Answer:
1 / 6
Step-by-step explanation:
The amount of parts is 1 + 5 = 6 and Joe only receives 1 part so the fraction is 1 / 6.
Find all of the missing angle measures. Remember you cannot assume right angles or diameters. Also think about how many degrees are in a triangle. Angle 1: Angle 2: Angle 3: Angle 4: Angle 5: Angle 6: Angle 7: Angle 8: Angle 9: Angle 10: Angle 11: Angle 12: Angle 13: Angle 14: Angle 15:
Answer:
See text below or attached figure
Step-by-step explanation:
Given arcs
AC=70
CR=18
therefore AR = 88
RB=80
BE=130
therefor EA = 360-(70+18+80+130) = 360-298 = 62
angles will be denoted (1) for angle 1, etc.
We ASSUME
ARD is a straight line
PFRB is a straight line
FCE is a straight line
Using inscribed angle theorem, angles subtended by chords/arcs equal to half the arc central angle.
Therefore
(4)=80/2=40
(13)=130/2=65
(12)=62/2=31
(11)=70/2=35
(5) = (70+18)/2 = 44
Consider triangle AEG,
(7)=(13)+(11)=65+35=100 [exterior angle]
Consider triangle EGB,
(10)=180-100-31 = 49 [sum of angles of a triangle]
Consider triangle AEH,
(3) = 180-(4)-(13)-(11) = 180-40-65-35 = 40 [sum of angles of a triangle]
From cyclic quadrilateral ARBE,
ARB+AEB=180 =>
ARB=180-AEB=180-(35+49) = 96
By the intersecting secants theorem,
(2) = (130-18)/2 = 56 [secants FE, FB]
(1) = (130+62 - (18+70))/2 = 104/2 = 52 [secants PA,PB]
(8) = (130+62 -80)/2 = 112/2 = 56
ARD is straight line (see assumptions above)
(9) = 180-96 = 84 [sum of angles on a line]
ARP = (9) = 84 [vertically opposite angles]
Consider triangle ARP
(14) = 180-52-84 = 44
Consider tangent PA
(15) = 180-(44+40+65) = 31 [sum of angles of a triangle]
Consider triangle ABD
(6) = 180 - (40+44+56) = 40 [sum of angles of a triangle]
This completes the search for all sixteen angles, as shown in the diagram, or in the text above.
Hi, if it's possible to answer this now, Thank you so much. If you don't know the answer, that's ok :D
Answer:
5x4^10
Step-by-step explanation:
Hope this helps have a nice day :)
Answer:
5. [tex]4^{9}[/tex]
Step-by-step explanation:
There is a common ratio r between consecutive terms, that is
r = 20 ÷ 5 = 80 ÷ 20 = 320 ÷ 80 = 4
This indicates the sequence is geometric with n th term
[tex]a_{n}[/tex] = a . [tex]r^{n-1}[/tex]
Here a = 5 and r = 4 , thus
[tex]a_{10}[/tex] = 5. [tex]4^{9}[/tex]
The population, P (t), of an Ontario city is modeled by the function p(t) = 14t^2 + 650t + 32,000. If t = 0 corresponds to the year 2,000. When was the population 25,000?
Answer:
The population of the city was 25,000 in 1970 and 1983.
Step-by-step explanation:
In order to find the year at which the population was 25,000 we need to make p(t) equal to that number and solve for t as shown below.
[tex]25000 = 14*t^2 + 650*t + 32000\\14*t^2 + 650*t + 7000 = 0\\t^2 + 46.43*t + 500 = 0\\t_{1,2} = \frac{-46.43 \pm \sqrt{(46.43)^2 - 4*1*500}}{2}\\t_{1,2} = \frac{-46.43 \pm \sqrt{155.75}}{2}\\t_{1,2} = \frac{-46.43 \pm 12.48}{2}\\t_1 = \frac{-33.95}{2} = -16.98\\t_2 = \frac{-58.91}{2} =- 29.5[/tex]
Since t = 0 corresponds to the year 2000, then t1 = 1983 and t2 = 1970.
A bank is advertising that new customers can open a savings account with a 2% interest rate compounded annually. Kristy invests $3000 in an account at this rate. If she makes no additional deposits or withdrawals on her account, find the amount of money she will have after 5 years. A.)1020.21 B.)2274.57 C.)3312.24 D.)4158.18
(please help) List the three lowest numbers that have the following characteristics. Work must be shown. 60 is a multiple of the number 3 is a factor of the number 4 is not a factor of the number
Answer:
3, 6, and 15
Step-by-step explanation:
Notice that if 60 is a multiple, the numbers in question could have the same factors as 60.
