Let's go to the movies: A random sample of 44 Foreign Language movies made since 2000 had a mean length of 110.8 minutes, with a standard deviation of 14.5 minutes. Part: 0/2 Part 1 of 2 Construct a 98% confidence interval for the true mean length of all Foreign Language movies made since 2000. Round the answers to one decimal place. A 98% confidence interval for the true mean length of all Foreign Language movies made since 2000 is << Get an education: In 2012 the General Social Survey asked 847 adults how many years of education they had. The sample mean was 8.55 years with a standard deviation of 8.52 years. Part: 0/2 Part 1 of 2 Construct a 99.9% interval for the mean number of years of education. Round the answers to two decimal places. A 99.9% confidence interval for the mean number of years of education is

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Answer 1

To construct a 98% confidence interval for the true mean length of all Foreign Language movies made since 2000, we can use the formula:

Confidence Interval = sample mean ± (critical value * standard error)

First, we need to calculate the standard error, which is given by the formula:

Standard Error = standard deviation / √(sample size)

Given:

Sample mean () = 110.8 minutes

Standard deviation (σ) = 14.5 minutes

Sample size (n) = 44

Standard Error = 14.5 / √44 ≈ 2.184

Next, we need to find the critical value for a 98% confidence level. Since the sample size is large (n > 30), we can use the Z-distribution. The critical value for a 98% confidence level is approximately 2.33.

Now, we can calculate the confidence interval:

Confidence Interval = 110.8 ± (2.33 * 2.184)

Confidence Interval ≈ (105.9, 115.7)

Therefore, the 98% confidence interval for the true mean length of all Foreign Language movies made since 2000 is approximately 105.9 to 115.7 minutes.

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Related Questions

Find the given quantity if v = 2i - 5j + 3k and w= -3i +4j - 3k. ||v-w|| |v-w|| = (Simplify your answer. Type an exact value, using fractions and radica

Answers

The quantity ||v - w|| simplifies to √142.

To find the quantity ||v - w||, where v = 2i - 5j + 3k and w = -3i + 4j - 3k, we can calculate the magnitude of the difference vector (v - w).

v - w = (2i - 5j + 3k) - (-3i + 4j - 3k)

= 2i - 5j + 3k + 3i - 4j + 3k

= (2i + 3i) + (-5j - 4j) + (3k + 3k)

= 5i - 9j + 6k

Now, we can calculate the magnitude:

||v - w|| = √((5)^2 + (-9)^2 + (6)^2)

= √(25 + 81 + 36)

= √142

Therefore, the quantity ||v - w|| simplifies to √142.

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Find all critical points of the function f(x, y) = 4xy-3x + 7y-x² - 8y² This critical point is
a: Select an answer
If critical point is Min or Max, then the value of f is point is______ (Type-1 if the critical saddle)

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To find the critical points of the function f(x, y) = 4xy - 3x + 7y - x² - 8y², we need to find the points where the partial derivatives with respect to x and y are equal to zero.

The partial derivative with respect to x:

∂f/∂x = 4y - 3 - 2x.

The partial derivative with respect to y:

∂f/∂y = 4x + 7 - 16y.

Setting both partial derivatives equal to zero, we have the following system of equations:

4y - 3 - 2x = 0,

4x + 7 - 16y = 0.

Solving this system of equations, we can find the critical point.

From the first equation, we can solve for x:

2x = 4y - 3,

x = 2y - 3/2.

Substituting this expression for x into the second equation, we have:

4(2y - 3/2) + 7 - 16y = 0,

8y - 6 + 7 - 16y = 0,

-8y + 1 = 0,

8y = 1,

y = 1/8.

Substituting this value of y back into the expression for x, we have:

x = 2(1/8) - 3/2,

x = 1/4 - 3/2,

x = -5/4.

Therefore, the critical point is (x, y) = (-5/4, 1/8).

the critical point is (x, y) = (-5/4, 1/8), and the value of f at the critical point is 55/8.

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Find a unit vector that is normal (or perpendicular) to the line 7x + 5y = 3. Write the exact answer. Do not round. Answer 2 Points 國 Ke Keyboards

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A unit vector normal to the line 7x + 5y = 3 is (7/√74, 5/√74).

We have,

To find a unit vector normal to the line 7x + 5y = 3, we need to determine the direction vector of the line and then normalize it to have a length of 1.

The direction vector of the line is the coefficients of x and y in the equation, which is (7, 5).

To normalize this vector, we divide each component by the magnitude of the vector:

Magnitude of (7, 5) = √(7² + 5²) = √74

Normalized vector = (7/√74, 5/√74)

Therefore,

A unit vector normal to the line 7x + 5y = 3 is (7/√74, 5/√74).

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find the vertex, focus, and directrix of the parabola. y2 6y 3x 3 = 0 vertex (x, y) = focus (x, y) = directrix

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the vertex, focus, and directrix of the given parabola are given by:
Vertex: (h, k) = (- 2, - 3)

Focus: (h - a, k) = (- 2 - 3/4, - 3)

= (- 11/4, - 3)

Directrix: x = - 5/4.

The equation of the given parabola is y² + 6y + 3x + 3 = 0. We are to find the vertex, focus, and directrix of the parabola.

We can rewrite the given equation in the form: y² + 6y = - 3x - 3 + 0y + 0y²

Completing the square on the left side, we get:

(y + 3)²

= - 3x - 3 + 9

= - 3(x + 2)

This is in the standard form (y - k)² = 4a(x - h), where (h, k) is the vertex. Comparing this with the standard form, we have: h = - 2,

k = - 3.

So, the vertex of the parabola is V(- 2, - 3).Since the parabola opens left, the focus is located a units to the left of the vertex,

where a = 1/4|4a|

= 3/4

The focus is F(- 2 - 3/4, - 3) = F(- 11/4, - 3).

The directrix is a line perpendicular to the axis of symmetry and is a distance of a units from the vertex.

Therefore, the directrix is the line x = - 2 + 3/4

= - 5/4.

Therefore, the vertex, focus, and directrix of the given parabola are given by:

Vertex: (h, k) = (- 2, - 3)

Focus: (h - a, k) = (- 2 - 3/4, - 3)

= (- 11/4, - 3)

Directrix: x = - 5/4.

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.Find the standard form of the equation of the ellipse satisfying the given conditions.
Endpoints of major​ axis: ​(−6​,1​) and​(−6​,−13​)
Endpoints of minor​ axis: (−2​,−6​) and​(−10​,−6​)

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The center has $y$-coordinate of $-6$. So, the center is at $(-6,-6)$. Now let us calculate the distances between the center and the endpoints of the major and minor axes:Length of major axis is $d_{1}=2a=2\times10=20$unitsLength of minor axis is $d_{2}=2b=2\times4=8$units.

