Is this an element?
Cu20
O Yes, it's made of 1 type of atoms
O No it's made of more than 1 type of atoms

Answers

Answer 1

Answer:

Yes, its made of 1 types of atoms

Explanation:

Cu20 is Copper(I) oxide or cuprous oxide


Related Questions

what is the percent composition of (NH4)2S?
if you can, include the problem shown pls
extra.
Mg(NO3)2
please don't just take the points please :(, do the problem
thank you <333

Answers

(NH₄)₂S

%N=  41.18%

%H =11.76%

%S=47.06%

Mg(NO₃)₂

%Mg=32.43%

%N=18.92%

%O=(64.86%

Further explanation

Given

(NH₄)₂S

Mg(NO₃)₂

Required

The percent composition

Solution

(NH₄)₂S MW=68 g/mol

%N=2. Ar N  / MW (NH₄)₂S x 100%

%N= (2.14/68) x 100% = 41.18%

%H =(8.1/68) x 100%=11.76%

%S=(32/68)x 100%=47.06%

Mg(NO₃)₂ MW=148 g/mol

%Mg=(2.24/148)x100%=32.43%

%N=(2.14/148)x100%=18.92%

%O=(6.16/148)x100%=64.86%

The wastewater produced by offices is called __

Answers

Sewage is the wastewater containing both liquid and solid wastes produced by human activities from homes, industries, hospitals, offices, etc. Sewage contains various contaminants including disease-causing bacteria and other microbes.

Answer:

sullage or grey water

Explanation:

sources include: sinks, showers, baths, washing machines, dishwashers and no not toliets.

Which activity is an example of a scientist using creativity?
a scientist exploring evidence from other fields of science to support findings
a scientist transferring data from one experiment into the data analysis from a second experiment
a scientist repeating an older experiment with the latest technology to verify the original findings
a scientist using the latest graphing software to analyze and present the research

Answers

A scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

What is creativity?

Creativity is a mental cognitive ability that involves the creation and/or discovery of a hidden process.

In science, creativity refers to the application of mental skills to create new experimental designs and extrapolate findings.

In conclusion, a scientist exploring evidence from other fields of science to support findings is an example of a scientist using creativity.

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Gaseous phosphorus pentachloride decomposes to gaseous phosphorus trichloride and chlorine at a temperature where K= 1.0x10^-3 mol/L. Suppose 2.0 mole of phosphorus pentachloride in a 2.0-L vessel is allowed to come to equilibrium. Calculate the equilibrium concentrations of all species.

Answers

Answer:

[PCl₃] = 0.031M

[Cl₂] = 0.031M

[PCl₅] = 0.969M

Explanation:

Based on the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

Keq is defined as:

Keq = 1.0x10⁻³ = [PCl₃] [Cl₂] / [PCl₅]

Where [] are equilibrium concentrations of each species

Inital [PCl₅] = 2.0mol / 2.0L = 1M.

In equilibrium:

[PCl₃] = X

[Cl₂] = X

[PCl₅] = 1M-X

Where X is reaction coordinate

Solving for X in Keq:

1.0x10⁻³ = [X] [X] / [1-X]

1.0x10⁻³ - 1.0x10⁻³X = X²

1.0x10⁻³ - 1.0x10⁻³X - X² = 0

X:

X = -0.032M. False solution, there is no negative concentration

X = 0.031M

That means equlibrium concentrations are:

[PCl₃] = 0.031M

[Cl₂] = 0.031M

[PCl₅] = 1-0.031M = 0.969M

[PCl₃] = 0.031M[Cl₂] = 0.031M[PCl₅] = 0.969M

What is the proper value for C in the above table.
A. 28
B. 30
C. 32
D. 65

Answers

Answer:

28

Explanation:

electron = atomic number - charge(if the charge is positive and addition if the charge is negative)

electron = 30 - 2

electron = 28

KOH + _co2 -_ксоз + _Н,0

Answers

Answer:

2KOH + 3co2 ------->2ксоз + 2Н20

: How are reefs impacted by disease?

Answers

Answer:

The frequency of coral diseases has increased significantly over the last 10 years, causing widespread mortality among reef-building corals. Many scientists believe the increase is related to deteriorating water quality associated with human-made pollutants and increased sea surface temperatures.

Explanation:

Diseases are classified into _______ and _____ based on their duration.

Answers

Answer:

communicable and non-communicable?

What group number is Plutonium in and how do you know?