So let's look at 60's prime factors:
60 = 2 * 2 * 3 * 5
we also know that 3 is a factor, so the factor 3 must be included in all three options, we also know that 4 is NOT a factor, so both factors 2 cannot be included (but only one of them could).
So, in order to build the lowest possible numbers that verify such conditions, we can use:
3
3 * 2 = 6
since 3 or 2 cannot be repeated, the next smaller would be:
3 * 5 = 15
Mei Su had 80 coins. She gave most of them to her friends in such a way that each of her friends got at least one coin and no two of her friends got the same number of coins. What is the largest number of friends to whom Mei Su could have given coins?
Answer: 12 friends.
Step-by-step explanation:
the data we have is:
Mei Su had 80 coins.
She gave the coins to her friends, in such a way that every friend got a different number of coins, then we have that:
The maximum number of friends that could have coins is when:
friend 1 got 1 coin
friend 2 got 2 coins
friend 3 got 3 coins
friend N got N coins
in such a way that:
(1 + 2 + 3 + ... + N) ≥ 79
I use 79 because "she gave most of the coins", not all.
We want to find the maximum possible N.
Then let's calculate:
1 + 2 + 3 + 4 + 5 = 15
15 + 6 + 7 + 8 + 9 + 10 = 55
now we are close, lets add by one number:
55 + 11 = 66
66 + 12 = 78
now, we can not add more because we will have a number larger than 80.
Then we have N = 12
This means that the maximum number of friends is 12.
Answer:
12
Step-by-step explanation:
my
The admission fee at an amusement park is $1.75 for children and $4.80 for adults. On a certain day, 303 people entered the park, and the admission fees collected totaled $881. How many children and how many adults were admitted? Number of children equals= ? Number of adults equals=?
Answer:
Children 188
Adults. 115
Step-by-step explanation:
Let the no. of children be x and adults be y
x + y = 303
x = 303 - y. .... .....(1)
1.75x + 4.80y = 881. ...........(2)
Substituting,
1.75(303-y) +4.80y = 881
530.25 -1.75y + 4.80y = 881
530.25 + 3.05y = 881
3.05y = 881 - 530.25
y = 350.75 / 3.05 = 115 = adults
Children = 303-115 = 188
What is the value of arc EDG°?
Answer:
210°
Step-by-step explanation:
By inscribed angle theorem:
[tex] m\angle DFG = \frac{1}{2} \times m\widehat{(EDG)} \\\\
105\degree = \frac{1}{2} \times m\widehat{(EDG)} \\\\
105\degree\times 2= m\widehat{(EDG)} \\\\
\huge \red {\boxed {\therefore m\widehat{(EDG)} = 210\degree}} [/tex]
please help!! Find the domain and range of the following function ƒ(x) = 5|x - 2| + 4
Domain: (-∞,∞) Range: (4,∞)
Domain: [4,8) Range: (-∞,∞)
Domain: (4,∞) Range: (-∞,∞)
Domain: (-∞,∞) Range: [4,∞)
Answer:
There are no restrictions on x, so the domain is (-∞,∞)
When x = 2, 5|x - 2| = 0, so the range is [4,∞)
Step-by-step explanation:
The domain and range of the function ƒ(x) = 5|x - 2| + 4 is (-∝, ∝) and [4, ∝) respectively. So, the 4th option is correct.
Domain and range of a function:A function's domain is the set of all values for which the function is defined, and its range is the set of all values that the function takes.
How to solve this problem?The given function is ƒ(x) = 5|x - 2| + 4.
This function is not undefined for any x-values. So, the domain of this function is (-∝,∝).
We know that
|x - 2| ≥ 0
i.e. 5|x - 2| ≥ 0
i.e. 5|x - 2| + 4 ≥ 4
i.e. f(x) ≥ 4
So, the range of this function is [4,∝).
Therefore, the domain and range of the function ƒ(x) = 5|x - 2| + 4 is (-∝, ∝) and [4, ∝) respectively. So, the 4th option is correct.
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Your friend is having trouble solving word problems. Create a word problem of your own and provide the answer along with a detailed explanation of how you solved your equation.
