Let O, P, and Q be distinct collinear points with PQ=3. Let P′ and Q′ be the images of points P and Q under dilation from point O with scale factor 4.

What is the length of the image segment P′Q′?

Answers

Answer 1

Given:

O, P, and Q be distinct collinear points with PQ=3.

P′ and Q′ be the images of points P and Q under dilation from point O with scale factor 4.

To find:

The length of the image segment P'Q'.

Solution:

We know that,

[tex]\text{Scale factor}=\dfrac{\text{Side length of image}}{\text{Corresponding side of original figure}}[/tex]

P′ and Q′ be the images of points P and Q under dilation from point O with scale factor 4. So, Segment P'Q' is the image of segment PQ and the scale factor is 4.

[tex]4=\dfrac{P'Q'}{PQ}[/tex]

It is given that PQ=3.

[tex]4=\dfrac{P'Q'}{3}[/tex]

Multiply both sides by 3.

[tex]4\times 3=P'Q'[/tex]

[tex]12=P'Q'[/tex]

Therefore, the length of the image segment P'Q' is 12 units.

Answer 2

A segment in the image is proportionally longer or shorter than the corresponding one in the pre-image.

The length of the image segment P′Q′

Given Information:

O, P, and Q be distinct collinear points with PQ=3.Dilation from point O with scale factor 4.

Solution:

Scale factor=Side length of image/corresponding side of original figure

Segment P'Q' is the image of segment PQ and the scale factor is 4.

4=P'Q'/ PQ

It is given that PQ=3

4=P'Q'/3

Multiply both sides by 3.

4*3=P'Q'

12=P'Q'

Therefore, the length of the image segment P'Q' is 12 units.

Learn more about segment, refer to the link:

https://brainly.com/question/18104026


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Explanation:

Points O, P, and Q are not collinear and form ∠POQ. Point R is on OP−→− between points O and P. Line l passes through R parallel to PQ¯¯¯¯¯¯¯¯. Line l intersects OQ−→− at point S. Use paper to draw a diagram to represent the situation described.



Which other pairs of segments have lengths in the same ratio as RS to PQ? Select all that apply.

Answers

Answer:

The answer is below

Explanation:

Two triangles are said to be similar to each other if the ratio of their corresponding sides are in the same proportion.

Given triangle ORS and triangle OPQ. ∠ROS = ∠POQ

∠ORS = ∠OPQ (corresponding angles are equal). Also, ∠OSR = ∠OQP (corresponding angles are equal)

Therefore using angle angle similarity theorem, we can say triangle ORS is similar to triangle OPQ.

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ratio of RS to PQ = ratio of OR to OP = ratio of OS to OQ  

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