To find the standard form of the equation of the ellipse satisfying the given conditions, we can use the formula below, which is the standard form of the equation of an ellipse centered at the origin:$\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$where $a$ is the distance from the center to the vertices along the major axis, and $b$ is the distance from the center to the vertices along the minor axis. To determine the values of $a$ and $b$, we need to find the distance between the given endpoints of the major and minor axes, respectively.Using the distance formula, we have:$\begin{aligned}a &= \frac{1}{2}\sqrt{(6 - (-6))^2 + (1 - (-13))^2}\\&= \frac{1}{2}\sqrt{12^2 + 14^2}\\&= \frac{1}{2}\sqrt{400}\\&= 10\end{aligned}$Therefore, $a = 10$. Similarly, we have:$\begin{aligned}b &= \frac{1}{2}\sqrt{(-10 - (-2))^2 + (-6 - (-6))^2}\\&= \frac{1}{2}\sqrt{8^2}\\&= 4\end{aligned}$Therefore, $b = 4$.Now, since the center of the ellipse is not given, we need to find it. The center is simply the midpoint of the major axis, which is:$\left(-6, \frac{1 - 13}{2}\right) = (-6, -6)$Therefore, the standard form of the equation of the ellipse is:$\frac{(x + 6)^2}{10^2} + \frac{(y + 6)^2}{4^2} = 1$Answer:More than 100 words. Standard form of the equation of an ellipse is given as $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2} =1$.Where $(h,k)$ are the coordinates of the center of the ellipse. Here the given endpoints of the major axis are $(-6,1)$ and $(-6,-13)$; thus, the major axis lies on the line $x = -6$. We can say that the midpoint of the major axis, which is also the center of the ellipse, has $x$-coordinate of $-6$. Similarly, the given endpoints of the minor axis are $(-2,-6)$ and $(-10,-6)$; hence the minor axis lies on the line $y=-6$.Therefore, the center has $y$-coordinate of $-6$. So, the center is at $(-6,-6)$. Now let us calculate the distances between the center and the endpoints of the major and minor axes:Length of major axis is $d_{1}=2a=2\times10=20$unitsLength of minor axis is $d_{2}=2b=2\times4=8$unitsFrom the equation, we have $a=10$ and $b=4$. Thus the equation of the ellipse is: $\frac{(x+6)^2}{10^2}+\frac{(y+6)^2}{4^2}=1$

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(2) Give the 2 x 2 matrix that will first shear vectors on the plane vertically by factor 2, then rotate counter-clockwise about the origin by, and finally reflect across the line y = 1. Find the image of a = (1.0) under this transformation and make a nice sketch

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The main answer: The 2 x 2 matrix that performs the given transformations is:

[[1, 2],

[-1, 1]]

What is the matrix that can be used to shear vectors vertically by a factor of 2, rotate them counter-clockwise about the origin, and reflect them across the line y = 1?

The given transformation involves three operations: vertical shearing by a factor of 2, counter-clockwise rotation, and reflection across y = 1. To perform these operations using a matrix, we can multiply the transformation matrices for each operation in the reverse order. The vertical shear matrix is [[1, 2], [-1, 1]], the rotation matrix depends on the angle, and the reflection matrix is [[1, 0], [0, -1]].

By multiplying these matrices, we obtain the combined transformation matrix. To find the image of the point a = (1, 0) under this transformation, we multiply the matrix with the vector (1, 0). The resulting transformed point can be plotted on a coordinate system to create a sketch.

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The Fourier expansion of a periodic function F(x) with period 2x is given by F(x)=a+ cos(nx)+ b. sin(nx) where F(x)cos(nx)dx 4--1 201 F(x)dx b.=--↑ F(x)sin(nx)dx Consider the following periodic function f(0) with period 2x, which is defined by f(0) == -π

Answers

Fourier series is a powerful mathematical tool used in solving partial differential equations that describe complex physical phenomena.

It is a way of expressing a periodic function in terms of an infinite sum of sines and cosines.

The Fourier expansion of a periodic function F(x) with period 2x is given by,

F(x) = a + Σcos(nx) + b. sin(nx)

where a, b are constants, n is an integer, and x is a variable.

The Fourier coefficients are given by

[tex]a0 = (1/2x) ∫_(-x)^(x)▒〖F(x) dx 〗an = (1/x) ∫_(-x)^(x)▒〖F(x)cos(nx)dx 〗bn = (1/x) ∫_(-x)^(x)▒〖F(x)sin(nx)dx 〗[/tex]

Consider the following periodic function f(0) with period 2x, which is defined by

f(0) = -πSo,

we have to calculate the Fourier coefficients of the function

[tex]f(0).a0 = (1/2x) ∫_(-x)^(x)▒f(0) dx = (1/2x) ∫_(-x)^(x)▒(-π)dx= -π/xan = (1/x) ∫_(-x)^(x)▒f(0)cos(nx)dx = (1/x) ∫_(-x)^(x)▒(-π) cos(nx) dx= (2π/ nx) (1- cos(nx))bn = (1/x) ∫_(-x)^(x)▒f(0)sin(nx)dx = (1/x) ∫_(-x)^(x)▒(-π) sin(nx) dx= 0[/tex]

Therefore, the Fourier expansion of the given function f(0) is,F(x) = -π + Σ(2π/ nx) (1- cos(nx)) cos(nx) where n is an odd integer.

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Mrs Rodriguez , a highschool school teacher in Arizona, claims that the average scores on a Algebra Challenge for 10th grade boys is not significantly different than that of 10th grade girls. The mean score for 24 randomly sampled girls is 80.3 with a standard deviation of 4.2, and the mean score of 19 randomly sampled boys is 84.5 with a standard deviation of 3.9. At alpha equal 0.1, can you reject the Mrs. Rodriguez' claim? Assume the population are normally distributed and variances are equal. (Please show all steps) .
a. Set up the Hypotheses and indicate the claim
b. Decision rule
c. Calculation
d. Decision and why?
e. Interpretation

Answers

a. Set up the Hypotheses and indicate the claim:

Null hypothesis (H0): The average scores on the Algebra Challenge for 10th grade boys [tex]($\mu_b$)[/tex] is the same as that of 10th grade girls [tex]($\mu_g$)[/tex].

Alternative hypothesis (H1): The average scores on the Algebra Challenge for 10th grade boys [tex]($\mu_b$)[/tex] is significantly different than that of 10th grade girls [tex]($\mu_g$).[/tex]

Claim by Mrs. Rodriguez: The average scores on the Algebra Challenge for 10th grade boys is not significantly different than that of 10th grade girls.

b. Decision rule:

The decision rule can be set up by determining the critical value based on the significance level [tex]($\alpha$)[/tex] and the degrees of freedom.

Since we are comparing the means of two independent samples and assuming equal variances, we can use the two-sample t-test. The degrees of freedom for this test can be calculated using the following formula:

[tex]\[\text{df} = \frac{{(\frac{{s_g^2}}{{n_g}} + \frac{{s_b^2}}{{n_b}})^2}}{{\frac{{(\frac{{s_g^2}}{{n_g}})^2}}{{n_g-1}} + \frac{{(\frac{{s_b^2}}{{n_b}})^2}}{{n_b-1}}}}\][/tex]

where:

- [tex]$s_g$ and $s_b$[/tex] are the standard deviations of the girls and boys, respectively.

- [tex]$n_g$ and $n_b$[/tex] are the sample sizes of the girls and boys, respectively.

Once we have the degrees of freedom, we can find the critical value (t-critical) using the t-distribution table or a statistical calculator for the given significance level [tex]($\alpha$).[/tex]

c. Calculation:

Given data:

[tex]$n_g = 24$[/tex]

[tex]$\bar{x}_g = 80.3$[/tex]

[tex]$s_g = 4.2$[/tex]

[tex]$n_b = 19$[/tex]

[tex]$\bar{x}_b = 84.5$[/tex]

[tex]$s_b = 3.9$[/tex]

We need to calculate the degrees of freedom (df) using the formula mentioned earlier:

[tex]\[\text{df} = \frac{{(\frac{{s_g^2}}{{n_g}} + \frac{{s_b^2}}{{n_b}})^2}}{{\frac{{(\frac{{s_g^2}}{{n_g}})^2}}{{n_g-1}} + \frac{{(\frac{{s_b^2}}{{n_b}})^2}}{{n_b-1}}}}\][/tex]

[tex]\[\text{df} = \frac{{(\frac{{4.2^2}}{{24}} + \frac{{3.9^2}}{{19}})^2}}{{\frac{{(\frac{{4.2^2}}{{24}})^2}}{{24-1}} + \frac{{(\frac{{3.9^2}}{{19}})^2}}{{19-1}}}}\][/tex]

After calculating the above expression, we find that df ≈ 39.484.

Next, we need to find the critical value (t-critical) for the given significance level [tex]($\alpha = 0.1$)[/tex] and degrees of freedom (df). Using a t-distribution table or a statistical calculator, we find that the t-critical value is approximately ±1.684.

d. Decision and why?

To make a decision, we compare the calculated t-value with the t-critical value.

The t-value can be calculated using the following formula:

[tex]\[t = \frac{{\bar{x}_g - \bar{x}_b}}{{\sqrt{\frac{{s_g^2}}{{n_g}} + \frac{{s_b^2}}{{n_b}}}}}\][/tex]

Substituting the given values:

[tex]\[t = \frac{{80.3 - 84.5}}{{\sqrt{\frac{{4.2^2}}{{24}} + \frac{{3.9^2}}{{19}}}}}\][/tex]

After calculating the above expression, we find that t ≈ -2.713.

Since the calculated t-value (-2.713) is outside the range defined by the t-critical values (-1.684, 1.684), we reject the null hypothesis (H0).

e. Interpretation:

Based on the results of the statistical test, we reject Mrs. Rodriguez's claim that the average scores on the Algebra Challenge for 10th grade boys is not significantly different than that of 10th grade girls. There is sufficient evidence to suggest that there is a significant difference between the mean scores of boys and girls on the Algebra Challenge.

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Find a bilinear transformation which maps the upper half plane into the unit disk and Imz outo I wisi and the point Zão onto the point wito

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Bilinear transformation which maps the upper half plane into the unit disk and Imz outo I wisi and the point Zão onto the point wito is given by:(z - Zão)/ (z - Zão) * conj(Zão))

where Zão is the image of a point Z in the upper half plane, and I wisi and Ito represent the imaginary parts of z and w, respectively.

This transformation maps the real axis to the unit circle and the imaginary axis to the line Im(w) = Im(Zão).

To prove this claim, we first note that the image of the real axis is given by:z = x, Im(z) = 0, where x is a real number.Substituting this into the equation for the transformation,

[tex]we get:(x - Zão) / (x - Zão) * conj(Zão)) = 1 / conj(Zão) - x / (Zão * conj(Zão))[/tex]

This is a circle in the complex plane centered at 1 / conj(Zão) and with radius |x / (Zão * conj(Zão))|.

Since |x / (Zão * conj(Zão))| < 1 when x > 0, the image of the real axis is contained within the unit circle.

Now, consider a point Z in the upper half plane with Im(Z) > 0. Let Z' be the complex conjugate of Z, and let Zão = (Z + Z') / 2.

Then the midpoint of Z and Z' is on the real axis, and so its image under the transformation is on the unit circle.

Substituting Z = x + iy into the transformation, we get:(z - Zão) / (z - Zão) * conj(Zão)) = [(x - Re(Zão)) + i(y - Im(Zão))] / |z - Zão|^2

This is a circle in the complex plane centered at (Re(Zão), Im(Zão)) and with radius |y - Im(Zão)| / |z - Zão|^2.

Since Im(Z) > 0, the image of Z is contained within the upper half plane and its image under the transformation is contained within the unit disk.

Furthermore, since the radius of this circle goes to zero as y goes to infinity, the transformation maps the upper half plane onto the interior of the unit disk.

Finally, note that the transformation maps Zão onto the origin, since (Zão - Zão) / (Zão - Zão) * conj(Zão)) = 0.

To see that the imaginary part of w is Im(Zão), note that the line Im(w) = Im(Zão) is mapped onto the imaginary axis by the transformation z = i(1 + w) / (1 - w).

Thus, we have found a bilinear transformation which maps the upper half plane into the unit disk and Im(z) onto Im(w) = Im(Zão) and the point Zão onto the origin.

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Solve the following differential equation by using integrating factors. y' + y = 4x, y(0) = 28

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To solve the given first-order linear differential equation y' + y = 4x, where y(0) = 28, we can use the method of integrating factors.

The integrating factor is obtained by multiplying the entire equation by the exponential of the integral of the coefficient of y. By applying the integrating factor, we can convert the left side of the equation into the derivative of the product of the integrating factor and y. Integrating both sides and solving for y gives the solution to the differential equation.  The given differential equation, y' + y = 4x, is a first-order linear equation. To solve it using the method of integrating factors, we first identify the coefficient of y, which is 1.

The integrating factor, denoted by μ(x), is calculated by taking the exponential of the integral of the coefficient of y. In this case, the integral of 1 with respect to x is simply x. Thus, the integrating factor is μ(x) = e^x.

