is this correct yes or no?

Is This Correct Yes Or No?

Answers

Answer 1

Answer:

I believe so. If I get this wrong I'm sorry.

Explanation:


Related Questions

What mass of sucrose is needed to make 300.0 mL of a 0.5 M solution? (molar mass=
342.34 g/mol)

Answers

i need points i’m sorry but yea lol good luck

3.05 moles of H2O is equivalent to (blank amount) molecules of water.

Show your work.

Answers

Answer:

[tex]1 \: mole \: = 6.02 \times {10}^{23} \: molecules \\ 3.05 \: moles \: = (3.05 \times 6.02 \times {10}^{23} ) \: molecules \\ = 1.8361 \times {10}^{24} \: molecules[/tex]

0=4
Balance this equation
H₂sicl2+ H₂O → H8Si4O4 + HCl

Answers

Balanced Equation is

4H2SiCl2+4H2O → H8Si4O4 + 8HCl

What is the function of a
catalyst?
A. Build enzymes
B. Speed up chemical reactions
C. Regulate the function of an enzyme

Answers

I believe it is to speed up chemical reactions

i also think it is speed up chemical reactions

Combustion of a 1.031-g sample of a compound containing only carbon, hydrogen,
and oxygen produced 2.265 g of CO2(g) and 1.236 g of H2O(g). What is the
empirical formula of the compound?
3 국
Molar masses in g/mol: CO2 = 44.01; H20 = 18.02; C = 12.01; H = 1.01
C3H50​

Answers

Answer:

C₃H₈O

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1.031 g

Mass of CO₂ = 2.265 g

Mass of H₂O = 1.236 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen in the compound. This can be obtained as follow:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C =?

Mass of C = molar mass of C / molar mass of CO₂ × mass of CO₂

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H =?

Mass of H = Molar mass of H₂ / Molar mass of H₂O × Mass of H₂O

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O =?

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 1.031 – 0.757

Mass of O = 0.274 g

Finally, we shall determine the empirical formula. This can be obtained as follow:

C = 0.618 g

H = 0.139 g

O = 0.274 g

Divide by their molar mass

C = 0.618 / 12.01 = 0.051

H = 0.139 / 1.01 = 0.138

O = 0.274 / 16 = 0.017

Divide by the smallest

C = 0.051 / 0.017 = 3

H = 0.138 / 0.017 = 8

O = 0.017 / 0.017 = 1

Therefore, the empirical formula of the compound is C₃H₈O

Based on the data provided, the empirical formula of the compound is C₃H₈O

What is empirical formula?

The empirical formula of compound is its simplest formula showing the mole ratio of the elements in the compound.

First, the mass of carbon, hydrogen and oxygen in the compound is determined first as follows:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 0.274 g

To determine the empirical formula of a compound, the mole ratio of the elements are determined as follows:

Mole ratio = reacting mass/molar mass

Mole ratio of the elements:

Carbon                Hydrogen         Oxygen

0.618 g/12.01    0.139 / 1.01         0.274 / 16

0.051                   0.138              0.017

Divide by the smallest ratio to convert to whole numbers

0.051 / 0.017     0.138 / 0.017  0.017 / 0.017

3           :            8           :               1

Therefore, the empirical formula of the compound is C₃H₈O

Learn more about empirical formula at: https://brainly.com/question/24297883

Thermal energy naturally flows from _________ matter to _______ matter.

Answers

Answer:

Warmer

Cooler

Explanation:

when 18.0 g H20 is mixed with 33.5 g Fe, which is the limiting reactant?

Answers

Answer:

si.mple fe

Explanation:

ghhsshzhzbbzhh

n-hexane boils at 68.7 oC at 1.013 bar and the heat of Vaporization is 28850
J/mol. Calculate Its Entropy ?