Step-by-step explanation:
Places A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the car travel in the same direction at different speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What are the speeds of the two cars?
Solution :
Let “x km/hr” be the speed of 1st car
Let “y km/hr” be the speed of the 2nd car
Time = Distance/Speed
Speed of both cars while they are traveling in the same direction = (x – y)
Speed of both cars while they are traveling in the opposite direction = (x + y)
5 = 100/(x -y)
x – y = 100/5
x - y = 20
x - y - 20 = 0 ---(1)
1 = 100/(x + y)
x + y = 100
x + y - 100 = 0--b----(2)
x/(100 + 20) = y/(-20 + 100) = 1/(1 + 1)
x/120 = y/80 = 1/2
x/120 = 1/2 y/80 = 1/2
x = 120/2 y = 80/2
x = 60 y = 40
So, the speed of first car = 60 km/hr
Speed of second car = 40 km/hr
2) A girl starts from a point A and walks 285m to B on a bearing of 078°. She then walks due south to a point C which is 307m from A. What is the bearing of A from C , and is the distance |BC| ?
Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) = [tex]\frac{187.84}{307} \times sin(78)[/tex]
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
If a function is defined by the equation y=5x−5, which equation defines the inverse of this function?
Answer:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
Or:
[tex]x + 5 = 5y[/tex]
Step-by-step explanation:
We have the function:
[tex]y=5x-5[/tex]
And we want to find its inverse.
To find the inverse of a function, we:
Flip x and y. And solve for y.Hence:
[tex]x=5y-5[/tex]
Solve for y. Add:
[tex]\displaystyle x + 5 = 5y[/tex]
Divide:
[tex]\displaystyle y = \frac{x+5}{5}[/tex]
Simplify. Hence:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
In conclusion, the inverse function is:
[tex]\displaystyle y = \frac{1}{5}x+1[/tex]
out of 8000 students of Chitwan district 10% take tuition in various subject before the SLC examination. Among them 40% take tuition in English only,20% in math only and 80 students in other subject. Compare the number of students who take tuition on both subject and the total number of students.
Answer:
Out of 8000 students, 10% take tuition in various subjects before the exam.
10% of 8000 is:
10/100 * 8000 = 800
Among the 800, 40% take tuition in English only and 20% take tuition in Math only.
80 students take tuition in other subjects, therefore, in percentage:
80/800 * 100 = 10%
Therefore, the percentage of students that take tuition in both Math and English is:
100% - (40% + 20% + 10%) = 100% - 70% = 30%
30% of the 800 students take tuition in both subjects. That is:
30/100 * 800 = 240 students
Therefore, among the 8000 students in the district, only 240 take tuition in both English and Math.
In percentage:
240/8000 * 100 = 3%
3% of students take tuition in both English and Math.
In Ratio:
3 : 100
3 out of 100 students take tuition in English and Math.
Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square.
Answer:
The area of the shaded region = (36·π - 72) cm²
The perimeter of the shaded region = (6·π + 12·√2) cm
Step-by-step explanation:
The given figure is a sector of a circle and a segment of the circle is shaded
We have that since the arc AC subtends an angle 90° at the center of the circle, the sector is a quarter of a circle, which gives;
Area of sector = 1/4×π×r²
As seen the radius, r = AB = 12 cm
∴ Area of sector = 1/4×π×12² = 36·π cm²
The area of the segment AB = Area of sector ABC - Area of ΔABC
Area of ΔABC = 1/2×Base ×Height =
Since the base and the height = The radius of the circle = 12 cm, we have;
Area of ΔABC = 1/2×12×12 = 72 cm²
The area of the segment AB = 36·π cm² - 72 cm² = (36·π - 72) cm²
The area of the shaded region = The area of the segment AB = (36·π - 72) cm²
The perimeter of the shaded region = 1/4 perimeter of the circle with radius r + Line Segment AC
The perimeter of the shaded region = 1/4 × π × 2 × r + √(12² + 12²) = 1/4 × π × 2 × 12 + 12·√2 = (6·π + 12·√2) cm
How many different "words" can be made from the given word by re-arranging the letters? 1. KINDNESS 2. MATHEMATICIAN
Answer:
Step-by-step explanation:
Permutation has to do with arrangement.
