Answer:
See Explanation
Step-by-step explanation:
Required
Complete the term and identify the rule
[tex](a)\ 5, 6, 8, [], 15[/tex]
We have:
[tex]5 + 1 = 6[/tex]
[tex]6 + 2 = 8[/tex]
[tex]8 + 3 = 11[/tex] --- Missing term
[tex]11 + 4 = 15[/tex]
The rule is:
Add current term to the position of term
i.e.
[tex]T_{n+1} = T_n + n[/tex]
[tex](b)\ 18, 20, 24, [], 38[/tex]
We have:
[tex]18 + 2*1 = 20[/tex]
[tex]20 + 2*2 = 24[/tex]
[tex]24 + 2 * 3 = 30[/tex] --- Missing term
[tex]30 + 2 * 4 = 38[/tex]
The rule is:
Add current term to twice the position of term
i.e.
[tex]T_{n+1} = T_n + 2 *n[/tex]
[tex](3)\ 14, 17, 20, 23, [][/tex]
We have:
[tex]14 + 3 = 17[/tex]
[tex]17 + 3 =20[/tex]
[tex]20 + 3 = 23[/tex]
[tex]23 + 3 = 26[/tex] --- Missing term
The rule is: Add 3
i.e.
[tex]T_{n+1} = T_n + 3[/tex]
[tex](4)\ 24, 30, 36, 42, [][/tex]
We have:
[tex]24 + 6 = 30[/tex]
[tex]30 + 6 = 36[/tex]
[tex]36 + 6 = 42[/tex]
[tex]42 + 6 = 48[/tex] --- Missing term
The rule is: Add 6
i.e.
[tex]T_{n+1} = T_n + 6[/tex]
[tex](5)\ 1, 10, 100[/tex]
We have:
[tex]10^0 = 1[/tex]
[tex]10^1 = 10[/tex]
[tex]10^2 = 100[/tex]
[tex]10^3 = 1000[/tex] -- Missing term
The rule is: 10 to the power of current position
i.e. [tex]T_n = 10^n[/tex]
Please this a really easy question. Does this mean I got an A on this test?! Please answer!!!!!!!!!!!!!!!
Answer:
yes it does. good job on your A.
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
Maggie bought c CDs for $12 each, b books for $7 each, and a purse costing $24.
a. Write an expression to show the total amount of money Maggie spent.
b. If Maggie bought 4 CDs and 3 books, how much money did she spend?
Answer:
b. (4×12)+(3×7)
48+21= 69
she spent $69
helpppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeee
Answer:
Area of a circle= π r square
22/7 × 6 ×6
22/7×36
= 792/7
=113.40
find the common difference of the arithmetic sequence 3, -2, -7
Answer:
-5
Step-by-step explanation:
To find the common difference, take the second term and subtract the first term
-2 - 3 = -5
Check with the third term and the second term
-7 - (-2) = -7 +2 = -5
The common difference is -5
Please help I really need help. I am super confused and would really appreciate it
Answer:
[tex] a^{5} [/tex]
Step-by-step explanation:
Given the mathematical expression;
a⁸/a³
To rewrite the expression in the form [tex] a^{m} [/tex]
We would have to apply the law of indices.
[tex] Law \; of \; division = \frac {a^{x}}{a^{y}} = a^{x - y} [/tex]
[tex] Law \; of \; division = \frac {a^{8}}{a^{3}} = a^{8 - 3} [/tex]
[tex] a^{m} = a^{8 - 3} = a^{5} [/tex]
WHAT IS 5 TIMES 2 I NEED HELP ASAP BECAUSE I CANT KEEP UP UGHHHH
Answer:
2X2
Step-by-step explanation:
Answer: 10
Step-by-step explanation: 5 x 2 = 10
5 + 5 = 10
ILL MARK BRAINLIEST!
Which of these points lies on the graph of the equation x – 9 = y?
A. (3, 6)
B. (2, 11)
C. (-3,-6)
D. (-2, -11)
Answer:
D. (-2, -11)
Step-by-step explanation:
Since -2 - 9 = -11, it fits into the equation x - 9 = y, with -2 being "x" and -11 being "y".
And out of all the options, D is the only one that works.
The "freshman 15" is the name of a common belief that college students, particularly women, gain an average of 15 pounds during their first year of college. In one study of 110 female first‐year college students (Psychology of Women Quarterly, vol 17, pp.119‐126, 1993), the mean weight was 130.6 pounds at the beginning of the study and 131.4 pounds six months later. The standard deviation was about 20 pounds at each time.
Required:
a. Estimate the change in the mean weight over this six‐month period.
b. Is this sufficient information to find a confidence interval or conduct at estimate about the change in the mean over six months? If not what else do you need to know?