Next, we multiply the entire equation by the integrating factor μ(x), resulting in μ(x) * y' + μ(x) * y = μ(x) * 4x.

The left side of the equation can be simplified to the derivative of the product μ(x) * y, which is d/dx (μ(x) * y). On the right side, μ(x) * 4x can be further simplified to 4x * e^x.

By integrating both sides of the equation, we obtain the solution:

μ(x) * y = ∫(4x * e^x) dx.

Evaluating the integral and solving for y, we can find the particular solution to the differential equation. Given the initial condition y(0) = 28, we can determine the value of the constant of integration and obtain the complete solution.

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6. Determine the number of terms in the arithmetic sequence below if a, is the first term, an is the last term, and S, is the sum of all the terms. a1=25, an = 297, Sn = 5635. A) 42 B) 35 C) 38 D) 27

Answers

The given arithmetic sequence is;

a1=25, an = 297 and Sn = 5635.

We need to determine the number of terms in the sequence. Using the formula for sum of n terms of an arithmetic sequence, Sn we can express the value of n as:

Sn = n/2(a1 + an)5635 = n/2(25 + 297)5635 = n/2(322)11270 = n(322)n = 11270/322n = 35

Thus, the number of terms in the arithmetic sequence below if a, is the first term, an is the last term, and S, is the sum of all the terms is 35.

Hence, option B 35 is the answer.

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For this problem, please do all 5-Steps: 1. State Null, Alternate Hypothesis, Type of test, & Level of significance. 2. Check the conditions. 3. Compute the sample test statistic, draw a picture and find the P-value. 4. State the conclusion about the Null Hypothesis. 5. Interpret the conclusion. A recent study claimed that at least 15% of junior high students are overweight In a sample of 160 students, 18 were found to be overweight At a = 0.05 test the claim Answer

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The 5 steps include stating the hypotheses and significance level, checking conditions, computing the test statistic and P-value, stating the conclusion about the null hypothesis, and interpreting the conclusion.

What are the 5 steps involved in hypothesis testing and interpreting the results for the given problem?

1. State Null, Alternate Hypothesis, Type of test, & Level of significance:

  Null Hypothesis (H0): The proportion of junior high students who are overweight is equal to or less than 15%.

  Alternative Hypothesis (H1): The proportion of junior high students who are overweight is greater than 15%.

  Type of test: One-tailed test.

  Level of significance: α = 0.05.

2. Check the conditions:

  Random sample: Assuming the sample is random. Independence: The sample students should be independent of each other.  Sample size: The sample size is large enough (n = 160) for the Central Limit Theorem to apply.

3. Compute the sample test statistic, draw a picture, and find the P-value:

  The sample test statistic can be calculated using the formula:

  z = (p - p0) / sqrt(p0(1-p0)/n)

  where p is the sample proportion, p0 is the hypothesized proportion, and n is the sample size.

  In this case, p = 18/160 = 0.1125.

  z = (0.1125 - 0.15) / sqrt(0.15(1-0.15)/160)

  After calculating the value of z, we can draw a picture and find the P-value.

4. State the conclusion about the Null Hypothesis:

  We compare the P-value with the level of significance (α = 0.05) to determine whether to reject or fail to reject the null hypothesis.

5. Interpret the conclusion:

  If the P-value is less than the level of significance (P < α), we reject the null hypothesis and conclude that there is evidence to support the claim that more than 15% of junior high students are overweight.

If the P-value is greater than the level of significance (P ≥ α), we fail to reject the null hypothesis and do not have enough evidence to support the claim.

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Let f (x, y) = (36 x3 y3,27 x4y2). Find a potential function for f (x, y). a √a |a| TT b (36 2³ y³,27 z¹y2). A sin (a)

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Separated Variable Equation: Example: Solve the separated variable equation: dy/dx = x/y To solve this equation, we can separate the variables by moving all the terms involving y to one side.

A mathematical function, whose values are given by a scalar potential or vector potential The electric potential, in the context of electrodynamics, is formally described by both a scalar electrostatic potential and a magnetic vector potential The class of functions known as harmonic functions, which are the topic of study in potential theory.

From this equation, we can see that 1/λ is an eigenvalue of A⁻¹ with the same eigenvector x Therefore, if λ is an eigenvalue of A with eigenvector x, then 1/λ is an eigenvalue of A⁻¹ with the same eigenvector x.

These examples illustrate the process of solving equations with separable variables by separating the variables and then integrating each side with respect to their respective variables.

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Completion Status 24 & Moving to another question will save this response Consider the following polynomial: P(x)=x8+2x5-x²+2 1) What is the degree of the polynomial? Answer: degree 6

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The degree of a polynomial is the highest exponent of the variable in the polynomial expression. For the given polynomial, P(x) = x⁸ + 2x⁵ - x² + 2, the degree is 8.

In the polynomial, the highest exponent of the variable 'x' is 8, which corresponds to the term x⁸. All other terms in the polynomial have exponents lower than 8. The degree of a polynomial helps determine its behavior, such as the number of roots or the shape of the graph. In this case, the polynomial has a degree of 8, indicating that it is an eighth-degree polynomial. To determine the degree of a polynomial, you look for the term with the highest exponent of the variable.

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If X,Y are two variables that have a joint normal distribution, expected values 10 and 20, and with variances 2 and 3, respectively. The correlation between both is -0.85.
1. Write the density of the joint distribution.
2. Find P(X > 12).
3. Find P(Y < 18|X = 11).

Answers

The density function of the joint normal distribution is given by;$$f_{X,Y}(x,y) = \frac{1}{2 \pi \sigma_X \sigma_Y \sqrt{1-\rho^2}} \exp{\left(-\frac{1}{2(1-\rho^2)}\left[\frac{(x-\mu_X)^2}{\sigma_X^2}-2\rho\frac{(x-\mu_X)(y-\mu_Y)}{\sigma_X \sigma_Y} + \frac{(y-\mu_Y)^2}{\sigma_Y^2}\right]\right)}$$where $\mu_X = 10$, $\mu_Y = 20$, $\sigma_X^2 = 2$, $\sigma_Y^2 = 3$ and $\rho = -0.85$.

