Answers
I believe it is, but report if I'm wrong.
Answer:
I think means of transportation would be muscles and structural support would be bones. Removes waste could be kidneys instead. The others seem right. This is just what I think but I'm not sure
Related Questions
Two cars approach each other from opposite directions each
with a velocity of 54 km/h. One of the cars emits a note of frequency 480 Hz. What will be the approximate frequency
heard in the other car before they cross each other?
Answers
Answer:524 Hz
Explanation:
Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.
What is frequency?Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.
For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,
[tex]f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1[/tex]
Here, [tex]V_s[/tex] is the speed of the sound.
Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.
Convert the unit of velocity of the car as,
[tex]\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s[/tex]
As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.
Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,
[tex]f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz[/tex]
The approximate frequency heard in the other car before they cross each other is 524 Hz.
Learn more about the frequency here;
https://brainly.com/question/1436295
I threw a plastic ball in the pool for my dog to fetch. The mass of the ball was 125g. What must the volume be to have a density of 0.500g/mL
Answers
Answer:
250 mL
Explanation:
Density equation:
[tex]Density = \frac{mass}{volume}[/tex]
Variables:
D = density
m = mass
V = volume
Solve:
M = 125 g
D = 0.500 g/mL
V = ?
[tex]0.500 g/mL = \frac{125 g}{V}[/tex]
V = 250 mL
Compare an earthquake with a Richter scale magnitude of 5.5 to one with a magnitude of 7.5.
____________________________________________________________________
A. 2 times stronger
B. 1000 times stronger
C. 100 times stronger
D. 20 times stronger
Answers
Answer:
100 stronger
Explanation:
Why do you think the Senate requires a greater percentage of votes?
Answers
Answer:
yes
Explanation:
yes
What is a wavelength of induced radiation quantum if 2-nd order diffraction maximum change on distancе 3.5 сm from сentral and distance between screen to diffraction lattice 0.5 m? Lattice period 0.01 mm.
Answers
Answer:
λ = 3,5 10⁻⁷ m
Explanation:
El fenómeno de difracción es descrito por la expresión
a sin θ = m λ
usemos trigonometría para encontrar el sino
tan θ = y/L
tan θ = sin θ /cos θ
los experiemtos de difraccion ocurran para langulos pequeños
tan θ = sin θ
sin θ =y/L
substituimos
a y/L = m λ
λ = a y /m L
calculemos
λ = 0,01 10-3 0,035 / 2 0,5
λ = 3,5 10⁻⁷ m
an object with a mass of 3.2 kg has a force of 7.3 newtons applied to it. what is the resulting acceleration of the object?
Answers
Answer:
2.28m/s^2
Explanation:
F=ma
a=F/m
a=7.3/3.2
a=2.28m/s^2
By riding an elevator up 200 m, a person’s GPE increases by 164,000 J. What is the person’s mass?
Answers
Answer:
Person’s mass M = 83.67 kg (Approx.)
Explanation:
Given:
Gravitational potential energy = 164,000 J
Height = 200 m
Find:
Person’s mass M
Computation:
Gravitational acceleration g = 9.8 m/s²
Gravitational potential energy = mgh
164,000 = (m)(9.8)(200)
Person’s mass M = 83.67 kg (Approx.)
when do we experience conservation of energy
Answers
Always, whether we notice it or not. It's a law of nature.
Method
1. Place a trolley on a smooth runway and tilt the runway very slightly so that the
slope compensate for the friction between the wheels and the runway. If
pushed gently, the trolley should move at a constant velocity.
2. Measure the mass of the trolleys.
3. Attach the ticker timer to the trolley and thread the tape through the ticker
timer.
4. Attach a smooth pulley vertically to the bottom of the runway.
Answers
Answer:
3
Explanation:
it's too because on you measuring mass of something
Which phase of matter makes up stars?
Answers
Answer:
Plasma is a phase of matter that makes up stars.
magnetism is an example of:
A. contact force
B. non-contact force
C.friction
Answers
Answer:
The answer is Non contract force
if an object isn't moving the forces are acting on the object are: A. not present B. unbalanced C. balanced D. accelerated
Answers
a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity
Answers
Answer:
v = 1.098 m/s
Explanation:
Given that,
A person walks 750m due north then 250 m due east of the entire walk takes 12 min.
