It cost $16.80 for a half dozen cookies. How much does one cookie cost?

Answer:A

Step-by-step explanation:line segment

Answer:

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

The total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We have:

The radius of the soup can r = 4 cm

The height of the soup can h = 10.5 cm

We know the surface area of the cylinder:

[tex]\rm S = 2\pi r(r+h)[/tex]

[tex]\rm S = 2\pi \times 4(4+10.5)[/tex]

S = 364.42 square cm

Thus, the total metal needed to make the can is 364.42 square centimeters if the soup can will have a radius of 4 cm and a height of 10.5 cm.

Learn more about the cylinder here:

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Answer:

indeed it does

Step-by-step explanation:

wheres the diagram exactly?

Answer:

Step-by-step explanation:

A=3.14 x 22m x 22m

A=69.08m x 22m

A=1519.76m2 (squared po yan)

Answer:

Multiply the radius, r, by 2. Keep the angle measure x.

Step-by-step explanation:

The area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is that Mancuso wants to draw a sector whose area is 2 times the area of the sector shown.

The area of the sector given is -

A = {x/180} x πr²

For the area to be double, we can write the area of the sector as -

A{new} = 2 × {x/180} × πr²

A{new} = {x/90} × πr²

Therefore, the area of the sector whose area is double as that of given sector is : A{new} = {x/90} × πr².

To solve more questions on sectors, visit the link-

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Answer:

95.2

Step-by-step explanation:

because u multiply 8.5 by 11.2 and get 95.2

Answer:

A triangle is dilated by scale factor of 1/5

Step-by-step explanation:

A triangle has three sides. All the corresponding angles of triangle must be congruent. When the triangle is dilated it is rotated 90 degrees clockwise about its origin. The shape of the triangle will not change due to rotation of dilation.

Answer:

17

Step-by-step explanation:

Range is the biggest number minus the smallest number. So 20-3=17

Answer:

option E

Step-by-step explanation:

have a great day

Answer:

SD = 2x

UD = x[tex]\sqrt{3}[/tex]

Step-by-step explanation:

The hypotenuse of a 30-60-90 triangle is 2 times the length of the shorter leg.

SU is the shorter leg = x

So, SD = 2x

The longer leg of a 30-60-90 triangle is [tex]\sqrt{3}[/tex] times the shorter leg.

So, UD = x[tex]\sqrt{3}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

In  a 30-60-90 triangle the sides are in the ratio 1:√3:2 so if the shortest side SU = x then the long leg = √3x and the hypotenuse = 2x.

Answer:its C because the base is the bottom of the figure and C goes to the middle point at the bottom of the figure

Step-by-step explanation:

Answer:

[tex]G = (-1.5,1.5)[/tex]

Step-by-step explanation:

Given

[tex]M = (-7,5)[/tex]

[tex]A = (6,5)[/tex]

[tex]T = (4,-2)[/tex]

[tex]H = (-9,-2)[/tex]

Required

Determine the coordinate of G

From the complete question, G is at the intersection of MT and AH.

So, G is calculated using midpoint formula

[tex]G = \frac{1}{2}(x_1 + x_2, y_1 + y_2)[/tex]

For MT:

[tex]M = (-7,5)[/tex]      [tex]T = (4,-2)[/tex]

[tex]G = \frac{1}{2}(-7 + 4, 5 -2)[/tex]

[tex]G = \frac{1}{2}(-3, 3)[/tex]

Open bracket

[tex]G = (-1.5,1.5)[/tex]

To show that [tex]G = (-1.5,1.5)[/tex]

We have:

[tex]A = (6,5)[/tex]       [tex]H = (-9,-2)[/tex]

[tex]G = \frac{1}{2}(x_1 + x_2, y_1 + y_2)[/tex]

[tex]G =\frac{1}{2}(6-9,5-2)[/tex]

[tex]G = \frac{1}{2}(-3, 3)[/tex]

Open bracket

[tex]G = (-1.5,1.5)[/tex]

Hence, the coordinates of G is:

[tex]G = (-1.5,1.5)[/tex]

Answer: Use the app photo math, you just take a picture and it gives you the answer and shows you the steps:)

1) x> 5

2) x< 2

3) x<-6

4) x< 2

5) x> 2

6) x> - 7/2

Step-by-step explanation:

See the images below for the work:)  The images will be in order with the number the first problem will be the answer to the first.

Answer:

[tex]\sf 1)\:4x - 2 > 2x + 8[/tex]

Add 2 from both sides:

[tex]\sf 4x-2+2>2x+8+2[/tex]

[tex]\sf 4x>2x+10[/tex]

Subtract 2x from both sides:

[tex]\sf 4x-2x>2x+10-2x[/tex]

[tex]\sf 2x>10[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{10}{2}[/tex]

[tex]\boxed{\sf x>5}[/tex]

_______________________________

[tex]\sf 2)\: -3x - 6 > 4x - 20[/tex]

Add 6 from both sides:

[tex]\sf -3x-6+6>4x-20+6[/tex]

[tex]\sf -3x>4x-14[/tex]

Subtract 4x from both sides:

[tex]\sf -3x-4x>4x-14-4x[/tex]

[tex]\sf -7x>-14[/tex]

Multiply both sides by -1:

[tex]\sf\left(-7x\right)\left(-1\right)<\left(-14\right)\left(-1\right)[/tex]

[tex]\sf 7x<14[/tex]

Divide both sides by 7:

[tex]\sf \cfrac{7x}{7}<\cfrac{14}{7}[/tex]

[tex]\boxed{\sf x<2}[/tex]

