Help me and also show steps thanks will mark brainliest.

Help Me And Also Show Steps Thanks Will Mark Brainliest.

Answers

Answer 1
2. If you follow the main equation y=mx + b using the numbers provided by the table, you will be able to generate the adequate equation. In this case is: y=7/3x + 1

3. Every second the bird drops 50 FT of altitude.

Related Questions

A wave is traveling with a speed of 500 m/sec and has a wavelength of 10 m. Determine its frequency.

Answers

Answer:

I'm gonna get more people here

Answer:

50 hz  yw pplz

Step-by-step explanation:

If (4,-3) is the midpoint of the line segment ST and the coordinates of S are (1,5), find the
coordinates of T.

Answers

Answer:

[tex](7,-11)[/tex]

Step-by-step explanation:

Given

[tex]S = (1,5)[/tex]

[tex]M = (4,-3)[/tex]

Required

Determine the coordinates of T

Midpoint is calculated as:

[tex]M(x,y) = \frac{1}{2}(x_1 +x_2,y_1+y_2)[/tex]

Where:

[tex](x,y) = (4,-3)[/tex]

[tex](x_1,y_1) = (1,5)[/tex]

Substitute these values in the above formula:

[tex](4,-3) = \frac{1}{2}(1 + x_2,5+y_2)[/tex]

Multiply through by 2

[tex]2 * (4,-3) = 2 * \frac{1}{2}(1 + x_2,5+y_2)[/tex]

[tex](8,-6) = (1 + x_2,5+y_2)[/tex]

By direct comparison:

[tex]1 + x_2 = 8[/tex] and [tex]5 + y_2 = -6[/tex]

Solving for x2

[tex]1 + x_2 = 8[/tex]

[tex]x_2 = 8 - 1[/tex]

[tex]x_2 = 7[/tex]

Solving for y2

[tex]5 + y_2 = -6[/tex]

[tex]y_2 = -6 - 5[/tex]

[tex]y_2 = -11[/tex]

Hence, the coordinates of T is: [tex](7,-11)[/tex]

A car and a truck leave the same intersection, the truck heading north at 60 mph and the car heading west at 55 mph. At what rate is the distance between the car and the truck changing when the car and the truck are 30 miles and 40 miles from the intersection, respectively?

Answers

Answer: -81

Step-by-step explanation:

Let x = the car moving towards west = 30

Let y = truck moving towards north = 40

dx/dt = -55

dy/dt = -60

We the use Pythagoras theorem to solve further where,

s² = x² + y²

s² = 30² + 40²

s² = 900 + 1600

s² = 2500

s =✓2500

s = 50

We then differentiate with respect to t, then we will have:

s² = x² + y²

2s ds/dt = 2x ds/dt + 2y dy/dt

50 ds/dt = (30 × -55) + (40 × -60)

50 ds/dt = -1650 - 2400

50 ds/dt = - 4050

ds/dt = -4050/50

ds/dt = -81

A communications tower is supported by two wires, connected at the same point on the ground. One is attached to the tower at D and the long-on at C. The angle AD makes with the ground is 30 ° and the angle between the two wires is 10 °. How much below the top of the tower is the shorter one attached?

Answers

Answer:

10.99 m

Step-by-step explanation:

✍️What we are basically asked to solve here is to find the distance between C and D.

To find CD, find the length of BC, and BD. Their difference will give us CD.

Thus, BC - BD = CD.

✍️Finding BC using trigonometric ratio formula:

[tex] \theta = 30 + 10 = 40 [/tex]

Opposite side = BC = ??

Adjacent side = 42 m

Thus:

[tex] tan(\theta) = \frac{opposite}{adjacent} [/tex]

Plug in the values

[tex] tan(40) = \frac{BC}{42} [/tex]

Multiply both sides by 42

[tex] tan(40) \times 42 = \frac{BC}{42} \times 42 [/tex]

[tex] 35.24 = BC [/tex]

BC = 35.24 m

✍️Finding BD using trigonometric ratio formula:

[tex] \theta = 30 [/tex]

Opposite side = BD = ??

Adjacent side = 42 m

Thus:

[tex] tan(\theta) = \frac{opposite}{adjacent} [/tex]

Plug in the values

[tex] tan(30) = \frac{BD}{42} [/tex]

Multiply both sides by 42

[tex] tan(30) \times 42 = \frac{BD}{42} \times 42 [/tex]

[tex] 24.25 = BD [/tex]

BD = 24.25 m

✍️How much below the top of the tower is the shorter one attached:

Thus,

BC - BD = CD

35.24 m - 24.25 m = 10.99 m

What is f(4) for the function f(x)= 6x+7?

Answers

Answer:

31

Step-by-step explanation:

f(4) = 6x4 + 7

= 24 + 7

= 31

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