

-6, -4, 3, 7

Step-by-step explanation:

First you need to know that negative numbers are smaller than positive numbers, the larger the number beside the negative sign is, the smaller the number.

Answer:

33

Step by step explanation of the answer

As you said, the equation is separable:

dy/dt = 2t / exp(y)

exp(y) dy = 2t dt

Integrate both sides:

∫ exp(y) dy = ∫ 2t dt

exp(y) + C₁ = t ² + C₂

Move the constant terms to one side. When you add them together, you get another constant, so you can ignore the subscript altogether:

exp(y) = t ² + C

Solve for y explicitly by taking the logarithm of both sides:

ln(exp(y)) = ln(t ² + C )

y = ln(t ² + C )

C can be any number; if it happens to be 0, then you have

y = ln(t ²) = 2 ln(t )

so B is the correct choice.

You can also approach this from the opposite angle: Assume y is one of the given solutions, then substitute it into the ODE. (Bit more trial-and-error involved, so not a good idea if you're short on time.)

For example, if y = 2 exp(t ) as in choice A, you have dy/dt = 2 exp(t ), so the ODE would become

2 exp(t ) = 2t / exp(2 exp(t ))

which is clearly (I hope) not true.

Answer:

by adding. positive, you move towards right.

Answer:

Right

Step-by-step explanation:

when looking at a number line, you will see 0, and you will notice all numbers go from 0 to the right in an increasing manner, so it would be 0, then 1, then 2, then 3....

its the other way for negative numbers tho, so (from a line of negative numbers) -3, then -2, then -1, then 0

a good way to remember is to imagine a race, you want to gain progress and go further away from the start (0) so the RIGHT way to go would be UP the number line and INCREASE your progress

Answer:

The dimensions of the field to maximise the area are 100 metres (width) and  200 metres (height).

Step-by-step explanation:

The formulas for the area ([tex]A[/tex]), measured in square metres, and the perimeter ([tex]p[/tex]), measured in metres, of the rectangle are, respectively:

[tex]A = x\cdot y[/tex] (1)

[tex]p = 2\cdot x +y[/tex] (2)

Where:

[tex]x[/tex] - Width, measured in metres.

[tex]y[/tex] - Height, measured in metres.

Note: We assume that height of the rectangle is parallel to the wall of the house.

By (2):

[tex]y = p - 2\cdot x[/tex]

In (1):

[tex]A = x\cdot (p-2\cdot x)[/tex]

[tex]A = p\cdot x - 2\cdot x^{2}[/tex] (3)

Then, we obtain its first and second derivatives by Differential Calculus:

[tex]A' = p - 4\cdot x[/tex] (4)

[tex]A'' = -4[/tex] (5)

By equalising (4) to zero, we find the following critical value for [tex]x[/tex]:

[tex]x = \frac{p}{4}[/tex]

And besides the Second Derivative Test, this solution is associated to an absolute maximum. Given that [tex]p = 400\,m[/tex], then the maximum area enclosed by fencing is:

[tex]x = 100\,m[/tex]

[tex]A = 20000\,m^{2}[/tex]

And the height of the triangle is:

[tex]y = 200\,m[/tex]

The dimensions of the field to maximise the area are 100 metres (width) and  200 metres (height).

Answer:

1/5

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Use the Pythagorean Theorem to solve.

10 squared minus 8 squared=36

Square rt = 6

6 + 6=12

The length, in centimeters, of AC should be considered as the 12

Since

In ABC, BD is perpendicular to AC. The dimensions are shown in centimeters.

So here the length should be like

= 10^2 - 8^2

= 100 - 64

= 36

= 6

So for AC it should be

=  6+ 6

= 12

Hence, The length, in centimeters, of AC should be considered as the 12

Learn more about length here: https://brainly.com/question/12497184

Step-by-step explanation:

    There is a rule that if c^2 > a^2 + b^2, then it is an obtuse triangle.

    *c is the longest side

     I attached more information on it below.

Answer:

I believe D. B12

Answer:

x<-13

Step-by-step explanation:

−3(x+3)>30

Divide both sides by −3. Since −3 is negative, the inequality direction has changed.

x+3<30/-3

Divide 30 by −3 to get −10.

x+3<−10

Subtract 3 from both sides.

x<−10−3

Subtract 3 from −10 to get −13.

x<−13

Graph for inequality:

Answer: 8

Step-by-step explanation:

(8 - 4) = 4

so then,

7(8 - 4) = 28

Answer:

y - 7 =  [tex]-\frac{1}{4}[/tex] (x - 4)

Step-by-step explanation:

Find Slope: m = [tex]\frac{y_{2-}y_{1} }{x_{2-}x_{1} }[/tex]

m = [tex]\frac{6-(7)}{8-(4)}[/tex]

m = [tex]\frac{-1}{4}[/tex]

Point Slope Form: y - [tex]y_{1}[/tex] = m ( x - [tex]x_{1}[/tex] )

y - 7 = [tex]-\frac{1}{4}[/tex] (x - 4)

Answer:

1. Ella can scale it up by 3 or by using the ratio 3:1, the smaller bed is exactly 1/3 of the bigger bed.

2A. No I am way taller than the 75".

2B. Ella can scale the bed up by 7:1 so that it can fit me.

Step-by-step explanation:

See diagram below.

===========================================================

Explanation:

The highest point on f(x) is the vertex point since the leading coefficient is negative. The vertex is located at (h,k)

For the general parabola y = ax^2 + bx + c, we can define h to be

h = -b/(2a)

In this case, we plug in a = -2 and b = 8 to find h to be...

h = -b/(2a)

h = -8/(2*(-2))

h = -8/(-4)

h = 2

Then the value of k is equal to f(h). So we plug x = 2 into the f(x) function to get

f(x) = -2x^2 + 8x - 1

f(2) = -2(2)^2 + 8(2) - 1

f(2) = -2(4) + 8(2) - 1

f(2) = -8 + 16 - 1

f(2) = 8 - 1

f(2) = 7

This means k = 7

So the vertex for f(x) is at (h,k) = (2,7)

The max value of f(x) is f(x) = 7 which is the same as y = 7.

The graph shows the highest point is at (0,10). The highest point of g(x) is when y = 10. So this is the largest g(x) can get. We only are concerned with output values when we want to maximize whatever the function is.

Therefore, g(x) produces the larger maximum value compared to f(x).

We can see that if we were to graph both f(x) and g(x) together. The g(x) curve peaks higher compared to f(x).

The diagram is shown below. I used GeoGebra to make the graph, though you could use Desmos or a TI calculator (or similar) if you want.

Answer:

The answer is b

Step-by-step explanation: