Physics High School

Katie and Mark sit next to one another in class. She has a mass of 40 kg and his mass is 65 kg.
If they are 0.5 meters apart, what is the gravitational force between Mark and Katie?

Answers

Answer 1
A :-) for this question , we should apply
F = GMm by d^2
( For making the calculation easy , first remove the decimals )
Given : G = 6.7 x 10^-11 Nm^2 / kg^2
= 67 x 10^-12 Nm^2 / Kg^2
M = 65 kg
m = 40 kg
d = 0.5 m
Solution -
F = GMm by d^2
F = 67 x 10^-12 x 65 x 40 by 0.5 x 0.5
F = 4355 x 40 x 10^-12 by 0.25
F = 174200 x 10^-12 by 0.25
F = 696800 x 10^-12

.:. The Gravitational force between mark and Katie is 696800 x 10^-12

Related Questions

Which describes an interaction within the musculoskeletal system?

Answers

Answer:

The musculoskeletal system involves the complex interactions of muscles, bones, and connective tissues.

When a muscle contracts, a bone will move. When a bone contracts, a muscle will move. When a ligament contracts, a tendon will move.

Answer:

A. when a muscle contracts , a bone will move

Explanation

thats the correct answer to this question on edg2021 :)

PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!

Answers

Answer:

d

Explanation:

A complex arrangement of pulleys forms what is called the block in a block and tackle. The rope used to lift the pulleys and the load is the tackle. A block and tackle is used to lift a truck engine, which has a weight and output force of nearly 8000 N. The input force required to lift this weight using the block and tackle is 400N. What is the mechanical advantage of the block and tackle?

Answers

Answer:

Mechanical advantage = 20

Explanation:

Given:

Output force = 8,000 N

Input force = 400 N

Find:

Mechanical advantage

Computation:

Mechanical advantage = Output force / Input force

Mechanical advantage = 8,000 / 400

Mechanical advantage = 20

Calculate Vector component in Y if the hypotenuse is 32 and angle is 45

Answers

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

[tex]v_y = v \times sin(\theta)[/tex]

Substituting the values from the question gives;

[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]

The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

Answers

Question:

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

A. sinks slightly  

B. rises slightly  

C. floats at the same height  

D. bobs up and down about its old position

Answer:

The correct answer is C)  floats at the same height  

Explanation:

The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.

Cheers!

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