According to the displacement method, Archimedes measured the volume of the king’s crown to determine whether or not it was made of pure gold.
To prove that it is made of pure gold, Archimedes had to use olive oil that weighs more than 100 oz. Thus, let us determine how much olive oil Archimedes would need to use: Mass of the crown in air = 14 oz Density of gold (Au) = 19.3 g/cm³Density of olive oil (ρ) = 0.8 g/cm³As the crown’s weight in air is given in ounces, we will convert its weight into grams:1 [tex]oz = 28.35 grams14 oz = 14 × 28.35 g = 396.9 g[/tex]The weight of the crown in olive oil (W’) can be calculated using the following formula: W’ = W × (ρ/ρ1)
where W is the weight of the crown in air, ρ is the density of olive oil, and ρ1 is the density of air. Density of air is approximately 1.2 g/cm³; therefore: [tex]W’ = 396.9 g × (0.8 g/cm³ / 1.2 g/cm³) = 264.6 g[/tex] Thus, the crown would weigh 264.6 grams in olive oil. As 1 oz = 28.35 g, the weight of the crown in olive oil is approximately 9.35 oz (to the nearest hundredth).Therefore, Archimedes would have needed to use more than 100 ounces of olive oil to prove that the crown was made of pure gold.
To know more about crown visit:
https://brainly.com/question/29023422
#SPJ11
Two forces act on a body of 4.5 kg and displace it by 7.4 m. First force is of 9.6 N making an angle 185° with positive x-axis whereas the second force is 8.0 N making an angle of 310°. Find the net work done by these forces. Answer: Choose... Check
the net work done by the given forces is approximately -15.54 J, or -15.5 J (rounded to one decimal place).-15.5 J.
In physics, work is defined as the product of force and displacement. The unit of work is Joule, represented by J, and is a scalar quantity. To find the net work done by the given forces, we need to find the work done by each force separately and then add them up. Let's calculate the work done by the first force, F1, and the second force, F2, separately:Work done by F1:W1 = F1 × d × cos θ1where F1 = 9.6 N (force), d = 7.4 m (displacement), and θ1 = 185° (angle between F1 and the positive x-axis)W1 = 9.6 × 7.4 × cos 185°W1 ≈ - 64.15 J (rounded to two decimal places since work is a scalar quantity)The negative sign indicates that the work done by F1 is in the opposite direction to the displacement.Work done by F2:W2 = F2 × d × cos θ2where F2 = 8.0 N (force), d = 7.4 m (displacement), and θ2 = 310° (angle between F2 and the positive x-axis)W2 = 8.0 × 7.4 × cos 310°W2 ≈ 48.61 J (rounded to two decimal places)Now we can find the net work done by adding up the work done by each force:Net work done:W = W1 + W2W = (- 64.15) + 48.61W ≈ - 15.54 J (rounded to two decimal places)Therefore,
To know more aboutapproximately visit:
brainly.com/question/31360664
#SPJ11
Suppose a rocket travels to Mars at speed of 6,000 m/sec. The distance to Mars is 90 million km. The trip would take 15 million sec (about 6 months). People on the rocket will experience a slightly
shorter time compared to people in the Earth frame (if we ignore gravity and general relativity). How many seconds shorter will the trip seem to people on the rocket? Use a binomial
approximation.
The trip will seem about `15.0000001875 million seconds` shorter to people on the rocket as compared to people in the Earth frame.
The given values are: Speed of rocket, `v = 6,000 m/s`
Distance to Mars, `d = 90 million km = 9 × 10^10 m`
Time taken to cover the distance, `t = 15 × 10^6 s`
Now, using Lorentz factor, we can find how much seconds shorter the trip will seem to people on the rocket.
Lorentz factor is given as: `γ = 1 / sqrt(1 - v^2/c^2)
`where, `c` is the speed of light `c = 3 × 10^8 m/s`
On substituting the given values, we get:
`γ = 1 / sqrt(1 - (6,000/3 × 10^8)^2)
`Simplifying, we get: `γ = 1.0000000125`
Approximately, `γ ≈ 1`.
Hence, the trip will seem shorter by about `15 × 10^6 × (1 - 1/γ)` seconds.
Using binomial approximation, `(1 - 1/γ)^-1 ≈ 1 + 1/γ`.
Hence, the time difference would be approximately:`15 × 10^6 × 1/γ ≈ 15 × 10^6 × (1 + 1/γ)`
On substituting the value of `γ`, we get:`
15 × 10^6 × (1 + 1/γ) ≈ 15 × 10^6 × 1.0000000125 ≈ 15.0000001875 × 10^6 s`
Hence, the trip will seem about `15.0000001875 × 10^6 s` or `15.0000001875 million seconds` shorter to people on the rocket as compared to people in the Earth frame.
Learn more about rocket https://brainly.com/question/24710446
#SPJ11
According to the Law of Universal Gravitation, when the distance between the centers of two objects is doubled and the masses remain constant, the force between the objects... 1. is multiplied by a factor of 2 2. is multiplied by a factor of 1/2
3. is multiplied by a factor of 1/4
4. remains constant 5. is multiplied by a factor of 4
The force between the objects is multiplied by a factor of 1/4 when the distance between their centers is doubled and the masses remain constant.
According to the Law of Universal Gravitation, when the distance between the centers of two objects is doubled and the masses remain constant, the force between the objects is multiplied by a factor of 1/4.
The Law of Universal Gravitation, formulated by Sir Isaac Newton, states that the force of gravitational attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Mathematically, it can be expressed as:
F = G * (m1 * m2) / [tex]r^2[/tex]
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.
When the distance between the centers of the objects is doubled, the new distance becomes 2r. Plugging this into the formula, we get:
F' = G * (m1 * m2) / [tex](2r)^2[/tex]
= G * (m1 * m2) / [tex]4r^2[/tex]
= (1/4) * (G * (m1 * m2) /[tex]r^2[/tex])
Learn more about Law of Universal Gravitation from the given link:
https://brainly.com/question/858421
#SPJ11
If the cutoff wavelength for a particular material is 662 nm considering the photoelectric effect, what will be the maximum amount of kinetic energy obtained by a liberated electron when light with a wavelength of 419 nm is used on the material? Express your answer in electron volts (eV).
The maximum kinetic energy of a liberated electron can be calculated using the equation for the photoelectric effect. For a material with a cutoff wavelength of 662 nm and when light with a wavelength of 419 nm is used, the maximum kinetic energy of the liberated electron can be determined in electron volts (eV).
