Answer:
The intensity of laser 2 is 4 times of the intensity of laser 1.
Explanation:
The intensity in terms of electric field is given by :
[tex]U=\dfrac{1}{2}\epsilon_o E^2[/tex]
E is electric field
It means, [tex]U\propto E^2[/tex]
In this problem, lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2.
Let E is electric field in the beam of laser 1 and E' is the electric field in the beam of laser 2. So,
[tex]\dfrac{U}{U'}=(\dfrac{E}{E'})^2[/tex]
We have,
E'=2E
So,
[tex]\dfrac{U}{U'}=\dfrac{E^2}{(2E)^2}\\\\\dfrac{U}{U'}=\dfrac{E^2}{4E^2}\\\\\dfrac{U}{U'}=\dfrac{1}{4}\\\\U'=4\times U[/tex]
So, the intensity of laser 2 is 4 times of the intensity of laser 1.
A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle is pin-connected to its center and subjected to force N. If the wheel rolls without slipping on the flat stationary ground surface, find its angular acceleration . Consider counterclockwise to be positive when reporting your answer.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]\alpha =2.538 \ rad/s^2[/tex]
Explanation:
From the question we are told that
The mass of the wheel is m = 6.9 kg
The radius is [tex]r = 0.69 \ m[/tex]
The radius of gyration is [tex]k_G = 0.4\ m[/tex]
The angle is [tex]\theta = 47^o[/tex]
The force which the massless bar is subjected to [tex]F = 22.5 \ N[/tex]
Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that point A is the center of rotation.
Generally the moment of inertia about A is mathematically represented as
[tex]I_a = I_G + M* r^2[/tex]
Here [tex]I_G[/tex] is the moment of inertia about G with respect to the radius of gyration which is mathematically represented as
[tex]I_G = M * k_G[/tex]
=>[tex]I_a = k_G* M + M* r^2[/tex]
=>[tex]I_a =0.4 * 6.9 + 6.9 * 0.69^2[/tex]
=>[tex]I_a =6.045 \ kg \cdot m^2[/tex]
Generally the torque experienced by the wheel is mathematically represented as
[tex]\tau = F * cos (47)[/tex]
=> [tex]\tau = 22.5 * cos (47)[/tex]
=> [tex]\tau = 15.34 \ kg \cdot m^2 \cdot s^{-2}[/tex]
Generally this torque is also mathematically represented as
[tex]\tau = I_a * \alpha[/tex]
=> [tex]15.34 = 6.045 * \alpha[/tex]
=> [tex]\alpha =2.538 \ rad/s^2[/tex]
A car is traveling at 70 mi/hr. The car travels for half an hour, how far has the car gone? Don't forget to include units of measurement.
Distance = (speed) x (time)
Distance = (70 mi/hr) x (0.5 hr)
Distance = 35 miles
50
1. Force = ? N mass = 65 kg acceleration = 25 m/s2 (Record your answer
by number only and don t.include units...)
Answer: el pepe
Explanation:
Answer:
8125 N.
Explanation:
F = M A
M is mass
A is acceleration
F = 65 X 25
F = 8125 N.
1.) True or False. Scientists have drilled through the crust to reach the mantle.
Answer:
False
Explanation:
We have never made it to the mantle.
A 50-kg cart is on an incline of 30 degrees above the horizontal. The cart is at rest. The static coefficient of the slope is 0.85 and the kinetic coefficient is 0.50. What is the force due to friction on the cart?
The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude w), the normal force (mag. n), and the friction force (maximum mag. f ).
In the horizontal direction, we have
n cos(120º) + f cos(30º) = 0
-1/2 n + √3/2 f = 0
n = √3 f
and in the vertical,
n sin(120º) + f sin(30º) + (-w) = 0
n sin(120º) + f sin(30º) = (50 kg) (9.80 m/s²)
√3/2 n + 1/2 f = 490 N
Substitute n = √3 f and solve for f :
√3/2 (√3 f ) + 1/2 f = 490 N
2 f = 490 N
f = 245 N
(pointed up the incline)
The process of blood cell formation is called
if air had a taste, would we all not need to eat again?