Answer:
A) - 0.8 Ibs
B) There isn't enough information
The standard deviations of the difference scores is needed
Step-by-step explanation:
N = 110 female first year college students
Mean weight at beginning of study = 130.6 Ib
Mean weight after six ( 6 ) months = 131.4 Ib
standard deviation = 20 pounds
A) Determine the change in the mean weight over the six(6) months period
mean weight at beginning - mean weight after six(6) months
= 130.6 - 131.4
= -0.8 Ibs
B) Determine if there is sufficient information to find a confidence interval
There isn't sufficient information to determine the confidence interval but in other to determine the confidence interval or conduct an estimate You need standard deviations of the difference scores to calculate the standard error of mean
Plz help its my last grade and i really need it to be good
Answer:
Option D
Step-by-step explanation:
[tex]60+45+75=180[/tex]
[tex]Triangle ~has ~the~ sum ~of ~angle =180[/tex]
--------------------------
hope it helps...
have a great day!!
Answer:
D will be your answer!!
Step-by-step explanation:
hope it helps
5x+25=75 pls help appreciated
Answer:
x=10
Step-by-step explanation:
I guess solve for x
5x=50
x=10
Answer:
x=10
Step-by-step explanation:
Subtract to 25 from both sides
5x+25-25=75-25
so 75- 25 is 50
then ur left with 5x=50 so u divide because 5 is by x which means multipy so u do the opposite which is divding
5÷50 =10
If y =
ya
x and x = -18, find y.
Answer:
y
=
3
√
−
2
a
x
y
=
−
3
√
−
2
a
x
Step-by-step explanation:
Prove the statement below directly from the definitions of the terms.
For all integers n, n2 + n +1 is odd.
Answer:
We know that:
If A is an even integer number, then A + 1 is an odd number
If B is an odd number, then B + 1 is an even number.
We also know that the product of two odd numbers is odd, and the product of two even numbers is even.
We want to prove that:
For all integers n, n^2 + n + 1 is odd.
We have two cases.
If n is even, then:
n^2 is the product of two even numbers, so is even.
n^2 + n is the sum of two even numbers, then it is even.
And:
(n^2 + n) + 1 is an even number plus one, so it is odd.
Now let's assume that n is odd.
n^2 is the product of two odd numbers, then n^2 is odd.
n^2 + n is the sum of two odd numbers, then it is even.
And similar as the previous case:
(n^2 + n) + 1 is an even number plus one, so it is odd.
Find the side lengths of the triangle in this picture.
Answer:
Hypotenuse: 41 meters, Long leg: 40 meters, Short leg: 9 meters.
Step-by-step explanation:
According to the statement, we have the following information about the lengths of the right triangle:
Hypotenuse
[tex]3\cdot x + 14[/tex]
Long leg
[tex]3\cdot x + 13[/tex]
Short leg
[tex]x[/tex]
By the Pythagoric Theorem, we have the following expression:
[tex](3\cdot x + 14)^{2} = x^{2} + (3\cdot x + 13)^{2}[/tex] (1)
[tex]9\cdot x^{2}+84\cdot x + 196 = x^{2} + 9\cdot x^{2} + 78\cdot x + 169[/tex]
[tex]9\cdot x^{2} + 84\cdot x + 196 = 10\cdot x^{2} + 78\cdot x +169[/tex]
[tex]x^{2} -6\cdot x -27 = 0[/tex]
[tex](x-9)\cdot (x+3) = 0[/tex]
As length is a positive variable by nature, then the only possible solution is [tex]x = 9[/tex]. Lastly, the side lengths of the right triangle are:
Hypotenuse: 41 meters, Long leg: 40 meters, Short leg: 9 meters.
A watermelon that weighed 12 pounds cost $5.76. What was the cost per ounce of the watermelon?
Answer:
69.12
Step-by-step explanation:
12x5.76
Answer
69
Step-by-step explanation:
12×5.75=69
Daryl can jump 2 1/2 yards. sarah can jump 8 feet michell can jump 72 inches, witch statement is true.
Answer:
Where are the statements?
Step-by-step explanation:
Where are the statements?
Which one of the following is an ordered pair?
{-3, 5}
(2, 4, 0)
(0, 6)
1, 3
9514 1404 393
Answer:
(c) (0, 6)
Step-by-step explanation:
Conventionally, an "ordered pair" is a pair of items in parentheses, separated by a comma. The items don't have to be numbers. (0, 6) is an ordered pair.
__
Comments on the other answer choices
Curly braces are usually used as delimiters of a set, not an ordered pair.
Three items do not constitute a "pair." Rather, they are a "triple."