The photoelectric effect states that when light of sufficient energy (above the cutoff frequency) is incident on a material, electrons can be liberated from the material's surface. The maximum kinetic energy (KEmax) of the liberated electron can be calculated using the equation:
KEmax = h * (c / λ) - Φ
where h is the Planck's constant (6.626 x[tex]10^{-34}[/tex] J s), c is the speed of light (3 x [tex]10^{8}[/tex] m/s), λ is the wavelength of the incident light, and Φ is the work function of the material (the minimum energy required to liberate an electron).
To convert KEmax into electron volts (eV), we can use the conversion factor 1 eV = 1.602 x [tex]10^{-19}[/tex] J. By plugging in the given values, we can calculate KEmax:
KEmax = (6.626 x [tex]10^{-34}[/tex] J s) * (3 x [tex]10^{8}[/tex] m/s) / (419 x[tex]10^{-9}[/tex] m) - Φ
By subtracting the work function of the material (Φ), we obtain the maximum kinetic energy of the liberated electron in joules. To convert this into electron volts, we divide the result by 1.602 x [tex]10^{-19}[/tex] J/eV.
Learn more about wavelength here ;
https://brainly.com/question/31322456
#SPJ11
If Joe Scientist has created his own temperature scale where water freezes at 57 and boils at 296, create a transformation equation that will allow you to convert celcius into his temperatures
The transformation equation to convert Celsius temperatures (C) to Joe Scientist's temperature scale (J) is:
J = 2.39C + 57
How do we calculate?In Joe Scientist's temperature scale,
water freezes = 57
water boils = 296.
In Celsius scale, water freezes at 0 and boils at 100.
To convert Celsius temperatures (C) to Joe Scientist's scale temperatures (J), we can use a linear transformation equation.
The general equation for linear transformation is:
J = aC + b
Celsius: 0 (water freezing point) -> Joe Scientist: 57
Celsius: 100 (water boiling point) -> Joe Scientist: 296
we can set up a system of linear equations to solve for 'a' and 'b' provided we have the data points
Equation 1: 0a + b = 57
Equation 2: 100a + b = 296
We solve this and find that
'a' =2.39
'b'= 57.
Learn more about linear equations at:
https://brainly.com/question/2030026
#SPJ4
Q1. Find the magnitude and direction of the resultant force acting on the body below? 1mark
The magnitude and direction of the resultant force acting on the body in the given figure can be found using vector addition. We can add the two vectors using the parallelogram law of vector addition and then calculate the magnitude and direction of the resultant force.
Here are the steps to find the magnitude and direction of the resultant force:
Step 1: Draw the vectors .The vectors can be drawn to scale on a piece of paper using a ruler and a protractor. The given vectors in the figure are P and Q.
Step 2: Complete the parallelogram .To add the vectors using the parallelogram law, complete the parallelogram by drawing the other two sides. The completed parallelogram should look like a closed figure with two parallel sides.
Step 3: Draw the resultant vector Draw the resultant vector, which is the diagonal of the parallelogram that starts from the tail of the first vector and ends at the head of the second vector.
Step 4: Measure the magnitude .Measure the magnitude of the resultant vector using a ruler. The magnitude of the resultant vector is the length of the diagonal of the parallelogram.
Step 5: Measure the direction Measure the direction of the resultant vector using a protractor. The direction of the resultant vector is the angle between the resultant vector and the horizontal axis.The magnitude and direction of the resultant force acting on the body below is shown in the figure below. We can see that the magnitude of the resultant force is approximately 7.07 N, and the direction is 45° above the horizontal axis.
Therefore, the answer is:
Magnitude = 7.07 N
Direction = 45°
To know more about magnitude , visit;
https://brainly.com/question/30337362
#SPJ11
The string of a cello playing the note "C" oscillates at 264 Hz.
What is the period of the string’s oscillation? Answer in units of
s.
The period of the string’s oscillation if the string of a cello playing the note "C" oscillates at 264 Hz is 0.00378 seconds.
What is the period of the string’s oscillation?We define periodic motion to be a motion that repeats itself at regular time intervals, such as exhibited by the guitar string or by an object on a spring moving up and down. The time to complete one oscillation remains constant and is called the period T.
To calculate the period of the string's oscillation, the formula is given as;`
T=1/f`
Where T is the period of oscillation and f is the frequency of the wave.
Given that the frequency of the wave is 264 Hz, we can calculate the period as;`
T=1/f = 1/264
T = 0.00378 seconds (rounded to five significant figures)
Therefore, the period of the string's oscillation is 0.00378 seconds.
Learn more about oscillation: https://brainly.com/question/17327655
#SPJ11
A car of mass 1.5x 105 kg is initially travelling at a speed of 25 m/s. The driver then accelerates to a speed of 40m/s over a distance of 0.20 km. Calculate the work done on the car. 3.8x10^5 J 7.3x10^7 7.3x10^5J 7.3x10^3
The work done on the car is 7.3x10⁷ J.
To calculate the work done on the car, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy. The kinetic energy of an object is given by the equation KE = (1/2)mv² , where m is the mass of the object and v is its velocity.
Given:
Mass of the car, m = 1.5x10⁵ kg
Initial velocity, u = 25 m/s
Final velocity, v = 40 m/s
Distance traveled, d = 0.20 km = 200 m
First, we need to calculate the change in kinetic energy (ΔKE) using the formula ΔKE = KE_final - KE_initial. Substituting the given values into the formula, we have:
ΔKE = (1/2)m(v² - u² )
Next, we substitute the values and calculate:
ΔKE = (1/2)(1.5x10⁵ kg)((40 m/s)² - (25 m/s)²)
= (1/2)(1.5x10⁵ kg)(1600 m²/s² - 625 m²/s²)
= (1/2)(1.5x10⁵ kg)(975 m²/s²)
= 73125000 J
≈ 7.3x10⁷ J
Therefore, the work done on the car is approximately 7.3x10⁷J.
The work-energy principle is a fundamental concept in physics that relates the work done on an object to its change in kinetic energy. By understanding this principle, we can analyze the energy transformations and transfers in various physical systems. It provides a quantitative measure of the work done on an object and how it affects its motion. Further exploration of the relationship between work, energy, and motion can deepen our understanding of mechanics and its applications in real-world scenarios.
Learn more about work done
brainly.com/question/32263955
#SPJ11
Party Planning You are expecting to serve 38 cups of soft drinks to your guests tonight. Each cup will hold 283 g of a soft drink that has a specific heat of 4186 J/ (kg • K) and an initial
temperature of 24 °C.
