Answer:
a) 50 rad/s
b) 39.8 rev
Explanation:
Given:
r = 0.36 m
v₀ = 0 m/s
a = 1.8 m/s
t = 10 s
a) Find: ω
v = at + v₀
v = (1.8 m/s) (10 s) + (0 m/s)
v = 18 m/s
ω = (18 m/s) / (0.36 m)
ω = 50 rad/s
b) Find: Δθ
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1.8 m/s) (10 s)²
Δx = 90 m
Δθ = (90 m) / (2π × 0.36 m)
Δθ = 39.8 rev
Newton’s third law of motion says that for every action there is a(n) and opposite reaction.
Answer:
Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
Explanation:
this is what i know but i am sorry if this doesn't help
Answer:
"equal"
Explanation:
ed 2021
hellllp me please anyone help Light travels from a region of air into a region of air, making an angle of incidence of 60 degrees. Which of the following best describes the path of the light as it moves into the air? A) The light will bend toward the normal B) The light will bend away from the normal C)The light will continue without bending D)The light will move in some manner not determined by the information here.
Answer:
(B)
Explanation:
Because what ever angle the surface is, the light will reflect of of it perpendicular.
Which of the following is an example of newton second law of motion?
Answer: Its answer C: A wheelbarrow is more difficult to move as More objects are placed inside.
Explanation: The greater the mass of the object the more force is needed to make it move.
Hope this helps!! :)
At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a force of 2000 N.(i) Using a scale of 1 cm = 500 N, make a scale drawing to show the resultant force on the truck. (ii) Use your diagram to find the magnitude and direction of the resultant force on the truck.
Answer:
1.) Magnitude = 5596 N
2.) Direction = 60 degrees
Explanation: You are given that the breakdown vehicle A is exerting a force of 4000 N at angle 45 degree to the vertical and breakdown vehicle B is exerting a force of 2000 N
Let us resolve the two forces into X and Y component
Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N
Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )
= 2000 + 2828.43
= 4828.43 N
The resultant force R will be
R = sqrt ( X^2 + Y^2 )
Substitutes the forces at X component and Y component into the formula
R = sqrt ( 2828.43^2 + 4828.43^2 )
R = sqrt ( 31313752.53 )
R = 5595.87 N
The direction will be
Tan Ø = Y/X
Substitute Y and X into the formula
Tan Ø = 4828.43 / 2828.43
Tan Ø = 1.707106
Ø = tan^-1( 1.707106 )
Ø = 59.64 degree
Therefore, approximately, the magnitude and direction of the resultant force on the truck are 5596 N and 60 degree respectively.
A 1500kg car accelerates from 50km/h to 75km/h. How much work was done?
Answer:
Work done, W = 181238.4 J
Explanation:
We have,
Mass of a car, m = 1500 kg
Initial speed, u = 50 km/h = 13.88 m/s
Final speed, v = 75 km/h = 20.84 m/s
Let W is the work done. It is equal to the change in kinetic energy of the car. So,
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\W=\dfrac{1}{2}\times 1500\times ((20.84)^2-(13.88)^2)\\\\W=181238.4\ J[/tex]
So, 181238.4 J of work was done by the car.
. A sample of 4 g of cobalt isotope is produced. If the half-life of is 30 years, what will be the mass of the cobalt remaining after 90 years?
Answer:
Half Life = 90/30 = 3 Half lives
Half Life = 30 years
So,
4 g Cobalt after 30 years = 4/2
=> 2 g
2 g Cobalt after next 30 years = 2/2
=> 1 g
1 g Cobalt after next 30 years = 1/2
=> 0.5 g
So, After 90 years, 0.5g of cobalt isotope will be left.
What is torque in physics ?
Answer:
Torque is a measure of the force that can cause an object to rotate about an axis.
Answer:
Torque is a measure of how a force acting on an object causes that object to rotate.
Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant velocity. Discuss the forces acting on the object
Answer:
At the point of dropping the object, by Newton's first law due to gravitational force [tex]F_g[/tex] = m × g, accelerates
By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)
As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out
The body then moves at a constant uniform motion down according to Newton's first law
Explanation:
At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g
As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force
Therefore, the force of the air drag becomes equal to the gravitational force, cancelling each other out and the object then moves according to Newton;s first law, in uniform motion of a constant speed while still falling down.