Answers

Answer:Actinide Group

Explanation:Plutonium is a member of the actinide group in the periodic table. Plutonium atoms have 94 electrons and 94 protons with 2 valence electrons in the outer shell. There are 150 neutrons in the most abundant isotope.

What is the product of the unbalanced combustion reaction below?

Answers

Answer: A

Explanation:

Answer:

C

Explanation:

because the combustion reaction produce vapor water and CO2

What is the volume of 1.8 moles of O2?

Answers

Answer:

33.6 i think

Explanation:

33.6 is the correct answer

A rigid vessel contains 2.5 mol of H2(g). How many grams of hydrogen are in the vessel.

Answers

Answer:

5 g of H₂ are contained in the vessel

Explanation:

A typical excersise of conversion:

We determine molar mass of H₂.

This is a dyatomic molecule, as molar mass of H is 1g/mol, molar mass of H₂ will be 2g/mol.

Let's make the conversion of units:

2.5 mol . 2g/mol = 5 g

5 g of H₂ are contained in the vessel

Mass of hydrogen in the vessel = 5 grams

Number of moles:

The number of moles is defined as the given mass over molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given:

Number of moles= 2.5 mol

To find:

Mass of hydrogen=?

Molar mass of hydrogen =2g/mol

On substituting the values in the given formula we will get:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}=2.5 mol* 2g/mol\\\\\text{Given mass}=5 g[/tex]

Thus, mass of hydrogen in the vessel is 5 grams.

Learn more:

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Please help me.
Thank you!

Answers

Answer: Positive

Explanation: Just a guess

Answer:

Positive

Explanation:

Compare and contrast protons and neutrons. Use A.C.E.

A= Answer
C= Cite Evidence
E= Expand

Answers

Like protons, neutrons are bound into the atom's nucleus as a result of the strong nuclear force. Protons and neutrons have approximately the same mass.also nutrons are neutral and protons are positively charged.

Workout the formula for:
Magnesium Bromide
Potassium Chloride ​

Answers

Magnesium bromide= MgBr2
Potassium chloride= KCl

WhT is the amount of NaCI that can be added to 50.0g of water at 60.0oc?

Answers

Answer:

the image won't load so maybe upload it again please

which atomic particles have no charge? ​

Answers

Answer:

the answer is neutron :)))))))))

EASY BUT I STILL NEED HELP
Compared to ice, how do molecules of water behave?
Group of answer choices

1.They Move less freely

2.They are locked into a crystal shape or lattice

3.They move more freely

4.They bounce off one another freely

Answers

Answer: 3 they move more freely since water is a liquid and ice is a solid in a solid molecules are more compact and cannot move around much but in a liquid it moves more freely than it would in a solid.

Explanation:

Compared to ice, molecules of water behave differently in that they move more freely. The Option C.

How do the behaviors of water molecules compare to those of ice?

In the solid state, water molecules arrange themselves into a crystal structure, forming a lattice in ice. This lattice structure restricts the movement of the water molecules causing them to vibrate in fixed positions.

On the other hand, in the liquid state, the water molecules have more kinetic energy allowing them to move more freely and interact with each other by forming temporary hydrogen bonds. This increased mobility of water molecules in the liquid state enables them to flow and take the shape of their container.

Read more about water molecules

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1.When acids react with carbonates,------------gas is liberated.

Answers

Answer:When acids react with carbonates,---CO2--------gas is liberated.

Explanation:

Acids liberate Carbon IV oxide when they react with  Carbonates  bicarbonate

For examples

Acid +carbonate  ⟶ Salt + Water + Carbon dioxide

Calcium carbonate + Hydrochloric acid  will give Calcium chloride with the liberation of CO2 gas and water

CaCO3 + 2HCl →CaCl2 + CO2 + H2O

To Test for the presence of the CO2 Liberated, we pass the gas through lime water, if the lime water turns milky, then C02 gas is confirmed.

16.
A mixture of methane and oxygen gases, at a total pressure of 701 mm Hg, contains 2.75 grams of methane and 3.45 grams of oxygen. What is the partial pressure of each gas in the mixture?

PCH4 = __
mm Hg
PO2 = ___
mm Hg

Answers

Answer:

P(O₂) = 287.41 mmHg

P(O₂) = 413.59 mmHg

Explanation:

Given data:

Total pressure = 701 mmHg

Mass of methane = 2.75 g

Mass of oxygen = 3.45 g

Partial pressure of each gas = ?