Answer:
prolly
Explanation:
Which of these forms due to the force of compression?
A) Anticline
B) Normal Fault
C) Strike-Slip Fault
D) Fault-Block Mountain
Answer:
anticline
Explanation:
hope u will understand
Answer:
Got it right on edge 2020
Explanation:
anticline
Which statement best describe one of George Berkeley's arguments against materialism?
O A. There cannot be two different substances; my mind exists; therefore, matter does not exist.
OB. To be is to be perceived; we don't perceive matter; therefore, matter does not exist.
OC. I can only perceive my own mind; therefore, matter does not exist.
OD.
I can only perceive other minds; therefore, matter does not exist.
Reset
Next
Answer:
the answer is B
Explanation:
materialism is just wanting to always buy new things B does the opposite
Which of the following is not a consequence of fossil fuel use?
a. increased concentrations of atmospheric carbon dioxide
b. destruction of wildlife habitats
C. leaching of waste into groundwater
d. none of the above
Answer:
its D
Explanation:
From the all given option, no one is the consequence of fossil fuel use. Option D is correct.
What are fossil fuels?Fossil fuels are obtained beneath the earth's crust, which is formed due to buried plants and animals. The excessive heat under the earth crust heats the plants and animals.
Fossil fuel took a long time to form, it comes under the nonrenewable source of energy.
The use of fossil fuels such as coal, oil, natural gas, and technical advancements in the contemporary age is driving the acceleration of change in human cultures today.
The benefit of using fossil fuels;
a. Increased concentrations of atmospheric carbon dioxide
b. Destruction of wildlife habitats.
C. leaching of waste into groundwater
From the all given option, no one is the consequence of fossil fuel use.
Hence, option D is correct.
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Aquatic organisms are going extinct five times faster than land organisms due to water pollution.
True
False
Answer:
true 知恵を yfyfhdftufvdughf
What can be described as a technology that uses high-frequency sound waves to create images?
A. ultrasound
B. echolocation
C. analog signal
D. digital signal
Answer:
Ultrasound can be described as a technology that uses high-frequency sound waves to create images.
Explanation:
Ultrasound can be described as a technology that uses high-frequency sound waves to create images.
What is ultrasound?Ultrasound imaging uses sound waves to produce pictures of the inside of the body. It helps diagnose the causes of pain, swelling and infection in the body's internal organs and to examine an unborn child (fetus) in pregnant women.
In infants, doctors commonly use ultrasound to evaluate the brain, hips, and spine. . It also helps guide biopsies, diagnose heart conditions, and assess damage after a heart attack. Ultrasound is safe, non-invasive, and does not use radiation.
This procedure requires little to no special preparation. Your doctor will tell you how to prepare, including whether you should not eat or drink beforehand. Leave jewellery at home and wear loose, comfortable clothing. You may need to change into a gown.
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What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
Complete Question
An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.
Answer:
The torque is [tex]\tau = 34.3 \ N\cdot m[/tex]
Explanation:
From the question we are told that
The mass of the steel ball is [tex]m = 3.0 \ kg[/tex]
The length of arm is [tex]l = 70 \ cm = 0.7 \ m[/tex]
The mass of the arm is [tex]m_a = 4.0 \ kg[/tex]
Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as
[tex]r = \frac{l}{2}[/tex]
=> [tex]r = \frac{ 0.7}{2}[/tex]
=> [tex]r = 0.35 \ m[/tex]
Generally the magnitude of torque about the athlete shoulder is mathematically represented as
[tex]\tau = m_a * g * r + m * g * L[/tex]
=> [tex]\tau = 4 * 9.8 * 0.35 + 3 * 9.8 * 0.70[/tex]
=> [tex]\tau = 34.3 \ N\cdot m[/tex]
What is the weight of an astronaut who has a mass of 90 kg on the moon? (Note: acceleration due to gravity of the moon is 1.62 N/kg
Answer:
W = 145.8 [N]
Explanation:
To solve this problem we must remember that weight is defined as the product of mass by gravity, in this case lunar gravity.