We need to find the average velocity of the person.
Displacement,
[tex]d=\sqrt{750^2+250^2} \\\\d=790.56\ m[/tex]
Average velocity = displacement/time
[tex]v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s[/tex]
So, the average velocity of the person is 1.098 m/s.
. The Soviet Yuri Gagarin was the first human to orbit Earth true or false
Answers
Answer:
true , I searched and got u the answer
4. What is the frequency of an electromagnetic wave with a wavelength
of 20 m?
Answers
Answer:
The frequency of radio waves with a wavelength of 20m is
1.5 e+7 Hertz (Hz) or 15 million Hertz.
This was obtained from the formula speed (c) is equal to the product of frequency (f) and wavelength (λ)
c = fλ
Since we are looking for the frequency, we will divide both sides of the formula above by the lamda symbol for wavelength, which gives us:
f = c / λ
The value of wavelength is already given which is 20 meters. The speed of radio waves is the same with the speed of light when travelling in a vacuum – also with the other electromagnetic waves. Hence the speed (c) is 3 e+8 m/s
f = 3 e+8 m/s / 20m
f = 1.5 e+7 H
Explanation:
this is the correct answer you want.
Wavelength and frequency have an inverse relationship. Which of these other examples also shows an inverse relationship?
A. Distance covered on a hike versus the number of steps taken
B. Grade on an assessment versus the amount of time spent studying
C. Time it takes to get somewhere versus driving speed
D. None of these shown an inverse relationship
Answers
When conducting an experiment, a scientist should exhibit all of these traits EXCEPT
a-bias
b-curiosity
c-honesty
d-skepticism
Answers
..............
When conducting an experiment, a scientist should exhibit all of these traits except bias. Thus, the correct option for this question is A.
What are the properties of scientists?The properties of scientists are as follows:
They must be curious about their work.They must have a lot of patience as they are required to repeat experiments multiple times. Their courageous behavior motivates them to perform consistently.They are open-minded and free from any type of cultural and religious bias. They are creative, persistent, communicative, and detail-orientated individuals.If scientists have properties of bias and discrimination, they never work consistently and are focused because their biased behavior ruins their interest, talent, and future perspectives.
Therefore, when conducting an experiment, a scientist should exhibit all of these traits except bias. Thus, the correct option for this question is A.
To learn more about Scientists, refer to the link:
https://brainly.com/question/26386481
#SPJ2
PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.
Answers
Answer:
282,250 joules
Explanation:
Given that :
Mass of liquid water = 125 gram.
Latent heat of vaporization, L = 2258 J/g
Recall :
Q = mL
Where, Q = quantity of heat required in Joules
Mass) m
L = latent heat of vaporization
Q = mL
Q = 125 g * 2258j/g
Q = 282,250 joules
Can someone please explain why the answer to this net torque question is +115 Nm
Answers
Answer:
Net torque in positive direction:
Fz = -450 * cos 30 deg * 1.5 = -585 N-M
Fz = 200 * 3.5 = 700 N-M
Net F = 115 N-M
Torque is generally defined as L = R X F
X cross Y = Z normal coordinate system
Note that Z will be out of the page giving the positive value for the torque.
given a force of 75N and an acceleration of 3m/s2, what is the mass
Answers
force = 75N --- (given)
acceleration = 3m/s² ---- (given)
FORCE = mass × acceleration75N = mass × 3m/s²
mass = 75÷3
mass = 25kg-----------------------------FOLLOW ME.What is the work done in a 20-Newton object that is being moved in a 4-meter distance? show
calculation *
Answers
Answer:
Explanation:
Harrison pursued the British forces and defeated them at the Battle of the Thames in October. This victory put an end to the British threat to the Northwest—and also claimed the life of Tecumseh, who died in the battle fighting for the British.
f=20N d=4m
W= f times d
W= 20 times 4
W= 80 joules
A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it take the driver to complete the course?