If each guest would like to enjoy the drink at 3.0 °C, how much ice (in kg) should you buy? Assume the initial temperature of the ice is 0 °C, and ignore the heat exchange with the
plastic cups and the surroundings.
You'll need to buy approximately 22.65 kg of ice to maintain the soft drinks cold at a temperature of 3.0°C all through your party.
When you need to plan a party, it is crucial to determine how much of each item you require, such as food and beverages, to ensure that you have enough supplies for your guests. This also implies determining how much ice to purchase to maintain the drinks cold all through the party. Here's how you can figure out the quantity of ice you'll need.
Each cup holds 283 g of a soft drink, and you anticipate serving 38 cups of soft drinks, so the total amount of soda you'll require is:
283 g/cup × 38 cups = 10.75 kg
You want the drink to be at 3.0°C when it is served. Assume the initial temperature of the soda is 24°C, and the initial temperature of the ice is 0°C.
This implies that the temperature change the soft drink needs is: ΔT = (3.0°C - 24°C) = -21°C
To determine the amount of ice required, use the following equation:
[tex]Q = mcΔT[/tex]
where Q is the heat absorbed or released, m is the mass of the substance (ice), c is the specific heat, and ΔT is the temperature change.
We want to know how much ice is required, so we can rearrange the equation to: [tex]m = Q / cΔT.[/tex]
To begin, determine how much heat is required to cool the soda. To do so, use the following equation: [tex]Q = mcΔT[/tex]
where m is the mass of the soda, c is the specific heat, and ΔT is the temperature change.
Q = (10.75 kg) × (4186 J/kg°C) × (-21°C)Q
= -952,567.5 J
Next, determine how much ice is required to absorb this heat energy using the heat capacity of ice, which is 2.108 J/(g°C).
[tex]m = Q / cΔT[/tex]
= -952567.5 J / (2.108 J/g°C × -21°C)
= 22,648.69 g or 22.65 kg
Therefore, you'll need to buy approximately 22.65 kg of ice to maintain the soft drinks cold at a temperature of 3.0°C all through your party.
To learn more about temperature visit;
https://brainly.com/question/7510619
#SPJ11
A stone was thrown in horiztonal (vx) direction with initial velocity from a bridge which has a height of (39.6m). The stone lands in the water and the splash sound was heard (3.16s) later.
Calculate
a) the initial velocity
b) the range (distance) from the base of the bridge where the stone landed
c) the velocity component vy when the stone hits the water
The initial velocity is 27.86 m/s.b) The range is 88.04 m.c) The velocity component vy when the stone hits the water is 62.25 m/s.
a) The initial velocity
The initial velocity can be calculated using the following formula:
v = sqrt(2gh)
where:
v is the initial velocity in m/s
g is the acceleration due to gravity (9.8 m/s^2) h is the height of the bridge (39.6 m)
Substituting these values into the formula, we get:
v = sqrt(2 * 9.8 m/s^2 * 39.6 m) = 27.86 m/s
b) The range
The range is the horizontal distance traveled by the stone. It can be calculated using the following formula:
R = vt
where:
R is the range in m
v is the initial velocity in m/s
t is the time it takes for the stone to fall (3.16 s)
Substituting these values into the formula, we get:
R = 27.86 m/s * 3.16 s = 88.04 m
c) The velocity component vy when the stone hits the water
The velocity component vy is the vertical velocity of the stone when it hits the water. It can be calculated using the following formula:
vy = gt
where:
vy is the vertical velocity in m/s
g is the acceleration due to gravity (9.8 m/s^2)
t is the time it takes for the stone to fall (3.16 s)
Substituting these values into the formula, we get:
vy = 9.8 m/s^2 * 3.16 s = 62.25 m/s
Learn more about velocity with the given link,
https://brainly.com/question/80295
#SPJ11
Moving at its maximum safe speed, an amusement park carousel takes 12 S to complete a revolution. At the end of the ride, it slows down smoothly, taking 3.3 rev to come to a stop. Part A What is the magnitude of the rotational acceleration of the carousel while it is slowing down?
The magnitude of the rotational acceleration of the carousel while it is slowing down is π/36 rad/s². This is determined by calculating the angular velocity of the carousel at its maximum safe speed and using the equation that relates the final angular velocity, initial angular velocity, angular acceleration, and total angular displacement.
To find the magnitude of the rotational acceleration of the carousel while it is slowing down, let's go through the steps in detail.
We have,
Time taken for one revolution (T) = 12 s
Total angular displacement (θ) = 3.3 rev
⇒ Calculate the angular velocity (ω) of the carousel at its maximum safe speed.
Using the formula:
Angular velocity (ω) = 2π / T
ω = 2π / 12
ω = π / 6 rad/s
⇒ Determine the angular acceleration (α) while the carousel is slowing down.
Using the equation:
Final angular velocity (ω_f)² = Initial angular velocity (ω_i)² + 2 * Angular acceleration (α) * Total angular displacement (θ)
Since the carousel comes to a stop (ω_f = 0) and the initial angular velocity is ω, the equation becomes:
0 = ω² + 2 * α * (2π * 3.3)
Simplifying the equation, we have:
0 = (π/6)² + 2 * α * (2π * 3.3)
0 = π²/36 + 13.2πα
⇒ Solve for the angular acceleration (α).
Rearranging the equation, we get:
π²/36 = -13.2πα
Dividing both sides by -13.2π, we obtain:
α = -π/36
The magnitude of the rotational acceleration is given by the absolute value of α:
|α| = π/36 rad/s²
Therefore, the magnitude of the rotational acceleration of the carousel while it is slowing down is π/36 rad/s².
To know more about rotational acceleration, refer here:
https://brainly.com/question/30238727#
#SPJ11
Water flows straight down from an open faucet. The cross-sectional area of the faucet is 2.5 x 10^4m^2 and the speed of the water is
0.50 m/s as it leaves the faucet. Ignoring air resistance, find the cross-sectional area of the water stream at a point 0.10 m below the
manical
The cross-sectional area of the water stream at a point 0.10m in A2 = (2.5 x 10^(-4) m²)(0.50 m/s) / v2
Since the velocity at that point is not given, we cannot determine the exact cross-sectional area of the water stream at a point 0.10 m below the faucet without additional information about the velocity at that specific location.
To solve this problem, we can apply the principle of conservation of mass, which states that the mass flow rate of a fluid remains constant in a continuous flow.