A body oscillates with 25hz what is its time period
Answer:
4 seconds
Explanation:
The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).
The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).
A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.
The period (T) is given as:
[tex]Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds[/tex]
if the input force on a wheel and axle is 2 N and the output force is 20N what is its mechanical advantage
Mechanical Advantage is always (Output Force) / (Input Force) .
MA = (20 N) / (2 N)
MA = 10
A broom with a long handle balances at its centre of gravity as shown in the figure. If you cut the broom into two parts through the centre of gravity and then weigh each part, which part will weigh more? a) The part with the broom will weigh more. b) The part without the broom will weigh more c) Both the parts will weigh the same d) It would depend on the weight of the broom
Answer:
c) Both the parts will weigh the same
Explanation:
center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts
(might be D if it is cutting against the center of gravity)
4
A fisherman notices that wave
crests pass the front of his boat
every 6.00 s. He measures the
distance between two crests to be
15.0 m. How fast are the waves
travelling?
(Unit = m/s)
Answer:
Speed of wave = 2.5 m/s
Explanation:
Given:
Time taken by wave = 6 second
Height (Distance) of wave = 15 meter
Find:
Speed of wave
Computation:
⇒ Speed = Distance / Time taken
⇒ Speed of wave = Height (Distance) of wave / Time taken by wave
⇒ Speed of wave = 15 / 6
Speed of wave = 2.5 m/s
A ball moving at a velocity of 10 meters/second has a momentum of 8.0 kilogram meters/second. What is its mass?
Answer:
0.8 kilogram
Explanation:
Mass:This can be defined as the quantity of matter a body contained. The S.I unit of mass if kg.
From the question,
M = mv................. Equation 1
Where M = momentum, m = mass. V = velocity
make m the subject of the equation
m = M/v.............. Equation 2
Given: M = 8.0 kilogram meters/second, v = 10 meters/second
Substitute these values into equation 2
m = 8.0/10
m = 0.8 kilogram
N 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040. About how old will she appear to be?
Answer:
she'll be 42.3 years old
Explanation:
The year she left is 2020
she returns in 2040
the time observed to have passed by on earth is 40 years
she traveled at a speed of 2.5 x 10^8 m/s
From relativity, the astronaut will experience a time dilation and will age more slowly.
the time that is observed to pass on her ship will be gotten from
t' = [tex]t\sqrt{1 - \frac{v^{2} }{c^{2} } } }[/tex]
where t is the time that is observed to pass by an earthly observer
v is the speed of her ship
c is the speed of light = 3 x 10^8 m/s
v/c = 2.5/3 = 0.83
t' = [tex]40{\sqrt{1 - 0.83^{2} } }[/tex] = 40 x 0.5578 = 22.3 years would have passed for her
This means that she'll be 20 + 22.3 = 42.3 years old
Modifiable strength improvement factors include all of the following except...??
Answer:
Muscle size and training specifiicty
Explanation:
It depends on all other factors such as anatomy and psychology, muscle fiber recruitment, motor pattern development and muscle memory but to increase modifiable strength, size plays no big role.
pls help, me, i nees to submit now
Answer:
12m
Explanation:
To obtain the answer to the question given, we must observe the characteristics of image formed by a plane mirror.
The image formed by a plane mirror have the following characteristics:
1. Laterally inverted.
2. Same distance as the object from the mirror.
3. Same height as the object.
4. Virtual.
With the above information, we can calculate the distance between the boy and his image as follow:
Initially:
Object distance (u) = 4m
Image distance (v) = 4m
The boy moved 2m away, therefore:
Object distance (u) = 2 + 4 = 6m
Image distanc(v) = 2 + 4 = 6m
The distance between the boy and his image will be the sum of his distance (u) and image distance (v) i.e (u + v)
The distance between the boy and his image = 6 + 6 = 12m
Therefore, the distance between the boy and his image is 12m.
Explain the concept of "charge" and how it relates to electricity?
Answer:
An Electric "charge" is a property of matter that causes a force to repel or attract when placed into a magnetic field. These charges can be replicated into positive and negative electrons when made from a chemical reaction.
