It takes to break an carbon-chlorine single bond. Calculate the maximum wavelength of light for which an carbon-chlorine single bond could be broken by absorbing a single photon. Round your answer to significant digits.

Answers

Answer 1

Answer:

It takes approximately [tex]5.43\times 10^{-19}\; \rm J[/tex] of energy to break one [tex]\rm C-Cl[/tex] single bond.

The maximum wavelength of a photon that can break one such bond is approximately [tex]3.66\times 10^{-7}\; \rm m[/tex] (in vacuum.) That's the same as [tex]3.66 \times 10^{2}\; \rm nm[/tex] (rounded to three significant figures.)

Explanation:

Energy per bond

The standard bond enthalpy of [tex]\rm C-Cl[/tex] single bonds is approximately [tex]\rm 327\; \rm kJ \cdot mol^{-1}[/tex] (note that the exact value can varies across sources.) In other words, it would take approximately [tex]327\; \rm kJ[/tex] of energy to break one mole of these bonds.

The Avogadro Constant [tex]N_A \approx 6.023\times 10^{23}\; \rm mol^{-1}[/tex] gives the number of [tex]\rm C-Cl[/tex] bonds in one mole of these bonds. Based on these information, calculate the energy of one such bond:

[tex]\begin{aligned}& E(\text{one $\mathrm{C-Cl}$ bond}) \\ &= \frac{E(\text{one mole of $\mathrm{C-Cl}$ bonds})}{N_A} = \frac{327\; \rm kJ\cdot mol^{-1}}{6.023\times 10^{23}\; \rm mol^{-1}} \\ &\approx 5.429\times 10^{-22}\; \rm kJ = 5.429\times 10^{-19}\; \rm J \end{aligned}[/tex].

Therefore, it would take approximately [tex]5.43\times 10^{-19}\; \rm J[/tex] of energy to break one [tex]\rm C-Cl[/tex] single bond.

Minimum frequency and maximum wavelength

The Einstein-Planck Relation relates the frequency [tex]f[/tex] of a photon to its energy [tex]E[/tex]:

[tex]E = h \cdot f[/tex].

The [tex]h[/tex] here represents the Planck Constant:

[tex]h \approx 6.63 \times 10^{-34}\; \rm J \cdot s[/tex].

A photon that can break one [tex]\rm C-Cl[/tex] single bond should have more than [tex]5.43\times 10^{-19}\; \rm J[/tex] of energy. Apply the Einstein-Planck Relation to find the frequency of a photon with exactly that much energy:

[tex]\begin{aligned}f &= \frac{E}{h}\\ &\approx \frac{5.43\times 10^{-19}\; \rm J}{6.63 \times 10^{-34}\; \rm J\cdot s} \\ &\approx 8.19 \times 10^{14}\; \rm s^{-1} = 8.19 \times 10^{14}\; \rm Hz\end{aligned}[/tex].

What would be the wavelength [tex]\lambda[/tex] of a photon with a frequency of approximately [tex]8.19 \times 10^{14}\; \rm Hz[/tex]? The exact answer to that depends on the medium that this photon is travelling through. To be precise, the exact answer depends on the speed of light in that medium:

[tex]\displaystyle \lambda = \frac{(\text{speed of light})}{f}[/tex].

In vacuum, the speed of light is [tex]c \approx 2.998\times 10^{8}\; \rm m \cdot s^{-1}[/tex]. Therefore, the wavelength of that [tex]8.19 \times 10^{14}\; \rm Hz[/tex] photon in vacuum would be:

[tex]\begin{aligned} \lambda &= \frac{c}{f} \\ & \approx \frac{2.998\times 10^{8}\; \rm m \cdot s^{-1}}{8.19\times 10^{14}\; \rm s^{-1}} \\ &\approx 3.66 \times 10^{-7}\; \rm m = 3.66 \times 10^{2}\; \rm nm\end{aligned}[/tex].

(Side note: that wavelength corresponds to a photon in the ultraviolet region of the electromagnetic spectrum.)