Substituting the values;$$f_{X,Y}(x,y) = \frac{1}{2 \pi \sqrt{6.94} \sqrt{5.17} \sqrt{0.27}} \exp{\left(-\frac{1}{2(0.27)}\left[\frac{(x-10)^2}{2}-2(-0.85)\frac{(x-10)(y-20)}{\sqrt{6}\sqrt{3}} + \frac{(y-20)^2}{3}\right]\right)}$$Simplifying the exponents, the density is;$$f_{X,Y}(x,y) = 0.000102 \exp{\left(-\frac{1}{0.54}\left[\frac{(x-10)^2}{2}+\frac{2.89(x-10)(y-20)}{9} + \frac{(y-20)^2}{3}\right]\right)}$$2. To find $P(X > 12)$,

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A ship leaves port on a bearing of 40.0° and travels 11.6 mi. The ship then turns due east and travels 5.1 mi. How far is the ship from port, and what is its bearing from port? **** The ship is mi fr

Answers

Given that a ship leaves port on a bearing of 40.0° and travels 11.6 miles, the ship is 6.96 miles from port and its bearing from port is 26.4°.

Let A be the port, B be the final position of the ship and C be the turning point. Then BC is the distance travelled due east and AC is the distance travelled on the bearing of 40°. Now, let x be the distance AB i.e the distance of the ship from port. According to the question, AC = 11.6 miles BC = 5.1 miles Angle CAB = 40°

From the triangle ABC, we can write; cos 40° = BC / AB cos 40° = 5.1 / xx = 5.1 / cos 40°x = 6.96 miles

So, the distance the ship is from port is 6.96 miles. Now, to find the bearing of the ship from port, we will have to find angle ABC. From the triangle ABC, we can write; sin 40° = AC / AB sin 40° = 11.6 / xAB = 6.96 / sin 40°AB = 11.05 miles Now, in triangle ABD, tan B = BD / AD

Now, BD = AB - AD = 11.05 - 5.1 = 5.95 miles tan B = BD / AD => tan B = 5.95 / 11.6

So, angle B is the bearing of the ship from port. B = tan-1 (5.95 / 11.6)B = 26.4°

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A researcher studying the proportion of 8 year old children who can ride a bike, found that 334 children can ride a bike out of her random sample of 917. What is the sample proportion? Round to 2 decimal points (e.g. 0.45).

Answers

The sample proportion is 0.36 (rounded to 2 decimal points).

The sample proportion is the proportion of successes in a random sample taken from a population.

A proportion of sample refers to the percentage of total instances in a given dataset that possesses a certain feature or attribute.

Sample proportion is the number of successes divided by the total sample size.

Using the given information, 334 children can ride a bike out of the researcher's random sample of 917.

To calculate the sample proportion, we have to divide the number of children who can ride a bike by the total number of children in the sample.

Thus, we get:

Sample proportion = number of children who can ride a bike / total number of children in the sample.

Sample proportion = 334/917

Sample proportion = 0.364 (rounded to 3 decimal points).

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Question 1
The short run total cost curve is derived by summing the short
term variable costs and the short term fixed costs. True or
False
Question 2
The Grossman’s investment model of health does

Answers

The statement "The short-run total cost curve is derived by summing the short-term variable costs and the short-term fixed costs" is true.

The Grossman's investment model of health does exist and it is a theoretical framework that explains individuals' decisions regarding investments in health. It considers health as a form of capital that can be invested in and improved over time. The model takes into account factors such as age, income, education, and other individual characteristics to analyze the determinants of health investment and the resulting health outcomes.

In economics, the short-run total cost curve represents the total cost of production in the short run, which includes both variable costs and fixed costs. Variable costs vary with the level of output, such as labor and raw material expenses, while fixed costs remain constant regardless of the output level, such as rent and machinery costs. Therefore, the short-run total cost curve is derived by summing these two components to determine the overall cost of production.

The Grossman's investment model of health, developed by Michael Grossman, is a well-known economic model that analyzes the relationship between health and investments in health capital. The model considers health as a form of human capital that can be improved through investments, such as medical treatments, preventive measures, and health behaviors. It takes into account various factors, including individual characteristics, socioeconomic factors, and the environment, to explain individuals' decisions regarding health investment and their resulting health outcomes. The model has been influential in the field of health economics and has provided valuable insights into the determinants of health and the role of investments in promoting better health outcomes.

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The angle of elevation to the top of a tall building is found to be 8° from the ground at a distance of 1.4 mile from the base of the building. Using this information, find the height of the building.

The buildings height is ? feet.
Report answer accurate to 2 decimal places.

Answers

To find the height of the building, we can use trigonometry. We have the angle of elevation (8°) and the distance from the base of the building to the observation point (1.4 miles).

Let's convert the distance from miles to feet:
1 mile = 5280 feet
1.4 miles = 1.4 * 5280 feet = 7392 feet

Now, we can set up a right triangle with the height of the building as the opposite side, the distance to the building as the adjacent side, and the angle of elevation as the angle. Using the tangent function:

tan(angle) = opposite/adjacent

tan(8°) = height/7392

To find the height, we can rearrange the equation:

height = tan(8°) * 7392

Calculating the value:

height ≈ 0.1405 * 7392

height ≈ 1039.52 feet

Therefore, the height of the building is approximately 1039.52 feet.








If n is a positive integer, prove that (In x)" dx = (−1)ªn! If f(x) = sin(x³), find f(15) (0).

Answers

The first part of the question asks to prove that the integral of (ln x)^n dx, where n is a positive integer, is equal to (-1)^(n+1) * n!. The second part of the question asks to find f(15) when f(x) = sin(x^3).

To prove that the integral of (ln x)^n dx is equal to (-1)^(n+1) * n!, we can use integration by parts. Let u = (ln x)^n and dv = dx. By applying integration by parts repeatedly, we can derive a recursive formula that involves the integral of (ln x)^(n-1) dx. Using the initial condition of (ln x)^0 = 1, we can prove the result (-1)^(n+1) * n! for all positive integers n. To find f(15) when f(x) = sin(x^3), we substitute x = 15 into the function f(x) and evaluate sin(15^3).

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verify that rolle's theorem can be applied to the function f(x)=x3−7x2 14x−8 on the interval [1,4]. then find all values of c in the interval such that f′(c)=0.