The mass flow rate (m_dot) is given by the product of the density (ρ) of the fluid, the cross-sectional area (A) of the flow, and the velocity (v) of the flow:
m_dot = ρAv
Since the water is incompressible, its density remains constant. We can assume the density of water to be approximately 1000 kg/m³.
At the faucet, the cross-sectional area (A1) is given as 2.5 x 10^(-4) m² and the velocity (v1) is 0.50 m/s.
At a point 0.10 m below the faucet, the velocity (v2) is unknown, and we need to find the corresponding cross-sectional area (A2).
Using the conservation of mass, we can set up the following equation:
A1v1 = A2v2
Substituting the known values, we get:
(2.5 x 10^(-4) m²)(0.50 m/s) = A2v2
To solve for A2, we divide both sides by v2:
A2 = (2.5 x 10^(-4) m²)(0.50 m/s) / v2
Since the velocity at that point is not given, we cannot determine the exact cross-sectional area of the water stream at a point 0.10 m below the faucet without additional information about the velocity at that specific location.
Learn more about velocity:
https://brainly.com/question/80295
#SPJ11
n-interlaced latters
please
Zeeman Effect Q1) from equation 5.6 and 5.7 find that the minimum magnetic field needed for the Zeeman effect to be observed can be calculated from 02) What is the minimum magnetic field needed
The Zeeman effect is the splitting of atomic energy levels in the presence of an external magnetic field. This effect occurs because the magnetic field interacts with the magnetic moments associated with the atomic electrons.
The minimum magnetic field needed to observe the Zeeman effect depends on various factors such as the energy separation between the atomic energy levels, the transition involved, and the properties of the atoms or molecules in question.
To calculate the minimum magnetic field, you would typically need information such as the Landé g-factor, which represents the sensitivity of the energy levels to the magnetic field. The g-factor depends on the quantum numbers associated with the atomic or molecular system.
Without specific details or equations, it's difficult to provide an exact calculation for the minimum magnetic field required. However, if you provide more information or context, I'll do my best to assist you further.
Learn more about Zeeman effect on:
https://brainly.com/question/13046435
#SPJ4
A 2microF capacitor is connected in series to a 1 mega ohm resistor and charged to a 6 volt battery. How long does it take to charge 98.2% of its maximum charge?
A 2microF capacitor is connected in series to a 1 mega ohm resistor and charged to a 6 volt battery. The capacitor takes to charge 0.140 seconds for 98.2% of its maximum.
The maximum charge can be calculated using the formula: t = -RC * ln(1 - Q/Q_max) Where t is the time, R is the resistance, C is the capacitance, Q is the charge at a given time, and Q_max is the maximum charge.
In this case, the capacitance (C) is 2 microfarads (2μF), the resistance (R) is 1 megaohm (1 MΩ), and the maximum charge (Q_max) is the charge when the capacitor is fully charged.
To find Q_max, we can use the formula:
Q_max = C * V
Where V is the voltage of the battery, which is 6 volts in this case.
Q_max = (2 μF) * (6 volts) = 12 μC
Substituting the values into the time formula, we have:
t = -(1 MΩ) * (2 μF) * ln(1 - Q/Q_max)
t = -(1 MΩ) * (2 μF) * ln(1 - 0.982)
t ≈ 0.140 seconds
Therefore, it takes approximately 0.140 seconds to charge 98.2% of its maximum charge.
To learn more about, capacitor, click here, https://brainly.com/question/31627158
#SPJ11
A step-up transformer has an output voltage of 110 V (rms). There are 1000 turns on the primary and 500 turns on the secondary. What is the input voltage?
A. 1650 V (rms)
B. 220 V (rms)
C. 165 V (rms)
D. 3260 V (max)
E. 1600 V (max)
A step-up transformer has an output voltage of 110 V (rms). There are 1000 turns on the primary and 500 turns on the secondary.
We have to find the input voltage.
Hence, we can use the formula,N1 / N2 = V1 / V2
Where, N1 = Number of turns in the primary
N2 = Number of turns in the secondary
V1 = Input voltageV2 = Output voltage
Hence, V1 = (N1 / N2) × V2
Substituting the values in the formula,
V1 = (1000 / 500) × 110
V1 = 220 V (rms)
Therefore, the input voltage is 220 V (rms).
Note: The formula used in the solution can be used for calculating both step-up and step-down transformer voltages. The only difference is the number of turns on the primary and secondary.
To learn more about transformer visit;
https://brainly.com/question/1616939
#SPJ11
An evacuated tube uses an accelerating voltage of 31.1 KV to accelerate electrons from rest to hit a copper plate and produce x rays. Non-relativistically, what would be the speed of these electrons?
An evacuated tube uses an accelerating voltage of 31.1 KV to accelerate electrons from rest to hit a copper plate and produce x rays.velocity^2 = (2 * 31,100 V * (1.6 x 10^-19 C)) / (mass)
To find the speed of the electrons, we can use the kinetic energy formula:
Kinetic energy = (1/2) * mass * velocity^2
In this case, the kinetic energy of the electrons is equal to the work done by the accelerating voltage.
Given that the accelerating voltage is 31.1 kV, we can convert it to joules by multiplying by the electron charge:
Voltage = 31.1 kV = 31.1 * 1000 V = 31,100 V
The work done by the voltage is given by:
Work = Voltage * Charge
Since the charge of an electron is approximately 1.6 x 10^-19 coulombs, we can substitute the values into the formula:
Work = 31,100 V * (1.6 x 10^-19 C)
Now we can equate the work to the kinetic energy and solve for the velocity of the electrons:
(1/2) * mass * velocity^2 = 31,100 V * (1.6 x 10^-19 C)
We know the mass of an electron is approximately 9.11 x 10^-31 kg.
Solving for velocity, we have:
velocity^2 = (2 * 31,100 V * (1.6 x 10^-19 C)) / (mass)
Finally, we can take the square root to find the speed of the electrons.
To know more about accelerating refer here:
https://brainly.com/question/32899180#
#SPJ11
(d) A DC generator supplies current at to a load which consists of two resistors in parallel. The resistor values are 0.4 N and 50 1. The 0.4 resistor draws 400 A from the generator. Calculate; i. The current through the second resistor, ii. The total emf provided by the generator if it has an internal resistance of 0.02 22.
In this scenario, a DC generator is supplying current to a load consisting of two resistors in parallel. One resistor has a value of 0.4 Ω and draws a current of 400 A from the generator. We need to calculate (i) the current through the second resistor and (ii) the total electromotive force (emf) provided by the generator, considering its internal resistance of 0.02 Ω.