Answers

He one 28850




C. C c c.

A silver bar with a specific heat of 0.235J/gºC has a mass of 250.g and is heated from 22.0°C to 68.5°C. How much heat will the silver bar absorb?​

Answers

Answer:

2731.875 J

Explanation:

Applying

Q = cm(t₂-t₁)................ Equation 1

Where Q = amount of heat, c = specific heat capacity of silver, m = mass of silver, t₂ = Final temperature of silver, t₁ = Initial temperature of silver

From the question,

Given: c = 0.235 J/g°C, m = 250 g, t₁ = 22.0°C, t₂ = 68.5°C

Substitute these values into equation 1

Q = 0.235×250(68.5-22.0)

Q = 58.75(46.5)

Q = 2731.875 J

Many enjoys the warm waters of a ______.
Geyser
Volcano
Hot spring
Furmarole
Tectonic​

Answers

Answer:

hot spring

Explanation:

The mineral water in hot springs can also help reduce stress by relaxing tense muscles. Meanwhile as your body temperature rises in the bath, and then cools once you exit can also help you relax and fall into a deeper sleep.

If the plant population decreased, the amount of carbon in the atmosphere would _______.



Increase


Stay the same


Decrease

Answers

Answer:

increase answer

Explanation:

i hope that is right

Which molecule will have double bonds?
(4 Points)

Fluorine

Nitrogen

Hydrogen

Oxygen

Answers

I believe its oxygen
hope this helps

What is the electronegativity difference
between sodium and chlorine?

Answers

Answer: 2.23 is the difference.

Explanation: Sodium has an electronegativity of 0.93 and Chlorine has an electronegativity of 3.16, so when Sodium and Chlorine form an ionic bond, in which the chlorine takes an electron away from sodium, forming the sodium cation, Na+, and the chloride anion, Cl-.

The blending together of some genes is called:

Answers

Answer:

its called molding

Explanation:

At the start of a reaction, there are 0.0249 mol N2,
3.21 x 10-2 mol H2, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. If the equilibrium constant, K, for the reaction:
N2(g) + 3H2(g)= 2NH3(g)
is 1.2 at this temperature, decide whether the system is at equilibrium or not. If it is not, predict in which direction, the net reaction will proceed.​

Answers

Answer:

Explanation:

The reaction is given as:

[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]

The reaction quotient is:

[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

From the given information:

TO find each entity in the reaction quotient, we have:

[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]

[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]

[tex][N_2] = 0.006857[/tex]

[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]

[tex][H_2] = 9.17 \times 10^{-3}[/tex]

[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]

However; given that:

[tex]K_c = 1.2[/tex]

By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

What is the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm?

Answers

Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: [tex]V_{1}[/tex] = 61 L,      [tex]T_{1}[/tex] = 183 K,      [tex]P_{1}[/tex] = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L[/tex]

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

A 0.682 g sample of a weak monoprotic acid, HA was dissolved in sufficient water to make 50.0 mL of solution and was titrated with a 0.135 molar NaOH solution. After the addition of 10.6 milliliters of base, a pH of 5.65 was recorded. The equivalence point was reached after the addition of 27.4 milliliters of the 0.135 molar NaOH.
a. Calculate the number of moles of acid in the original sample.
b. Calculate the molar mass of the acid HA.
c. Calculate the [H3O+] at pH = 5.65
d. Calculate the number of moles of unreacted HA remaining in solution when the pH was 5.65.
e. Calculate the value of the ionization constant, Ka, of the acid HA.
f. Calculate the value of the ionization constant, Kb, and explain how you would use it to determine the pH of a solution of a known mass of the sodium salt (Na)(A) dissolved in a known volume of water.

Answers

I think it would be A

Which of the following
describes the zone of the
ocean where no light reaches?
A. up to 200 meter depth and includes
photosynthetic plants, sea anemones,
sponges, crabs, and clams
B. the "twilight zone" between 200-1000
meters deep and includes whales and octopi
and little life
C. permanent darkness below 1000 meters
with bioluminescent bacteria, bottom
feeders, and angler fish

Answers

Answer:

Bathypelagic

54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.

Explanation:

The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.

Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.

What is Darkness?

This is referred to the state of being dark as a result of absence of light in the area.

The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.