Answer:
an electri
Explanation:
Select the correct the answer.
What do the circled arrows in the image indicate?
A. CO2 absorbed by the atmosphere
B. CO2 released to the atmosphere
C. oxygen absorbed by the atmosphere
D. oxygen released by the atmosphere
Answer:
it shows that co2 is absorbed by the atmosphere.
when the animals respire they produce co2 which is release in atmosphere and in presence of sunlight and chlorophyll the plants manufacturs the food and releases the oxygen in the atmosphere .
hope it helps..
Answer:
Its A
Explanation:
The cartoon of the roadrunner and the coyote usually has rockets going at around 8 kilometers per minute. How much is this in miles per hour? (1m = .00062 miles)If we have a terrain with a square house in the middle, the walls of the square house are 50.0 yards long and has 10 yards high ceilings. What is the volume of the interior of the house in cubic meters and cubic centimeters? (1 yard = 3 feet, 1 meter = 3.28 foot)The acceleration of an object is given by 314,000 Hectometers per hour squared. Convert the units to Meter per second square and miles per second square.
Answer:
1 feet
Explanation:
1 feet = 1 feet so its one feet
With an initial velocity of 9.8 m / sg, an object is thrown upwards from the roof of a 100 m high building. Determine maximum height from the ground, time it takes to reach the ground, and the speed with which it reaches the ground.
Answer:
104.9 m
5.63 s
45.3 m/s
Explanation:
Given:
y₀ = 100 m
v₀ = 9.8 m/s
a = -9.8 m/s²
Find: y when v = 0 m/s
v² = v₀² + 2a (y − y₀)
(0 m/s)² = (9.8 m/s)² + 2 (-9.8 m/s²) (y − 100 m)
y = 104.9 m
Find: t when y = 0 m
y = y₀ + v₀ t + ½ at²
0 m = 100 m + (9.8 m/s) t + ½ (-9.8 m/s²) t²
0 = 100 + 9.8t − 4.9t²
t = [ -9.8 ± √(9.8² − 4(-4.9)(100)) ] / 2(-4.9)
t = (-9.8 ± 45.3) / -9.8
t = 5.63 s
Find: v when y = 0 m
v² = v₀² + 2a (y − y₀)
v² = (9.8 m/s)² + 2 (-9.8 m/s²) (0 m − 100 m)
v = -45.3 m/s
|v| = 45.3 m/s
9. [03.03]
When comparing two circuits, you note that circuit one has twice the voltage and half the resistance of circuit two.
Answer:
Circuit one will have more current than circuit two
Explanation:
I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -
V = IR,
where V = voltage / potential difference, I = current, and R = resistance
If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -
2V = I( 1 / 2R ),
4V = IR,
I = 4V / R
Whereas in the second circuit -
V = IR,
I = V / R
As you can note, voltage is directly proportional to the current ( I ) as well as the resistance. The only difference between the two formulas I = 4V / R, and I = V / R is the difference in the voltage. With the voltage being 4 times greater in the first circuit, and current is 4 times greater in the first circuit as well.
Hence, circuit one will have more current than circuit two
That's a very interesting observation. When you notice that, does it stimulate any questions in your mind due to your natural curiosity ?
For example, do you walk away wondering, perhaps, how the current in the two circuits might compare ? If so, you've come to the right place. Read on:
Take the form of Ohm's Law for current . . . I = V / R . . . and apply it to both circuits:
For the second circuit: I₂ = V / R
For the first circuit:
I₁ = (2V) / (R/2)
Multiply numerator and denominator by 2 :
I₁ = (4V) / R
I₁ = 4 (V / R)
I₁ = 4 I₂
Compare the atmospheric pressure of two places 500m and 2 km respectively above sea-level. Give reason for your answer.
Answer:
Explanation:
The average pressure at mean sea-level (MSL) in the International Standard Atmosphere (ISA) is 1013.25 hPa, or 1 atmosphere (atm), or 29.92 inches of mercury. Pressure (p), mass (m), and the acceleration due to gravity (g), are related by P = F/A = (m*g)/A, where A is surface area.