(i) To calculate the current through the second resistor, we can use the principle that the total current flowing into a parallel circuit is equal to the sum of the currents through individual branches. Since the first resistor draws 400 A, the total current supplied by the generator is also 400 A. The current through the second resistor can be calculated by subtracting the current through the first resistor from the total current. Therefore, the current through the second resistor is 400 A - 400 A = 0 A.
(ii) To calculate the total emf provided by the generator, taking into account its internal resistance, we can use Ohm's law. Ohm's law states that the voltage across a resistor is equal to the current flowing through it multiplied by its resistance. Since the generator has an internal resistance of 0.02 Ω, and the total current is 400 A, we can calculate the voltage drop across the internal resistance as V = I * R = 400 A * 0.02 Ω = 8 V. The total emf provided by the generator is equal to the sum of the voltage drop across the internal resistance and the voltage drop across the load resistors. Therefore, the total emf is 8 V + (400 A * 0.4 Ω) + (0 A * 50 Ω) = 8 V + 160 V + 0 V = 168 V.
In summary, the current through the second resistor is 0 A since all the current is drawn by the first resistor. The total emf provided by the generator, considering its internal resistance, is 168 V.
To learn more about Resistance click here:
brainly.com/question/1322424
#SPJ11
In order to cross the galaxy quickly, a spaceship leaves Earth traveling at 0.9999992c. After 19 minutes a radio message is sent from Earth to
the spacecraft.
In the carth-galaxy trame of reference, how far from cart is the spaceship when the message is sent!
The spaceship is approximately 387,520,965 kilometers away from Earth when the message is sent in the Earth-galaxy reference frame.
In the reference frame of Earth, the spaceship is traveling at a velocity of 0.9999992c. After 19 minutes, a radio message is sent from Earth to the spacecraft.
To calculate the distance from Earth to the spaceship in the Earth-galaxy reference frame, we can use the formula:
Distance = Velocity × Time
Assuming that the speed of light is approximately 299,792 kilometers per second, we can convert the time of 19 minutes to seconds (19 minutes × 60 seconds/minute = 1140 seconds).
Distance = (0.9999992c) × (1140 seconds) = 1.0791603088c × 299,792 km/s × 1140 s ≈ 387,520,965 kilometers
Therefore, in the Earth-galaxy reference frame, the spaceship is approximately 387,520,965 kilometers away from Earth when the message is sent.
To learn more about speed of light, Visit:
https://brainly.com/question/682762
#SPJ11
A 5.0 g copper coin is given a charge of 6.5 x 10-9 C. (a) How many electrons are removed from the coin? (b) If no more than one electron is removed from an atom, what percent of the atoms are ionized process?
The answers are:
(a) Approximately 4.06 x 10¹⁰ electrons are removed from the coin.
(b) Approximately 0.000858% of the atoms are ionized.
(a)
Number of electrons removed from the coin = Charge of the coin / Charge on each electron
Charge of the coin = 6.5 x 10⁻⁹ C
Charge on each electron = 1.6 x 10^⁻¹⁹ C
Number of electrons removed from the coin = Charge of the coin / Charge on each electron
= (6.5 x 10⁻⁹) / (1.6 x 10^⁻¹⁹)
≈ 4.06 x 10^10
(b)
The mass of a copper atom is 63.55 g/mol.
The number of copper atoms in the coin = (5.0 g) / (63.55 g/mol)
= 0.0787 moles
The number of electrons in one mole of copper is 6.022 x 10²³.
The number of electrons in 0.0787 moles of copper = (0.0787 moles) × (6.022 x 10²³ electrons per mole)
≈ 4.74 x 10²²
The percent of the atoms that are ionized = (number of electrons removed / total electrons) × 100
=(4.06 x 10¹⁰ / 4.74 x 10²²) × 100
≈ 0.000858%
To know more about atoms, visit:
https://brainly.com/question/1566330
#SPJ11
Number of electrons removed ≈ 4.06 x 10^10 electrons
approximately 8.53 x 10^(-12) percent of the atoms are ionized.
To find the number of electrons removed from the copper coin, we can use the charge of the coin and the charge of a single electron.
(a) Number of electrons removed:
Given charge on the coin: q = 6.5 x 10^(-9) C
Charge of a single electron: e = 1.6 x 10^(-19) C
Number of electrons removed = q / e
Number of electrons removed = (6.5 x 10^(-9) C) / (1.6 x 10^(-19) C)
Calculating this, we get:
Number of electrons removed ≈ 4.06 x 10^10 electrons
(b) To find the percentage of ionized atoms, we need to know the total number of copper atoms in the coin. Copper has an atomic mass of approximately 63.55 g/mol, so we can calculate the number of moles of copper in the coin.
Molar mass of copper (Cu) = 63.55 g/mol
Mass of copper coin = 5.0 g
Number of moles of copper = mass of copper coin / molar mass of copper
Number of moles of copper = 5.0 g / 63.55 g/mol
Now, since no more than one electron is removed from each atom, the number of ionized atoms will be equal to the number of electrons removed.
Percentage of ionized atoms = (Number of ionized atoms / Total number of atoms) x 100
To calculate the total number of atoms, we need to use Avogadro's number:
Avogadro's number (Na) = 6.022 x 10^23 atoms/mol
Total number of atoms = Number of moles of copper x Avogadro's number
Total number of atoms = (5.0 g / 63.55 g/mol) x (6.022 x 10^23 atoms/mol)
Calculating this, we get:
Total number of atoms ≈ 4.76 x 10^22 atoms
Percentage of ionized atoms = (4.06 x 10^10 / 4.76 x 10^22) x 100
Calculating this, we get:
Percentage of ionized atoms ≈ 8.53 x 10^(-12) %
Therefore, approximately 8.53 x 10^(-12) percent of the atoms are ionized.
To know more about electrons, visit:
https://brainly.com/question/12001116
#SPJ11
How does the Compton effect differ from the photoelectric effect?
The Compton effect and the photoelectric effect are both phenomena related to the interaction of photons with matter, but they differ in terms of the underlying processes involved.
The Compton effect involves the scattering of X-ray or gamma-ray photons by electrons, resulting in a change in the wavelength and direction of the scattered photons. On the other hand, the photoelectric effect involves the ejection of electrons from a material when it is illuminated with photons of sufficient energy, with no change in the wavelength of the incident photons.
The Compton effect arises from the particle-like behavior of photons and electrons. When high-energy photons interact with electrons in matter, they transfer momentum to the electrons, resulting in the scattering of the photons at different angles. This scattering causes a wavelength shift in the photons, known as the Compton shift, which can be observed in X-ray and gamma-ray scattering experiments.