Read more about Darkness here https://brainly.com/question/24581271

URGENT
Best answer gets Brainliest!
Mg+ 2HCI ——> MgCI2+ H2

Answers

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

What is the Ksp expression for the dissociation of calcium oxalate?Immersive Reader
(4 Points)

Ksp=[Ca⁺²] x [C₂O₄⁻²]

Ksp=[Ca⁺²]² x [C₂O₄⁻²]

Ksp=[Ca⁺²]⁴ x [C₂O₄⁻²]

Ksp=[Ca⁺²] x [C₂O₄⁻²]²

Answers

Answer:

Ksp = [Ca⁺²] × [C₂O₄⁻²]

Explanation:

Step 1: Write the balanced reaction for the dissociation of calcium oxalate

CaC₂O₄(s) ⇄ Ca⁺²(aq) + C₂O₄⁻²(aq)

Step 2: Write the expression for the solubility product constant (Ksp) of calcium oxalate

The solubility product constant is the equilibrium constant for the dissociation reaction, that is, it is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It doesn't include solids nor pure liquids because their activities are 1.

Ksp = [Ca⁺²] × [C₂O₄⁻²]

Estimate the volume of a solution of 5M NaOH that must be added to adjust the pH from 4 to 9 in 100 mL of a 100 mM solution of a phosphoric acid?

Answers

Answer:

3mL of 5M NaOH must be added to adjust the pH to 7.20

Explanation:

When NaOH is added to phosphoric acid, H₃PO₄, the reaction that occurs are:

NaOH + H₃PO₄ ⇄ NaH₂PO₄ + H₂O pKa1 = 2.15

NaOH + NaH₂PO₄ ⇄ Na₂HPO₄ + H₂O pKa2 = 7.20

NaOH + Na₂HPO₄ ⇄ Na₃PO₄ + H₂O pKa3 = 12.38

We can adjust the pH at 7.20 = pKa2 if NaH₂PO₄ = Na₂HPO₄. To make that, we must convert, as first, all H₃PO₄ to NaH₂PO₄ and the half of NaH₂PO₄ to Na₂HPO₄. To solve this question we need to find the moles of phophoric acid in the initial solution. 1.5 times these moles are the moles of NaOH that must be added to fix the pH to 7.20:

Moles H₃PO₄:

100mL = 0.100L * (0.100mol / L) = 0.0100 moles H₃PO₄

Moles NaOH:

0.0100 moles H₃PO₄ * 1.5 = 0.0150 moles NaOH

Volume NaOH:

0.0150 moles NaOH * (1L / 5moles) = 3x10⁻³L 5M NaOH are required =

3mL of 5M NaOH must be added to adjust the pH to 7.20

3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

What is pH?

It is the negative log of the concentration of Hydrogen ions in the solution.

To calculate the volume of NaOH first, calculate the moles of NaOH and H₃PO₄.

Moles of H₃PO₄.

[tex]\rm moles \ of \ H_3PO_4 = 100\rm \ mL = 0.100\rm \ L \times (0.100 \ mol / L)\\\\\rm moles \ of \ H_3PO_4 = 0.01[/tex]

The moles of NaOH:

[tex]\rm Moles \ of \ NaOH =0.01 \ moles \ H_3PO_4\times 1.5 \\\\\rm Moles \ of \ NaOH= 0.0150[/tex]

The volume of NaOH:

[tex]\rm Volume\ of \ NaOH = \rm 0.0150\ moles\ NaOH \times (1 \ L / 5 \ moles) \\\\\rm Volume\ of \ NaOH = 3\times 10^{-3} L[/tex]

Therefore, 3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

Learn more about pH:

https://brainly.com/question/3262317

Calculate the energy of an electron in the n = 2 level of a hydrogen atom.

Answers

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and [tex]n^{th}[/tex] orbit of an atom is as follows.

[tex]E = - \frac{13.6}{n^{2}} eV[/tex]

Substitute the values into above formula as follows.

[tex]E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV[/tex]

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

what is an example of a change in genetic traits of an organism do to human affect

Answers

Answer:

A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.

