1.5 x 10 to the power of 11

Answer:

40 feet

Step-by-step explanation:

Answer:

1,695.6 in. 3

Step-by-step explanation:

Answer:

A=-7

Step-by-step explanation:

7=35+A4

4A=-28

A=-7

Answer:

A. make a point on the line to the right 2 units from 0

B. the opposite of 2 isn't located at the same place as point P on the number line because the opposite of 2 is -2 and the point P is the opposite of negative 2 which would be positive 2. So the two points are not in the same place because they have different signs.

Step-by-step explanation:

hope this helps

I know the wording is a bit complicated lol <3

Answer:

x = 15

Step-by-step explanation:

15 * 15 = 225

Answer:

X = 15

Step-by-step explanation:

This is because if you square 15, you get 225.

Answer:

The height of prism A is 4, the height of prism B is 5, the height of prism C is 4, and the height or prism D is 2. Since 4=4, prisms A and C have the same height.

Hope this helped! If it did, please give me brainliest! It would help a lot! Thanks! :D

Answer:

65

Step-by-step explanation:

( (23 * 13) / 2 ) - ( (13 * 13) / 2 ) = ( 299 / 2 ) - ( 169 / 2 ) = 149.5 - 84.5 = 65

Numbers are slightly unclear but I think this is right.

Answer:d

Step-by-step explanation:fkjfkjfkjfkjfkjf

Answer:

La pastelería de Luisa regaló 216 galletas a la casa hogar.

Step-by-step explanation:

De acuerdo con el enunciado, la pastelería de Luisa regalan 18 galletas a una casa hogar por cada 60 galletas horneadas en una semana. El total de galletas regaladas por hornear 720 galletas se determina por la siguiente Regla de Tres Simple:

[tex]x = \frac{18}{60}\times 720[/tex]

[tex]x = 216[/tex]

La pastelería de Luisa regaló 216 galletas a la casa hogar.

Answer:

101.9 degrees

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Let's define what we have:

Conner's morning temperature: 101.2 degrees

Conner's last night temperature: morning temperature + 0.7 degrees

We know that Conner's last night temperature is addition because it was higher (key word) than the morning temperature.

Therefore, we simply add the values together to get our answer:

101.2 + 0.7 = 101.9 degrees

Answer:

700

Step-by-step explanation:

Answer:

[tex]g(x)=3x^2[/tex]

The medians are about the same.

Option C is the correct answer.

It is the middle value of the given set of numbers after arranging the given set of numbers in order.

We have,

Movie theater 1.

From the box plot given,

The median is 995.

Movie theater 2.

From the box plot given,

The median is 995.

Thus,

The median in both the box plot is the same.

Learn more about the median here:

https://brainly.com/question/28060453

#SPJ2

Answer:

D) 20º

Step-by-step explanation:

if one angle is 70º, and the other is 90º, that means that the first two angles equal 160º. since all three interior angles of a triangle have to add up to 180º, the third angle must be 20º.

Answer:

3. D 4. B

Step-by-step explanation:

3.  e^2 = g^2 + f^2, answer is d

4. Let a = 3, b = 4, c = 5

2c = 10

2b = 8

2a = 6

10^2 = 8^2 + 6^2

answer is b

3. The Pythagorean theorem states the hypotenuse squared is equal to each side squared added to each other.

The answer is D. E^2 = f^2 + g^2

4.

To keep the proportion you could multiply the sides by the same numbers . The answer would be 2A, 2b, 2c

Answer:

$60.75×m

Step-by-step explanation:

'5'5"5"5""55

Answer:

The equation that will represent the number of grams present after n hours is [tex]A(n) = 150(0.85)^n[/tex]

3.035 grams will be left one day from now.

Step-by-step explanation:

Exponential equation for the amount of a substance:

The exponential equation for the amount of a substance is given by:

[tex]A(t) = A(0)(1-r)^t[/tex]

In which A(0) is the initial amount and r is the decay rate, as a decimal, and t is the time period.

A radioactive isotope is decaying at a rate of 15% every hour.

This means that [tex]r = 0.15[/tex]

Currently there are 150 grams of the substance.

This means that [tex]A(0) = 150[/tex]

Write an equation that will represent the number of grams present after n hours.

[tex]A(n) = A(0)(1-r)^n[/tex]

[tex]A(n) = 150(1-0.15)^n[/tex]

[tex]A(n) = 150(0.85)^n[/tex]

How much will be left one day from now?