Related Questions

Each of these geometric shapes has a different number of sides. Arrange the shapes in order from the shape with the greatest number of sides to the shape with the fewest number of sides.
1. triangle
2. square
3. rectangle
4. octagon
5. hexagon
6. pentagon

Answers

1. Octagon 8 sides
2. Hexagon 6 sides
3. Pentagon 5 side
4. Rectangle 4 side
5. Square 4 sides
6. Triangle 3 side
I don’t know if that’s what u meant

What are the three types of combustion reactions

Answers

Answer:

Slow combustion

Spontaneous combustion

Explosive combustion

Explanation:

-Slow combustion reactions: Occurs at low temperatures. Cellular respiration is an example.

-Spontaneous combustion reactions: Occurs suddenly without an outside heat source. The heat source is the result of oxidation.

-Explosive combustion reactions: Involves an oxidizing agent.

hopefully this helped :3

Answer:

Three types are: Rapid Combustion, Complete Combustion, and Spontaneous Combustion.

Explanation:

Note: there are more types! This is just three random ones I picked to list. Hope this helps! :)

In a study of the decomposition of the compound XX via the reaction

X(g)⇌Y(g)+Z(g)X(g)⇌Y(g)+Z(g)

the following concentration-time data were collected:

Time (min)(min) [X](M)[X](M)
0 0.467
1 0.267
2 0.187
3 0.144
4 0.117
5 0.099
6 0.085
7 0.075

Given that the rate constant for the decomposition of hypothetical compound XX is is 1.60 M^−1⋅min^−1. Calculate the concentration of XX after 18.0 minmin .

Answers

Answer:

( About ) 0.03232 M

Explanation:

Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [[tex]X_o[/tex]]"

This formula would be true for the following information -

{ [tex]X_o[/tex] = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }

________

Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6

1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X

1 / [X] = 28.8 + 1 / ( 0.467 ),

1 / [X] = 28.8 + 2.1413...,

1 / [X] = 31,

[X] = 1 / 31 = ( About ) 0.03232 M

Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M

The concentration after 18 minutes is 1.45 × 10^-13 M.

We have the equation of the reaction as; X(g)⇌Y(g)+Z(g)X(g)⇌Y(g)+Z(g) and we are informed in the question that the reaction follows the first order kinetics.

From the first order kinetics; ln[A] = ln[A]o - kt

Where;

[A] = concentration at time t

[A]o = initial concentration

k = rate constant

t = time taken

Hence;

ln[A] = ln[0.467] - (1.60 M^−1⋅min^−1 × 18 min)

A = 1.45 × 10^-13 M

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Norepinephrine, increases blood pressure and nerve transmission
Give your answer as number of carbon from aromatic group.

Answers

Answer:

6

Explanation:

Norepinephrine has one benzene cycle , so it has 6 carbon atoms in aromatic group.

A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular weight of the oil 100 g/mol, what was the partial pressure of the oil during distillation assuming atmospheric pressure is 760 mm Hg

Answers

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

An aqueous solution____

Answers

Answer:

A solution in which the solvent is water.

Explanation:

Something is dissolved in water.

For the reaction: PCl5(g) ⇌ PCl3(g) + Cl2(g) at 600.0 K, the equilibrium constant is 11.5. Suppose that 1.500 g of PCl5 (MW=208.22 g/mol) is placed in an evacuated 500.0 mL bulb, which is then heated to 600.0 K. What is the total pressure (in atm) in the bulb at equilibrium?

Answers

Answer:

1.418688 atm

Explanation:

(a)  Moles of PCl5 = mass / molar mass

                      =1.5 g / 208.22 g/mol

                     = 0.0072 moles

Also given,

T = 600 K

V = 0.500 L

Pressure of PCl5, P = nRT / V

                             = 0.0072 mol×0.0821 L-atm / (mol.K)×600 K / 0.500 L

                             = 0.709344 atm

(b)  PCl5(g) ⇄ PCl3(g) + Cl2(g)

Initial               0.965         0               0

Change               -x            +x             +x

Equilibrium (0.709344 -x)         x               x

K_p = 11.5 = x×x / (0.965 -x)

solving, we get x = 0.67027

So partial pressure of PCl5 at equilibrium = 0.709344 - 0.67027 = 0.039074 atm

(c)   Partial pressure of PCl3 = Cl2 = 0.709344 atm

So total pressure = 0.709344+0.039074+ 0.67027= 1.418688 atm

Question 14 of 25
2 Points
Which of the following is a cost of mining aluminum from new bauxite
deposits?
A. It helps preserve plants and animals in rain forests.
O O O
B. It requires a large amount of energy.
C. It takes less energy to transport this lightweight metal
D. It can be recycled over and over again.

Answers

Answer:

it can be recycled over and over again

Answer:

It requires a large amount of energy

Explanation:

Describe the formation of an aqueous libr solution when solid libr dissolves in water
Fill in the blanks with words given below.
K and I atoms
K and IF ions
dissociation
atoms
KI molecules
polar dilution
hydration
molecules ions
nonpolar
At the_______ surface of the solid _____________are pulled into solution by___________ the water molecules, where the______________ process surrounds separate with water molecules.

Answers

Answer and Explanation:

The water is a polar solvent which dissolves into the LiBr molecules and converts into [tex]Li^+[/tex] and [tex]Br^-[/tex] ions far from the solid also into the solution, when they are hydrated.

Now, the complete words are as given below:-

The [tex]K^+[/tex] and [tex]I^-[/tex] ions at the surface of the solid are pulled into the solution by the polar water molecules, where the hydration process surrounds separate ions with water molecules.

LiBr has been the ionic compound and has been dissociated in the water by the force of the polar water molecules. The water molecules that have been polar in nature exert the force onto the ionic compounds and help in the dissociation.

At the dissociation surface of the solid KI molecules, are pulled into the solution by the polar water molecules, where the hydration process surrounds ions and separates them with water molecules.

For more information about the hydration process, refer to the link:

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1. Corrosion in metals is an example of what?​

Answers

it’s an example of electrochemical corrosion i believe

Answer:

In the most common use of the word, this means electrochemical oxidation of metal in reaction with an oxidant such as oxygen or sulfates. Rusting, the formation of iron oxides, is a well-known example of electrochemical corrosion.

Rubidium has two naturally occurring isotopes. The average atomic mass of Rb is 85.4678 amu. If 72.15% of Rb is found as Rb-85 (84.9117 amu), what is the mass of the other isotope?

Answers

Answer:

x = 86.908 amu

Explanation:

Average mass of isotope =  85.4678 amu

Rb-85 = 84.9117 amu, Percentage = 72.15% = 0.7215

Other isotope = x, Percentage = 100 - 72.15 = 27.85% = 0.2785

Average mass = (Percentage * Mass of Rb-85)  + (Percentage * Mass of Rb-87)

85.4678 = (0.7215 * 84.9117) + (0.2785 * x)

85.4678 = 61.2638 + 0.2785x

0.2785x = 24.204

x = 24.204 / 0.2785

x = 86.908 amu

86.908 amu

It is given that:

Average atomic mass of Rb = 85.4678 amu.

Also the mass of Rb-85 = 84.9117 amu and its Percentage = 72.15% = 0.7215

Let the mass of other isotope (Rb-87) = x

So, Percentage of other isotope (Rb-87) = 100 - 72.15 = 27.85% = 0.2785

Average mass = (Percentage * Mass of Rb-85)  + (Percentage * Mass of Rb-87)

85.4678 = (0.7215 * 84.9117) + (0.2785 * x)

85.4678 = 61.2638 + 0.2785x

0.2785 x = 24.204

x = 24.204 / 0.2785

x = 86.908 amu

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What information does the geologic time scale provide?

Answers

The geologic time scale is an important tool used to portray the history of the Earth—a standard timeline used to describe the age of rocks and fossils, and the events that formed them. It spans Earth's entire history and is separated into four principle divisions.

Answer:

The answer is D or information about when plants first appeared.

Explanation:

A cylindrical rod of length 1 m and radius 1 cm is submerged in water. The rod has a non-uniform mass distribution such that one half of the rod is much more massive than the other half. At which point in the rod can the buoyant force be considered to be acting?

A) at the rod's geometrical center

B) two of the given choices are correct

C) none of these

D) at the rod's center of mass

E) at the rod's center of gravity

Answers

Answer:

A) at the rod's geometrical center

Explanation:

Let us assume that the rod is replaced by water. And now this water volume is in translational and in rotational equilibrium.