To form different word by rearranging the word KINDNESS, this can be done in the following way;
The total letters present in kindness = 8 letters
Repeated letters are 2N's and 2S's
The arrangement is done in [tex]\frac{8!}{2!2!}[/tex] ways
[tex]= \frac{8!}{2!2!} \\= \frac{8*7*6*5*4*3*2!}{2!*2}\\ = 8*7*3*5*4*3\\= 10,080 \ different\ words[/tex]
For MATHEMATICIAN;
The total letters present in kindness = 13 letters
Repeated letters are 2M's, 2T'S 2I'sand 3A's
The number of words formed =
[tex]\frac{13!}{2!2!2!3!} \\= \frac{13*12*11*10*9*8*7*6*5*4*3!}{6*3!}\\= 13*2*11*10*9*8*7*6*5*4\\= 172,972,800\ different\ words[/tex]
Simplify fully
e x e x e x e x f ÷ e x e x e x f x f
Answer:
e/f
Step-by-step explanation:
Common factors in the numerator and denominator cancel.
[tex]\dfrac{e\times e\times e\times e\times f}{e\times e\times e\times f\times f}=\dfrac{e}{e}\times\dfrac{e}{e}\times\dfrac{e}{e}\times\dfrac{e}{f}\times\dfrac{f}{f}=1\times1\times1\times\dfrac{e}{f}\times1=\boxed{\dfrac{e}{f}}[/tex]
The required simplification of the expression is [tex]\dfrac{e}{f}[/tex].
We have to the given expression, e x e x e x e x f ÷ e x e x e x f x f.
The given expression is simplify in the following steps given below.
Expression; [tex]\dfrac{e \times e \times e \times e \times f}{e \times e \times e \times f \times f}[/tex]
Then,
The simplification of the given expression,
[tex]=\dfrac{e \times e \times e \times e \times f}{e \times e \times e \times f \times f}\\\\[/tex]
Cancel out the same term from denominator and numerator,
[tex]= \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{e}{f} \times \dfrac{f}{f} \\\\= 1 \times 1 \times 1 \times \dfrac{e}{f} \times 1 \\\\= \dfrac{e}{f}[/tex]
Hence, The required simplification of the expression is [tex]\dfrac{e}{f}[/tex]
To know more about Multiplication click the link given below.
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Will give BRAINLIEST, someone please help! easy question, please explain your answer
Answer:
TRUE
Step-by-step explanation:
Notice that point P is at the center of the circle. Notice also that it is being crossed by two diameters (segments RT and SQ). Then, the central angles RPS and TPQ must be equal because they are opposed by their vertex (center point P). Notice as well that the two triangles formed (triangle SRP, and triangle TPQ) are both isosceles triangles since they have the two sides that are adjacent to the central angles mentioned above, equal to the circle's radius. Therefore, the sides opposite to the central angles (RS in one triangle, and QT in the other) must be equal among themselves.
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Answer:
second option
Step-by-step explanation:
Given
[tex]x^{4}[/tex] + 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± [tex]\sqrt{-1}[/tex] = ± i ( noting that [tex]\sqrt{-1}[/tex] = i ), and
x² = - 5 ( take the square root of both sides )
x = ± [tex]\sqrt{-5}[/tex] = ± [tex]\sqrt{5(-1)}[/tex] = ± [tex]\sqrt{5}[/tex] × [tex]\sqrt{-1}[/tex] = ± i[tex]\sqrt{5}[/tex]
Solutions are x = ± i and x = ± i[tex]\sqrt{5}[/tex]
Erin travels north and south from Main Station. The distance, in km, of the train from Main Station is
modeled by the function d(t) = t3 - 9t2 + 6t, where North is positive and South is negative. Time
elapsed after the start of a shift, in hours, is represented by t, where t € (0,12]. 'If the shift starts at
noon, determine at which time(s) the train is more than 16 km south of Main Station.
