Answer:
30%
Step-by-step explanation:
20 cookies in total - 14 remains = 6
6 / 20 = 0.3
0.3 = 30%
Oof :<
I can’t put my fInGer on this question
Answer:
B 21.50 dollars
Step-by-step explanation:
PLEASE HELP WILL MARK BRAINLIEST
Find the new coordinates of the dilation D2 (XYZ).
X' =
Y' =
Z' =
Answer:
X = 1 , 2
Y = -1 , 2
Z = -2 , -1
9) Find the measurement of angle XAW. *
Answer:
50 degrees
Step-by-step explanation:
They are verticle angles
What are the coordinates of the vertex for f(x) = x2 + 4x + 10?
(2, 2)
(2,6)
(-2, 2)
(-2, 6)
9514 1404 393
Answer:
(d) (-2, 6)
Step-by-step explanation:
We can rewrite the function using vertex form.
f(x) = (x^2 +4x) +10
f(x) = (x^2 +4x +4) +10 -4 . . . . . . . add and subtract (4/2)^2
f(x) = (x +2)^2 +6
Compare to vertex form:
f(x) = (x -h)^2 +k
we see that (h, k) = (-2, 6) . . . . the vertex
_____
Additional comment
The value added and subtracted is the square of half the x-coefficient. Inside parentheses, that value "completes the square". Outside parentheses, that value ensures the overall function remains unchanged.
6. Ria purchased a car for
$14,775. Sales tax in her
county is 6.8%.
a. What is the total price of
the car including tax?
b. If she puts $2,100 down,
how much will she be
financing?
c. What will her monthly
payment be if the term of
the loan is 72 months with
an APR of 3.5%?
9514 1404 393
Answer:
a) $15,779.70
b) $13,679.70
c) $210.92
Step-by-step explanation:
a) When tax is added, the total cost is ...
total = price × (1 +tax rate)
total = $14,775 × 1.068 = $15,779.70
__
b) The amount financed is the difference between the total cost and the down payment.
financed = total - down35
financed = $15,779.70 -2100 = $13,679.70
__
c) The monthly payment is found using the amortization formula. It can also be found using any of a number of financial calculators, spreadsheets, or apps.
A = P(r/12)/(1 -(1 +r/12)^-n) . . . . annual rate r, n monthly payments, principal P
A = $13,679.70(0.035/12)/(1 -(1 +0.035/12)^-72) ≈ $210.92
6.5 ft 6 ft- 11 ft N 5 ft What is the surface area? A 258 square feet B 195 square feet C 228 square feet D 330 square feet
Answer:
Step-by-step explanation:
area of base = 5×11 = 55 ft²
area of triangle = ½×5×6 = 15 ft²
area of rectangular face = 6.5×11 = 71.5 ft²
surface area = 55 + 2×15 + 2×71.5 = 228 ft²
Solve the inequality and graph its solution...
3+v≤-9
Answer:
v≤-12, and the graph is left 12
Step-by-step explanation:
Arthur is organising his collection of dvds he has 135 altogether. The ratio of comedy films to action horror is 6 : 8 : 1
Answer: See explanation
Step-by-step explanation:
The number of comedy films will be:
= 6/(6+8+1) × 135
= 6/15 × 135
= 54 comedy films
The number of action films will be:
= 8/(6+8+1) × 135
= 8/15 × 135
= 72 action films
The number of horror films will be:
= 1/(6+8+1) × 135
= 1/15 × 135
= 9 horror films
You are assigned 30 math problems for homework. You complete 24 of them before
dinner. What percent of the homework have you completed? Write AND solve a
proportion or equation to calculate the solution to the question. Show work.
Answer:
You have completed 80%.
24/80=.8, .8=80%
^^(proportion)
Step-by-step explanation:
Answer:
80%
Step-by-step explanation:
You have completed 80% of your homework questoins before you ate dinner.