Therefore, a net upward force must have been exerted by the surrounding liquid which acts at the center of mass of the water volume.

This force determines through the geometric center of the column of the cylindrical water  

Moreover, the force is also independent of submerged body into it

Hence, the first option is correct

For the reaction below, initially the partial pressure of all 3 gases is 1.0atm. . 2NH3(g)--> N2(g) + 3H2(g) K, 0.83 1. When the reaction reach equilibrium the partial pressure of N2 will be greater than 1atm The reaction would shift toward the reactants The reaction would shift toward the products 2. When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm 3. When the reaction reach equilibrium the partial pressure of H2 will be greater than 1atm

Answers

Answer:

The reaction would shift toward the reactants

When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm

Explanation:

For the reaction:

2NH₃(g) ⇄ N₂(g) + 3H₂(g)

Where K is defined as:

[tex]K = \frac{P_{N_{2}}*P_{H_2}^3}{P_{NH_3}^2} = 0.83[/tex]

As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:

[tex]Q = \frac{1atm*{1atm}^3}{1atm^2} = 1[/tex]

As Q > K, the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.

Thus, there are true:

The reaction would shift toward the reactantsWhen the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm

Given that a theoretical yield for isolating Calcium Carbonate in this experiment would be 100%. From that information and based on the results you obtained in this experiment, describe your success in the recovery of calcium carbonate and suggest two possible sources of error that would have caused you to not obtain 100% yield.

Answers

Answer:

It's well Explained below.

Explanation:

First of Excess product of CaCO_3 would be produced due to the fact that there would not be enough CaCl_2 to react with Na_2•CO_3. The main purpose of having stoichiometric quantities is for us to know the correct amount or near the correct amount of each reactant in order to create a product that will be close to the theoretical amount and thus have a higher percent yield.

If the ligand has a negative charge at a particular location, what would happen if you tried to put electrons from the metal near the electrons from the ligand?

Answers

Answer:

The two would end up repelling each other very strongly and more energy would ultimately be required to keep the metal-ligand system in place

Explanation:

A complex is made up a central metal atom or ion and ligands. Ligands are lewis bases and they possess lone pairs of electrons. A complex is formed when electrons are donated from ligand species to metals.

However, if the ligand has a negative charge at a particular location and we try to put electrons from the metal near the electrons from the ligand, the two would end up repelling each other very strongly and more energy would ultimately be required to keep the metal-ligand system in place.

If you tried to put electrons from the metal near the electrons from the ligand is :

- They will repel each other.

Electrons

If you tried to put electrons from the metal near the electrons from the ligand is

The two would end up repelling each other exceptionally strongly and more vitality would eventually be required to keep the metal-ligand framework in place

A complex is made up a central metal particle or particle and ligands. Ligands are lewis bases and they have solitary sets of electrons.

A complex is shaped when electrons are given from ligand species to metals.

Learn more about "Electrons":

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A 1.766-g sample of impure sodium oxalate (Na2C2O4) is dissolved in water and titrated to methylred end point with 0.250 M HCl. The reaction is: Na2C2O4(s) + 2HCl(aq) o H2C2O4(aq) + 2NaCl(aq) If 44.15 mL of the acid is used for this reaction, what is the percent by mass of sodium oxalate in the sample?

Answers

Answer:

41.9(w/w) %

Explanation:

Based on the reaction:

Na₂C₂O₄(s) + 2HCl(aq) → H₂C₂O₄(aq) + 2NaCl(aq)

Where 1 mole of sodium oxalate reacts with 2 moles of HCl

Moles of HCl solution to reach end point are:

44.15mL = 0.04415L ₓ (0.250mol / L) = 0.01104 moles of HCl

As 2 moles of HCl reacts per mole of Na₂C₂O₄:

0.01104mol HCl ₓ (1 mol Na₂C₂O₄ / 2 mol HCl) = 5.519x10⁻³ moles Na₂C₂O₄ are in the sample.