Answer:
The times are t = 9, t = 10, t = 11 and t = 12
Step-by-step explanation:
For the train to be more than 16 km South and since south is taken as negative,
d(t) > -16
t³ - 9t² + 6t > -16
t³ - 9t² + 6t + 16 > 0
Since -1 is a factor of 16, inserting t = -1 into the d(t), we have
d(-1) = (-1)³ - 9(-1)² + 6(-1)+ 16 = -1 - 9 - 6 + 16 = -16 + 16 = 0. By the factor theorem, t + 1 is a factor of d(t)
So, d(t)/(t + 1) = (t³ - 9t² + 6t + 16)/(t +1) = t² - 10t + 16
Factorizing t² - 10t + 16, we have
t² - 2t - 8t + 16
= t(t - 2) - 8(t - 2)
= (t -2)(t - 8)
So t - 2 and t - 8 are factors of d(t)
So (t + 1)(t -2)(t - 8) > 0
when t < -1, example t = -2 ,(t + 1)(t -2)(t - 8) = (-2 + 1)(-2 -2)(-2 - 8) = (-1)(-4)(-10) = -40 < 0
when -1 < t < 2, example t = 0 ,(t + 1)(t -2)(t - 8) = (0 + 1)(0 -2)(0 - 8) = (1)(-2)(-8) = 16 > 0
when 2 < t < 8, example t = 3 ,(t + 1)(t -2)(t - 8) = (3 + 1)(3 -2)(3 - 8) = (4)(1)(-5) = -20 < 0
when t > 8, example t = 9,(t + 1)(t -2)(t - 8) = (9 + 1)(9 -2)(9 - 8) = (10)(7)(1) = 70 > 0
Since t cannot be negative, d(t) is positive in the interval 0 < t < 2 and t > 8
Since t ∈ (0, 12]
In the interval 0 < t < 2 the only value possible for t is t = 1
d(1) = t³ - 9t² + 6t = (1)³ - 9(1)² + 6(1) = 1 - 9 + 6 = -2
Since d(1) < -16 this is invalid
In the interval t > 8 , the only possible values of t are t = 9, t = 10.t = 11 and t = 12.
So,
d(9) = 9³ - 9(9)² + 6(9) = 0 + 54 = 54 km
d(10) = 10³ - 9(10)² + 6(10) = 1000 - 900 + 60 = 100 +60 = 160 km
d(11) = 11³ - 9(11)² + 6(11) = 1331 - 1089 + 66 = 242 + 66 = 308 km
d(12) = 12³ - 9(12)² + 6(12) = 1728 - 1296 + 72 = 432 + 72 = 504 km
can you help me to find the values of abc and cde ?
Answer:
88° and 132°
Step-by-step explanation:
The sum of angles in a pentagon ( a 5-sided shape) is given as
= (5 - 2) 180°
= 540°
The angles ∠EAB and ∠AED are supplementary hence the sum is 180° Therefore,
∠AED + 110 = 180
∠AED = 180 - 110
= 70°
Given that the sum of the angles in a pentagon is 540° then
110 + 70 + 2k + 140 + 3k = 540
5k + 320 = 540
5k = 540 - 320
5k = 220
k = 220/5
= 44°
Hence the angle ∠ABC
= 2 × 44
= 88°
∠CDE
= 3 × 44
= 132°
Which linear inequality is represented by the graph? y ≤ 2x + 4 y ≤ one-halfx + 3 y ≥ One-halfx + 3 y ≥ 2x + 3
Answer:
Option B.
Step-by-step explanation:
From the given graph it is clear that the related line passes through the points (0,3) and (2,4).
So, the equation of related line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-3=\dfrac{4-3}{2-0}(x-0)[/tex]
[tex]y-3=\dfrac{1}{2}x[/tex]
Add 3 on both sides, we get
[tex]y=\dfrac{1}{2}x+3[/tex]
The related line is a solid line and shaded portion lies below the line. So, the sign of inequality must be ≤.
[tex]y\leq \dfrac{1}{2}x+3[/tex]
Therefore, the correct option is B.
Answer:
y ≤ one-halfx + 3
Step-by-step explanation:
Expand the following bracket -5(3c+6)
Answer:
-15c - 30
Step-by-step explanation:
-5(3c+6)
Expand or distribute the term outside the bracket to the terms inside.
-5(3c) - 5(6)
-15c - 30
Answer:
The answer is -15c - 30
Step-by-step explanation:
You have to apply Distributive Law :
[tex]a(m + n) = am + an[/tex]
So for this question :
[tex] - 5(3c + 6)[/tex]
[tex] = - 5(3c) - 5(6)[/tex]
[tex] = - 15c - 30[/tex]
Given that r = (7,3,9) and v=(3,7,-9), evaluate r + v. A. (-21,-21,81) B. (10,10,0) C. (21,21,-81) D. (-10,-10,0)
Answer:
B. (10, 10, 0)
Step-by-step explanation:
Each component of the sum is the sum of corresponding components:
r + v = (7, 3, 9) +(3, 7, -9) = (7+3, 3+7, 9-9) = (10, 10, 0)
Henrik grew 3 times as many potatoes as Derek grew. Derek managed to grow 49 potatoes. Henrik already had 173 potatoes harvested from his other field. How many potatoes does Henrik have in all?