Items without any particular indicator of grouping are usually not considered a "pair."
Determine the area of this triangle...
Answer:
650,000 cm²
Step-by-step explanation:
10x6.5=65 METERS squared. They want it in CENTIMETERS squared.
65m² = 650,000cm²
Answer:
32.5[tex]m^{2}[/tex]
Step-by-step explanation:
The coloured triangle with the blank triangle area =
(14m x 6.5m)÷2 = 45.5[tex]m^{2}[/tex]
The blank triangle area =
[(14-10m) x 6.5m]÷2 = 13[tex]m^{2}[/tex]
Therefore:
The coloured triangle area =
(45.5 - 13)[tex]m^{2}[/tex]
=32.5[tex]m^{2}[/tex]
The radius of a cylinder is 5 cm and the height is 7 cm.
Find the volume of the cylinder.
O 17517
7011
12011
No answer text provided.
Answer:
V = πr²h
V = 3.14 (5cm)²(7 cm)
V = 3.14 (25cm²) ( 7 cm)
V = 3.14 (175 cm³)
V = 549.50 cm³
Helllppppp me quick!!!!!!!
Answer:
F(x) =2x+3
Step-by-step explanation:
F(x) =2x+3...............
Answer:
[tex]consider : (0, 3) \: and \: (1, 5) \\ gradient = \frac{5 - 3}{1 - 0} \\ = 2 \\ from : \: y = mx + c \\ consider \: (0, 3) \\ 3 = (2 \times 0) + c \\ c = 3 \\ therefore \: equation \: is : \\ y = 2x + 3[/tex]
Can someone help me I am stuck on this question it would mean the world if u helped me! and TYSM! for the people who helped me have a wonder full day!
Answer:
1.25 gallons of orange juice needed
Step-by-step explanation:
2(3/4)=3/2 cups per 1 person
24 x 3/2=36 cups for everyone
36 cups=18 pints
18-8=10 pints of orange juice
10 pints = 1.25 gallon
Answer:
1.25 gallons of orange juice
Step-by-step explanation:
24x2=48
3/4x48=36
36 cups into pints is 18 pints
18-8=10
10 pints into gallons is 1.25 gallons
A store sells small notebooks for $8 and large notebooks for $16. If a student buys 6 notebooks and spends $80, how many of each size did he buy?
Answer:
Small-6
Large-2
Step-by-step explanation:
small-$8
large-$16
$8×6=$48
$80-$48=$32
32÷16=2(large)
An equation with real coefficients has (1-i), 3, and 4 among its roots. What is the lowest possible degree of the equation?
A: 3
B: 4
C: 5
D: 6
Answer:
D
Step-by-step explanation:
(x2 + 5x +4) × (x + 4)
׳+9x²+24×+16 ...............
Classify the following triangle. Check all that apply.
A
I A. Equilateral
B. Right
C. Acute
I D. Isosceles
O E Obtuse
O F. Scalene
Answer:
A and C
Step-by-step explanation:
The triangle given has three equal sides and three equal angles.
Since the sum of a triangle = 180°, therefore, each angle equals 60°
Thus, we can conclude that the triangle is an acute triangle because an acute triangle has all three sides measuring less than 90°. This implies that all it's angles are acute angles.
Also, since all its sides are equal and the same as well as it's three angles, based on this, we can equally say the triangle is an equilateral triangle.
The triangle can be referred to as an acute triangle and also as an equilateral triangle.
Please, help meeeeee
Answer:
y = 500x + 1000
Step-by-step explanation:
The standadrd equation of a line is expressed as y = mx+b
m is the slope
is the y-intercept
Using the coordinate points (0, 1000) and (6, 4000)
Slope = y2-y1/x2-x1
Slope = 4000 - 1000/6-0
Slope m = 3000/6
Slope m = 500
Since the line cut the y axis at y = 1000, hence the intercept b = 1000
Get the required equation;
Reall that y = mx+b
y = 500x + 1000
Question 12: Angle M and Angle P are what type of angles?
m
n
o
Р
qr
st
adjacent
right
obtuse
O vertical
Answer:
adjacent anf o vertical
Step-by-step explanation:
Find the length of a to the nearest tenth using the Pythagorean theorem
Answer:
Ab^2 = CA^2 + BC^2
8^2 = 6^2 + a^2
64 = 36 + a^2
64-36 = a^2
28 = a^2
square root of 28 = square root of a^2
5 ,29 = a
5 = a
Solve
W times 4 - 10=42
Please help quick thank you
Answer:
13
Step-by-step explanation:
4w-10=42
4w=52
w=52/4
w=13
A leasing firm claims that the mean number of miles driven annually, , in its leased cars is less than miles. A random sample of cars leased from this firm had a mean of annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is miles. Assume that the population is normally distributed.