Molar mass of Na₂C₂O₄ is 134g/mol; thus, mass of 5.519x10⁻³ moles Na₂C₂O₄ is:

5.519x10⁻³ moles Na₂C₂O₄ ₓ (134g / mol) = 0.740g of Na₂C₂O₄ in the sample.

Thus, percent by mass of sodium oxalate in the sample is:

0.740g of Na₂C₂O₄ / 1.766g ₓ 100 =

41.9(w/w) %

Classify each of the following word equations as a synthesis, decomposition, single displacement, or double displacement reaction.


Will give brainliest.

Answers

Answer:

12: This is decomposition because nitrogen triiodide is breaking apart.

13: This is double displacement because the elements in the compounds are "switching".

14: This is synthesis because the water and carbon dioxide are combining.

15: This is also synthesis because the hydrogen and oxygen are combining.

16: This is single displacement because the sodium is "switching" the element it's bonding with.

How many formula units make up 36.0 g of magnesium chloride (MgCl2)?
Express the number of formula units numerically.

Answers

Answer: There are [tex]2.29\times 10^{23}[/tex] formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles[/tex]

1 mole of [tex]MgCl_2[/tex] contains = [tex]6.023\times 10^{23}[/tex] formula units

Thus 0.38 moles of [tex]MgCl_2[/tex] contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23}[/tex] formula units

Thus there are [tex]2.29\times 10^{23}[/tex] formula units

Electrons in atoms exist in particular energy level. A ___ must be emitted or absorbed to move between energy levels.

Answers

Answer:

Photon of light

Explanation:

According to Bohr's model of the atom, electrons in atoms are found in specific energy levels. These energy levels are called stationary states, an electrons does not radiate energy when it occupies any of these stationary states.

However, an electron may absorb energy and move from one energy level or stationary state to another. The energy difference between the two energy levels must correspond to the energy of the photon of light absorbed in order to make the transition possible.

Since electrons are generally unstable in excited states, the electron quickly jumps back to ground states and emits the excess energy absorbed. The frequency or wavelength of the emitted photon can now be measured and used to characterize the transition. This is the principle behind many spectrometric and spectrophotometric methods.

Consider the following four solutions: a. NaCl in water b. Acetic acid in water c. Acetic acid in benzene d. Naphthalene in benzene Which of these solutions has the strongest solute-solvent interactions and the interaction is of which type?1. Acetic acid in water; hydrogen bonding2. Acetic acid in benzene; dipole-induced dipole interaction3. NaCl in water; ion-dipole interaction4. Naphthalene in benzene; London Dispersion Forces5. NaCl in water; hydrogen bonding

Answers

Answer:

NaCl in water; ion-dipole interaction

Explanation:

Sodium chloride is an ionic solid. Ionic solids dissolve in water due to ion dipole interaction. Ionic solids are composed of an ion pair which are strongly bound by electrostatic interaction between the oppositely charged ions in the solid state.

When an ionic substance is dissolved in water, the positive ion interacts with the negative end of the dipole in water while the negative ion interacts with the positive end of the dipole in water. Hence the ions are pulled apart by this ion-dipole interaction and the crystal structure of the solid collapses as the ionic solid dissolves in water.

Sodium chloride is an ionic solid. Interaction between the sodium ion and the negative end of the dipole in water as well as chloride ion and the positive end of the dipole in water leads to the dissolution of sodium chloride solid in water. This is the strongest solute-solvent interaction in the list.

When The strongest solute-solvent interactions and the interaction the correct option is A NaCl in water; ion-dipole interaction

What is Sodium chloride?

Sodium chloride is an ionic solid. Ionic solids liquefy in water due to ion-dipole interaction. Ionic solids are formed of an ion team that is strongly bound by electrostatic interaction between the differently delegated ions in the solid-state.

When an ionic substance is disbanded in water, the positive ion interacts with the negative end of the dipole in the water while the opposing ion interacts with the positive end of the dipole in water. Therefore the ions are dragged apart by this ion-dipole interaction and also when the crystal configuration of the solid collapses as the ionic solid dissolves in water.

Sodium chloride is an ionic solid. The interchange between the sodium ion and the negative future of the dipole in water as well as the chloride ion and the positive end of the dipole in water leads to the abolishment of sodium chloride solid in water. This is the strongest solute-solvent exchange on the list.