Answer:
Step-by-step explanation:
Analysis
Answer:
49 x 3 = 147
147 + 173 = 320
Step-by-step explanation:
Step 1 Henrik grew 3 times as many potatoes as Derek grew. Derek managed to grow 49 potatoes.
49 x 3 = 147
Step 2 Henrik already had 173 potatoes harvested from his other field.
173 + 147
three solid shapes A,B and C are similar the surface of shape A is 9cm² the surface of shape B is 16cm² the ratio of the volume of shape B to the volume to shape C is 27:125 work out the ratio of the height of shape A to the height of shape C. give your answer in its simplest form
PLEASE ANSWER ASAP
Answer:
A:C = 9:20
Step-by-step explanation:
The computation of the ratio is shown below:
We can say that
Surface area ratio = Ratio square
i.e
[tex](\frac{A}{B})^2 = \frac{9}{16}[/tex]
Now squaring both sides
[tex]\frac{A}{B} = \sqrt{\frac{9}{16} } \\\\ \frac{A}{B} =\frac{3}{4}[/tex]
The ratio is 3: 4
Now in the other case
Volume ratio = Cube ratio
i.e
[tex](\frac{B}{C})^3 = \frac{27}{125}[/tex]
Now cubing root both sides
So,
[tex]\frac{B}{C} = \frac{3}{5}[/tex]
Therefore
B : C = 3:5
Now for making the equivalent ratios
A:B:C = 9:12:20
So,
A:C = 9:20
Solve (x - 4)2 = 5.
O A. x-5+
O B. * = 41.5
O C. X = 9 and x = -1
O D. X=-4115
Answer:
x=4_+√5option B is the correct option.
Solution,
[tex] {(x - 4)}^{2} = 5 \\ [/tex]
x-4=_+√5
X=4_+√5
Hope this helps...
Good luck on your assignment...
Answer:
(x-4)^2 =5
x^2-16=5
x^2=5+16
x^2=21
√x^2=√21
x=√21
Step-by-step explanation :
First of all open the bracket which has square
Secondly change the position of 16
Note: when a number changes its place , the symbol also changes
then when you get the value take the square root on both sides
and you'll get the answer
Which ordered pair is a solution to the system of inequalites graphed here?
Answer:
B. (2, 2)
Step-by-step explanation:
In order for the coordinate to be a solution of the systems of inequalities, it has to be in the shaded region (not on the line since both are dotted). Only B fits in the shaded region.
Which table of values represents the exponential function f(x)=(15)x?
Answer:
Step-by-step explanation:
Unfortunately, f(x)=(15)x is not an exponential function. I will assume that you meant
f(x) = 5^x
The second table fits this function. Note that if x = -2, f(-2) = 5^(-2) = 1/25.
PLEASE HELP!!:(((
A sphere has a circumference of its great curled equal to 20 Pi what is the volume of that sphere
If you could please answer this I would highly appreciate it!!!
Answer:
Third one
Step-by-step explanation:
The circumference of a circle is given by the formula:
P = d*π d is the diameterP= 20π ⇒ d*π = 20π ⇒ d= 20
The volume of a sphere is given by the formula:
V = [tex]\frac{4}{3}[/tex]*π*r³ r is the radius wich is d/2r = 20/2 = 10V= [tex]\frac{4}{3}[/tex]*π*10³
V= 1333.33*π
A chord is 80 inches long. It is 96 inches from the center of the circle. What is the radius of the circle?
Answer:
104 inches
Step-by-step explanation:
To solve this, we use a circle theorem. The circle theorem to use is that a line from the center of a circle is perpendicular to a chord and it divides the chord into exactly two equal parts.
So therefore, we shall be having a right angled triangle if we join the edge of the chord to the center of the circle.
So in this circle, we have the distance from the center of the circle to the chord, the radius of the circle and half the length of the chord.
The length of the radius serves as the hypotenuse.
Let’s call the radius r.
The other two sides measure; 40 and 96 respectively.
Mathematically, using Pythagoras’ theorem which states that the square of the hypotenuse equals the sum of the squares of the two other sides;
r^2 = 40^2 + 96^2
r^2 = 10,816
r = √(10,816)
r = 104 inches