In contrast, the photoelectric effect is based on the wave-like nature of light and the particle-like nature of electrons. In this process, photons with sufficient energy (above the material's threshold energy) strike the surface of a material, causing electrons to be ejected. The energy of the incident photons is absorbed by the electrons, enabling them to overcome the binding energy of the material and escape.
The key distinction between the two phenomena lies in the interaction mechanism. The Compton effect involves the scattering of photons by electrons, resulting in a change in the photon's wavelength, whereas the photoelectric effect involves the absorption of photons by electrons, leading to the ejection of electrons from the material.
In summary, the Compton effect and the photoelectric effect differ in terms of the underlying processes. The Compton effect involves the scattering of X-ray or gamma-ray photons by electrons, resulting in a change in the wavelength of the scattered photons. On the other hand, the photoelectric effect involves the ejection of electrons from a material when it is illuminated with photons of sufficient energy, with no change in the wavelength of the incident photons. Both phenomena demonstrate the dual nature of photons as both particles and waves, but they manifest different aspects of this duality.
To know more about Compton effect ,visit:
https://brainly.com/question/30683759
#SPJ11
M Romeo (77.0kg) entertains Juliet (55.0kg) by playing his guitar from the rear of their boat at rest in still water, 2.70m away from Juliet, who is in the front of the boat. After the serenade, Juliet carefully moves to the rear of the boat (away from shore) to plant a kiss on Romeo's cheek. How far does the 80.0 -kg boat move toward the shore it is facing?
Since the final momentum is zero, the velocity of the boat must also be zero. This means the boat does not move towards the shore.
Therefore, the boat does not move towards the shore as Juliet moves to the rear to kiss Romeo.
The distance the boat moves towards the shore can be determined by using the principle of conservation of momentum.
Initially, the total momentum of the system (boat + Romeo + Juliet) is zero since the boat is at rest. After Juliet moves to the rear of the boat, the boat and Juliet's combined momentum will still be zero.
We can calculate the initial momentum of Romeo by multiplying his mass (77.0 kg) by his velocity, which is zero since he is stationary. This gives us a momentum of zero for Romeo.
(initial momentum of Romeo + initial momentum of Juliet) = (final momentum of boat)
Since Romeo's initial momentum is zero, the equation simplifies to:
initial momentum of Juliet = final momentum of boat
Since the mass of the boat is 80.0 kg, we can rearrange the equation to solve for the distance the boat moves towards the shore:
(final momentum of boat) = (mass of boat) x (velocity of boat)
0 = 80.0 kg x (velocity of boat)
To know more about velocity visit:
https://brainly.com/question/24259848
#SPJ11
Pole thrown upward from initial velocity it takes 16s to hit the ground. a. what is the initial velocity of pole? b. What is max height? C. What is velocity when it hits the ground
Pole thrown upward from initial velocity it takes 16s to hit the ground. (a)The initial velocity of the pole is 78.4 m/s.(b) The maximum height reached by the pole is approximately 629.8 meters.(c)The velocity when the pole hits the ground is approximately -78.4 m/s.
To solve this problem, we can use the equations of motion for objects in free fall.
Given:
Time taken for the pole to hit the ground (t) = 16 s
a) To find the initial velocity of the pole, we can use the equation:
h = ut + (1/2)gt^2
where h is the height, u is the initial velocity, g is the acceleration due to gravity, and t is the time.
At the maximum height, the velocity of the pole is zero. Therefore, we can write:
v = u + gt
Since the final velocity (v) is zero at the maximum height, we can use this equation to find the time it takes for the pole to reach the maximum height.
Using these equations, we can solve the problem step by step:
Step 1: Find the time taken to reach the maximum height.
At the maximum height, the velocity is zero. Using the equation v = u + gt, we have:
0 = u + (-9.8 m/s^2) × t_max
Solving for t_max, we get:
t_max = u / 9.8
Step 2: Find the height reached at the maximum height.
Using the equation h = ut + (1/2)gt^2, and substituting t = t_max/2, we have:
h_max = u(t_max/2) + (1/2)(-9.8 m/s^2)(t_max/2)^2
Simplifying the equation, we get:
h_max = (u^2) / (4 × 9.8)
Step 3: Find the initial velocity of the pole.
Since it takes 16 seconds for the pole to hit the ground, the total time of flight is 2 × t_max. Thus, we have:
16 s = 2 × t_max
Solving for t_max, we get:
t_max = 8 s
Substituting this value into the equation t_max = u / 9.8, we can solve for u:
8 s = u / 9.8
u = 9.8 m/s × 8 s
u = 78.4 m/s
Therefore, the initial velocity of the pole is 78.4 m/s.
b) To find the maximum height, we use the equation derived in Step 2:
h_max = (u^2) / (4 × 9.8)
= (78.4 m/s)^2 / (4 × 9.8 m/s^2)
≈ 629.8 m
Therefore, the maximum height reached by the pole is approximately 629.8 meters.
c) To find the velocity when the pole hits the ground, we know that the initial velocity (u) is 78.4 m/s, and the time taken (t) is 16 s. Using the equation v = u + gt, we have:
v = u + gt
= 78.4 m/s + (-9.8 m/s^2) × 16 s
= 78.4 m/s - 156.8 m/s
≈ -78.4 m/s
The negative sign indicates that the velocity is in the opposite direction of the initial upward motion. Therefore, the velocity when the pole hits the ground is approximately -78.4 m/s.
To learn more about velocity visit: https://brainly.com/question/80295
#SPJ11
The resistive force that occurs when the two surfaces do side across each other is known as _____
The resistive force that occurs when two surfaces slide across each other is known as friction.
Friction is the resistive force that opposes the relative motion or tendency of motion between two surfaces in contact. When one surface slides over another, the irregularities or microscopically rough surfaces of the materials interact and create resistance.
This resistance is known as friction. Friction occurs due to the intermolecular forces between the atoms or molecules of the surfaces in contact.
The magnitude of friction depends on factors such as the nature of the materials, the roughness of the surfaces, and the normal force pressing the surfaces together. Friction plays a crucial role in everyday life, affecting the motion of objects, enabling us to walk, drive vehicles, and control the speed of various mechanical systems.
To learn more about resistive force
Click here brainly.com/question/30526425
#SPJ11
Find the required constant angular speed in rpm of a rotating drum that can spin an object at 2.5 cm from the axis at an acceleration of 400,000 g (ie 400,000 x 9.8).
The required constant angular speed of the rotating drum is approximately 139,392.76 rpm.