Answers
Answer:
t = 1023.9 seconds
Explanation:
Given that,
The average velocity of a Mustang, v = 33m/s
Distance, d = 21 miles = 33789 m
Let the driver takes t seconds. So,
Speed = distance/time
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{33789}{33}\\\\t=1023.9\ s[/tex]
So, it will take 1023.9 seconds to complete the course.
15. If a dog pulls a 5 kg sled with a force of 70 N, what is its acceleration?
Answers
Answer:
14 m/s^2
Explanation:
We have to use the equation F=ma because the question is a Newton's second law question.
First, list known values
F (force) = 70 N
m (mass) = 5 kg
a (acceleration) = ? (we have to solve for this)
Second, plug in known values into equation.
F=ma
70=5a
Third, solve. To solve this all you have to do is divide both sides by 5
70/5=5/5a
Fourth, your answer will be 14 meters per second squared (m/s^2)
I hope this answer helps and have a great day!
pick the correct answer there are three correct answers
Answers
An object has a mass 4kg kept at a height 6m what is its gravitational energy?
Answers
Answer:
-24 from the solution I got using this formula pe=mgh and pe=0 then make g as a subject of the formula
A rocket is launched vertically and returns its launch point in 7 seconds.
a. What us it’s launch velocity?
b. How high did it go?
C. What is its velocity right before it hits ground?
Answers
Answer:
A. 35 m/s
B. 61.25 m
C. 35 m/s
Explanation:
From the question given above, the following data were obtained:
Time of flight (T) = 7 s
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Time of flight (T) = 7 s
Time (t) take to reach maximum height =?
T = 2t
7 = 2t
Divide both side by 2
t = 7/2
t = 3.5 s
A. Determination of the Lauch velocity.
Time (t) to reach maximum height = 3.5 s
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) =?
v = u – gt (since the rocket is going against gravity)
0 = u – (10 × 3.5)
0 = u – 35
Collect like terms
0 + 35 = u
u = 35 m/s
Thus, the Lauch velocity is 35 m/s
B. Determination of maximum height reached by the rocket.
Final velocity (v) = 0 (at maximum height)
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) = 35 m/s
Maximum height (h) =?
v² = u² – 2gh (since the rocket is going against gravity)
0² = 35² – (2 × 10 × h)
0 = 1225 – 20h
Rearrange
20h = 1225
Divide both side by 20
h = 1225 / 20
h = 61.25 m
Thus, the maximum height reached by the rocket is 61.25 m
C. Determination of the velocity before hitting ground.
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 10 m/s²
Time (t) to reach the ground from the maximum height = 3.5 s
Final velocity (v) =?
v = u + gt (since the rocket is moving towards gravity)
v = 0 + (3.5 × 10)
v = 0 + 35
v = 35 m/s
Thus, the velocity of the rocket before hitting ground is 35 m/s
A diver leaves the end of a 5.00 m high diving board and reaches a maximum height of 5.50 m before she strikes the water below. The landing point is 3.25 m beyond the end of the diving board in the horizontal direction. You may approximate the diver as a point particle. Hint: Carefully consider your placement of the origin before starting your calculations.
Determine:_____.
(a) After the diver leaves the diving board, how long does it take for her to strike the water?
(b) The initial velocity of the projectile 7. (hint: a vector has both direction and magnitude).
(c) The final velocity with which the diver enters the water ö, (hint: a vector has both direction and magnitude).