Answers

Given function is: f(x) = x³ - 7x² + 14x - 8We are to verify Rolle's theorem on the interval [1,4] and find all values of c in the interval such that f'(c) = 0.Rolle's Theorem: Let f(x) be a function which satisfies the following conditions:i) f(x) is continuous on the closed interval [a, b].ii) f(x) is differentiable on the open interval (a, b).iii) f(a) = f(b).Then there exists at least one point 'c' in (a, b) such that f'(c) = 0.Verifying the conditions of Rolle's Theorem:We have the function f(x) = x³ - 7x² + 14x - 8Differentiating f(x) w.r.t x, we get:f'(x) = 3x² - 14x + 14For applying Rolle's Theorem, we need to verify the following conditions:i) f(x) is continuous on the closed interval [1, 4].ii) f(x) is differentiable on the open interval (1, 4).iii) f(1) = f(4).i) f(x) is continuous on the closed interval [1, 4].Since f(x) is a polynomial function, it is continuous at every real number, and in particular, it is continuous on the closed interval [1, 4].ii) f(x) is differentiable on the open interval (1, 4).Differentiating f(x) w.r.t x, we get:f'(x) = 3x² - 14x + 14This is a polynomial, and hence it is differentiable for all real numbers. Thus, it is differentiable on the open interval (1, 4).iii) f(1) = f(4).f(1) = (1)³ - 7(1)² + 14(1) - 8 = -2f(4) = (4)³ - 7(4)² + 14(4) - 8 = -2Hence, we have f(1) = f(4).Thus, we have verified all the conditions of Rolle's Theorem on the interval [1, 4].So, by Rolle's Theorem, we can say that there exists at least one point c in the interval (1, 4) such that f'(c) = 0, i.e.3c² - 14c + 14 = 0Solving the above quadratic equation using the quadratic formula, we get:c = [14 ± √(14² - 4(3)(14))]/(2·3)= [14 ± √(-104)]/6= [14 ± i√104]/6= [7 ± i√26]/3Hence, the required values of c in the interval [1, 4] are c = [7 + i√26]/3 and c = [7 - i√26]/3.

The statement "Rolle's Theorem can be applied to the function f(x) = x³ - 7x² + 14x - 8 on the interval [1, 4]" is verified as follows:

Since f(x) is a polynomial function, it is a continuous function on its interval [1,4] and differentiable on its open interval (1,4).Next, it's needed to confirm that f(1) = f(4).

Let's compute:

f(1) = (1)³ - 7(1)² + 14(1) - 8

= -2f(4) = (4)³ - 7(4)² + 14(4) - 8

= -2T

herefore, f(1) = f(4). The function satisfies the conditions of Rolle's Theorem.To find all values of c in the interval [1, 4] such that f′(c) = 0, it is necessary to differentiate the function f(x) with respect to x:f(x) = x³ - 7x² + 14x - 8f'(x) = 3x² - 14x + 14

To find the values of c in [1, 4] such that f′(c) = 0, we'll solve the equation f′(x) = 0.3x² - 14x + 14 = 0

Multiplying both sides by (1/3), we get:x² - 4.67x + 4.67 = 0

Solving the quadratic equation above, we get:x = {1.582, 2.915}

Therefore, the values of c in the interval [1,4] such that f′(c) = 0 are c = 1.582 and c = 2.915.

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.if f(x) = e^2x, find f'.f",f"",f), and look for a pattern to determine a general formula for the nth derivative of [4] f(x). Use your general formula to evaluate the nth derivative at x = 1./2 or f(n)(1/2)

Answers

Upon evaluating, the derivatives of f(x) = e^2x are as follows:

f'(x) = 2e^2x

f''(x) = 4e^2x

f'''(x) = 8e^2x

f''''(x) = 16e^2x

To find the first derivative, f'(x), we use the chain rule. The derivative of e^2x with respect to x is 2e^2x. Therefore, f'(x) = 2e^2x.

For the second derivative, f''(x), we take the derivative of f'(x) = 2e^2x. Applying the chain rule again, we get f''(x) = 4e^2x.

Continuing this process, the third derivative, f'''(x), is found by taking the derivative of f''(x) = 4e^2x. Applying the chain rule once more, we obtain f'''(x) = 8e^2x.

For the fourth derivative, f''''(x), we differentiate f'''(x) = 8e^2x, resulting in f''''(x) = 16e^2x.

By observing the pattern, we can generalize the formula for the nth derivative as f^(n)(x) = 2^n * e^2x, where n is a positive integer.

To evaluate the nth derivative at x = 1/2, we substitute x = 1/2 into the general formula, yielding f^(n)(1/2) = 2^n * e^(1/2).

Therefore, the nth derivative of f(x) = e^2x evaluated at x = 1/2 is f^(n)(1/2) = 2^n * e^(1/2).

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Only 11% of registered voters voted in the last election. Will voter participation decline for the upcoming election? Of the 338 randomly selected registered voters surveyed, 24 of them will vote in the upcoming election. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: H: ? Select an answer (please enter a decimal) H: ? Select an answ v (Please enter a decimal) c. The test statistic?v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should select an answer the null hypothesis. 8. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly lower than 11% at a = 0.01, SO there is statistically significant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be equal to 11%. The data suggest the population proportion is not significantly lower than 11% at a = 0.01, so there is statistically insignificant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be lower than 11%. The data suggest the populaton proportion is significantly lower than 11% at a = 0.01, so there is statistically significant evidence to conclude that the the percentage of all registered voters who will vote in the upcoming election will be lower than 11%.

Answers

The percentage of registered voters who will vote in the upcoming election is not significantly lower than 11% at a = 0.01.

Is there statistically significant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be lower than 11%?

In a study involving 338 randomly selected registered voters, only 24 of them (approximately 7.1%) indicated they will vote in the upcoming election. To analyze this data, we can conduct a hypothesis test at a significance level of 0.01.

The null hypothesis (H₀) states that the population percentage of registered voters who will vote in the upcoming election is equal to or higher than 11%. The alternative hypothesis (H₁) suggests that the population percentage is lower than 11%.

Using the given data, we can calculate the test statistic and the p-value. The test statistic is calculated by comparing the observed sample percentage (7.1%) to the hypothesized percentage of 11%. The p-value represents the probability of observing a sample percentage as extreme as the one obtained, assuming the null hypothesis is true.

After performing the calculations, if the p-value is less than 0.01 (the significance level), we would reject the null hypothesis and conclude that there is statistically significant evidence to support the claim that the percentage of registered voters who will vote in the upcoming election is lower than 11%.

However, if the p-value is greater than or equal to 0.01, we would fail to reject the null hypothesis, indicating that there is not enough evidence to conclude that the percentage is significantly lower than 11%.

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Simple random samples of high-interest mortgages and low-interest mortgages were obtained. For the 24 high-interest mortgages, the borrowers had a mean FICO score of 434 and a standard deviation of 35. For the 24 low-interest mortgages, he borrowers had a mean FICO credit score of 454 and a standard deviaiton of 22. Test the claim that the mean FICO score of borrowers with high- interest mortgages is different than the mean FICO score of borrowers with low-interest mortgages at the 0.02 significance level. Claim: Select an answer v which corresponds to Select an answer Opposite: Select an answer which corresponds to Select an answer The test is: Select an answer The test statistic is: t = (to 2 decimals) The critical value is: 1 (to 3 decimals) Based on this we: Select an answer Conclusion There Select an answer v appear to be enough evidence to support the claim that the mean FICO score of borrowers with high-interest mortgages is different than the mean FICO score of borrowers with low-interest mortgages.