Please help me will give Brain
Answer: i BELIEVE YOUR ANSWER IS
.....
B
Step-by-step explanation:
round off 45682 in two significant figure
Answer:
Rounded it's 46,000
Step-by-step explanation:
find the area of the shaded region
(the number is 8 for anyone not able to read it)
Answer:
≈ 18.3 m²
Step-by-step explanation:
The shaded area (A) is calculated as
A = area of sector - area of right triangle
area of sector = area of circle × fraction of circle
A = πr² × [tex]\frac{90}{360}[/tex]
= π × 8² × [tex]\frac{1}{4}[/tex] = 64π × [tex]\frac{1}{4}[/tex] = 16π m²
area of triangle = [tex]\frac{1}{2}[/tex] × 8 × 8 = 4 × 8 = 32 m²
shaded area is then
A = 16π - 32 ≈ 18.3 m² ( to the nearest tenth )
Fran thinks of a two digit number. The firs digit is 6 more than the second digit, and the number is prime. What number did fran think of
Answer: The number which Fran is thinking about is 82 or 93.
Step-by-step explanation:
A two-digit number can be written as:
a*10 + b
Where a and b are single-digit numbers.
We know that:
"the first digit is 6 more than the second digit"
then:
a = b + 6
And we know that the second digit is a prime number.
Then we can have:
b = 2
b = 3
b = 5
b = 7
Now let's try with these different options.
if b = 2, then:
a = 2 + 6 = 8
Then the number is:
8*10 + 2 = 82
If b = 3, then:
a = 3 + 6 = 9
Then the number is:
9*10 + 3 = 93
if b = 5, then:
a = 5 + 6 = 11
But a needs to be a single-digit number, then b can not be 5 or larger.
Then the only two possible numbers are:
82 and 93.
So the number which Fran is thinking about is 82 or 93.
Geometry review worksheet
Graphing Trigonometric Functions
Illustrations in reverce order
Explanations:
6. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]
You can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes, so you figure out what you want to put in the blank, but make sure it is not a numerical value. Not even ZERO can be plased there.
_______________________________________________
5. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 4[/tex]
You can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.
_______________________________________________
4. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{2}{1}\pi \\ Amplitude \hookrightarrow 3\frac{1}{2}[/tex]
Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midine.
_______________________________________________
3. [tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow \frac{1}{2}[/tex]
Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.
_______________________________________________
2. [tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]
Again, you can choose to figure the period out by using wavelengths, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period. Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline.
_______________________________________________
1. [tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\pi}{1} \\ Amplitude \hookrightarrow N/A[/tex]
Again, you can choose to figure the period out by looking at the distanse between each endpoint on the x-axis, or by using the formula put in plase. Just simply plug the B-term into the formula to get the period.
I am delighted to assist you at any time.
*I also apologise for the sixth photograph not being present [exercise 1]. The system ALL OF A SUDDEN no longer allows me to display more than five photographs. You will have to see the graph somewhere elce.
please help! literally desperate for help asap!
QTR & TRS
.....................................
Answer:
triangle TQR to triangle TRS
AS angle QRT= angle RTS
QR=TS
and their height are same
hope it helps! :)
Hannah is putting in a tile floor. She needs to determine the angles that should be cut in the tiles to fit the corner. The angle in the corner measures 90. One piece of the tile will have a measure of 38. Write an equation, and use it to determine the measure of the unknown angle.
Answer:
equation
180=90+38+x
where x equals missing angle
x=52
Step-by-step explanation:
Hello There!
remember the sum of the interior angles of a triangle is 180
so to find the measure of the missing angle we subtract the given angles from 180
180-90-38=52
so the measure of the missing angle is 52
"find the area" = _in^2
Answer:
84 in^2
Step-by-step explanation:
Answer:
84in^2
Step-by-step explanation:
First we can calculate the rectangle which would be
6*11=66
then we can calculate the triangle
we know that the base is 6, so if we cut it in half we get two triangles which could get put back together in another rectangle so we would just need to do
6*3=18
then add them together
66+18=84
In triangle ABC below, D,E, and F are midpoints. What is the perimeter of DEF?