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A 25.0-mL sample of 0.150 M hydrochloric acid is titrated with a 0.150 M NaOH solution. The pH at the equivalence point is _____________.

Answers

Answer:

7 (neutral).

Explanation:

Hello,

In this case, for the chemical reaction:

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]

We can notice that since hydrochloric acid and sodium hydroxide are strong, they will fully dissociate during the titration, therefore, as they are in stoichiometric proportions in equal concentrations for the equivalence point, the pH will be 7 (neutral) since all the chloride ions are neutralized by the sodium ions.

Moreover, for the given acid solution, the required volume of sodium hydroxide will be:

[tex]V_{NaOH}=\frac{25.0mL*0.150M}{0.150M}=25.0mL[/tex]

To attain a complete titration until the equivalence point.

Best regards.

A chemical bond is a strong attraction between two or more atoms. Can you identify the properties of different types of chemical bonds?1. A(n) ___________ bond forms when one atom gives up one or more electrons to another atom.2. Atoms or molecules with a net electric charge due to the loss or gain of one or more electrons are ____________.3. A(n) __________bond involves the sharing of electron pairs between atoms, also known as amolecular bond.4. When one pair of electrons is shared between two atoms, a ___________bond is formed.5. When two pairs of electrons are shared between two atoms, a _____________bond is formed.6. A _____________bond is a type of chemical bond where a pair of electrons is unequally shared betweentwo atoms. As a result, one end of the molecule has a slightly negative charge and the other a slightlypositive charge.7. Atoms involved in a ___________bond equally share electrons; there is no charge separation to the molecule.8. A weak bond called a____________bond results from an attraction between a slightly positive regionin a molecule and a slightly negative region in the same or a different molecule.a. Hydrogen b. Double c. Polar d. Covalent e.Ions f. Single g. Nonpolar

Answers

Answer:

1. Ionic bond.

2.Ions

3. Covalent

4.Single bond

5. Double bond

6. Polar bond

7.Non polar bond

8. Hydrogen bond

Answer:

1. Ionic bond.

2.Ions

3. Covalent

4.Single bond

5. Double bond

6. Polar bond

7.Non polar bond

8. Hydrogen bond

Explanation:

2 physical changes that happen in aquaponics

and endothermic reactions that happen in aquaponics

3 chemical changes that happend in aquaponics

A conclusion about matter and energy and explain how both can change ecosystems and earth surface with time.

Answers

Answer:

The physical and chemical change that occurs in the aquaponics are given below.

Explanation:

The plants and animals grow in size and decrease the mass of plant due to eating by the fishes is a physical changes which occurs in aquaponics. The sunlight has a heat energy which is absorb by the plants present in aquaponics which is a type of endothermic reaction. In aquaponics, the ammonia present in water is converted into nitrates which is used by the plants as a nutrients. When the mass is converted into energy, it increases the temperature of the ecosystem and also the earth surface. For example, if a wood is burn, it change into heat energy which increases the temperature and cause the global warming on the earth surface.

9. Hydrogen peroxide decomposes to form water and oxygen gas according to the following equation:
2H2O2(aq) to 2H2O(l) + O2(g)
If 315 g of hydrogen peroxide, H2O2, decomposes and all the O2 gas is collected in a balloon at 0.792 atm and 23 degrees C, what is the volume of the O2 gas collected?

Answers

Answer:

[tex]V=142L[/tex]

Explanation:

Hello,

In this case, for the given reaction:

[tex]2H_2O_2(aq) \rightarrow 2H_2O(l) + O_2(g)[/tex]

Starting with 315 g of hydrogen peroxide, we can compute the yielded moles of oxygen by using the following stoichiometric factor whereas the hydrogen peroxide to oxygen mole ratio is 2:1:

[tex]n_{O_2}=315gH_2O_2*\frac{1molH_2O_2}{34gH_2O_2}*\frac{1molO_2}{2molH_2O_2} \\\\n_{O_2}=4.63molO_2[/tex]

Then, by using the ideal gas equation we can compute the resulting volume if the 4.63 moles of oxygen are collected at 0.792 atm and 23 °C as shown below:

[tex]PV=nRT\\\\V=\frac{nRT}{P}=\frac{4.63mol*0.082\frac{atm*L}{mol*K}*(23+273.15)K}{0.792 atm}\\ \\V=142L[/tex]

Best regards.