Explanation:

how to solve x² in differential​

Answers

Answer:

x² = mutiphy by them self

Explanation:

1. Calculate and interpret the equilibrium constant. Using the reaction below.

The equilibrium concentrations 0.60 M for E, 0.80 M for F, and 1.30 M for G. (Note: E, F, and G are all gases.) Do not include your solution.

Answers

Answer:

kc = [G]² / [E] [F], kc = [1.30M]² / [0.60M] [0.80M]

Explanation:

The reaction is:

E + F ⇄ 2G

The equilibrium constant, kc, must be written as the ratio of the molar concentrations of products over reactants. Each concentration powered to its coefficient.

For the reaction of the problem, kc is:

kc = [G]² / [E] [F]

Replacing the given concentrations:

kc = [1.30M]² / [0.60M] [0.80M]

Chemical bond stretching frequencies depend on two major factors, namely atomic weight and bond stiffness. The frequency absorbed is directly proportional to the bond strength (stiffness) but inversely proportional to the atomic weight. Which of the following bonds will give the highest absorption frequency value?
A. C single bond C.
B. C double bond C.
C. All would be the same frequency.
D. C triple bond C.

Answers

Answer:

D. C triple bond C.

Explanation:

The absorption frequency value is highest for carbon-carbon triple bond. The stretching frequencies are much higher than the bending frequency. It mainly depends upon the strength of the bonds as well as masses of the bonded atoms.

The triple bonds have higher stretching strength than the double bonds and double bonds have higher strength than single carbon to carbon bonds.

The triple bonds has a higher bond order, i.e. 3. So it has maximum stretching bonds.

A 0.750 M sample of phosphorus pentachloride decomposes to give phosphorus trichloride and chlorine gases.If the equilibrium concentration of PCl5 is 0.650M,what is the equilibrium constant for the reaction?
PCl5(g) --------> PCl3(g)+ Cl₂(g)
A) Keq = 0.0133
B) Keq = 0.0154
C) Keq = 0.133
D) Keq = 0.154
E) Keq = 65.0

Answers

Answer:

Explanation:

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₅(g) --------> PCl₃(g)+ Cl₂(g)

1 mole               1 mole      1 mole

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₃(g) and  Cl₂(g) formed are .10 M and .10 M

Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]

= .10 M x .10 M / .65 M

= .0154

B ) is the correct choice .

What is the pH of a 6.2 x 10-5 M NaOH solution?

Answers

Answer:

4.21

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]

We have the final answer as

4.21

Hope this helps you

chemical properties of citric acid​

Answers

Answer:

Citric Acid is a weak acid with a chemical formula C6H8O7.

...

Properties of Citric Acid – C6H8O7.

C6H8O7 Citric Acid

Molecular Weight/ Molar Mass 192.124 g/mol

Density 1.66 g/cm³

Boiling Point 310 °C

Melting Point 153 °C

Hope it helps❤️

Chemical formula: C6H8O7
Properties: No color, no smell, Crystal like appearance, Boiling point of 175 C, Melting point of 153 C, Density of 1.66 g/ml, Weak acid

Please help
Apply your knowledge and understanding of equilibrium constant in solving the following problems:

The equilibrium constant Kc for the reaction below is 170 at 500 K.

Determine whether the reaction mixture is at equilibrium when the concentrations of the components at this temperature are as follows:
[N2]=1.50
[H2]=1.00
[NH3]=8.00

If it is not at equilibrium, state and explain in which direction the reaction will proceed.Multi Line Text.
2()+32() ⇄ 23()

Answers

Answer:

The reaction will proceed to the right to attain the equilibrium.

Explanation:

Step 1: Write the balanced equation

2 N₂(g) + 3 H₂(g) = 2 NH₃(g)

Step 2: Calculate the reaction quotient

The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Qc = [NH₃]² / [N₂]² × [H₂]³

Qc = 8.00² / 1.50² × 1.00³ = 28.4

Since Qc ≠ Kc, the reaction is not at equilibrium.

Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.

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