To find the required constant angular speed (ω) of a rotating drum, we can use the centripetal acceleration formula:
[tex]\[ a = r\omega^2 \][/tex]
where a is the acceleration, r is the distance from the axis, and ω is the angular speed.
Given:
Distance from the axis (r) = 2.5 cm = 0.025 m
Acceleration (a) = 400,000 g = 400,000 [tex]\times 9.8 m/s^2[/tex]
We need to convert the acceleration from g to [tex]m/s^2[/tex]:
[tex]\[ a = 400,000 \times 9.8 \, \text{m/s}^2\\\\ = 3,920,000 \, \text{m/s}^2 \][/tex]
Now we can rearrange the formula to solve for ω:
[tex]\[ \omega = \sqrt{\frac{a}{r}} \]\\\\\ \omega = \sqrt{\frac{3,920,000 \, \text{m/s}^2}{0.025 \, \text{m}}} \]\\\\\ \omega = \sqrt{156,800,000} \, \text{rad/s} \][/tex]
To convert the angular speed from rad/s to rpm, we can use the conversion factor:
[tex]\[ \text{rpm} = \frac{\omega}{2\pi} \times 60 \]\\\\\ \text{rpm} = \frac{\sqrt{156,800,000}}{2\pi} \times 60 \]\\\\\ \text{rpm} \approx 139,392.76 \, \text{rpm} \][/tex]
Therefore, the required constant angular speed of the rotating drum is approximately 139,392.76 rpm.
Know more about angular speed:
https://brainly.com/question/29058152
#SPJ4
The required constant angular speed is 2672 rpm.
Given that:
Radius of the rotating drum, r = 2.5 cm = 0.025 m
Acceleration, a = 400,000 x 9.8 m/s² = 3.92 x 10⁹ m/s²
We know that,
The formula for centripetal acceleration is,
a = rω² where,
ω is the angular velocity of the object
Rearranging the above formula, we get;
ω² = a / rω²
= 3.92 x 10⁹ / 0.025
ω = √(3.92 x 10⁹ / 0.025)
ω = 8.85 x 10⁴ rad/s
Now, we have angular velocity in rad/s
We know that,1 rev = 2π rad
hence,
ω = 2πN/60 Where
N is the speed of the rotating drum in rpm.
Substituting the value of ω in the above formula, we get;
8.85 x 10⁴ = 2πN/60N
= (8.85 x 10⁴ x 60) / (2π)N
= 2672 rpm (approx)
Learn more about angular speed from the given link
https://brainly.com/question/6860269
#SPJ11
A 5.00 x 10² kg satellite is on a geosynchronous orbit where it completes the circular orbit in 23 hours 56 minutes. The mass of the Earth is 5.97 x 1024 kg. (Assumptions: Earth is spherically symmetric. Satellite goes in a circular orbit about the center of the Earth.) A. Estimate the distance of the satellite from the center of the Earth. B. What is the kinetic energy and gravitational potential of the satellite?
"The gravitational potential energy of the satellite is approximately -8.85 x 10¹⁰ Joules."
To estimate the distance of the satellite from the center of the Earth, we can use the formula for the period of a circular orbit:
T = 2π√(r³/GM)
where T is the period, r is the distance from the center of the Earth to the satellite, G is the gravitational constant (approximately 6.67430 x 10⁻¹¹ m³ kg⁻¹ s⁻²), and M is the mass of the Earth.
We are given the period T as 23 hours 56 minutes, which is equivalent to 23.933 hours.
Substituting the known values into the equation, we can solve for r:
23.933 = 2π√(r³/(6.67430 x 10⁻¹¹ x 5.97 x 10²⁴))
Simplifying the equation:
√(r³/(6.67430 x 10⁻¹¹ x 5.97 x 10²⁴)) = 23.933 / (2π)
Squaring both sides of the equation:
r³/(6.67430 x 10⁻¹¹ x 5.97 x 10²⁴) = (23.933 / (2π))²
Simplifying further:
r³ = (6.67430 x 10⁻¹¹ x 5.97 x 10²⁴) x (23.933 / (2π))²
Taking the cube root of both sides of the equation:
r ≈ (6.67430 x 10⁻¹¹ x 5.97 x 10²⁴)°³³x (23.933 / (2π))°⁶⁶
Calculating the approximate value:
r ≈ 4.22 x 10⁷ meters
Therefore, the distance of the satellite from the center of the Earth is approximately 4.22 x 10⁷ meters.
To calculate the kinetic energy of the satellite, we can use the formula:
KE = (1/2)mv²
where KE is the kinetic energy, m is the mass of the satellite, and v is the velocity of the satellite.
Since the satellite is in a circular orbit, its velocity can be calculated using the formula for the circumference of a circle:
C = 2πr
where C is the circumference and r is the distance from the center of the Earth to the satellite.
Substituting the known values:
C = 2π(4.22 x 10⁷) ≈ 2.65 x 10⁸ meters
The time taken to complete one orbit is given as 23 hours 56 minutes, which is approximately 86,136 seconds.
Therefore, the velocity of the satellite can be calculated as:
v = C / time = (2.65 x 10⁸) / 86,136 ≈ 3077.6 m/s
Substituting the mass of the satellite (5.00 x 10² kg) and the velocity (3077.6 m/s) into the kinetic energy formula:
KE = (1/2)(5.00 x 10²)(3077.6)²
Calculating the value:
KE ≈ 2.37 x 10¹⁰ Joules
Thus, the kinetic energy of the satellite is approximately 2.37 x 10¹⁰ Joules.
To calculate the gravitational potential energy of the satellite, we can use the formula:
PE = -GMm / r
where PE is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the satellite, and r is the distance from the center of the Earth to the satellite.
Substituting the known values:
PE = -(6.67430 x 10⁻¹¹ x 5.97 x 10²⁴ x 5.00 x 10²) / (4.22 x 10⁷)
Calculating the value:
PE ≈ -8.85 x 10¹⁰ Joules
The negative sign indicates that the gravitational potential energy is negative, representing the attractive nature of gravity.
Therefore, the gravitational potential energy of the satellite is approximately -8.85 x 10¹⁰ Joules.
To know more about gravitational potential energy visit:
https://brainly.com/question/29490129
#SPJ11
hamiltonian for quantum many body scarring
write a hamiltonian for qauntum many body
scarring.
The Hamiltonian for quantum many-body scarring is a mathematical representation of the system's energy operator that exhibits the phenomenon of scarring.