Answers

The test is two-tailed, the test statistic is -3.46, the critical value is ±2.807, and based on this, we reject the null hypothesis, concluding that there is enough evidence to support the claim that the mean FICO score of borrowers with high-interest mortgages is different than the mean FICO score of borrowers with low-interest mortgages at the 0.02 significance level.

Claim: The mean FICO score of borrowers with high-interest mortgages is different than the mean FICO score of borrowers with low-interest mortgages.

The test is: Two-tailed.

The test statistic is: t = -3.46 (to 2 decimals).

The critical value is: ±2.807 (to 3 decimals).

Based on this, we: Reject the null hypothesis.

Conclusion: There appears to be enough evidence to support the claim that the mean FICO score of borrowers with high-interest mortgages is different than the mean FICO score of borrowers with low-interest mortgages.

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Find the exponential form of 27^3*9^2*3

Answers

Answer:

3¹⁴

------------------------

We know that:

27 = 3³ and9 = 3²

Substitute and evaluate the given expression:

27³ × 9² × 3 = (3³)³ × (3²)² × 3 = 3⁹ × 3⁴ × 3 = 3⁹⁺⁴⁺¹ =3¹⁴

1. Find the area of the region that lies inside the first curve and outside the second curve. r = 3 - 3 sin(θ), r = 3. 2. Find the area of the region that lies inside the first curve and outside the second curve. r = 9 cos(θ), r = 4 + cos(θ)

Answers

The area of the region in the curves of r = 3 - 3sin(θ) and r = 3 is 6 square units

The area in r = 9cos(θ) and r = 4 + cos(θ) is 16π/3 +8√3 square units

How to find the area of the region in the curves

From the question, we have the following parameters that can be used in our computation:

r = 3 - 3sin(θ) and r = 3

In the region that lies inside the first curve and outside the second curve, we have

θ = 0 and π

So, we have

[0, π]

This represents the interval

For the surface generated from the rotation around the region bounded by the curves, we have

A = ∫[a, b] [f(θ) - g(θ)] dθ

This gives

[tex]A = \int\limits^{\pi}_{0} {(3 - 3\sin(\theta) - 3)} \, d\theta[/tex]

[tex]A = \int\limits^{\pi}_{0} {(-3\sin(\theta))} \, d\theta[/tex]

Integrate

[tex]A = 3\cos(\theta)|\limits^{\pi}_{0}[/tex]

Expand

A = |3[cos(π) - cos(0)]|

Evaluate

A = 6

Hence, the area of the region in the curves is 6 square units

Next, we have

r = 9cos(θ) and r = 4 + cos(θ)

In the region that lies inside the first curve and outside the second curve, we have

θ = π/3 and 5π/3

So, we have

[π/3, 5π/3]

This represents the interval

For the surface generated from the rotation around the region bounded by the curves, we have

A = ∫[a, b] [f(θ) - g(θ)] dθ

This gives

[tex]A = \int\limits^{\frac{5\pi}{3}}_{\frac{\pi}{3}} {(4 + \cos(\theta) - 9\cos(\theta))} \, d\theta[/tex]

This gives

[tex]A = \int\limits^{\frac{5\pi}{3}}_{\frac{\pi}{3}} {(4 - 8\cos(\theta))} \, d\theta[/tex]

Integrate

[tex]A = (4\theta - 8\sin(\theta))|\limits^{\frac{5\pi}{3}}_{\frac{\pi}{3}}[/tex]

Expand

A = |[4 * 5π/3 - 8 * sin(5π/3)] - [4 * π/3 - 8 * sin(π/3)]|

Evaluate

A = |[4 * 5π/3 - 8 * -√3/2] - [4 * π/3 - 8 * √3/2|

So, we have

A = |20π/3 + 4√3 - 4π/3 + 4√3|

Evaluate

A = 16π/3 +8√3

Hence, the area of the region in the curves is 16π/3 +8√3 square units

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Find a basis for the subspace of P2 (the polynomials of degree 2 or less) given by
B:
=
2-1
x-
W = {p€ P2 : ['* p(x)da =
=

Answers

{1,x,x²} is a basis for subspace W.

Given

B:
=
2-1
x-
W = [tex]{p € P2 : ∫_0^1▒〖p(x)dx=0〗}[/tex]

We need to find a basis for the subspace of P2 given by W.

W is a subspace of P2 since it contains the zero vector (take p(x)=0), and if p and q are in W and c is a scalar, then

[tex](cp+q)(x) = cp(x)+q(x) and∫_0^1▒〖(cp(x)+q(x))dx= c∫_0^1▒〖p(x)dx+∫_0^1▒〖q(x)dx= 0〗+0= 0〗[/tex]

Thus,

cp+q ∈ W.

Let p(x)=ax²+bx+c, where a,b and c are real numbers.

Then

[tex]∫_0^1▒〖p(x)dx= [(a/3)x³+(b/2)x²+cx)|_0^1= (a/3)+(b/2)+c=0]⟹2a+3b+6c=0⟹a=-3/2c-b/2.[/tex]

∴ [tex]{1,x,x²}[/tex]

is a basis for W.

Note: For any k, [tex]{1,x,x²,...,x^k}[/tex]is a basis for Pk.

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Given f(x) = 3x2 - 9x + 7 and n = f(-2), find the value of 3n.

Answers

The value of 3n, where n = f(-2), is 111.

To find the value of 3n, where n = f(-2), to evaluate f(-2) using the given function:

f(x) = 3x² - 9x + 7

Substituting x = -2 into the function,

f(-2) = 3(-2)² - 9(-2) + 7

= 3(4) + 18 + 7

= 12 + 18 + 7

= 37

calculate the value of 3n:

3n = 3(37)

= 111

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Write the following numbers in the polar form r(cosθ+isinθ),0≤θ<2π
(a) 4
r=____ θ=____
(b) 7i
r=___ θ=____
(c) 7+8i
r=_____ θ=_____

Answers

(a) To express the number 4 in polar form:

r = 4

θ = 0 (since 0 ≤ θ < 2π)

The polar form of 4 is: 4(cos(0) + isin(0))

(b) To express the number 7i in polar form:

r = 7 (the absolute value of 7i)

θ = π/2 (since 0 ≤ θ < 2π)

The polar form of 7i is: 7(cos(π/2) + isin(π/2))

(c) To express the number 7+8i in polar form:

r = √(7² + 8²) = √113

θ = arctan(8/7) (taking the inverse tangent of the imaginary part divided by the real part)

The polar form of 7+8i is: √113(cos(arctan(8/7)) + isin(arctan(8/7)))

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Question 19 2 pts
We select a random sample of (36) observations from a population with mean (81) and standard deviation (6), the probability that the sample mean is more (82) is
O 0.0668
O 0.8413
O 0.9332
O 0.1587

Answers

The probability that the sample mean is more than 82 is 0.1587. Option d is correct.