W = m*g
where:
m = mass = 90 [kg]
g = gravity acceleration = 1.62 [kg/m²]
W = 90*1.62
W = 145.8 [N]
WILL MARK BRAINLIEST PLS HELPPP -- Which of Newton’s Laws explains why the satellite would collide with the moon if gravity is “turned off?”
picture attached
Answer:
b
Explanation:
Optical astronomers need a clear, dark sky to collect good data. Explain why radio astronomers have no problem observing in the UK where it is often very cloudy.
Answer:
In the clarification portion elsewhere here, the definition of the concern is mentioned.
Explanation:
So like optical telescopes capture light waves, introduce it to concentrate, enhance it, as well as make it usable through different instruments via study, so radio telescopes accumulate weak signal light waves, introduce that one to focus, enhance it, as well as make this information available during research. To research naturally produced radio illumination from stars, galaxies, dark matter, as well as other natural phenomena, we utilize telescopes.
Optical telescopes detect space-borne visible light. There are some drawbacks of optical telescopes mostly on the surface:
Mostly at night would they have been seen. Unless the weather gets cloudy, bad, or gloomy, they shouldn't be seen.Although radio telescopes monitor space-coming radio waves. Those other telescopes, when they are already typically very massive as well as costly, have such an improvement surrounded by optical telescopes. They should be included in poor weather and, when they travel through the surrounding air, the radio waves aren't obscured by clouds. Throughout the afternoon and also some at night, radio telescopes are sometimes used.
*Earth Science Question*
Uses an array of mirrors to allow the collection of more light*
A. Reflecting
B. Refracting
C. Multiple Mirror
D. CCD
hi people see bye 18 45 36
Answer:
bye
Explanation:
Some help me on this please
What can be said for certain about the affect of an external net force on
an object? *
A.It changes the object's mass.
B.It changes the object's kinetic energy.
C.It changes the object's temperature.
D.It changes the object's momentum.
Answer:
Changes in the object's momentum (answer D)
Explanation:
A net force will cause an object to change its velocity, and that will affect the object's momentum, which is defined by the product of the object's mass times its velocity.
So, select the last option (D) in the given list.
A car with a mass of 1240kg starts from rest and accelerates to a speed of 19.4m/s in 10.2s. Assume that the force of resistance remains constant at 376N during this time. What is the average power developed by the car's engine?
Answer:
Power, P = 38459.16 W
Explanation:
Given that,
Mass of a car, m = 1240 kg
Initial speed, u = 0
Final speed, v = 19.4 m/s
Time, t = 10.2 s
The resistance force, R = 376 N
We need to find the average power developed by the car's engine. It is given by the formula as follows :
[tex]P=F\times v\\\\P=(ma-R)v\\\\P=(\dfrac{mv}{t}-R)v\\\\P=(\dfrac{1240\times 19.4}{10.2}-376)\times 19.4\\\\P=38459.16\ W[/tex]
So, the required power is 38459.16 watts.
In a head-on collision, a ball of mass 0.3 kg travelling with velocity 2.8 m/s in the positive x-direction hits a stationary second ball of mass 0.4 kg. What is the velocity of the 0.3 kg ball after the collision? Assume collision is elastic.
Answer:
The final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.
Explanation:
Given;
mass of the first object, m₁ = 0.3 kg
initial velocity of the first ball, u₁ = 2.8 m/s
mass of the second ball, m₂ = 0.4 kg
initial velocity of the second ball, u₂ = 0
let the final velocity of the first ball, = v₁
let the final velocity of the second ball, = v₂
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.3 x 2.8) + (0.4 x 0) = 0.3v₁ + 0.4v₂
0.84 = 0.3v₁ + 0.4v₂
2.8 = v₁ + 1.333v₂ -------equation (1)
Apply one-direction velocity;
u₁ + v₁ = u₂ + v₂
2.8 + v₁ = 0 + v₂
v₂ = 2.8 + v₁
substitute the value of v₂ into equation (1)
2.8 = v₁ + 1.333v₂
2.8 = v₁ + 1.333(2.8 + v₁)
2.8 = v₁ + 3.732 + 1.333v₁
2.8 - 3.732 = v₁ + 1.333v₁
-0.932 = 2.333v₁
v₁ = -0.932 / 2.333
v₁ = -0.4 m/s
Therefore, the final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.