Solution:

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 2.75 g/ 16 g/mol

Number of moles = 0.17 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 3.45 g/ 32 g/mol

Number of moles = 0.12 mol

Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol

Partial pressure of oxygen:

P(O₂)  = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.12  / 0.29 ] × 701 mmHg

P(O₂) = 0.41 × 701 mmHg

P(O₂) = 287.41 mmHg

Partial pressure of methane:

P(O₂)  = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.17  / 0.29 ] × 701 mmHg

P(O₂) = 0.59 × 701 mmHg

P(O₂) = 413.59 mmHg

A silver cube with an edge length of 2.28 cm and a gold cube with an edge length of 2.75 cm are both heated to 82.8 ∘C and placed in 111.5 mL of water at 20.2 ∘C . What is the final temperature of the water when thermal equilibrium is reached?

Answers

Solution :

Given :

length of silver cube = 2.28 cm

length of gold cube = 2.75 cm

Initial temperature = 82.8°C

Volume of silver cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.28)^3$[/tex]

                [tex]$= 11.8 \ cm^3$[/tex]

mass of silver cube

Mass, [tex]$m_s = \text{density} \times \text{volume} $[/tex]

                = 10.5 x 11.8

                = 123.9 g

Similarly, the volume of gold cube is

Volume [tex]$=(\text{edge length})^3$[/tex]

               =    [tex]$(2.75)^3$[/tex]

                [tex]$= 20.79 \ cm^3$[/tex]

mass of gold cube

Mass, [tex]$m_g = \text{density} \times \text{volume}$[/tex]

                = 19.3 x 20.79

                = 401.247 g

Now

heat lost by silver and gold cube = heat gained by water

∴[tex]$m_g .c_g \Delta T + m_s .c_s \Delta T = m_w.c_w \Delta T$[/tex]

[tex]$m_g .c_g (82.8- T) + m_s .c_s (82.8- T) = m_w.c_w (T - 20.2)$[/tex]

[tex]$401.247 \times 0.1264 (82.8- T) + 123.9 \times 0.2386 (82.8- T) = 111.5 \times 4.184 (T - 20.2)$[/tex]

Now solving the equation

[tex]$50.71 (82.8- T) + 29.56 (82.8- T) = 466.51 (T - 20.2)$[/tex]

Final temperature, T = 31.27°C

Marianne designs an experiment involving electrically charged objects. She wants to know which objects will be attracted to a negatively charged balloon. Identify the test variable, the outcome variable, and the control variable for this experiment.
WILL GIVE BRAINIST

Answers

Answer:

When one object is rubbed against another, static electricity can be created. This is because the rubbing creates a negative charge that is carried by electrons. The electrons can build up to produce static electricity. For example, when you shuffle your feet across a carpet, you are creating many surface contacts between your feet and the carpet, allowing electrons to transfer to you, thereby building up a static charge on your skin. When you touch another person or an object, you can suddenly discharge the static as an electrical shock.

Similarly, when you rub a balloon on your head it causes opposite static charges to build up both on your hair and the balloon. Consequently, when you pull the balloon slowly away from your head, you can see these two opposite static charges attracting one another and making your hair stand up.

Materials

• Balloon

• An object made out of wool (such as a sweater, scarf, blanket or ball of yarn)

• Stopwatch

• A wall

• A partner (optional)

Preparation

• Blow up the balloon and tie off the end.

• Have your partner prepare to use the stopwatch.

Procedure

• Hold the balloon in a way that your hand covers as little of its surface area as possible, such as by using only your thumb and pointer finger or by gripping the balloon by its neck where it is tied off.

• Rub the balloon on the woolly object once, in one direction.

• Hold the balloon up on the wall with the side that was rubbed against the wool facing the wall, then release it. Does the balloon stay stuck on the wall? If the balloon stays stuck, have your partner immediately start the stopwatch to time how long the balloon remains bound to the wall. If the balloon does not stick, move to the next step.

• Touch the balloon to a metal object. Why do you think this is important to do?

• Repeat the above process but each time increase the number of times you rub the balloon on the woolly object. Rub the balloon in the same direction each time. (Do not rub the balloon back and forth.)

Observations and results

In general, did the balloon stick to the wall for a longer amount of time as you increased the number of times you rubbed the balloon on the woolly object?

Wool is a conductive material, which means it readily gives away its electrons. Consequently, when you rub a balloon on wool, this causes the electrons to move from the wool to the balloon's surface. The rubbed part of the balloon now has a negative charge. Objects made of rubber, such as the balloon, are electrical insulators, meaning that they resist electric charges flowing through them. This is why only part of the balloon may have a negative charge (where the wool rubbed it) and the rest may remain neutral.