4in
6in
7in
34in
17in
Answer: 34
Step-by-step explanation:
D+F+E = 12+14+8=34
Answer:
17 in
Step-by-step explanation:
DE = 1/2(14) = 7
DF = 1/2(8) = 4
EF =1/2(12) = 6
7 + 4 + 6 = 17 in
Rewrite the polynomial in the form ax^2+bx+cax 2 +bx+c and then identify the values of a,a, b,b, and cc. -x+5x^2+1
Given:
The polynomial is
[tex]-x+5x^2+1[/tex]
To find:
The polynomial in the form [tex]ax^2+bx+c[/tex] and find the values of a, b and c.
Solution:
We have,
[tex]-x+5x^2+1[/tex]
Arranging the terms in descending order of their degrees, we get
[tex]=5x^2-x+1[/tex]
[tex]=(5)x^2+(-1)x+1[/tex]
On comparing this polynomial with [tex]ax^2+bx+c[/tex], we get
[tex]a=5,b=-1,c=1[/tex]
Therefore, the value of a is 5, the value of b is -1 and the value of c is 1.
plz help asap I'll mark brainliest!!!
1. Diego runs a 10 kilometer race and keeps track of his speed. What was diegos speed at the kilometer mark in the race?
Answer: 10 km/ hr
Step-by-step explanation:
In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.
Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.
Answer all the four q
Answer:
MATHMATICS - MTHMTCS
SEPTEMBER - SPTMBR
ANCILLARY - NCLLR
PTERODACTYL-PTRDCTL
Hopefully this helps <3
Pre-image ABCD was dilated to produce image A′B′C′D′ .
What is the scale factor from the pre-image to the image?
Enter your answer in the box as a fraction in simplest form.
Two quadrilaterals labeled A B C D and A-prime, B-prime, C-prime, D-prime. Quadrilateral A B C D is larger than the other quadrilateral, which is to the right of quadrilateral A B C D. Side B C is labeled twelve, and side B-prime, C-prime is labeled nine.
Answer:
0.75
Step-by-step explanation:
find the value (s) of the variables (s) in each parallelogram.
Step-by-step explanation:
As we can see it is a parallelogram so here the diagonals bisect so
6y + 1 = 4y + 9
6y - 4y = 9 - 1
2y = 8
y = 8 / 2
y = 4
2x - 5 =x + 7
2x + x = 7 + 5
3x = 12
x = 12 / 3
x = 4
Hope it will help :)
I need help ......................
Answer:
this is to hard
Step-by-step explanation:
7, 8 ,9 ,0 10
help i don't know what to do!!!!!!!!!!!
Answer:
x=⅗ or 0.6ft
y=7ft
step by step explanation
Answer:
Divide both numbers by five, apparently
I am glad i helped! Have a good day and remember to be tiger fierce!! :)
Can someone help I’m so confused
Answer: Use M A T H W A Y
Independent Assessment 1
Directions: Simplify each expressions using the laws of exponent. Write your
answer on the blank.
1. 8°
6. (y)
2.
7.
a7b3
a6b8
- 3.
8. (2xyz
4. 32.43
9. (5)2 (3)
m10
5.
10.
mio
12
"with a solution"
Answer:
1)1
2)x3
3)x8
4)576
5)36
Step-by-step explanation:
Answer:
1. 1 2. x³ 3.x∧8 4. 576 5. 6² 6. y∧12
7. a¹b∧-5 8. 8x∧9y∧6 9. 225 10. mº=1
Step-by-step explanation:
Can anyone help solve step by step?
Answer:
x=8
Step-by-step explanation:
a=8x-13
b=13x-65
a+b=90
8x-13+13x-65=90
21x=168
x=8