The kinetic friction coefficient between a cabinet and the floor is 0.3. Mass of the cabinet is 300kg. A man pushes the cabinet along the floor with a 1000N force. Find the acceleration of the cabinet. g
Answer:
0.39m/s^2Explanation:
Step one:
given data
mass m= 300kg
applied force F= 1000N
coefficient of friction μ= 0.3
Step two:
The net force Fn= applied force-friction force
Fn=F-F1
F1= limiting force
F1=μ*m*g
F1=0.3*300*9.81
F1=882.9N
the Net force= 1000-882.9
Fn=117.1N
Step three:
we know that
F=ma
Fnet=ma
a= Fnet/m
a=117.1/300
a=0.39m/s^2
a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration? how much time will take to complete the around?
Answer:
[tex]a=200\ m/s^2[/tex] and t = 0.5 s
Explanation:
Given that,
Mass of the object, m = 90 gram = 0.09 kg
Diameter of the circle, d = 2.56 m
Radius, r = 1.28 m
Speed, v = 16 m/s
We need to find the object acceleration. On the circular path, acceleration is given by :
[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{1.28}\\\\a=200\ m/s^2[/tex]
So, the object's acceleration is [tex]200\ m/s^2[/tex].
Let t is time it will take to complete the around. Speed is given by :
[tex]v=\dfrac{2\pi r}{t}\\\\t=\dfrac{2\pi r}{v}\\\\t=\dfrac{2\pi \times 1.28}{16}\\\\t=0.5\ s[/tex]
So, time to cover one complete round is 0.5 s.
1. An object carries a charge of q = +4x10-8C.
How many electrons are needed to make it elec-
trically neutral?
Answer: i can help you
Explanation:
[tex]2.5[/tex]×[tex]10^{11}[/tex] electrons are needed to make an object neutral which is carrying a charge of [tex]q=+4[/tex]×[tex]10^{-8}[/tex]
What is a charge of an electron?The elementary charge (e) has a negative sign, and the electron's charge is equal to its magnitude. The charge of the electron is -1.602 x [tex]10^{-19}[/tex] coulombs (C), while the elementary charge is approximately 1.602 x [tex]10^{-19}[/tex] coulombs (C).Thus, -e can be used to represent the charge of an electron. The proton only possesses an e-charge despite being far more massive than the electron. The number of protons and electrons in neutral atoms is constant.The electron was unquestionably discovered by JJ Thomson. He only succeeded in obtaining the electron's charge-to-mass ratio, though, despite all the experiments he conducted on it. Robert Millikan holds the distinction of being the first to quantify the charge on an electron through his oil-drop experiment in 1909.To learn more about charge, refer to
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What is the ratio of a 0.7 in circle in centimeters.
A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s^2 ?
Answer:
The bicyclist's acceleration is 2.2m/s^2
Explanation:
Given
[tex]u = 2.5m/s[/tex] ---- Initial Velocity
[tex]v = 12.5m/s[/tex] ---- Final Velocity
[tex]t = 4.5s[/tex] ---- Time
Required
Determine the acceleration
This will be solved using the first equation of motion
[tex]v = u + at[/tex]
Substitute values for v, u and a
[tex]12.5 = 2.5 + a * 4.5[/tex]
[tex]12.5 = 2.5 + 4.5a[/tex]
Collect Like Terms
[tex]4.5a = 12.5 - 2.5[/tex]
[tex]4.5a = 10.0[/tex]
Solve for a
[tex]a = 10.0/4.5[/tex]
[tex]a = 2.2m/s^2[/tex] ---- (approximated)
Hence, the bicyclist's acceleration is 2.2m/s^2