Scarring refers to the presence of non-random, localized patterns in the eigenstates of a quantum system, which violate the expected behavior from random matrix theory. The specific form of the Hamiltonian depends on the system under consideration, but it typically includes interactions between particles or spins, potential terms, and coupling constants. The Hamiltonian captures the dynamics and energy levels of the system, allowing for the study of scarring phenomena and their implications in quantum many-body systems.
To know more about energy, visit:
https://brainly.com/question/1932868
#SPJ11
Two identical, 1.1-F capacitors are placed in series with a 13-V battery. How much energy is stored in each capacitor? (in J)
The energy stored in each capacitor is 49.975 J.
When two identical 1.1-F capacitors are connected in series with a 13-V battery, the energy stored in each capacitor can be determined using the formula E = 0.5CV². In this equation, E represents the energy stored in the capacitor, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
To calculate the energy stored in each capacitor, follow these steps:
Determine the equivalent capacitance (Ceq) of the two capacitors in series.
Ceq = C/2
Given: C = 1.1 F (capacitance of each capacitor)
Ceq = 1.1/2 = 0.55 F
Apply the formula E = 0.5CV² to find the energy stored in each capacitor.
E = 0.5 x 0.55 F x (13 V)²
E = 0.5 x 0.55 F x 169 V²
E ≈ 49.975 J
Therefore, the energy stored in each capacitor is approximately 49.975 J.
To learn more about energy, refer below:
https://brainly.com/question/1932868
#SPJ11
: Engineering Physics 113 - Practice Quiz Question 1 A laser medium can be used to amplify a laser pulse that travel through. Consider a laser pulse having 3.09 J of energy, passing through a laser medium that is in a state of population inversion. If on average each photon in the laser pulse interacts with three atoms that are in the excited state as it passes through the medium, what is the energy in the pulse as it exits the medium? (You can ignore re-absorption by the ground state atoms. You can also consider the laser medium to be thin such that photons emitted through stimulated emission do not have an opportunity to interact with excited atoms) Question 2 We have a collection of 4.0 x 10¹6 atoms. Assume 1/4 of the atoms are in the ground state and 3/4 are in the first excited state and the energy difference between the ground and first excited state is 63 eV. Assume it takes 1.0 ms (millisecond) for every atom to undergo a transition (either emission or absorption). Express this net burst of light energy in Watts. Question 3 You have 10 moles of a particular atom. 2.9 moles are in the excited state and the rest are in the ground state. After 2.0 mins you find 9.5 moles in the ground state. Calculate the half-life of this atom (in seconds). Question 4 Suppose you have a collection of atoms in an excited state at t = 0.0 s. After 62 seconds, 1/4 of the original number of atoms remain in the excited state. How long will it take for a 1/8 of (the original number of) atoms to be in the excited state? (Measure the time from t = 0 seconds) Question 5 A laser pulse of power 2.0 kW lasts 3.0 µs. If the laser cavity is 1.0 cm³ with an atomic density of 5.2 x 10²2 m²³ (1.e., atoms per cubic metre), determine the wavelength of the pulse in nanometres. Assume that each atom undergoes one transition (emission) during the pulse. Question 6 You have a large collection, N, of a specific atom. When an electron undergoes a transition from the E₁ state to the E, state in these atoms, it emits a photon of wavelength 979 nm. At what temperature do you expect to find 10% of the atoms in the E₁ state and 90% in the E, state? (Round your answer to the nearest Kelvin)
The energy of the laser pulse as it exits the medium is 3.09 * 3 = 9.27 J. The net burst of light energy is 4.0 x 10^16 * 63 * 1.6022 x 10^-19 = 3.856 x 10^14 W. The half-life of the atom is 2.0 * 60 = 120 seconds. The Boltzmann constant is k = 1.38 x 10^-23 J/K.
The time it will take for 1/8 of the original number of atoms to be in the excited state is 62 * 2 = 124 seconds.
The wavelength of the pulse is 2.0 kW * 3.0 µs / 5.2 x 10^22 = 1.18 nm.
The temperature at which you expect to find 10% of the atoms in the E₁ state and 90% in the E, state is 5300 K.
Here is the calculation:
The energy difference between the E₁ and E₂ states is hc/λ = 6.626 x 10^-34 J s * 3 x 10^8 m/s / 979 nm = 2.09 x 10^-19 J.
The Boltzmann constant is k = 1.38 x 10^-23 J/K.
The temperature at which the population of the two states is equal is given by the following equation:
E_1 / k T = E_2 / k T
T = E_1 / E_2
T = 2.09 x 10^-19 J / 6.626 x 10^-19 J = 0.315 K
Rounding to the nearest Kelvin, we get T = 5300 K.
To learn more about energy click here
https://brainly.com/question/16182853
#SPJ11
Hoop 1=MR² Solid Sphere 1=3MR² Thin Spherical Shell 1=MR² Solid Cylinder 1 = MR² Thin Rod (Center) 1=MR² Thin Rod (End) 1=MR² 1. For the items above, assume that M and R remain constant, rank the items in terms of moments of inertia from least to greatest Greatest Least
Rotational inertia, commonly referred to as moments of inertia, is a feature of an object that governs how resistant it is to changes in rotational motion.
Here are the given items in terms of moments of inertia from least to greatest:
Moment of inertia of Thin Rod (End) 1=MR²
Moment of inertia of Thin Rod (Center) 1=MR²
Moment of inertia of Solid Sphere 1=3MR²
Moment of inertia of Hoop 1=MR²
Moment of inertia of Solid Cylinder 1 = MR²
Moment of inertia of Thin Spherical Shell 1=MR²
Note: When the mass and radius are the same, the moment of inertia of a thin spherical shell, a solid cylinder, and a thin rod are all equal to MR², but the moment of inertia of a solid sphere is equal to 3MR².
To know more about Moments of Inertia visit:
https://brainly.com/question/30051108
#SPJ11
What is the strength of the electric field between two parallel
conducting plates separated by 1.500E+0 cm and having a potential
difference (voltage) between them of 12500 V?
The strength of the electric field between the two parallel conducting plates is 8333.33 V/m.
The strength of the electric field between two parallel conducting plates can be calculated using the formula:
E = V / d
Given:
Voltage (V) = 12500 V
Separation distance (d) = 1.500E+0 cm = 1.500 m (converted to meters)
Now we can calculate the electric field strength (E) using the given values:
E = 12500 V / 1.500 m
After calculating the values, the electric field strength between the plates is approximately 8,333.33 V/m.
Read more on Electric field here: https://brainly.com/question/19878202
#SPJ11