When 0.7521 g of benzoic acid was burned in a calorimeter containing 1000 g of water, a temperature increase of 3.60 ℃ was observed. What is the heat capacity of the bomb calorimeter, excluding water? The heat of combustion of benzoic acid is -26.42 kJ/g.

Answers

Answer:

The correct answer is 1335.4 J/ °C.

Explanation:

Based on the given information, the amount of benzoic acid burned is 0.7521 grams, the amount of water present within a calorimeter is 1000 grams and there is an elevation in temperature of 3.60 °C. The heat of combustion of benzoic acid given is -26.42 kJ per mole.  

Now the amount of heat discharged in a reaction is:  

= 0.7521 grams × -26.42 kJ / gram = -19.872 kJ or -19870 J

qreaction = - (qwater + qcal)

-19870 J = - (mwatersΔT + CcalΔT

= - [(1000 grams × 4.184 J/g degree C × 3.60 degree C) + (Ccal 3.60 °C)] (The specific heat of water is 4.184 J/gram °C)

(1000 gram × 4.184 J/g °C × 3.60 °C) + (Ccal 3.60 °C) = 19870 J

15062 J + Ccal 3.60 °C = 19870 J

Ccal 3.60 °C = 4807.6 J

Ccal = 4807.6 J / 3.60 °C = 1335.4 J/°C or 1.3 kJ/°C.  

You are provided with a compound fertilizer, 40-15-10.Calculate the quantity of fertilizer to add to a one hectare field supply (a) Nitrogen at 120kg/ha (b) Nitrogen at 90kg/ha (c) Phosphorus at a rate of 60kg/ha (d) Potassium at a rate of 60kg/ha

Answers

Answer:

a. 300 kg of Fertilizer

b. 225 kg of fertilizer

c.400 Kg of fertilizer

d.600 Kg of fertilizer

Explanation:

The percentage composition ratio of Nitrogen, Phosphorus and Potassium bag of the given fertilizer is 40:15:10.

The percentages can be expressed as fractions as follows:

For nitrogen; 40/100 = 0.4

For phosphorus; 15/100 = 0.15

For potassium; 10/100 = 0.1

To find the quantity of fertilizer required to add to a hectare to supply the given amount of nutrients, the amount to be provided is divided by the percentage or fractional compostion of each nutrient.

Quantity of fertilizer required to add to a hectare to supply;

a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer

b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer

c. Phosphorus at  60 kg/ha = 60/0.15 = 400 Kg of fertilizer

d. Potassium at 60 kg/ha = 60/0.1 = 600 Kg of fertilizer

Use your trendline equation to determine the gas pressure at 200 K and 400 K. (notice the temperature units) How many times greater is the pressure at 400 K in comparison to 200 K? Is this what you’d expect? Why?

Answers

Answer:

The pressure will be twice the initial pressure

Explanation:

Gay-Lussac's law states that the pressure of a gas is directely proportional to absolute temperature under constant volume. That is because vibrations of a gas increase when temperature increases, increasing the pressure of the gas.

That means if the temperature of a gas is doubled, the pressure will be twice the initial pressure.

Which element's neutral atoms will have the electron configuration
1s22s22p3s23p'?
a. boron
b. carbon
c. silicon
d. aluminum

Answers

Answer:

Alumunium

Explanation:

Alumunium = [Ne] 3s² 3p¹

Ne = [He]2s²2p⁶

He = 1s

Alumunium = 1s 2s²2p⁶3s² 3p¹

Answer:

D

Explanation:

How many oxygen molecules are needed to make 10 carbon dioxide molecules according to the following balanced chemical equation? 2 CO + O2 → 2 CO2

Answers

answer.

five oxygen molecules

step by step explanation.

according to the equation,one molecule of oxygen is enough to react with two carbon molecules thus 10 carbon molecules need 5oxygen molecules

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