Answers
Answer:
a) 1.38 s
b) v₀ = 3.92 m/s θ₀ = 53.1º
c) vf = 10.7 m/s θf = -77.2º
Explanation:
a)
Once the diver leaves the board, she has an initial velocity vector, that we can split in two directions perpendicular each other, the vertical direction (coincident with the y-axis, positive upward) and the horizontal direction (coincident with the x-axis, positive away from the diving board).These velocities, are independent each other, due to they are perpendicular.In the horizontal direction, since no acceleration takes place, she keeps the horizontal component v₀ₓ, constant.In the vertical direction, she is always accelerated downward by gravity, which constant value is g = 9.8m/s2.With this all information, we can find the total time since she left the diving board till she strikes the water below, taking advantage of the fact that she reached to a maximum height of 5.5 m,i.e. , 0.5m above the diving board. When at this point, the vertical component of the velocity is zero, so we can write the following kinematic equation:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (1)[/tex]
Solving for v₀y in (1):[tex]v_{oy} = \sqrt{2*g*\Delta_{ymax} } = \sqrt{2*9.8m/s2*0.5m} = 3.13 m/s (2)[/tex]
When she is at the highest point, her final vertical speed is zero, so we can find the time when she reached to this point, applying the definition of acceleration, as follows:[tex]v_{fyhmax} = v_{oy} - g*t_{hmax} = 0 (3)[/tex]
Solving for t in (3), we get:[tex]t_{hmax} =- \frac{v_{oy}}{g} =\frac{3.13m/s}{9.8m/s2} = 0.32 s (4)[/tex]
Since at this point, the vertical speed is zero, we can apply the equation for the displacement (vertical in this case) for a total displacement of 5.5 m (taking as the origin the point just below the end of the diving board, on the surface of the water), with initial speed equal to zero, as follows:[tex]\Delta y = \frac{1}{2}* g * t^{2} = 5.5 m (5)[/tex]
Solving for t (which we will call t₂) in (5), we get:[tex]t_{2} = \sqrt{\frac{2*\Delta y}{g}} = \sqrt{\frac{2*5.5m}{9.8m/s2} } = 1.06 s (6)[/tex]
The total time will be just the sum of (4) (since leaving the diving board till reaching the maximum height) and (6) (from there until she strikes the water), as follows:Δt = thmax + t₂ = 0.32 s + 1.06 s = 1.38 s (7)b)
In order to know the value of v₀, we need first to get the values of vox and voy.We know that the horizontal speed remains constant, so, if we know the total time traveled (same as in a)) and the horizontal distance (given), we can find v₀ₓ applying the definition of average velocity, as follows:[tex]v_{ox} =\frac{\Delta x}{\Delta t} =\frac{3.25m}{1.38s} = 2.36 m/s (8)[/tex]
We know the value of v₀y from (2):[tex]v_{oy} = 3.13 m/s (9)[/tex]
Applying the Pythagorean theorem, we can get the magnitude of v₀ as follows:[tex]v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{(2.36m/s)^{2} + (3.13m/s)^{2}} = 3.92m/s (10)[/tex]
We can find the angle that it makes with the horizontal, applying the definition of tangent of an angle, as follows:[tex]tg_{(\theta o)} = \frac{v_{oy}}{v_{ox} } = \frac{3.13}{2.36} = 1.33 (11)[/tex]
⇒ θ₀ = tg⁻¹ (1.33) = 53.1º
c)
In order to find the vertical component of the final velocity, we can use the following kinematic equation, for the total vertical displacement of 5.5 m since it started to fall after reaching to the maximum speed:[tex]v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (12)[/tex]
When it started to fall, in the vertical direction, the diver was at rest, so in (12) we have v₀y = 0.Solving for vfy in (12) we get:[tex]v_{fy} = \sqrt{2*g*\Delta_{y} } = \sqrt{2*9.8m/s2*5.5m} = -10.4 m/s (13)[/tex]
We already know that the horizontal component is the same as the initial v₀ₓ, so we can find the magnitude of the final velocity applying the Pythagorean Theorem as follows:[tex]v_{f} = \sqrt{v_{fx}^{2} + v_{fy}^{2}} = \sqrt{(2.36m/s)^{2} + (-10.4m/s)^{2}} = 10.7 m/s (14)[/tex]
Finally, as we did in (11) to find the angle that it makes with the horizontal, we can find θf as follows:[tex]tg_{(\theta f)} = \frac{v_{fy}}{v_{fx} } = \frac{-10.4}{2.36} = -4.41 (15)[/tex]
⇒ θf = tg⁻¹ (-4.41) = -77.2º
Which of the following DOES NOT affect the electric force?
Answers
Answer:did you get an answer ?
Explanation:
When you mix red and blue pigment, you produce the color:
orange
black
red
violet
Answers
Answer:
violet
Explanation:
pick the correct answer