2. Find the time taken by the bus to reach the stop. need only group B, 2 answer
Answer:
t = 2 seconds
Explanation:
In 2nd question, the question is given the attached figure.
Initial speed of the bus, u = 0
Acceleration of the bus, a = 8 m/s²
Final speed, v = 16 m/s
We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :
[tex]a=\dfrac{v-u}{t}[/tex]
t is time taken
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{16-0}{8}\\\\t=2\ s[/tex]
The bus will take 2 seconds to reach the stop.
A 17-tooth spur pinion has a diametral pitch of 8 teeth/in, runs at 1016 rev/min, and drives a gear at a speed of 508 rev/min. Find the number of teeth on the gear and the theoretical center-to-center distance.
What is the measure, in degrees, of the acute angle formed by the minute hand and the hour hand on a standard clock when it indicates $9$:$40$
Answer:
9.666666º
Explanation:
In this exercise we must transform from hexadecimal units and decimal units.
For this we must take into account that in the sexagesimal system the base is 60 and in the decimal system the base is 10. This means that by taking 60 minutes we have a degree
transform
9º 40 ’a Aº
we use a direct proportion rule, where 60 minutes is equivalent to 10 decinal minutes
40 ’[hexadecimals] = 40‘ (10/60) = 6,666 ’[decimals]
let's take these pleasant decimal minutes
6.666 ’= 6.6666 (1/10) = 0.66666º
we already have all the units in degrees, we can add them
9º + 0.666666º = 9.666666º
Find the electric field a distance z above a circular ring carrying a constant line charge. For extra credit you may derive the electric field a distance z above a disk carrying a constant surface charge density. 3 Find the force between an electron and a proton in a typical hvdrogen atom.
Answer:
F = 8.23 × 10⁻⁸N
Explanation:
F= kq²/r²
k= 9×10⁹Nm²/C²
q= 1.6×10⁻¹⁹C
r= 5.29×10⁻¹¹m
F= 9×10⁹× (1.6×10⁻¹⁹)²/ (5.29×10⁻¹¹)²
F = 8.23 × 10⁻⁸N
I NEED HELP PLEASE, THANKS! :)
The electric field around a positive charge is shown in the diagram. Describe the nature of these lines.
Answer:
They move outwards.
They don't intersect each other at any point.
They show the electric field.
Explanation:
Answer:
Please read the answer below
Explanation:
the nature of these lines refers to the fact that positive charges generate field lines that are directed out of the positive charges, and in turn are directed towards some negative charge present somewhere in the universe.
By consensus, the electric field lines leave the positive charges and enter the negative charges. That is the reason why in a scheme like the shown in the image, is considered implicitly the existence of a negative charge, in some place of the universe.
Using the letters for the seven colours and starting with R (Red), what is the correct order for the colours in a rainbow? Your answer should be in the form RXXXXXX Which of these seven colours has the shortest wavelength?
Answer:
Red
Orange
Yellow
Green
Blue
Indigo
Violet
shortest wavelength: violet (380 nanometers)
¯\(°_o)/¯
Answer:
Red Orange Yellow Green Blue Indigo Violet
violet has the shortest wavelength
happy to help :)
A particle starts at velocity of 3 m/s and accelerates uniformly at 1.5m/s². How far does it go in 1s, 5s and the 4th second
Answer:
Please go through the 2nd photo for the last part of the question that is " how far does it go in the 4th second "
Answer:
[tex]x=\frac{1}{2}at^{2}+v_{0}t\\\\1s: x=0.75(1)^{2}+3(1)=3.75m\\5s: x=0.75(5)^{2}+3(5)=33.75m\\4th=3s>>4s: x_{4} =(0.75(4)^{2}+3(4))-(0.75(3)^{2}+3(3))=8.25m[/tex]
I've written all the needed equations for you. All you have to do is some replacements.
Please do not hesitate to ask further questions.
This equation is missing which motion variable?
Answer:
Option A. a
Explanation:
Motion variables include:
1. Final velocity (vf).
2. Initial velocity (vi).
3. Time (t).
4. Acceleration (a)
5. Distance (x)
Considering the equation given in the question:
Δx = ½(vf + vi) t
We can see that the acceleration (a) is missing in the equation.