When the balloon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall. Although the wall should normally have a neutral charge, the charges within it can rearrange so that a positively charged area attracts the negatively charged balloon. Because the wall is also an electrical insulator, the charge is not immediately discharged. However, because metal is an electrical conductor, when you rub the balloon against metal the extra electrons in the balloon quickly leave the balloon and move into the metal so the balloon is no longer attracted and does not adhere.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST

The test variables and the control variable and the outcome variables are Balloons, the electrical insulators, and resist electric charges flowing through them.

What are variables?

When we brush a balloon against our head, the hair and balloon both develop opposing static charges. We can see how these two opposing static charges attract one another and make our hair stand up as the balloon is gently dragged away from our head.

When a balloon is rubbed to the wall, it will be attracted to the wall. Because the wall is an electrical insulator, the charge is not quickly discharged.

The excess electrons in the balloon immediately leave the balloon and go into the metal when it is rubbed against metal. As a result, the balloon is no longer attracted to the metal and does not adhere.

Therefore, Balloons, which act as electrical insulators and prevent the flow of electric charges, serve as the test, control, and outcome variables.

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how are volcanologist and meteorologist similar and different?​

Answers

Answer:

They are different because one is someone who studies volcanoes and the other is someone who studies weather

Explanation:

which is an example of radiation?
Hot air rises and cool air moves in to take its place.

Heated water begins circulating in a fish tank.

Your car parked in the sun is hot when you return.

You burn your feet on a hot sidewalk on a sunny day.

Answers

Answer:

Heated water begins circulating in a fish tank.

Explanation:

Answer:

Heated water begins circulating in a fish tank.

What is the molarity of a solution with 1.43 moles of sodium chloride in 0.875 liters of solution?

Answers

Answer:

1.63 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Chemistry

Unit 0

Reading a Periodic TableWriting Compounds

Aqueous Solutions

Molarity = moles of solute / liters of solutionExplanation:

Step 1: Define

1.43 mol NaCl (sodium chloride)

0.875 L solution

Step 2: Find M

Substitute [M]:                      x M = 1.43 mol NaCl / 0.875 LDivide:                                   x = 1.63429 M

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.63429 M ≈ 1.63 M

animal and Plant Cells Worksheet Word ​

Answers

Answer:

u didnt give a worksheet

Explanation:

16.A mixture of carbon dioxide and hydrogen gases contains carbon dioxide at a partial pressure of 217 mm Hg and hydrogen at a partial pressure of 703 mm Hg. What is the mole fraction of each gas in the mixture?

XCO2 =

XH2 =

Answers

x CO₂  = 0.236

x H₂  = 0.764

Further explanation

Given

P CO₂ = 217 mmHg

P H₂ = 703 mmHg

Required

The mole fraction

Solution

Dalton's law :

The total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

P tot for the mixture :

= 217 mmHg + 703 mmHg

= 920 mmHg

Mole fraction of each gas :

x CO₂ = 217 mmHg/920 mmHg = 0.236

x H₂ = 703 mmHg/920 mmHg = 0.764

The specific branch of chemistry that focuses on molecules such as salts and water that constitute non-living matter, but are still important to living things, is termed

Answers

Answer: Inorganic chemistry

Explanation:

Inorganic chemistry can be defined as the branch of chemistry which studies the behavior of the inorganic compounds. Inorganic compounds are those compounds which lack carbon hydrogen bonding. The carbon monoxide, carbon dioxide, sodium chloride and water are the examples of inorganic compounds. This branch also studies the effect of these chemical compounds on the living things. The water and salts are chemicals which regulate the chemical and physiological reactions in the body.

What is the completed balanced reaction for the replacement Al×H2SO4

Answers

Answer:

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + 3 H₂(g)

Explanation:

Let's consider the unbalanced equation for the single replacement reaction between Al and H₂SO₄.

Al(s) + H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

We will begin balancing S atoms by multiplying H₂SO₄ by 3.

Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

Then, we balance Al atoms by multiplying Al by 2.

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + H₂(g)

Finally, we get the balanced equation by multiplying H₂ by 3.

2 Al(s) + 3 H₂SO₄(aq) ⇒ Al₂(SO₄)₃(aq) + 3 H₂(g)

100 POINTS!!! ANSWER ASAP

Answers

Answer:

1eV

Explanation:

Answer:

1ev

Explanation:

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