_______________________________

[tex]\sf 3)\: 4(x + 1) < 3x - 2[/tex]

Apply distributive property:

[tex]\sf 4x+4<3x-2[/tex]

Subtract 4 from both sides:

[tex]\sf 4x+4-4<3x-2-4[/tex]

[tex]\sf 4x<3x-6[/tex]

Subtract 3x from both sides:

[tex]\sf 4x-3x<3x-6-3x[/tex]

[tex]\boxed{\sf x<-6}[/tex]

_______________________________

[tex]\sf 4)\: 2x + 3 + x < -2x + 1 + 12[/tex]

Combine like terms:

[tex]\sf (2x+x)= 3x[/tex]

[tex]\sf( 1+12)=13[/tex]

[tex]\sf 3x+3<-2x+13[/tex]

Subtract 3 from both sides:

[tex]\sf 3x+3-3<-2x+13-3[/tex]

[tex]\sf 3x<-2x+10[/tex]

Add 2x from both sides:

[tex]\sf 3x+2x<-2x+10+2x[/tex]

[tex]\sf 5x<10[/tex]

Divide both sides by 5:

[tex]\sf \cfrac{5x}{5}<\cfrac{10}{5}[/tex]

[tex]\boxed{\sf x<2}[/tex]

________________________________

[tex]\sf 5)\: 2(x - 1) > 4x + 4 - 5x[/tex]

Combine like terms:

[tex]\sf (4x-5x)=-x[/tex]

[tex]\sf 2\left(x-1\right)>-x+4[/tex]

Apply distributive property:

[tex]\sf 2x-2>-x+4[/tex]

Add 2 from both sides:

[tex]\sf 2x-2+2>-x+4+2[/tex]

[tex]\sf 2x>-x+6[/tex]

Add x from both sides:

[tex]\sf 2x+x>-x+6+x[/tex]

[tex]\sf 3x>6[/tex]

Divide both sides by 3:

[tex]\sf \cfrac{3x}{3}>\cfrac{6}{3}[/tex]

[tex]\boxed{\sf x>2}[/tex]

_______________________________

[tex]\sf 6)\: 2 + 4x -7 < 8x + 2 - 2x[/tex]

Subtract 2 from both sides:

[tex]\sf 2+4x-7-2<8x+2-2x-2[/tex]

[tex]\sf 4x-7<8x-2x[/tex]

Combine like terms:

[tex]\sf (8x-2x)=6x[/tex]

[tex]\sf 4x-7<6x[/tex]

Add 7 from both sides:

[tex]\sf 4x-7+7<6x+7[/tex]

[tex]\sf 4x<6x+7[/tex]

Subtract 6x from both sides:

[tex]\sf 4x-6x<6x+7-6x[/tex]

[tex]\sf -2x<7[/tex]

Multiply both sides by -1:

[tex]\sf \left(-2x\right)\left(-1\right)>7\left(-1\right)[/tex]

[tex]\sf 2x>-7[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{-7}{2}[/tex]

[tex]\boxed{\sf x>-\frac{7}{2}}[/tex]

_______________________________________

Answer:

+ 7 and - 2

Step-by-step explanation:

Given

x² + 5x - 14

Consider the factors of the constant term (- 14) which sum to give the coefficient of the x- term (+ 5)

The factors are + 7 and - 2 , since

7 × - 2 = - 14 and 7 - 2 = + 5 , then

x² + 5x - 14 = (x + 7)(x - 2) ← in factored form

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

Answer:

6561

Step-by-step explanation:

3^2= 3*3=9   9^4= 9*9*9*9= 6561

Answer:

[tex]((3)^2)^4 = (9)^4 = 6561\\\\\\OR\\\\\\(3)^2)^4= 3^8 = 6561[/tex]

Answer:

-1

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The graph of this square root function extends upward and to the right of the point (-5, -1). The domain is the horizontal extent of the graph, so is ...

  x ≥ -5

The range is the vertical extent of the graph, so is ...

  y ≥ -1

9514 1404 393

Answer:

  C.  17.25

Step-by-step explanation:

The product of distances from the common point to the two circle intersection points is the same for each secant.

  5(5+12) = 4(4+a)

  69 = 4a . . . . . . . . subtract 16, simplify

  17.25 = a . . . . . . . divide by 4

Answer:

24

Step-by-step explanation:

if you add all of them together u get 108 divide it by 44 and u get 24

Answer:

70

Step-by-step explanation:

∠J and ∠K are supplementary angles

Supplementary angles have a sum of 180°

Thus, ∠J + ∠K = 180

110 + ∠K = 180

subtract 110 from each side

180 - 110 = 70

110 - 110 cancels out

we're left with ∠K = 70°

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

Step 1: Simplify both sides of the equation.

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

[tex](\frac{7}{2}x+\frac{1}{2}x)=\frac{9}{2}x+\frac{1}{2}[/tex]  (Combine Like Terms)

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

Step 2: Subtract [tex]\frac{9}{2}x[/tex] from both sides.

[tex]4x-\frac{9}{2}x=\frac{9}{2}x+\frac{1}{2}-\frac{9}{2}x[/tex]

[tex]\frac{-1}{2}x=\frac{1}{2}[/tex]

Step 3: Multiply both sides by [tex](\frac{2}{-1})[/tex].

[tex](\frac{2}{-1})*(\frac{-1}{2}x)=(\frac{2}{-1})*(\frac{1}{2})[/tex]

[tex]x=-1[/tex]

Therefore, [tex]x=-1[/tex] will be your final answer.

Sorry this took very long. I had to calculate all of this.