Is there support for the firm's claim at the level of significance?
Perform a one-tailed test.
null hypothesis?
alternative hypothesis?
type of test statistic?
value of the test statistic?
the p-value?
Can we support the leasing firm's claim that the mean number of miles driven annually is less than 12800 miles?
Complete question is;
A leasing firm claims that the mean number of miles driven annually, u , in its leased cars is less than 12800 miles. A random sample of 50 cars leased from this firm had a mean of 12499 annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is 3140 miles. Is there support for the firm's claim at the 0.05 level of significance?
Perform a one-tailed test.
null hypothesis?
alternative hypothesis?
type of test statistic?
value of the test statistic?
the p-value?
Can we support the leasing firm’s claim that the mean number of miles driven annually is less than 12800 miles?
Answer:
A) Null hypothesis; μ ≥ 12800
Alternative hypothesis; μ < 12800
B) type of test statistic: z-score test
C) test statistic; z = -0.678
D) p - value = 0.2489
E) No, we can't support the leasing firms claim
Step-by-step explanation:
We are given;
Population mean; μ = 12800 miles
Sample mean; x¯ = 12499 miles
Sample size; n = 50
Population standard deviation; σ = 3140
Let's define the hypothesis;
Null hypothesis; μ ≥ 12800
Alternative hypothesis; μ < 12800
The alternative hypothesis is the claim.
Since sample size is greater than 30, we will use z-score test.
Formula for z-score;
z = (x¯ - μ)/(σ/√n)
z = (12499 - 12800)/(3140/√50)
z = -0.678
From online p-value from z-score calculator attached, using z = -0.678 with one tailed hypothesis and significance value of 0.05,we have;
p - value = P(z < -0.678) = 0.2489
The p-value is greater than the significance value, so we will fail to reject the null hypothesis and conclude that there is no sufficient information to support the leasing firm's claim
A market researcher would like to know how much time the average college student spends watching sports. Suppose he does a preliminary study based upon a sample of 25 college students. The mean amount of time spent watching sports, by those in the sample, is 90 minutes per day with a standard deviation of 15 minutes per day.
(a) Which of the following numbers gives the value of the point estimate?
a. 15.
b. 25.
c. 90.
d. 0.
e. 95.
(b) Using the information given above, calculate the margin of error (in minutes) of the point estimate. Assume we would like to estimate the population mean with 95% confidence.
(c) Suppose that the researcher is not content with the current margin of error. He would like the margin of error of the point estimate to be no more than 4 minutes with 95% confidence. The researcher is unwilling to trust that the sample standard deviation from his previous study accurately estimates the true population standard deviation. He does, however, know that college students tend to watch sports between 0 and 120 minutes per day. What is the minimum sample size needed to obtain this amount of precision?
Answer:
a) c. 90.
b) The margin of error of the point estimate is of 6.19 minutes.
c) The minimum sample size needed to obtain this amount of precision is 289.
Step-by-step explanation:
(a) Which of the following numbers gives the value of the point estimate?
The value of the point estimate is the sample mean, of 90 minutes. So the answer is given by option c.
(b) Using the information given above, calculate the margin of error (in minutes) of the point estimate. Assume we would like to estimate the population mean with 95% confidence.
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.0639.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}}[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
Here, we have [tex]s = 15, n = 25[/tex]. So
[tex]M = T\frac{s}{\sqrt{n}}[/tex]
[tex]M = 2.0639\frac{15}{\sqrt{25}}[/tex]
[tex]M = 6.19[/tex]
The margin of error of the point estimate is of 6.19 minutes.
Question c:
College students tend to watch sports between 0 and 120 minutes per day, which means that the standard deviation for population can be estimated as the standard deviation of an uniform distribution with [tex]a = 0, b = 120[/tex]. This standard deviation is:
[tex]\sigma = \sqrt{\frac{(b-a)^2}{12}}[/tex]
Then
[tex]\sigma = \sqrt{\frac{(120-0)^2}{12}}[/tex]
[tex]\sigma = 34.64[/tex]
Minimum sample size:
Now, since we have an estimate for the standard deviation of the population, we use the z-distribution.
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
The minimum sample size is n for which M = 4. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]4 = 1.96\frac{34.64}{\sqrt{n}}[/tex]
[tex]4\sqrt{n} = 1.96*34.64[/tex]
[tex]\sqrt{n} = \frac{1.96*34.64}{4}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*34.64}{4})^2[/tex]
[tex]n = 288.1[/tex]
Rounding up:
The minimum sample size needed to obtain this amount of precision is 289.