Given that a random sample of 36 observations is selected from a population with mean μ = 81 and standard deviation σ = 6.

The standard error of the sampling distribution of the sample mean is given as:

SE = σ/√n

= 6/√36

= 1

Thus, the z-score corresponding to the sample mean is given as:

z = (X - μ)/SE = (82 - 81)/1 = 1

The probability that the sample mean is more than 82 can be calculated using the standard normal distribution table.

Using the table, we can find that the area to the right of z = 1 is 0.1587.

Hence, option D is the correct answer.

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At the end of the current period, the fund contained $38 and had the following receipts: entertainment, $51 postage, $23; and printing. $8. Prepare journal entries to record (a) establishment of the fund and (b) reimbursement of the fund at the end of the current period. View transaction list Journal entry worksheet 1 2 Record the establishment of the petty cash fund. Note: Enter debits before credits Debit General Journal Transaction Credit 1a Record entry Clear entry View general Journal 2. Identify the two events from the following that cause a Petty Cash account to be credited in a journal entry. (Single click the box with the question mark to produce a check mark for a correct answer and double click the box with the question mark to empty the box for a wrong answer.) Fund amount is being reduced. Fund amount is being increased, Fund is being eliminated Fund is being established Suppose that a matrix A has the characteristic polynomial (A + 1) (a + + b) for some a, b = R. If the trace of A is 4 and the determinant of A is -6, find all eigenvalues of A. (a) Enter the eigenvalues as a list in increasing order, including any repetitions. For example, if they are 1,1,0 you would enter 0,1,1: (b) Hence determine a: 1 (c) and b: 1 what actions involving the four marketing mix elements might be used to reach the target market in question 4? what is the basic criterion used to determine the reporting entity for a governmental unit? Use a truth table to determine whether the symbolic form of the argument on the right is valid or invalid. 9-p ..p> Choose the correct answer below. a. The argument is valid b. The argument is invalid. b) the least square regression equation shows the best relationship between ridership and number of tourists is ( round your decimal points to three places)^y= ______ + ______ xwhere ^y = Dependent vairiable and X = Independent variablec) If it is expected that 10 million tourists will visit london, then the expected ridership = ____ million riders( round your answer to two decimal places)d) If there are no tourists at all then the model still predicts a ridership. This is due to that tourists are outside the range of data used to develop the modele) The standard error of the estimate developed using the least squares regression= _____ (round response to three decimal places)f) the coefficient of correlation for the least squares regression model is ______ ( round response to three decimal places)The coefficient of determination for the least square regression model = ________ (round to three decimal places) 2. Solve for all values of real numbers x and y in the following equation | -(x + jy) = x + jy. The half-life of a radioactive substance is 140 days. An initial sample is 300 mg. a) Find the mass, to the nearest milligram, that remains after 50 days. (2marks) b) After how many days will the sample decay to 200 mg? (2marks) c) At what rate, to the nearest tenth of a milligram per day, is the mass decaying after 50 days? (2marks) Q26 27 give correct answer in 15 mins i will thumb upthanksQUESTION 26 Barr Company acquires 80, 10%, 5 year, 1,000 Community bonds on January 1, 2017 for 80,000. Assume Community pays interest each January 1. The journal entry at December 31, 2017 woul answer those fast and no plagiarism please from the case its a test Insurance Company reaching compliance In ABC Co. employees could bring n USB drives from home, install whatever they wanted including games, and otherwise modify their workstations. The consequence was that IT spent considerable time dealing with corrupted operating systems and had substantial expenses replacing machines. Rebuilding systems took a lot of effort" according to an employee, and inevitably users had files in additional unexpected places, requiring manual efforts to retrieve those files. Users were down for a day or more. These incidents took time away from priority IT initiatives and required 3-24 hours each to identify the issue, mitigate and remediate. Educating users was helpful, but users still couldn't manage themselves, particularly given increasingly sophisticated social engineering exploits. The Vice President of IT addressed several issues to improve the security of the infrastructure over the past five years, expanding on what was working and changing what needed improvement. They virtualized 98% of the infrastructure, and still utilize custom-built applications where needed. According to an employee, "In the Windows environment we wanted to eliminate the havoc of allowing users admin rights. It makes me nervoes from a security perspective, bar it also inhibits productivity of both IT and end users." They initially selected a product that had seemed simple in their trials, and it offered to fully automate deployment of software to local and remote employees via an intuitive web interface. It even offered remote access capabilities for remote employees. The results of a trial deployment, however, were much less than expected - important applications could not work without admin rights the way that product was designed. That's when the IT department tested "PowerBroker" for Windows on his personal PC. "With "PowerBroker" for Windows I could navigate and discover assets, identify vulnerabilities, and most importantly lock down all applications to implement least privilege and remove all admin rights from users' PCs." Romious discovered. And PowerBroker had flexibility in how it could be deployed and managed, which did take some time to decide, but in the end PowerBroker for Windows easily scaled to meet their enterprise needs and allow removal of admin rights from all Windows systems. PowerBroker has solved these challenges. On an application-by-application basis, IT can then review the risk and vulnerabilities associated with the requested application by using the Beyondinsight platform included with PowerBroker for Windows. The Beyondinsight IT Risk Management Platform provides centralized reporting and analytics, giving visibility into the risks associated with assets that can be discovered and profiled. "Beyondinsight used with PowerBroker for Windows allows us to proactively assess and approve applications when warranted for business and when safe, rather than remediating after the havoc." The vulnerability scanner incorporated into PowerBroker for Windows and the Beyondinsight platform"has been invaluable" according to Romious. It ensures patches are applied, vulnerabilities are mitigated, and that nothing else becomes broken in the process. Fred Allen, VP of IT agrees, "The deployment of PowerBroker for Windows with Beyondinsight has gone well. It's good to have a win-win after the challenges of the previous attempt to eliminate admin rights on users PCs. 1. Keeping in mind the IT security problem at ABC Co., what solution's "PowerBroker" provided, from the perspective of the E-Commerce Security Environment you are aware of from ITMA 401 course? 2. What 3 vulnerable e-commerce points, which you studied of in ITMA 401 course, you also directly or indirectly encountered in this case study at ABC Co.? 3. What and how the 3 key technology concepts, of the Internet, got threatened at ABC Co.? Page: 8/10 - Find: on,7. Show that yn EN, n/2^n For a laboratory assignment, if the equipment is working, the density function of the observed outcome X is as shown below. Find the variance and standard deviation of X. f(x) ={ (1/2)(4-x), 0 < < 4 0, otherwise