Answers
Answer:
1) 1.5 kg
2) 0.6 kg
Explanation:
[tex](3)(30) = 60m, m = 90/60 = 1.5[/tex] kg
[tex](0.8)(15) = 20m, m = 12/20 = 0.6[/tex] kg
Related Questions
Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
(a) SO3
(b) N2O (N is central)
(c) CH2C12
Answers
Solution :
a). [tex]$SO_3$[/tex]
This compound is known as sulfur trioxide.
The molecular shape of sulfur trioxide is trigonal planer.
And the bond angle is 120°.
b). [tex]$N_2O$[/tex]
This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.
It is linear in shape.
The bond angle between them is 180°.
c). [tex]$CH_2Cl_{2}$[/tex]
This compound is known as the Dichloromethane.
The molecular shape of the compound is tetrahedral.
The bond angles is 120°
how to solve x² in differential
Answers
Answer:
x² = mutiphy by them self
Explanation:
How long will it take a 500-W heater to raise the temperature of 400 g of water from 15.0 °C to 98.0
°C?
Answers
Explanation:
E=(98-15)×400×4.2
E=139440J
t=E/P
E=139440/500=278.88s
hope it helps❣️
don't forget to mark me as brainliest and follow❣️
Three biologically important diatomic species, either because they promote or inhibit life, are
(a) CO,
(b) NO3 and
(c) CN-.
The first binds to hemoglobin, the second is a chemical messenger, and the third interrupts the respiratory electron transfer chain. Their biochemical action is a reflection of their orbital structure. Deduce their ground state electron configurations.
Answers
Answer:
See Explanation
Explanation:
We can write the molecular orbital configuration of molecules in the same way as we write the orbital electron configuration of atoms. The valence electrons in the molecule are filled into molecular orbitals of appropriate energy in accordance to the Aufbau principle.
For CO;
σ2s2, σ*2s2, Π2py2, Π2pz2, σ2px2
For NO;
σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2, Π*2px1
For CN-;
σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2
These are the ground state electron configurations of these molecules.
Balanced equation: K2S(aq) + BaCl2(aq) =
Answers
Answer:
K2S(aq) + BaCl2(aq) = 2KCl(aq) + BaS(s)
In the image attached, it is explained how the solution is balanced.
The number of atoms of any element in the given chemical formula is the number that is written on the foot of the symbol of that element. The balanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
What is Balanced equation?Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.
The unbalanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]KCl(aq) + BaS(s)
The number of atoms of K on reactant side is 2 while on product side it is 1, so to balance K we need to multiply KCl by 2
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
The atoms of sulfur on reactant and product side is 1, so it is balanced.
The atoms of Ba on reactant and product side is 1, so it is balanced.
The atoms of Cl on reactant and product side is 2, so it is balanced.
Therefore the balanced equation is
K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)
Learn more about the balanced equation, here:
https://brainly.com/question/7181548
#SPJ2
Please help
Apply your knowledge and understanding of equilibrium constant in solving the following problems:
The equilibrium constant Kc for the reaction below is 170 at 500 K.
Determine whether the reaction mixture is at equilibrium when the concentrations of the components at this temperature are as follows:
[N2]=1.50
[H2]=1.00
[NH3]=8.00
If it is not at equilibrium, state and explain in which direction the reaction will proceed.Multi Line Text.
2()+32() ⇄ 23()
Answers
Answer:
The reaction will proceed to the right to attain the equilibrium.
Explanation:
Step 1: Write the balanced equation
2 N₂(g) + 3 H₂(g) = 2 NH₃(g)
Step 2: Calculate the reaction quotient
The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.
Qc = [NH₃]² / [N₂]² × [H₂]³
Qc = 8.00² / 1.50² × 1.00³ = 28.4
Since Qc ≠ Kc, the reaction is not at equilibrium.
Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.