One day is 24 hours, so this is A(24).

[tex]A(24) = 150(0.85)^{24} = 3.035[/tex]

3.035 grams will be left one day from now.

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

[tex]P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444[/tex]

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

[tex]P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333[/tex]

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172[/tex]

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Answer:

Ben is 4 meters below the surface area.

Answer:

I believe the correct answer is C

Answer: p/7 + 8

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

Hello good afternoon

Step-by-step explanation:

you have to put this link

Answer:

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

Step-by-step explanation:

Let [tex]A[/tex] denote a Boolean variable.

The negation of [tex]A[/tex] ([tex]\lnot A[/tex]) is false if when [tex]\!A[/tex] is true, and true when [tex]A\![/tex] is false. In a truth table:

[tex]\begin{array}{c||c} A & \lnot A \\ \cline{1-2} \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c||c} A & \lnot A \\ \hline \rm T & \rm F \\ \rm F & \rm T\end{array}[/tex].

Let [tex]B[/tex] denote another Boolean variable. The material implication "[tex]A[/tex] implies [tex]\!B[/tex]" ([tex]A \to B[/tex]) is true unless [tex]B\![/tex] is false when [tex]A\![/tex] is true.  

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex]

The logical or "[tex]A[/tex] or [tex]B[/tex]" is true when either [tex]A\![/tex] or [tex]B\![/tex] is true (and also when both are true.)

[tex]\begin{array}{c|c||c} A & B & A \lor B \\ \cline{1-3} \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm T \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F\end{array}[/tex]

[tex]\begin{array}{c|c||c} A & B & A \to B \\ \hline \rm T & \rm T & \rm T \\ \rm T & \rm F & \rm F \\ \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm T\end{array}[/tex].

Start by finding the value of [tex]\lnot X[/tex], [tex](X \to Y)[/tex], and [tex](Z \to \lnot X)[/tex] for each of the [tex]2^3 = 8[/tex] possible combinations of [tex]X[/tex], [tex]Y[/tex], and [tex]Z[/tex].

[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \cline{1-6} \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \cline{1-6} \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].

[tex]\begin{array}{c|c|c||c||c|c}X & Y & Z & \lnot X & (X \to Y) & (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm F & \rm T & \rm F\\ \rm T & \rm T & \rm F & \rm F & \rm T & \rm T \\ \rm T & \rm F & \rm T & \rm F & \rm F & \rm F \\ \rm T & \rm F & \rm F & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm T & \rm T & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T & \rm T & \rm T \end{array}[/tex].

The value of [tex](X \to Y) \lor (Z \to \lnot X)[/tex] is true whenever either [tex](X \to Y)[/tex] or [tex](Z \to \lnot X)[/tex] is true (or both.) The combination [tex]X = \rm T[/tex], [tex]Y = \rm F[/tex], and [tex]Z = \rm T[/tex] is the only one among the eight where neither [tex](X \to Y)\![/tex] nor [tex](Z \to \lnot X)\![/tex] is true. [tex](X \to Y) \lor (Z \to \lnot X)\![/tex] would evaluate to true for all other combinations.

Hence, the truth table would be:

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \cline{1-4} \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \cline{1-4} \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

[tex]\begin{array}{c|c|c||c}X & Y & Z & (X \to Y) \lor (Z \to \lnot X) \\ \hline \rm T & \rm T & \rm T & \rm T\\ \rm T & \rm T & \rm F & \rm T \\ \rm T & \rm F & \rm T & \rm F \\ \rm T & \rm F & \rm F & \rm T \\ \hline \rm F & \rm T & \rm T & \rm T \\ \rm F & \rm T & \rm F & \rm T \\ \rm F & \rm F & \rm T & \rm T \\ \rm F & \rm F & \rm F & \rm T\end{array}[/tex].

Answer:

Compound interest is that which, once generated, is added to the capital, in order to expand the calculation base on which, in turn, new interests will be generated. Thus, in short, if the interest is, for example, 5 percent, said interest will be added to the initial capital, with which that 5% generated will be increasing, since it will be calculated on an increasingly large basis.

Compound interest is very important for financial investments, as it maximizes the results of said investments, even more so when compared to simple interest, in which the interest generated is not added to the initial capital.

Answer:

Answer:

D

Step-by-step explanation: